Dhibaatooyinka lagu xalliyay Fiisigiska Aasaasiga ah

Adeegsiga ilaalinta tamarta farsamada ee dhaqdhaqaaqa dhicitaanka xorta ah - dhibaatooyinka iyo xalalka

1. Jidh 1-kg ah ayaa si xor ah uga soo dhacaya nasashada, isagoo ka soo dhacaya dherer dhan 80 m. Dardargelinta cufjiidka awgeed is 10 m / s²Waa maxay tamar kuleylka marka jidhku dhulka ku dhaco.

La yaqaan:

Mass (m) = 1 kg

Dhererka (h) = 80 m

Dardargelinta cufjiidka awgeed (g) = 10 m/s²

SE buska: tamarta dhaqdhaqaaqa marka jirku dhulka ku dhaco

Xalka:

hore The tamarta farsamada (ANIGA)_o) = tamarta awoodda cufisjiidadka (CAG)

ME_o =PE = mgh = (1)(10)(80) = 800 Joules

Tamarta farsamada ee ugu dambeysa (ME_t) = tamar kuleylka (KE)

Mabda ' ilaalinta tamarta farsamada :

ME_o =ME_t

PE =KE

800=KE

Tamarta dhaqdhaqaaqa ugu dambeysa waa 800 Joules.

2. Jir 4-kg ah free-dhaco laga bilaabo nasasho, laga bilaabo dherer dhan 10 m. Dardargelinta cufisjiidadka ayaa ah 10 ms^-2Waa maxay tamarta dhaqdhaqaaqa iyo xawaaraha 5 mitir oo dhulka ka sarreeya.

La yaqaan:

Isbeddelka dhererka (h) = 10 – 5 = 5 mitirs

Cufnaanta (m) = 4 kg

Dardargelinta cufjiidka awgeed (g) = 10 m/s²

SE buska: Tamarta dhaqdhaqaaqa ee 5 mitir dhulka ka sarreysa iyo xawaaraha 5 mitir oo dhulka ka sarreeya

Xalka:

(A) Tamarta dhaqdhaqaaqa ee 5 mitir dhulka ka sarreysa

Tamarta farsamada ee bilowga ah (ME_o) = tamarta awoodda cufisjiidadka (PE)

ME_o =PE = mgh = (4)(10)(5) = 200 Joules

Tamarta farsamada ee ugu dambeysa (EM)_t) = tamar kuleylka (EK)

ME_t =KE

Mabda'a ilaalinta tamarta farsamada ayaa sheegaya in tamarta farsamada bilowga ah = tamarta farsamada ugu dambeysa.

ME_o =ME_t

200=KE

Tamarta dhaqdhaqaaqa ee 5 mitir dhulka ka sarreysa waa 200 Joules.

(B) xawaaraha Mitirka 5dhulka ka sarreeya

Tamarta farsamada ee bilowga ah (ME_o) = tamarta farsamada ee ugu dambeysa (ME_t)

PE =KE

200 = ½ mv²

2(200) / 4 = v²

100 = v²

v = √100

v = 10 m / s

Xawaaraha jirka ee 5 mitir ka sarreeya dhulka waa 10 m/s.

3. Cambe Si xor ah ayuu uga dhacaa nasashada, dhererkiisuna waa 2 mitir. Dardargelinta cufisjiidadka awgeed waa 10 ms^-2Go'aami xawaaraha cambe marka uu dhulka ku dhaco.

La yaqaan:

Dhererka (h) = 2 mitirs

Dardargelinta cufjiidka awgeed (g) = 10 m/s²

La doonayo: Xawaaraha cambaha marka uu dhulka ku dhaco.

Xalka:

Tamarta farsamada ee bilowga ah (ME_o) = tamarta awoodda cufisjiidadka (PE)

ME =PE = mgh = m (10)(2) = 20 m

Tamarta farsamada ee ugu dambeysa (ME_t) = tamarta dhaqdhaqaaqa (KE)

ME_t =KE = ½ mv²

Mabda'a ilaalinta tamarta farsamada ayaa sheegaya in tamarta farsamada bilowga ah = tamarta farsamada ugu dambeysa.

ME_o =ME_t

20 m = ½ mv²

20 = ½ v²

2(20) = v²

40 = v²

v = √40 = √(4)(10) = 2√10 m/s

[wpdm_package id='1166′]

Akhri wax dheeraad ah

Adeegsiga ilaalinta tamarta farsamada ee dhaqdhaqaaqa toosan ee xilliga dayrta xorta ah - dhibaatooyinka iyo xalalka

1. Qof ayaa dhagax 1-kg ah kor u tuuraya 2 m/s isagoo taagan geeska dhagax si dhagaxu ugu dhaco salka dhagaxa 40 mitir hoos. Waa maxay? tamar kuleylka dhagax 10 mitir ka sarreeya dhulka? Dardargelinta cufjiidka awgeed g = 10 m/s².

La yaqaan:

Mass (m) = 1 kg

Xawaaraha bilowga ah (v)_o) = 2 m/s

Isbeddelka dhererka = 40 - 10 = 30 mitir

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

La doonayo: tamarta dhaqdhaqaaqa dhagaxa oo 10 mitir ka sarreysa dhulka

Xalka:

Tamarta farsamada ee bilowga ah

Tamarta awoodda cufisjiidadka ee bilowga ah (EP) = mgh = (1)(10)(30) = 300 Joules

Tamarta dhaqdhaqaaqa bilowga ah (KE) = ½ mv_o² = ½ (1)(2)² = ½ (4) = 2 Joule

hore The tamarta farsamada = bilowga tamarta awoodda cufisjiidadka + tamarta dhaqdhaqaaqa bilowga ah = 300 + 2 = 302 Joules.

Tamarta farsamada ee ugu dambeysa

Tamarta farsamada ee ugu dambeysa = tamarta dhaqdhaqaaqa ugu dambeysa = tamarta awoodda cufisjiidadka bilowga ah + tamarta dhaqdhaqaaqa bilowga ah = 300 + 2 = 302 Joules.

2. Qofku wuxuu hawada ku tuuraa shay 1-kg ah oo kor u socda iyadoo xawaare bilow ah uu yahay 10 m/s. Go'aami (a) tamarta cufisjiidadka ee dhererka ugu badan (b) dhererka ugu badan.

Xawaaraha cufisjiidadka awgeed waa 10 m/s²

La yaqaan:

Cufnaanta (m) = 1 kg

Xawaaraha bilowga ah (v)_o) = 10 m/s

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

rabay : tamarta cufisjiidadka ee dhererka ugu badan iyo dhererka ugu badan

Xalka:

(a) tamarta cufisjiidadka ee dhererka ugu sarreeya

Tamarta farsamada ee bilowga ah:

Tamarta farsamada bilowga ah (ME) = tamarta dhaqdhaqaaqa bilowga ah (KE) = ½ mv_o² = ½ (1)(10)² = ½ (100) = 50 Joules.

Tamarta farsamada ee ugu dambeysa:

Tamarta farsamada ee ugu dambeysa (ME) = tamarta awoodda cufisjiidadka (PE)

Mabda'a ilaalinta tamarta farsamada:

Tamarta farsamada bilowga ah = tamarta farsamada ee ugu dambeysa

KE = PE

50 = PE

Tamarta cufisjiidadka waa 50 Joules.

(b) Dhererka ugu badan

PE = mgh

50 = (1)(10) saac

50 = 10 saacadood

h = 50 / 10 = 5 mitir

Dhererka ugu badan waa 5 mitir dhulka ka sarreeya.

