Awoodda korantada - dhibaatooyinka iyo xalalka

Awoodda korantada - dhibaatooyinka iyo xalalka

1. Saddex dallacaad sida ku cad jaantuska hoose . Waa maxay xoogga korontada ee uu la kulmo dallacaad B. k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C.

La yaqaan:

qA = 10 µC = 10 x 10-6 C = 10-5 CoulombXoogga korontada - dhibaatooyinka iyo xalalka 1

q B = 10 µC = 10 x 10 -6 = 10 -5 Coulombs

q C = 20 µC = 20 x 10 -6 = 2 x 10 -5 Coulombs

r AB = 0.1 m = 10 -1 m

r BC = 0.1 m = 10 -1 m

k = 9 x 10 9 Nm 2 C −2

La Raadinayo: Awood koronto oo ay khibrad u leedahay dallac B

Xalka:

Waxaa jira laba xoog oo koronto ah oo ku shaqeeya dallacaadda B, taas oo ah xoogga korontada ee u dhexeeya dallacaadda A iyo dallacaadda B (F AB ) iyo sidoo kale xoogga korontada ee u dhexeeya dallacaadda B iyo C (F BC ). Xoogga korontada ee ay la kulanto dallacaadda B waa natiijada xoogga F AB iyo xoogga F BC.

Xoogga korontada ee u dhexeeya dallacaadaha A iyo B:

Xoogga korontada - dhibaatooyinka iyo xalalka 2

Dalacaadda A waa togan tahay, dalacaadda B-na waa togan tahay, sidaa darteed jihada F AB waxay tilmaamaysaa dalacaadda C.

Xoogga korontada ee u dhexeeya dallacaadaha B iyo C:

Xoogga korontada - dhibaatooyinka iyo xalalka 3

Kharash B waa togan yahay, kharash C-na waa togan yahay, sidaa darteed F BC waxay tilmaamaysaa kharash A.

Awoodda korantada ee ay soo martay dallacaadda B:

F B = F BC – F AB = 180 – 90 = 90 N.

Baaxadda xoogga korontada ee uu la kulmo dallacaadda B (F B ) waa 90 Newtons. Jihada F B waxay la mid tahay jihada F BC , waxayna tilmaamaysaa dallacaadda A.

2. Waa maxay baaxadda iyo jihada xoogga korontada ee ku jira dallacaadda B. ( k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)

Xoogga korontada - dhibaatooyinka iyo xalalka 4

La yaqaan:

Dalac A (q A ) = +Q

Dalac B (q B ) = -2Q

Dalacaadda C (q C ) = -Q

Masaafada u dhaxaysa khidmadaha A iyo B (r AB ) = r

Masaafada u dhaxaysa khidmadaha B iyo C (r BC ) = 2r

k = 9 x 10 9 Nm 2 C −2

La Doonayo: Cabbirka iyo jihada xoogga korontada ee ku jira dallacaadda B.

Xalka:

Xoogga korontada ee u dhexeeya dallacaadaha A iyo B:

Xoogga korontada - dhibaatooyinka iyo xalalka 5

Kharash A waa togan yahay, kharash B-na waa togan yahay, sidaa darteed jihada F AB waxay tilmaamaysaa kharash A.

Xoogga korontada ee u dhexeeya dallacaadda B iyo dallacaadda C:

Xoogga korontada - dhibaatooyinka iyo xalalka 6

Kharash B waa taban, kharash C-na waa taban si jihada F BC ay u tilmaamto kharash A.

Ciidanka saafiga ah wuxuu ku shaqeeyaa dacwadda B:

F = F AB + F BC = 2 k Q 2 / r 2 + 0.5 k Q 2 / r 2 = 2.5 k Q 2 / r 2 = 2.5 k Q 2 r -2

Jihada xoogga korontadu waxay tilmaamaysaa in la dallaco A (bidix).

3. Laba dallac koronto, oo ka muuqda sawirka hoose. Dalacaadda barta A waa 8 µC awoodda korontaduna waxay ku shaqeysaa labada dallac waa 45 N. Haddii dallacaadda A ay u dhaqaaqdo dhanka midig 1 cm, waa maxay xoogga soo jiidashada leh ee ku shaqeeya labada dallac. k = 9.10 9 Nm 2 .C -2.

