1. Qeexidda xarunta culeyska
Jidh adag wuxuu ka kooban yahay walxo badan; sidaas darteed, xoogga cufisjiidadka ayaa ku shaqeeya mid kasta oo ka mid ah walxahan. Si kale haddii loo dhigo, walax kastaa waxay leedahay miisaankeeda. Xarunta cufisjiidadka walaxdu waa bar ku taal shayga halkaas oo miisaanka dhammaan qaybaha shayga loo arko inuu xuddun u yahay meeshaas.

Haddii shay uu isku mid yahay (cufnaanta qayb kasta oo shayga ah waa isku mid ama shaygu wuxuu ka kooban yahay walxo isku mid ah) qaabka shayguna waa isku mid (tusaale ahaan labajibbaaran, afargeesle, goobo)
markaas miisaanka shaygu wuxuu la mid yahay bartamaha cufka shayga, oo ku yaal bartamaha shayga. Saddexagal, bartamaha cufka wuxuu ku yaal 1/3 saac (h = dhererka saddexagalka).

2. Isle'egta xarunta cufisjiidadka
Haddii qaabka shaygu uu yahay mid siman oo shayguna uu yahay mid isku mid ah, markaas xarunta cufisjiidadka shaygu waxay la mid tahay xarunta cufisjiidadka shayga,
halkaas oo xarunta cufisjiidadka iyo xarunta cuf-isjiidadka ay ku yaalliin bartamaha shayga. Taas beddelkeeda, haddii shaygu uu yahay mid isku mid ah laakiin aan isku mid ahayn, markaa booska miisaanka shayga waxaa lagu go'aamin karaa qaacidada soo socota.
Isku-duwayaasha miisaanka shayga ee dhidibka x:
![]()
Isku-duwayaasha miisaanka shayga ee dhidibka y:
![]()
x = bartamaha shayga ku yaal dhidibka x, y = bartamaha shayga ku yaal dhidibka y, A = aagga. Haddii shaygu uu saddex cabbir yahay, marka laga reebo go'aaminta isku-duwayaasha miisaanka shayga ee dhidibka x iyo y, waxay sidoo kale go'aaminaysaa isku-duwayaasha miisaanka shayga ee dhidibka z. Bedka (A) waxaa lagu beddelaa mugga (V).
Muunad dhibaato 1.
Go'aami isku-duwayaasha xarunta cufisjiidadka ee shayga isku midka ah ee ku yaal sawirka dhinaca!
Solution:
Walxaha u qaybi saddex qaybood.
A 1 = (10-0)(10-0) = (10)(10) = 100
A2 = (20-10)(30-0) = (10)(30) = 300
A 3 = (30-20)(10-0) = (10)(10) = 100
x 1 = 1⁄2 (10-0) = 1⁄2 (10) = 5
x 2 = 1⁄2 (20-10) + 10 = 1⁄2 (10) + 10 = 5 + 10 = 15
x 3 = 1⁄2 (30-20) + 20 = 1⁄2 (10) + 20 = 5 + 20 = 25
y 1 = 1⁄2 (10-0) = 1⁄2 (10) = 5
y 2 = 1⁄2 (30-0) = 1⁄2 (30) = 15
y 3 = 1⁄2 (10-0) = 1⁄2 (10) = 5
Isku-duwayaasha miisaanka shayga ee dhidibka x:

Isku-duwayaasha miisaanka shayga ee dhidibka y:

Isku-duwayaasha miisaanka shayga waa (15; 11)
Muunad dhibaato 2.
Go'aami isku-duwayaasha miisaanka shayga ee sawirka!
Solution:
U qaybi shayga laba qaybood, bedka 1 = labajibbaaran, bedka 2 = saddexagal.
A 1 = (5-1)(3-0) = (4)(3) = 12
A 2 = 1⁄2 (6-0)(9-3) = 1⁄2 (6)(6) = (3)(6) = 18
x 1 = 1⁄2 (5-1) + 1 = 1⁄2 (4) + 1 = 2 + 1 = 3
x 2 = 1⁄2 (6-0) = 1⁄2 (6) = 3
y 1 = 1⁄2 (3-0) = 1⁄2 (3) = 1.5
y 2 = 1/3 (9-3) + 3 = 1/3 (6) + 3 = 2 + 3 = 5
Isku-duwayaasha miisaanka shayga ee dhidibka x:

Isku-duwayaasha miisaanka shayga ee dhidibka y:

Isuduwidda miisaanka shayga waa (3; 3.6)