[wpdm_package id='1174′]

Akhri wax dheeraad ah

Tamarta suurtagalka ah ee guga dabacsan - dhibaatooyinka iyo xalalka

1. Cufnaan 2-kg ah ayaa lagu dhejiyay guga. Haddii dhererka gu'gu uu yahay 4 cm, go'aami tamarta suurtagalka ah ee guga laastikada ah. Dardargelinta cufjiidka awgeed waa 10 m/s².

La yaqaan:

Mass (m) = 2 kg

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

Miisaanka (w) = mg = (2)(10) = 20 N

Dheereynta (x) = 4 cm = 0.04 m

La doonayo: Tamarta suurtagalka ah ee guga laastikada ah

Xalka:

Qaacidada Sharciga Hooke :

F = kx

F = xoog, k = joogto guga, x = isbeddelka dhererka guga

Joogtada guga:

k = w / x = 20 / 0.04 = 500 N/m

Tamarta suurtagalka ah ee guga laastikada ah:

PE = ½ kx² = ½ (500)(0.04)² = (250)(0.0016) = 0.4 Joules

Xal kale:

PE = ½ kx² = ½ (w / x) x² = ½ wx = ½ mgx

w = miisaan, m = cufnaan, x = isbeddelka dhererka guga

PE = ½ (2) (10) (0.04) = (10) (0.04) = 0.4 Joules.

2. Dheeraynta gu'ga oo lagu fidiyo xoog F = 50 N waa 10 cm. Waa maxay tamarta suurtagalka ah ee gu'ga dabacsan haddii dheereynta gu'gu ay tahay 12 cm.

La yaqaan:

Dheereynta (x) = 10 cm = 0.1 m

Xoogga (F) = 50 N

rabay Tamarta suurtagalka ah ee guga dabacsan

Xalka:

Joogtada guga:

k = F / x = 50 / 0.1 = 500 N/m

Tamarta suurtagalka ah ee guga dabacsan haddii dhererka gu'gu yahay 12 cm.:

PE = ½ kx² = ½ (500)(0.12)² = (250)(0.0144) = 3.6 Joules.

3. Garaafka F iyo x ee lagu muujiyey sawirka hoose. Waa maxay tamarta suurtagalka ah ee gu'ga laastikada ah, haddii dheereynta gu'gu ay tahay 10 cm.

Tamarta suurtagalka ah ee guga dabacsan - dhibaatooyinka iyo xalalka 1

La yaqaan:

Xoogga (F) = 5 N

Dheeraynta gu'ga (x) = 2 cm = 0.02 m

SE buska: Tamarta suurtagalka ah ee guga dabacsan haddii dhererka gu'gu yahay 0.1 m.

Xalka:

Joogtada guga:

k = F / x = 5 / 0.02 = 250 N/m

Tamarta suurtagalka ah ee guga laastikada ah haddii dhererka gu'gu yahay 0.1 m:

PE = ½ kx² = ½ (250)(0.1)² = (125)(0.01) = 1.25 Joules.

4. Ciyaaryahan ayaa ku boodaya qalab muusig oo miisaankiisu yahay 500 N, gu'guna wuxuu soo gaabinayaa 4 cm. Go'aami xaddiga tamarta suurtagalka ah ee lagu qasbi karo ciyaaryahanka.

A. 20 Joule

B. 10 Joule

C. 5 Joule

D. 2 Joule

La yaqaan:

Xoogga (F) = 500 N

Isbeddelka dhererka guga (Δx) = 4 cm = 0.04 m

SE buska: Tamarta suurtagalka ah ee guga

Xalka:

Xisaabi joogtada laastikada ah ee guga adoo isticmaalaya isle'egta sharciga Hooke:

k = F / Δx = 500 N / 0.04 m = 12500 N/m

Tamarta laastikada ee guga:

PE = ½ k Δx²= ½ (12500)(0.04)² = (6250)(0.0016)

PE = 10 Joule

Jawaabta saxda ah waa B.

5. Gu' marka laalaaday tiro badan oo ah 500 garaam, dhererkeeda waxay kordhisaa 5 cm. Go'aami joogto ah iyo ay tamarta suurtagalka ah.

La yaqaan:

Cufka shayga (m) = 500 garaam = (500/1000) kg = 5/10 kg = 0.5 kg

Dardargelinta (g) = 10 m/s²

Miisaanka walaxda (w) = mg = (0.5 kg)(10 m/s)²) = 5 kg m/s² = 5 Newton

Isbeddelka dhererka guga (Δx) = 5 cm = 0.05 m

La doonayo: joogtada ah ee gu'ga (k) iyo tamarta suurtagalka ah (PE)

Xalka:

Marka hore, xisaabi joogtada gu'ga adoo isticmaalaya isle'egta sharciga Hooke:

k = w / Δx = 5 N / 0.05 m = 100 N/m

Laastikada suurtagalka ah ee guga:

PE = ½ k Δx²= ½ (100)(0.05)² = (50)(0.0025)

PE = 0.125 Joule

[wpdm_package id='1179′]

Akhri wax dheeraad ah

Tamarta awoodda cufisjiidadka - dhibaatooyinka iyo xalalka

1. Jir 1-kg ah free-dhaco laga bilaabo nasashada, laga bilaabo dherer dhan 10 m.

Go'aami:

(A) Shaqada lagu sameeyay xoog of cuf

(b) Isbeddelka ku yimid tamarta awoodda cufisjiidadka

Dardargelinta cufjiidka awgeed (g) = 10 m/s²

Tamarta awoodda cufisjiidadka - dhibaatooyinka iyo xalalka 1 La yaqaan:

Mass (m) = 1 kg

Dhererka (h) = 10 m

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

Miisaanka (w) = mg = (1 kg)(10 m/s²) = 10 N

Xalka:

(A) Shaqada lagu sameeyo xoogga cufisjiidadka

W = wh = mgh

W = (1)(10)(10) = 100 Joule

(B) Isbeddelka tamarta awoodda cufisjiidadka

Isbeddelka tamarta awoodda cufisjiidadka waxay la mid tahay shaqada uu qabto cufisjiidadka.

ΔEP = 100 Joule

2. Shay 10 N ah ayaa hoos ugu simbiririxanaya diyaaradda siman ee 2 mitir u janjeerta. Go'aami shaqada lagu qabtay xoogga miisaanka!

Tamarta awoodda cufisjiidadka - dhibaatooyinka iyo xalalka 2 La yaqaan:

miisaanka (w) = 10 N

w_x = w dembi θ = (10)(dembi 30^o) = (10)(0.5) = 5 N

d = 2 m

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

La doonayo: shaqada lagu sameeyo xoogga miisaanka

Xalka:

W = F d = w_x d = (5)(2) = 10 Joule

Xal kale:

Dembiga 30^o = saac / d

0.5 = saac / 2

h = (0.5)(2)

h = 1m

Shaqada lagu sameeyo xoogga miisaanka;

W = F d = wh = (10 N)(1 m) = 10 N m = 10 Joules

3. Shay 1,500 garaam ah 20 mitir oo dhulka ka sarreysa, dhulka oo si xor ah ugu dhaca. Waa maxay tamarta cufisjiidadka ee shayga. Xawaaraha ay sababto cufisjiidadka waa 10 m/s².

La yaqaan:

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

Cufnaanta (m) = 1500 garaam = 1500/1000 kiilo garaam = 1.5 kiilo garaam

Dhererka (h) = 20 mitir

La doonayo: Tamarta awoodda cufisjiidadka

Xalka:

PE = mgh = (1.5 kg)(10 m/s²)(20 m) = 300 kg m²/s² = 300 Joule

4. Iyada oo ku saleysan sawirka hoose, haddii cufka shayga 1 uu yahay 2 kg miisaanka shayga 2na uu yahay 4 kg, Isbarbardhigga tamarta suurtagalka ah ee shayga 1aad iyo shayga 2aad waa…..