La yaqaan:

Dareeraha korontada ee barta A (q)A) = 8 µC = 8 x 10-6 CoulombXoogga korontada - dhibaatooyinka iyo xalalka 7

Xoogga korontada ayaa ku shaqeeya labada kharash (F) = 45 Newtons

Masaafada u dhaxaysa labada dallac (r AB ) = 4 cm = 0.04 mitir = 4 x 10 -2 mitir

Joogto ah (k) = 9 x 10 9 Nm 2 .C -2

La Doonayo: Xoogga korontada ee u dhexeeya labada dallac haddii dallac A uu u dhaqaaqo dhanka midig 1 cm.

Xalka:

Koronto ku dallac barta B :

Isle'egta xoogga korontada:

F = k (q A )(q B ) / r 2

F r 2 = k (q A )(q B )

q B = F r 2 / k (q A )

Koronto ku dallac barta B :

q B = (45)(4 x 10 -2 ) 2 / (9 x 10 9 )(8 x 10 -6 )

q B = (45)(16 x 10 -4 ) / 72 x 10 3

q B = (720 x 10 -4 ) / (72 x 10 3 )

q B = 10 x 10 -7 Coulombs

Xoogga korontada ee u dhexeeya dallacaadaha korontada A iyo B:

Haddii dallacaadda A ay u dhaqaaqdo dhanka midig 1 cm markaas masaafada u dhaxaysa labada dallac waa 3 cm = 0.03 mitir = 3 x 10 -2 mitir.

Arag sidoo kale  Istaatiko dareere ah - dhibaatooyinka iyo xalalka

F = k (q A )(q B ) / r 2

F = (9 x 10 9 )(8 x 10 -6 )(10 x 10 -7 ) / (3 x 10 -2 ) 2

F = (9 x 10 9 )(80 x 10 -13 ) / (9 x 10 -4 )

F = (1 x 10 9 )(80 x 10 -13 ) / (1 x 10 -4 )

F = (80 x 10 -4 ) / (1 x 10 -4 )

F = 80 Newton

4. Laba dallac koronto oo ku yaal meelaha P iyo Q waxaa loo kala saaraa masaafo dhan 10 cm, waxayna la kulmaan xoogga soo jiidashada leh ee 8 Newton. Haddii dallac Q uu u dhaqaaqo 5 cm si uu u dallaco P, markaa waa maxay xoogga korontada. (1 µC = 10 -6 C iyo k = 9 x 10 9 Nm 2 .C -2 ).

La yaqaan:

Masaafada u dhaxaysa khidmadaha P iyo Q (r)PQ) = 10 cm = 0.1 m = 1 x 10-1 m Xoogga korontada - dhibaatooyinka iyo xalalka 8

Xoogga korontada ee u dhexeeya dallacaadaha P iyo Q (F) = 8 N

Dakhli koronto Q (q Q ) = 40 µC = 40 x 10 -6 C

Joogto ah (k) = 9 x 10 9 Nm 2 .C -2

La Raadinayo: Awoodda korantada ee u dhaxaysa dallacaadaha P iyo Q haddii dallacaadda Q loo raro 5 cm si loogu dallaco P.

Xalka:

Marka hore, xisaabi lacagta korontada ee P, ka dibna xisaabi xoogga korontada ee u dhexeeya labada dallac, haddii lacagta korontada ee Q loo raro 5 cm si loogu dallaco P.

Dakhli koronto P :

q P = F r 2 / k (q Q )

q P = (8)(1 x 10 -1 ) 2 / (9 x 10 9 )(40 x 10 -6 )

q P = (8)(1 x 10 -2 ) / 360 x 10 3

q P = (8 x 10 -2 ) / (36 x 10 4 )

q P = (1 x 10 -2 ) / (4.5 x 10 4 )

q P = (1 / 4.5) x 10 -6 Coulombs

Xoogga korontada ee u dhexeeya dallacaadaha korontada P iyo Q:

Haddii dallacaadda barta Q loo raro 5 cm dhanka bidix markaas masaafada u dhaxaysa labada dallac waa 5 cm = 0.05 mitir = 5 x 10 -2 mitir.