La yaqaan:

Cufka shayga 1 (m₁) = 2 kiilo garaam Tamarta awoodda cufisjiidadka - dhibaatooyinka iyo xalalka 5

Cufka shayga 2 (m₂) = 4 kiilo garaam

Dhererka 1 (h)₁) = 12 mitir

Dhererka 2 (h)₂) = 9 mitir

SE buska: Cisbarbardhigga tamarta suurtagalka ah ee shayga 1aad iyo shayga 2aad

Xalka:

PE = mgh

m = cufnaan (cutubkeeda caalamiga ah waa kiilogaraam, oo la soo gaabiyey kg)

g = dardargelinta cufisjiidadka awgeed (cutubkeeda caalamiga ah waa mitir ilbiriqsikiiba laba jibbaaran, oo la soo gaabiyey m/s²)

h = dherer (cutubkeeda caalamiga ah waa mitir, oo loo soo gaabiyo m)

PE = tamarta awoodda cufisjiidadka (cutubkeeda caalamiga ah waa kg m²/s²ama Joule)

Tamarta awoodda cufisjiidadka ee shayga 1aad:

EP₁= m₁gh₁= (2)(g)(12) = 24 g

Tamarta awoodda cufisjiidadka ee shayga 2aad:

EP₂= m₂ gh₂ = (4)(g)(9) = 36 g

Cisbarbardhigga tamarta suurtagalka ah ee shayga 1aad iyo shayga 2aad:

PE₁: PE₂

24 g: 36 g

24: 36

24/12: 36/12

2: 3

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Akhri wax dheeraad ah

Mabda'a tamarta shaqada-farsamada - dhibaatooyinka iyo xalalka

1. Sanduuqa 2-kg wuxuu ka yareeyaa 10 m/s ilaa uu nasto. is jiidjiid jiinis ah waa 0.2. Dardargelinta cufjiidka awgeed waa 10 m/s²Waa maxay baaxadda barakac?

Mabda'a tamarta shaqada-farsamada - dhibaatooyinka iyo xalalka 2

La yaqaan;

Mass (m) = 2 kg

Xawaaraha bilowga ah (v)_o) = 10 m/s

Xawaaraha kama dambaysta ah (v)_t) = 0 m/s

Isugeynta is-jiidjiidka dhaqdhaqaaqa (μ_k= 0.2

Miisaanka (w) = mg = (1 kg)(10 m/s²) = 10 kg m/s² = 10N

La doonayo: Baaxadda barokaca (d)

Xalka:

Mabda'a tamarta shaqada-farsamada :

W_nc = ΔEM

W_nc = ΔEK + ΔEP

W_nc = ½ m (v)_t² - v_o²) + mgh

W_nc = shaqada waxaa sameeyay awood aan muxaafid ahayn ku shaqaynta shayga

ΔEK = isbeddelka ku yimid tamar kuleylka

ΔEP = isbeddelka ku yimid tamar macquul ah

m = cufnaan

v = xawaare

g = dardargelinta cufisjiidadka awgeed

h = isbeddelka dhererka

Isbeddelka dhererka h = 0 sidaas darteed ΔEP = 0

W_nc = ΔEK

Shaqada ay qabtaan xoog aan muxaafid ahayn:

W_nc = -F_c d = – μ_k N d = – μ_k wd = – μ_k mgd

W_nc = -(0.2)(2)(10)(s)

W_nc = – (4)(2)

Calaamadda laga jaray waxay muujinaysaa in jihada xoogga is-jiidjiidka uu ka soo horjeedo jihada barokaca.

Isbeddelka tamarta dhaqdhaqaaqa:

ΔEK = ½ m (v)_t² - v_o²) = ½ (2)(0 – 10)²) = 0 – 100 = -100

Baaxadda barokaca:

W_nc = ΔEK

– 4 ilbiriqsi = – 100

s = -100/-4

s = 25 m

2. Baloog ayaa hoos ugu dhacaya meel u janjeerta. Isku-darka is-jiidjiidka dhaqdhaqaaqa waa 0.4. Dardargelinta cufisjiidadka awgeed waa g = 10 ms^-2Go'aami xawaaraha ugu dambeeya marka balooggu dhulka ku dhaco.

La yaqaan: Mabda'a tamarta shaqada-farsamada - dhibaatooyinka iyo xalalka 3

Dhererka bilowga ah (h)_o) = 6 m

Dhererka kama dambaysta ah (h)_t) = 0 m

Xawaaraha bilowga ah (v)_o= 0

Isugeynta is-jiidjiidka dhaqdhaqaaqa (μ_k= 0.4

Dardargelinta cufisjiidadka awgeed (g) = 10 ms^-2

cos θ = 8 / 10

Qaybta toosan ee miisaanka = w_y = w cos θ = mg cos θ = m (10)(8/10) = m (10)(4/5) = m (40/5) = 8 m

Xoogga caadiga ah = N = w_y = 8 m

Xoogga is-jiidjiididda dhaqdhaqaaqa = f_k= μ_k N= μ_k w_y= (0.4)(8 m) = 3.2 m

La doonayo: Xawaaraha kama dambaysta ah (v)_t)

Xalka:

Mabda'a tamarta shaqada-farsamada:

W_nc= ΔEM

W_nc = ΔEK + ΔEP

Isbeddelka tamarta dhaqdhaqaaqa:

ΔEK = 1/2 m (v_t² - v_o²) = 1/2 m (v_t² - 0) = 1/2 mv_t²

Isbeddelka ku yimaada tamarta suurtagalka ah:

ΔEP = mg (h)_t - h_o) = m (10)(0-6) = m (10)(-6) = – 60 m

Shaqada lagu sameeyo xoogga isku dhaca dhaqdhaqaaqa:

W_nc = – f_k s = – (3.2 m)(10) = – 32 m

Calaamadda laga jaray waxay muujinaysaa in jihada xoogga ee is-jiidjiidka uu ka soo horjeedo jihada barokaca.

Xawaaraha ugu dambeeya (v)_t):

W_nc = ΔEK + ΔEP

- 32 m = 1/2 mv_t² - 60 m

- 32 m = m (1/2 v)_t² - 60)

- 32 = 1/2 v_t² - 60

– 32 + 60 = 1/2 v_t²

28 = 1/2 v_t²

2 (28) = v_t²

56 = v_t²

v_t = .4.14

v_t = 2√14 ms^-1

3. Baloog ayaa hoos ugu dhacaya meel u janjeerta si qallafsan. Xawaaraha bilowga ah waa 0 m/s, xawaaraha ugu dambeeyana waa Ms 10^-1Haddii xoogga is-jiidjiidku yahay 2 N iyo dardargelinta cufisjiidadka awgeed g = 10 ms^-2, waa maxay dhererka (h)?

La yaqaan: Mabda'a tamarta shaqada-farsamada - dhibaatooyinka iyo xalalka 5

Cufnaanta (m) = 1 kg

Xawaaraha bilowga ah (v)_o= 0 (nasasho baloog)

Xawaaraha kama dambaysta ah (v)_t) = 10 ms^-1

Dhererka bilowga ah (h)_o) = h

Dhererka kama dambaysta ah (h)_t= 0

Xoogga is-jiidjiididda dhaqdhaqaaqa (f)_k) = 2 N

Dardargelinta cufisjiidadka awgeed (g) = 10 ms^-2

La doonayo: Dhererka (h)

Xalka:

Shaqada waxaa lagu sameeyaa xoogga isku dhaca dhaqdhaqaaqa:

W_nc = – f_k s = – (2))(15) = – 30

Calaamadda laga jaray waxay muujinaysaa in jihada xoogga ee is-jiidjiidka uu ka soo horjeedo jihada barokaca.

Isbeddelka tamarta dhaqdhaqaaqa:

ΔEK = 1/2 m (v_t² - v_o²) = 1/2 (1)(10² - 0) = 1/2 (10²) = 1/2 (100= 50

Isbeddelka ku yimaada tamarta suurtagalka ah:

ΔEP = mg (h)_t - h_o) = (1)(10)(0-s) = (10)(-s) = -10s

Mabda'a tamarta shaqada-farsamada:

W_nc = ΔEK + ΔEP

– 30 = 50 – 10 saacadood

10 saacadood = 50 + 30

10 saacadood = 80

h = 80/10

h = 8m

4Haddii baloog uu hoos ugu dhaco meel u janjeerta si qallafsan, markaas….
A. Shaqada ay ku qabato xoogga cufisjiidadka baloogga waxay ka weyn tahay isbeddelka tamarta suurtagalka ah ee baloogga
B. Tamarta farsamoyaqaanku way korodhaa
C. Tirada tamarta dhaqdhaqaaqa iyo tamarteeda suurtagalka ah ayaa la dhimay
D. Shaqada waxaa lagu qabtaa xoogga is-jiidjiidka oo la mid ah isbeddelka tamarta dhaqdhaqaaqa ee baloogga
Solution

A waa qalad

Shaqada ay ku qabato xoogga cufisjiidadka ee baloogga waxay la mid tahay isbeddelka tamarta cufisjiidadka ee baloogga.

B waa qalad

Haddii gudahacDiyaaradda laalaaban waa siman tahay markaa tamarta farsamada ee baloogga waa mid joogto ah. Marka ay ku taal dusha sare ee diyaaradda janjeerta oo aan weli dhaqaaqin, tamarta farsamada ee baloogga waxay la mid tahay tamarta awoodda jiidista. Balooggu wali wuu nasanayaa sidaa darteed tamartiisa dhaqdhaqaaqa waa eber. Marka ay hoos ugu socoto diyaarad janjeerta, dhererka baloogga waa la dhimaa sidaas darteed tamarta awoodda jiidista ayaa sidoo kale la dhimaa. Tamarta awoodda jiidista ayaa hoos u dhacda sababtoo ah waxay isu beddeshaa tamarta dhaqdhaqaaqa. In kasta oo tamarta awoodda jiidista ay isu beddesho tamarta dhaqdhaqaaqa, tamarta farsamada waa mid joogto ah.

Haddii diyaaradda u janjeerta ay qallafsan tahay, tamarta farsamada ee baloogga ayaa hoos u dhacda sababtoo ah shaqada taban ee ay qabato xoogga is jiidjiidka. Xoogga is jiidjiidka waa xoog aan muxaafid ahayn. Shaqada ay qabato xoog aan muxaafid ahayn oo ku socda shay waxay sababtaa in tamarta farsamada ee shayga ay yaraato.

C waa sax

Diyaaradda u janjeerta waa mid qallafsan sidaa darteed waxaa jira xoog is jiidjiid ah oo caqabad ku ah dhaqdhaqaaqa baloogga. Xoogga is jiidjiidku waa xoog aan muxaafid ahayn. Tamarta shaqada-farsamada ee aragtiyeed waxay sheegaysaa in shaqada ay qabato xoog aan muxaafid ahayn (tusaale ahaan xoogga is jiidjiidku) ay la mid tahay isbeddelka tamarta farsamada. Raadintan, tamarta farsamada ayaa hoos u dhacaysa.

Tamarta farsamada ee baloogga = tamarta awoodda cufisjiidadka + tamarta dhaqdhaqaaqa.

D waa qalad.

Shaqada ay qabato xoogga is jiidjiidka ee ku yaal baloogga waxay la mid tahay isbeddelka tamarta farsamada ee baloogga, ee maaha isbeddelka tamarta is jiidjiidka ee baloogga. Run ahaantii xoogga is jiidjiidka ayaa caqabad ku ah dhaqdhaqaaqa baloogga sidaas darteed waxay yareysaa xawaaraha baloogga waxayna yareysaa tamarta is jiidjiidka ee baloogga. Laakiin ogaaw in tamarta is jiidjiidka ee baloogga ay ka timaaddo tamarta awoodda cufisjiidka. Markaa waa run in shaqada la qabto iyadoo la siman yahay isbeddelka tamarta farsamada (tamarta farsamada ayaa hoos u dhacda).

Jawaabta saxda ah waa C.

5. Shay ku yaal dabaq qallafsan ayaa la garaacaa si uu u dhaqaaqo 3 ilbiriqsi ka dibna wuu joogsadaa. Haddii cufka la yaqaan ee shaygu yahay 10 garaam, xoogga is-jiidjiid ee u dhexeeya shayga iyo dabaqa waa 2 kilodyne. Go'aami shaqada ay qabatay xoogga is-jiidjiidku.

A. 0.18 J

B. -0.18 J

C. 0.36 J

D. -0.36 J

La yaqaan:

Muddada (t) = 3 ilbiriqsi

Xawaaraha kama dambaysta ah (v)_t) = 0 m/s (nasashada walxaha)

Cufka shayga (m) = 10 garaam = 10/1000 kg = 1/100 kg = 0.01 kg

Xoogga is-jiidjiid (F) = 2 kiilodyne = 2 x 10³dyne

La doonayo: Shaqada (W) waxaa lagu sameeyaa xoog is jiidjiid ah

Xalka:

Beddelka cutubyada xoogga:

1 Newton = 1 x 10⁵dyne

1 dheen = 1/10⁵ Newton = 1 x 10^-5Newton = 10^-5 Newton

Xoogga is-jiidjiidashada (F) = 2 x 10³dyne = 2 x 10³ x 10^-5 Newton = 2 x 10^-2 Newton = 2/100 Newton = 0.02 Newton

Aragtida tamarta shaqada-farsamada waxay sheegaysaa in shaqada ay qabato xoog aan muxaafid ahayn oo ku socda shay la mid ah isbeddelka tamarta farsamada ee shayga.

Haddii shay uu ku socdo diyaaradda u janjeerta markaas tamarta farsamada (ME) = tamarta awoodda cufisjiidadka (PE) + tamarta dhaqdhaqaaqa (KE). Laakiin haddii shaygu uu ku socdo diyaarad toosan sidaas darteed ma jiro isbeddel ku yimaada dhererka tamarta farsamada = tamarta dhaqdhaqaaqa. Diyaaradda toosan, tamarta awoodda cufisjiidadka waa eber sababtoo ah ma jiro isbeddel ku yimaada dhererka.

Xoogga is-jiidjiidku waa xoog aan ilaalinayn. Xoogga is-jiidjiidku badanaa wuxuu yareeyaa xawaaraha shayga iyo tamarta dhaqdhaqaaqa shayga. Waxaan ku soo gabagabayn karnaa in shaqada ay qabato xoogga is-jiidjiidku ee shayga ay la mid tahay hoos u dhaca tamarta farsamada.

Xisaab ahaan:

Shaqada (W) = Isbeddelka tamarta farsamada (ΔEM)

Fs = ΔEP + ΔEK

Fs = mg Δh + ½ m (v_t² - v_o²)

Fs = mg (0) + ½ m (0)² - v_o²)

Fs = 0 + ½ m (– (v_o²))

F s = – ½ mv_o²———— Isle'egta 1aad

Sharaxaad: F = xoog is jiidjiid, d = barokac, m = cuf, v_o = xawaaraha bilowga ah

Barakaca (d) iyo xawaaraha bilowga ah (v)_o) weli lama oga sababtoo ah marka hore xisaabi v_o ama d. Shaqada ay qabatay xoogga is-jiidjiid ee lagu xisaabiyay mid ka mid ah isle'egyada ka dib v la yaqaan_o ama d.