F = k (q P )(q Q ) / r 2

F = (9 x 10 9 )( (1 / 4.5) x 10 -6 )(40 x 10 -6 ) / (5 x 10 -2 ) 2

F = (2 x 10 3 )(40 x 10 -6 ) / (25 x 10 -4 )

F = (80 x 10 -3 ) / (25 x 10 -4 )

F = 3.2 x 10 1

F = 32 Newton

5. Xoogga korontada ee uu ku dhaco dahaadhka q B waa 8 N (1 µC = 10 -6 C iyo k = 9.10 9 Nm 2 .C -2 ). Haddii dahaadhka q B uu ka dhaqaaqo 4 cm A, markaa waa maxay xoogga korontada ee uu ku dhaco q B.

La yaqaan:

Masaafada u dhaxaysa khidmadaha A iyo B (r)AB) = 2 cm = 0.02 m = 2 x 10-2 m Xoogga korontada - dhibaatooyinka iyo xalalka 9

Xoogga korontada ee u dhexeeya dallacaadaha A iyo B (F) = 8 N

Dareeraha korontada A (q A ) = 2 µC = 2 x 10 -6 C

Joogto ah (k) = 9 x 10 9 Nm 2 .C -2

La Rabo: Awoodda korantada ee u dhaxaysa dallacaadaha A iyo B haddii masaafada u dhaxaysa labada dallac ay tahay 4 cm.

Xalka:

Marka hore, xisaabi dallacaadda korantada B, ka dibna xisaabi xoogga korontada ee u dhexeeya labada dallac, haddii masaafada labada dallac ay tahay 4 cm = 0.04 mitir = 4 x 10 -2 mitir.

Korontada ku jirta B :

q B = F r 2 / k (q A )

q B = (8)(2 x 10 -2 ) 2 / (9 x 10 9 )(2 x 10 -6 )

q B = (8)(4 x 10 -4 ) / (18 x 10 3 )

q B = (32 x 10 -4 ) / (18 x 10 3 )

q B = (32/18) x 10 -7

qB = (16/9) x 10 -7 Coulombs

Xoogga korontada ee u dhexeeya dallacaadaha A iyo B:

F = k (q A )(q B ) / r 2

F = (9 x 10 9 )(2 x 10 -6 )( (16/9) x 10 -7 ) / (4 x 10 -2 ) 2

F = (18 x 10 3 )( (16/9) x 10 -7 ) / (16 x 10 -4 )

F = (2 x 10 3 )(16 x 10 -7 ) / (16 x 10 -4 )

F = (2 x 10 3 )(1 x 10 -7 ) / (1 x 10 -4 )

F = (2 x 10 -4 ) / (1 x 10 -4 )

F = 2 Newton

6. Saddex dallacaad A, B iyo C sida ka muuqata sawirka hoose. AB = BC = 20 cm dallacaadduna waa isku mid (q = 2µC). k = 9.10 9 Nm 2 .C -2 , 1 µ = 10 -6 . Waa maxay baaxadda shaqada xoogga korontadu ku leedahay barta B.

La yaqaan:

Arag sidoo kale  Adeegsiga sharciga koowaad ee thermodynamics-ka qaar ka mid ah hababka thermodynamic-ka (Isobaric Isothermal Isochoric)

Ku dallacaadda barta A (q)A) = 2 µC = 2 x 10-6 Coulomb Xoogga korontada - dhibaatooyinka iyo xalalka 10

Dareeraha barta B (q B ) = 2 µC = 2 x 10 -6 Coulomb

Dareeraha barta C (q C ) = 2 µC = 2 x 10 -6 Coulomb

Masaafada u dhaxaysa B ilaa C (r BC ) = 20 cm = 0.2 mitir = 2 x 10 -1 mitir

Masaafada u dhaxaysa B ilaa A (r BA ) = 20 cm = 0.2 mitir = 2 x 10 -1 mitir

k = 9.10 9 Nm 2 .C -2

La Doonayo: Cabbirka xoogga korontadu wuxuu ku shaqeeyaa barta B

Xalka:

Xoogga korantada ee u dhexeeya dallacaadaha meelaha B iyo C:

F BC = k (q B )(q C ) / r BC 2

F BC = (9 x 10 9 )(2 x 10 -6 )(2 x 10 -6 ) / (2 x 10 -1 ) 2

F BC = (9 x 10 9 )(4 x 10 -12 ) / (4 x 10 -2 )

F BC = (36 x 10 -3 ) / (4 x 10 -2 )

F BC = 9 x 10 -1

F BC = 0.9 Newton

Dakhliyada korantada ee dhibcaha B iyo C waa kuwo togan si jihada xoogga korontada F BC ay u socoto bidix ugana fogaato barta C.