Isle'egta barokaca (d) ee dhaqdhaqaaqa toosan ee aan isku mid ahayn:

v_t² =v_o² + 2 (-a) s

Xawaaraha ugu dambeeya (v)_t) = 0 iyo dardargelinta (a) waxaa loo calaamadeeyay taban sababtoo ah shayga ayaa yaraaday (xawaaraha shayga ayaa yaraaday).

0 = v_o² – 2 xayeysiis

v_o² = 2 xayeysiis

d = v_o² / 2 a ———— Isle'egta 2

Isbeddelka d ee isle'egta 2 iyo d ee isle'egta 1:

F d = – ½ mv_o²

F (v)_o²/2a) = – ½ mv_o²

(F/2a) v_o²= – ½ mv_o²

F/2a = – ½ m

F = (2)(a)(-1/2)(m)

F = – (a)(m)

a = – (F / m)

a = – 0.02 Newtons / 0.01 kiilogaraam

a = – 2 Newton/kiilo

a = – 2 m/s²

Isla'egta lagu xisaabinayo xawaaraha bilowga ah (v)_o) dhaqdhaqaaq toosan oo aan isku mid ahayn:

v_t =v_o + at —–> Xawaaraha kama dambaysta ah (v_t) = 0, Dardargelinta (a) = 2 m/s², waqtiga u dhexeeya (t) = 3 ilbiriqsi

0 = v_o + (-2)(3)

0 = v_o - 6

v_o = 6 mitir/ilbiriqsi

Shaqada (W) oo ay qabato xoogga is jiidjiidka:

W = – ½ mv_o²= -1/2 (0.01)(6)²) = -1/2 (0.01)(36)

W = -1/2 (0.36)

W = – 0.18 Joule

Shaqada ay qabato xoogga is jiidjiidka waxaa lagu calaamadeeyay mid taban taasoo macnaheedu yahay in shaqadu ay yareyso tamarta farsamada ee shayga.

Haddii la yaqaan d shaqadu waxay xisaabin kartaa iyadoo la adeegsanayo isla'egta W = F d.

Jawaabta saxda ah waa B.

[wpdm_package id='1178′]

Akhri wax dheeraad ah

Tamarta shaqada iyo dhaqdhaqaaqa - dhibaatooyinka iyo xalalka

Tamarta Shaqada-Kinetic :

1. Gaari 5000-kg ah ayaa ka soo kabanaya nasashada ilaa 20 m/s. Go'aami shabakadda. shaqada lagu sameeyay gaariga.

La yaqaan:

Mass (m) = 5000 kg

Xawaaraha bilowga ah (v_o) = 0 m/s (nasashada gaariga)

Xawaaraha kama dambaysta ah (v_t) = 20 m/s

rabay : shaqada saafiga ah

Xalka:

Mabda'a tamarta shaqada-kinetic :

W_net = ΔEK

W_net = ½ m (v)_t² - v_o²)

W_net = shaqada saafiga ah

ΔEK = isbeddelka tamarta dhaqdhaqaaqa

m = cufnaan (kg),

v_t = xawaaraha kama dambaysta ah (m/s),

v_o = xawaaraha bilowga ah (m/s).

Shabakad:

W_net = ½ m (v)_t² - v_o²)

W_net = ½ (5000)(20)² - 0²)

W_net = (2500)(400 – 0)

W_net = (2500)(400)

W_net = 1000,000 Joule

2. Shay 10-kg ah ayaa ka xawaareynaya 5 m/s ilaa 10 m/s. Go'aami shaqada saafiga ah ee lagu sameeyay shayga!

La yaqaan:

Mass (m) = 10 kg

Xawaaraha bilowga ah (v_o) = 5 m/s

Xawaaraha kama dambaysta ah (v_t) = 10 m/s

rabay : shaqada saafiga ah

Xalka:

Shabakad:

W_net = ΔEK

W_net = ½ m (v)_t² - v_o²)

W_net = ½ (10)(10)² - 5²)

W_net = (5)(100 – 25)

W_net = (5)(75)

W_net = 375 Joule

3. Gaari 2000-kg ah ayaa hoos u dhacaya 10 m/s ilaa 5 m/s. Waa maxay shaqada laga qabto gaariga?

La yaqaan:

Gaariga mdameer (m) = 2000 kg

Xawaaraha bilowga ah (v_o) = 10 m/s

Xawaaraha kama dambaysta ah (v_t) = 5 m/s

SE buska: shaqada saafiga ah

Xalka:

Shabakad:

W_net = ΔEK

W_net= ½ m (v)_t² - v_o²)

W_net = ½ (2000)(5)² - 10²)

W_net = (1000)(25 – 100)

W_net= (1000)(-75)

W_net = -75,000 Joule

Calaamadda laga jaray waxay muujinaysaa in jihada barokaca ay ka soo horjeeddo jihada xoogga saafiga ah.

4. Xoog joogto ah oo 60-N ah oo lagu saaray shay 10-kg ah muddo 12 ilbiriqsi ah. Xawaaraha bilowga ah ee shay waa 6 m/s jihada shaygana waa la mid ah jihada xoogga.

(1) Shaqada lagu sameeyo shayga waa 30,240 Joules

(2) Tamarta dhaqdhaqaaqa ugu dambeysa waa 30,240 joules

(3) Power waa 2,520 Watt

(4) Kordhinta tamarta dhaqdhaqaaqa ee shayga waa 180 Joules

Weedhaha saxda ah waa…

La yaqaan:

Xoogga (F) = 60 N

Muddada (t) = 12 ilbiriqsi

Cufka shayga (m) = 10 kg

Xawaaraha bilowga ah (v)_o) = 6 m/s

La doonayo: Weedhaha saxda ah

Xalka:

Dardargelinta shayga:

∑F = ma

60 = 10 a

a = 60/10 = 6 m/s²

Xawaaraha ugu dambeeya:

v_t =v_o + at

v_t = 6 + (6)(12)

v_t = 6 + 72

v_t = 78m/s

The masaafada safar 12 ilbiriqsi gudahood:

s = v_o t + 1/2 at²

s = (6)(12) + 1/2 (6)(12)²

s = 72 + (3)(144)

s = 72 + 432

s = 504 mitir

(1) Shaqada lagu qabtay xoog

W = F s = (60)(504) = 30,240 Joules

(2) Tamarta dhaqdhaqaaqa ugu dambeysa

KE = 1/2 mv_t² = 1/2 (10)(78)²= (5)(6084) = 30,420 Joules

(3) Awood

P = W / t = 30,240 / 12 = 2,520 Joules/ilbiriqsi

(4) Kordhinta tamarta dhaqdhaqaaqa

ΔKE = 1/2 mv_t²– 1/2 mv_o²= 1/2 m (v)_t²- v_o²) = 1/2 (10)(78)²- 6²) = 5 (6084 –36) = 5 (6048)

ΔKE = 30,240 Joule

5. Shaqada weyn waxaa lagu sameeyaa lambarka shayga…

Tamarta Kinetic - dhibaatooyinka iyo xalalka 1

Xalka:

Shaqada saafiga ah = isbeddelka tamarta dhaqdhaqaaqa

W_net = ½ m (v)_t² - v_o²)

Shaqada weyn:

W₁ = ½ (8)(4)² - 2²) = (4)(16 – 4) = (4)(12) = 48 Joules

W₂ = ½ (8)(5)² -3²) = (4)(25 – 9) = (4)(16) = 64 Joules

W₃ = ½ (10)(6)² - 5²) = (5)(36 – 25) = (5)(11) = 55 Joules

W₄ = ½ (10)(4)² - 0²) = (5)(16 – 0) = (5)(16) = 80 Joules

W₅ = ½ (20)(3)² - 3²) = (10)(9 – 9) = (10)(0) = 0 Joules

6. Gaari 4000-kg ah ayaa ku socda xariiq toosan 25 m/s. Gaarigu wuu yareeyaa si xawaaraha ugu dambeeya ee gaarigu u noqdo 15 m/s. Waa maxay shaqada laga qabtay gaariga.

La yaqaan:

Cufnaanta (m) = 4000 kg

Xawaaraha bilowga ah (v)_o) = 25 m/s

Xawaaraha ugu dambeeya (v)_t) = 15 m/s

rabay : Shaqada laga qabtay gaariga

Xalka:

W_net = ½ m (v)_t² - v_o²) = ½ (4000) (15)²-25²) = (2000)(225-625) = (2000)(-400) = -800,000 Joules = -800 kJ

7. 0.1-kg oo si toosan loogu tuuray 6 m/s dhererka 5 mitir. Haddii dardargelinta cuf-isjiidadka waa 10 m/s², markaa waa maxay tamarta dhaqdhaqaaqa ee kubbadda dhererka 2 mitir.

La yaqaan: Tamarta Kinetic - dhibaatooyinka iyo xalalka 2

Cufnaanta (m) = 0.1 kg

Isbeddelka dhererka (s) = 5 m – 2 m = 3 mitir

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

La doonayo: Tamarta dhaqdhaqaaqa ee dhererka 2 mitir.

Xalka:

Dhaqdhaqaaqa matoorka waxaa lagu fahmi karaa iyadoo si gaar ah loo falanqeeyo qaybaha toosan iyo kuwa toosan ee dhaqdhaqaaqa. Dhaqdhaqaaqa jihada toosan ayaa loo falanqeeyay sida dhaqdhaqaaqa xawaaraha joogtada ah dhaqdhaqaaqa jihada toosanna waa la falanqeeyay sida dhaqdhaqaaq xor ah oo dhicitaan ah ama dhaqdhaqaaq toosan.

hore The tamarta farsamada = waa tamarta awoodda cufisjiidadka.

PE = mgh = (0.1)(10)(3) = 3 Joules.

The final tamarta farsamada = tamarta dhaqdhaqaaqa.

KE = 3 Joules.

8. Gaari 1000-kg ah ayaa ka soo kaca nasashada wuxuuna ku socdaa 5 m/s. Waa maxay shaqada uu qabto gaarigu?

La yaqaan:

Cufnaanta (m) = 1000 kg

Xawaaraha bilowga ah (v)_o= 0

Xawaaraha kama dambaysta ah (v)_t) = 5 m/s

La doonayo: Shaqada (W) ee lagu qabto baabuur

Xalka:

W_net = ½ m (v)_t² - v_o²)

Shaqada lagu sameeyo gaariga:

W_net = ½ (1000)(5)² - 0²) = (500)(25 – 0) = (500)(25) = 12,500 Joules

9. Kubbad 500-garaam ah ayaa si toosan kor looga soo tuurayaa dusha sare ee dhulka iyadoo xawaare bilow ah uu yahay 10 m/s.²Dardargelinta cufisjiidadka awgeed waa 10 ms^-2Waa maxay shaqada ay qabato xoogga miisaanku marka kubbadu gaarto dhererka ugu badan?

Known :

Cufka kubbadda (m) = 500 garaam = 0.5 kg

Xawaaraha bilowga ah (v)_o) = 10 m/s²

Xawaaraha kama dambaysta ah (v)_t) = 0 (xawaaraha meesha ugu sarreysa)

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

La doonayo: Shaqada (W) ee lagu sameeyay miisaanka

Xalka:

Shaqada saafiga ah ee ay sameeyaan xoogga saafiga ah ee ku jira shay = isbeddelka tamarta dhaqdhaqaaqa.

W_net = ΔEK = EK_t– EK_o

Wnet = ½ mv_t² – ½ mv_o²= ½ m (v)_t² - v_o²)

KE_t = tamarta dhaqdhaqaaqa ugu dambeysa, KE_o= tamarta dhaqdhaqaaqa bilowga ah, m = cufka walaxda, v_t = xawaaraha ugu dambeeya ee shayga, v_o = xawaaraha bilowga ah ee shayga.

Shabakad:

W_net= ½ m (v)_t² - v_o²) = ½ (0.5)(0)² - 10²)

W_net = (0.25)(-100) = -25 Joule

Calaamadda laga jaray waxay muujinaysaa in jihada barokaca ay ka soo horjeedo miisaanka kubadda. Jihada kubbadu waa toosan tahay jihada miisaankuna waa toosan tahay.

10. Shay 1-kg ah oo aan lahayn wax hoos u dhaca iyadoo farqiga dhererka uu yahay = 2.5 mitir. Dardargelinta cufisjiidadka awgeed waa 10 ms.^-2Waa maxay shaqada laga qabtay shayga?

La yaqaan:

Cufka kubadda (m) = 1 kg

Xawaaraha bilowga ah (v)_o) = 0 m/s

Dhererka (h) = 2.5 mitir

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

La doonayo: Shabakadda inta lagu jiro barakaca

Xalka:

Xawaaraha kama dambaysta ah ee kubadda (v_t)

Waxaa lagu xisaabiyaa iyadoo la adeegsanayo isle'egta dhaqdhaqaaqa xorta ah ee dhaca. La yaqaan: Dardargelinta cufisjiidadka awgeed (g) = 10 m/s², Isbeddelka dhererka kubadda (h) = 2.5 mitir. La doonayo: Xawaaraha kama dambaysta ah.

v_t² = 2 gh = 2(10)(2.5) = 2(25)

v_t = √2(25)

v_t = 5√2

Shaqada saafiga ah = isbeddelka tamarta dhaqdhaqaaqa

W_net = ΔEK = ½ m (v)_t² - v_o²) = ½ (1){(5√2)² - 0²}

W_net = ½ (25)(2) = 25 Joule

11. Shay 2-kg ah ayaa ku socda 72 km/saacaddii. Kadib marka uu socdo 400 mitir, xawaaraha ugu dambeeya ee shaygu waa 144 km/saacaddii. Xawaaraha cufisjiidadka awgeed waa 10 ms.^-2Soo hel shabakadda.

La yaqaan:

Cufka shayga (m) = 2 kg

Xawaaraha bilowga ah (v)_o) = 72 km/saacaddii = 20 m/s

Xawaaraha kama dambaysta ah (v)_t) = 144 km/saacaddii = 40 m/s

masaafada (s) = 400 mitir

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

La doonayo: Shabakadda

Xalka:

Shaqada saafiga ah = isbeddellada tamarta dhaqdhaqaaqa

W_net= ΔEK = ½ m (v)_t² - v_o²) = ½ (2)(40)² - 20²}

W_net = ½ (2)(1600 – 400) = 1200 Joules

12. Shay 2-kg ah ayaa ku dhex socda 2 ms^-1Shaqada lagu sameeyay shayga waa 21 Joules. Waa maxay xawaaraha ugu dambeeya ee shayga.