Xoogga korantada ee u dhexeeya dallacaadaha dhibcaha B iyo A:

F BA = k (q B )(q A ) / r BA 2

F BA = (9 x 10 9 )(2 x 10 -6 )(2 x 10 -6 ) / (2 x 10 -1 ) 2

F BA = (9 x 10 9 )(4 x 10 -12 ) / (4 x 10 -2 )

F BA = (36 x 10 -3 ) / (4 x 10 -2 )

F BA = 9 x 10 -1

F BA = 0.9 Newton

Dalacadaha korantada ee dhibcaha B iyo A waa kuwo togan sidaa darteed jihada xoogga korontada F BA hoos ayay u socotaa, meel ka fog barta A.

Natiijada ka dhalatay xoogagga korontada:

Xoogga korontada - dhibaatooyinka iyo xalalka 11

7. Saddex dallacaad Q 1 , Q 2 , iyo Q 3 sida ku cad jaantuska hoose. Dhererka AB = dhererka BC = 30 cm. La yaqaan: k = 9.10 9 Nm 2 .C -2 iyo 1 µ = 10 -6 ka dibna natiijada xoogga korontada ee dallacaadda Q 1.

La yaqaan:

Ku dallacaadda barta A (q)A) = 3 µC = 3 x 10-6 Coulomb Xoogga korontada - dhibaatooyinka iyo xalalka 12

Dareeraha barta B (q B ) = -10 µC = -10 x 10 -6 Coulombs

Dareeraha barta C (q C ) = 4 µC = 4 x 10 -6 Coulomb

Masaafada u dhaxaysa B ilaa C (r BC ) = 30 cm = 0.3 mitir = 3 x 10 -1 mitir

Masaafada u dhaxaysa B ilaa C (r BA ) = 30 cm = 0.3 mitir = 3 x 10 -1 mitir s

k = 9.10 9 Nm 2 .C -2

La Doonayo: Natiijada ka dhalatay xoogga korantada ee barta B

Xalka:

Xoogga korantada ee u dhexeeya dallacaadaha meelaha B iyo C:

F BC = k (q B )(q C ) / r BC 2

F BC = (9 x 10 9 )(10 x 10 -6 )(4 x 10 -6 ) / (3 x 10 -1 ) 2

F BC = (9 x 10 9 )(40 x 10 -12 ) / (9 x 10 -2 )

F BC = (360 x 10 -3 ) / (9 x 10 -2 )

F BC = 40 x 10 -1

F BC = 4 Newton

Dareeraha korantada ee barta B waa taban, dareeraha korontada ee barta C waa togan, si jihada xoogga korontada F BC ay u socoto dhanka midig, ilaa barta C.

Xoogga korantada ee u dhexeeya dallacaadaha dhibcaha B iyo A:

F BA = k (q B )(q A ) / r BA 2

F BA = (9 x 10 9 )(10 x 10 -6 )(3 x 10 -6 ) / (3 x 10 -1 ) 2

F BA = (9 x 10 9 )(30 x 10 -12 ) / (9 x 10 -2 )

F BA = (270 x 10 -3 ) / (9 x 10 -2 )

F BA = 30 x 10 -1

F BA = 3 Newton

Dakhalka korantada ee barta B waa taban, dakhalka korontada ee barta A waa togan, sidaa darteed jihada xoogga korontada F BA waxay kor ugu socotaa barta A.

Natiijada ka dhalatay xoogga korontada:

Xoogga korontada - dhibaatooyinka iyo xalalka 13

  1. Waa maxay xoogga korontada? Jawaab: Xoogga korontadu waa xoog aasaasi ah oo ka dhaca walxaha dhexdooda sababo la xiriira dallacaaddooda korontada. Waxay noqon kartaa mid soo jiidasho leh (inta u dhaxaysa dallacaadyada iska soo horjeeda) ama mid laga xumaado (inta u dhaxaysa dallacaadyada isku midka ah).
  2. Sidee loo go'aamiyaa baaxadda xoogga korontada ee u dhexeeya laba dallacaad oo dhibco ah? Jawaab: Cabbirka xoogga korontada ee u dhexeeya laba dallacaad oo dhibic ah waxaa bixiya sharciga Coulomb. Waxay si toos ah ugu dhigantaa natiijada baaxadda dallacaadyada waxayna si liddi ku ah ugu dhigantaa labajibbaaranaha masaafada u dhaxaysa. , halkaas oo waa joogtada Coulomb.
  3. Maxaa ku dhacaya xoogga korontada haddii masaafada u dhaxaysa laba dallacaad la labanlaabmo? Jawaab: Haddii masaafada u dhaxaysa laba dallacaad la labanlaabo, xoogga korontadu wuxuu noqonayaa afar meelood meel qiimahiisii ​​asalka ahaa, sababtoo ah xooggu si liddi ku ah ayuu ugu kala duwan yahay labajibbaaranaha masaafada.
  4. Sidee xoogga korontadu ula barbar dhigi karaa xoogga cufisjiidadka? Jawaab: Xoogga korontada waxay noqon karaan kuwo soo jiidasho leh oo laga naxo, halka xoogga cufisjiidadka ay yihiin kuwo soo jiidasho leh oo keliya. Intaa waxaa dheer, walxaha caadiga ah iyo masaafadaha, xoogga korontadu badanaa aad ayuu uga xoog badan yahay xoogga cufisjiidadka, maadaama xoogga cufisjiidadka uu ka daciifsan yahay heerar badan oo baaxad leh marka loo eego xoogga korontada.
  5. Waa maxay mabda'a ku-meel-gaadhka ah ee la xiriira xoogga korontada? Jawaab: Mabda'a sare u qaadidda ayaa sheegaya in xoogga korontada ee saafiga ah ee ku jira dallac ay sabab u tahay ururinta dallacyada kale ay tahay wadarta falgalka ee xoogga ay qaadaan dallac kasta oo si gaar ah loo qaato.
  6. Maxaan u dareemi weynay awoodaha korontada ee walxaha maalinlaha ah inkastoo ay ka samaysan yihiin walxo la dallacay? Jawaab: Walxaha maalinlaha ah badanaa waa kuwo dhexdhexaad ah oo koronto ahaan, taasoo la micno ah inay leeyihiin tiro isku mid ah oo ah dallacaad togan iyo mid taban. Xoogga u dhexeeya dallacaadyadan ayaa is dheellitiran, sidaa darteed xoogga korontada saafiga ah waa eber.
  7. Sidee bay dhulka u saamaysaa xoogga korontada ee shay la dallacay? Jawaab: Ku dul-samaynta shay la dallacay waxay u oggolaanaysaa dallacaadda inay u dhex marto shayga iyo Dhulka ilaa shayga la dhexdhexaadiyo, taasoo si wax ku ool ah u baabi'inaysa xoogga korontada ee shayga sababtoo ah dallacaadda bilowga ah.
  8. Xoogga korontadu ma ku shaqeyn karaa meel bannaan? Jawaab: Haa, xoogga korontadu wuxuu ku shaqeyn karaa meel faaruq ah. Uma baahna wax dhexdhexaad ah si uu u faafo. Tani waxay ka muuqataa sida goobaha korontadu u jiri karaan oo ay u saameyn karaan walxaha lagu shubay hawada sare.
  9. Doorkee ayuu joogtada korontada (ama ogolaanshaha booska xorta ah) ka ciyaaraa go'aaminta xoogga xoogga korontada? Jawaab: Joogtada korantada, oo sidoo kale loo yaqaan ogolaanshaha booska xorta ah, waxay saamaysaa xoogga xoogga korontada ee u dhexeeya dallacaadaha. Ogolaansho sare waxay tilmaamaysaa xoogagga korontada oo daciif ah, iyo caksigeeda. Joogtada Coulomb, , waxay la xiriirtaa qiimahan sida .

  10. Haddii laba dallacaad ay is barbar socdaan, ma is beddelaan xoogga u dhexeeya? Jawaab : Haddii laba dallacaad ay is barbar socdaan, waxay soo saari karaan goobo birlab ah marka lagu daro goobaha korontada. Tani waxay ka dhigan tahay in isdhexgalka u dhexeeya dallacaadyada dhaqaaqa uusan kaliya ku xirnayn xoogagga korontada laakiin sidoo kale xoogagga birlabka. Isdhexgalka isku dhafan waxaa lagu qeexay xoogga korantada. Markaa, halka xoogga korontada ee ka dhasha dallacaadyadu uusan si fudud isu beddelin sababtoo ah way dhaqaaqayaan, haddana xoogga guud wuu isbeddeli karaa sababtoo ah saamaynta birlabka.

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