La yaqaan:

Cufnaanta (m) = 2 kg

Xawaaraha bilowga ah (v)_o) = 2 m/s

Shaqada (W) = 21 Joule

La doonayo: xawaaraha kama dambaysta ah (v)_t)

Xalka:

W_net= ΔEK

W_net= 1/2 mv_t² -1/2 mv_o²

W_net = 1/2 m (v)_t² - v_o²)

21 = 1/2 (2) (v_t² - 2²)

21 = (v_t² - 2²)

21 = v_t² - 4

v_t²= 21 + 4 = 25

v_t = √25

v_t = 5m/s

13. Xoog joogto ah oo 8 N ah ayaa ku shaqeeya shay miisaankiisu yahay 16 kg. Haddii shaygu markii hore nasto, markaa go'aami xawaaraha shayga ka dib marka xooggu ku shaqeeyo shayga muddo 4 ilbiriqsi ah.

La yaqaan:

Xoogga joogtada ah (F) = 8 Newton

Cufka shayga (m) = 16 kg

Xawaaraha bilowga ah ee shayga (v)_o) = 0 m/s

Xoogga muddada u dhaxaysa wuxuu ku shaqeeyaa shayga (t) = 4 ilbiriqsi

La doonayo: Xawaaraha ugu dambeeya (v)_t)

Xalka:

Shaqada = Isbeddelka tamarta dhaqdhaqaaqa

W = KE kama dambaysta ah – KE bilowga

W = ½ mv_t² – ½ mv_o²

W = ½ mv_t² - 0

W = ½ mv_t² —— Isle'egta 1aad

Shaqada = Xoog x Barakac

W = F d

W = 8 d

Adeegso isle'egta dhaqdhaqaaqa toosan ee aan isku mid ahayn ee hoose si aad u xisaabiso barokaca (d):

d = v_o t + ½ at²

d = barokac, v_o = xawaaraha bilowga ah, t = waqtiga u dhexeeya, a = dardargelinta

d = 0 + ½ at² = ½ at²—-> a = (v)_t - v_o) / t = v_t /t

d = ½ (v)_t / t) t²

^d= ½ (v)_t) t

Beddel barokaca (d) marka la eego isle'egta Shaqada leh barokaca (d) ee isle'egtan:

W = 8 d

W = 8(1/2)(v_t)(t)

W = (4)(v)_t)(t) —— isla'egta 2

Isle'egta 1 = Isle'egta 2

W = W

½ mv_t²= (4)(v)_t)(t)

½ mv_t= (4)(t)

½ (16) (v)_t) = 4(4)

8v_t = 16

v_t = 16/8

v_t = 2 mitir/ilbiriqsi

14Si aad u kordhiso xawaaraha shay, u beddel 2 jeer xawaaraha bilowga ah, go'aami shaqada looga baahan yahay habka…

La yaqaan:

Cufka shayga (m) = 1 kg

Xawaaraha bilowga ah (v)_o) = 1 m/s

Xawaaraha kama dambaysta ah (v)_t) = 2 x xawaaraha bilowga ah = 2 x 1 = 2 m/s

La doonayo: Work

Xalka:

Tamarta dhaqdhaqaaqa bilowga ah:

Xarafka KE = ½ mv_o² = ½ (1)(1)² = ½ (1)(1) = ½ (1) = 0.5

Tamarta dhaqdhaqaaqa ugu dambeysa marka xawaaraha shaygu uu noqdo 2 jeer xawaarihiisa hore:

KE kama dambaysta ah = ½ mv_t² = ½ (1)(2)² = ½ (4) = 2

Aragtida tamarta shaqada-kinetic-ga:

Shaqada = Isbeddelka tamarta dhaqdhaqaaqa

Shaqada = Tamarta dhaqdhaqaaqa ugu dambeysa - tamarta dhaqdhaqaaqa bilowga ah

Shaqada = 2 – 0.5

Shaqada = 1.5

Tamarta dhaqdhaqaaqa bilowga ah = 0.5

Shaqada = 3 x 0.5 = 1.5

Shaqada loo baahan yahay waa 3 jeer ka badan tamartii hore ee dhaqdhaqaaqa.

15Gaadhi culeyskiisu yahay 1500 kg ayaa ku socda xawaare dhan 36 km/saacaddii waddo toosan oo siman. Gaadhigu wuxuu u socday 72 km/saacaddii. Go'aami shaqada loo baahan yahay si loo dedejiyo gaariga.

La yaqaan:

Culeyska gaariga (m) = 1500 kg

Xawaaraha bilowga ah ee gaariga (v)_o) = 36 km/saacaddii = 36,000 mitir / 3600 ilbiriqsi = 10 mitir/ilbiriqsi

Xawaaraha kama dambaysta ah ee gaariga (v)_t) = 72 km/saacaddii = 72,000 mitir / 3600 ilbiriqsi = 20 mitir/ilbiriqsi

La doonayo: Shaqada loo baahan yahay si loo dedejiyo gaariga

Xalka:

Aragtida tamarta shaqada-kinetic-ga:

W = EK kama dambays ah - EK bilow ah

W = ½ mv_t² – ½ mv_o² = ½ m (v)_t² –v_o²)

W = ½ (1500)(20)² - 10²)

W = ½ (1500)(400 – 100)

W = ½ (1500)(300)

W = (1500)(150)

W = 225,000 Joules

16Shay culeyskiisu yahay 2 kg ayaa marka hore ku socda xawaare dhan 72 km saacaddii^-1Ka dib markaad ku socoto waddo toosan oo toosan ilaa 400 m, xawaaraha shaygu waa 144 km saacaddii^-1Go'aami wadarta shaqada ee shayga.

La yaqaan:

Cufka shayga (m) = 2 kg

Xawaaraha bilowga ah (v)_o) = 72 km/saacaddii = 72,000 mitir / 3600 ilbiriqsi = 20 m/s

Xawaaraha kama dambaysta ah (v)_t) = 144 km/saacaddii = 144,000 mitir / 3600 ilbiriqsi = 40 m/s

Barakaca shayga = 400 mitir

La doonayo: Shabakad ku taal shayga

Xalka:

Aragtida tamarta shaqada-kinetic-ga waxay sheegaysaa in shaqada shabakadu ay ku shaqeyso shay la mid ah isbeddelka tamarta kinetic-ga ee shayga.

W net = KU GUULEYSTAHA – KU GUULEYSTAHA bilowga

Shabaq W = ½ mv_t² – ½ mv_o²

Shabaq W = ½ m (v)_t² - v_o²)

Shabaq W = ½ (2)(40)² - 20²)

Shabaq W = 1600 – 400

W net = 1200 Joule

Description:

W = Shaqada, KE = tamarta dhaqdhaqaaqa

Tamarta Kinetic

17. Xabad 10-gram ah oo ku socota xawaare joogto ah 100 m/s. Waa maxay tamarta dhaqdhaqaaqa ee rasaasta.

La yaqaan:

Cufka rasaasta (m) = 10 garaam = 10/1000 kiilo garaam = 1/100 kiilo garaam = 0.01 kiilo garaam

Xawaaraha rasaasta (v) = 100 mitir/ilbiriqsi

SE buska: Tamarta Kinetic

Xalka:

KE = 1/2 mv²

KE = 1/2 (0,01 kg) (100 m/s)²

KE = 1/2 (0,01 kg) (10.000 m²/s²)

KE = (0,01 kg) (5000 m)²/s²)

KE = 50 kg m²/s²

KE = 50 Joule

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Akhri wax dheeraad ah

Shaqada lagu sameeyay xoog - dhibaatooyinka iyo xalalka

1. Qofku wuxuu jiidayaa baloog 2 m ah oo ku teedsan dusha sare ee siman isagoo adeegsanaya xoog joogto ah F = 20 N. Go'aami shaqada lagu sameeyay xoog F oo ku shaqeynaya baloogga.

Shaqada lagu sameeyo xoog - dhibaatooyinka iyo xalalka 1

La yaqaan:

Xoogga (F) = 20 N

Barakaca (s) = 2 m

Xagasha (θ)) = 0

rabay Shaqada (W)

Xalka:

W = F d cos θ = (20)(2)(cos 0) = (20)(2)(1) = 40 Joules

2. Xoog F = 10 N oo ku shaqeeya sanduuq 1 m ah oo ku teedsan dusha sare ee siman. Xooggu wuxuu ku shaqeeyaa 30^o xagal sida ku cad sawirka hoose. Go'aami shaqada lagu sameeyay xoog F!

Shaqada lagu sameeyo xoog - dhibaatooyinka iyo xalalka 2

Known :

Xoogga (F) = 10 N

Xoogga jiifa (F)_x) = F cos 30^o = (10)(0.5√3) = 5√3 N

Barakac (d) = 1 mitir

rabay : Shaqada (W)?

Solution :

W = F_x d = (5√3)(1) = 5√3 Joule

3. Jidhku si xor ah ayuu uga dhacaa nasashada, dhererkiisuna waa 2 m. Haddii dardargelinta cuf-isjiidadka awgeed waa 10 m/s², go'aami shaqada ay qabteen xoogga cufisjiidadka!

La yaqaan:

Shayga mass (m) = 1 kg

Dhererka (h) = 2 m

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

La doonayo: Shaqada waxaa qabta xoogga cufisjiidadka (W)

Xalka:

W = F d = wh = mgh

W = (1)(10)(2) = 20 Joule

W = shaqo, F = xoog, d = masaafada, w = miisaanka, h = dherer, m = cufnaan, g = dardargelin cufisjiidadka awgeed.

4. Shay 1-kg ah ayaa ku xiran guga sidaas darteed waa la dheereeyaa 2 cm. Haddii dardargelinta cufisjiidadka awgeed ay tahay 10 m/s², go'aami (a) joogtada guga (b) shaqada ay ku qabato xoogga guga ee shayga

La yaqaan:

Cufnaanta (m) = 1 kg

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

Dheereynta (x) = 2 cm = 0.02 m

Miisaanka (w) = mg = (1 kg)(10 m/s²) = 10 kg m/s²= 10N

La doonayo: Joogtada ah ee gu'ga iyo shaqada ay qabtaan ciidanka gu'ga

Xalka:

(a) Joogtada guga

Qaacidada Sharciga Hooke :

F = k x.

k = F / x = w / x = mg / x

k = (1)(10) / 0.02 = 10 / 0.02

k = 500 N/m

(b) shaqada ay qabteen ciidanka guga

W = – ½ kx²

W = – ½ (500)(0.02)²

W = – (250)(0.0004)

W = -0.1 Joule

Calaamadda laga jaray waxay muujinaysaa in jihada xoogga gu'gu uu ka soo horjeedo jihada barakicinta walxaha.

5. Xoog F = 10 N ayaa ku dardar gelinaya sanduuq meel ka baxsan 2 m. Dabaqa waa qallafsan yahay wuxuuna sameeyaa a xoogga is jiidka F_k= 2 N. Go'aami shaqada saafiga ah ee lagu sameeyay sanduuqa.

Shaqada lagu sameeyo xoog - dhibaatooyinka iyo xalalka 3

La yaqaan:

Xoogga (F) = 10 N

Xoogga is-jiidjiididda dhaqdhaqaaqa (F)_k) = 2 N

Barakaca (d) = 2 m

La doonayo: Shabakad (W)_net)

Xalka:

Shaqada waxaa qabtay xoog F:

W₁ = F d cos 0 = (10)(2)(1) = 20 Joules

Shaqada waxaa lagu sameeyaa xoogga isku dhaca dhaqdhaqaaqa (F)_k):

W₂ =F_k d = (2) (2) (cos 180) = (2) (2) (-1) = -4 Joules

Shabakad:

W_net =W₁ - W₂

W_net = 20 - 4

W_net = 16 Joule

6Waa maxay shaqada ay ciidamada F ka qabtaan baloogga?

La yaqaan: Shaqada lagu sameeyay xoog - dhibaatooyinka iyo xalalka 1

Xoogga (F) = 12 Newton

Barakac (d) = 4 mitir

SE buska: Shaqada (W)

Xalka:

W = F d = (12 Newton)(4 mitir) = 48 N m = 48 Joules

7Baloog waxaa riixaya xoog dhan 200 N. Barxadda balooggu waa 2 mitir. Waa maxay shaqada laga qabtay baloogga?

La yaqaan:

Xoogga (F) = 200 Newton

Barakac (d) = 2 mitir

SE buska: Shaqada (W)

Xalka:

Shaqada:

W = F s

W = (200 Newton)(2 mitir)

W = 400 N m

W = 400 Joule

8. Darawalka gaariga sedan-ka ayaa doonaya inuu gaarigiisa dhigto meel sax ah oo 0.5 mitir u jirta gaariga xamuulka qaada kaasoo 10 mitir u jira booska gaariga sedan-ka. Waa maxay shaqada looga baahan yahay gaariga sedan-ka?

La yaqaan: Shaqada lagu sameeyay xoog - dhibaatooyinka iyo xalalka 2

Barakac (d) = 10 mitir – 0.5 mitir = 9.5 mitir

Xoogga (F) = 50 Newton

La doonayo: Shaqada (W)

Xalka:

W = F s

W = (50 Newton)(9.5 mitir)

W = 475 N m

W = 475 Joule

Shaqada lagu sameeyay xoog - dhibaatooyinka iyo xalalka 3

Shaqada waxaa qabtay Tom iyo Jerry si gaarigu u dhaqaaqo ilaa 4 mitir. Xoogga ay sameeyeen Tom iyo Jerry waa 50 N iyo 70 N.

La yaqaan:

Barakaca (yada) = 4 mitir

Xoogga saafiga ah (F) = 50 Newtons + 70 Newtons = 120 Newtons

SE buska: Shaqada (W)

Xalka:

W = F s = (120 Newton)(4 mitir) = 480 N m = 480 Joules

10Darawal ayaa gaari jiidaya si gaarigu u dhaqaaqo ilaa 1000 cm. Waa maxay shaqada laga qabanayo gaariga?

La yaqaan: Shaqada lagu sameeyay xoog - dhibaatooyinka iyo xalalka 4

Xoogga (F) = 250 Newton

Barakaca (yada) = 1000 cm = 1000/100 mitir = 10 mitir

La doonayo: Shaqada (W)

Xalka:

W = F s = (250 Newton)(10 mitir) = 2500 N m = 2500 Joules

11. Iyada oo ku saleysan sawirka hoose, haddii shaqada ay qabteen xoogga saafiga ah ay tahay 375 Joules, go'aami meesha uu shaygu ka socdo.

Shaqada lagu sameeyay xoog - dhibaatooyinka iyo xalalka 11

La yaqaan:

Work (W) = 375 Joule

Xoogga saafiga ah (ΣF) = 40 N + 10 N - 25 N = 25 Newtons (dhanka midig)

La doonayo: Barakaca (d)

Xalka:

Isle'egta shaqada:

W = F s

Barakaca Shayga:

d = W / F = 375 Joules / 25 Newtons

d = 15 mitirs

12. Hawlaha hoose wtaas ha samayn shaqada is ...

A. Riix shay ilaa 10 mitir

B. Riix gaari ilaa uu dhaqaaqo

C. Riix darbi

D. Sanduuq ayaan soo jiiday

Xalka:

Isle'egta shaqada:

W = ΣF s

W= shaqada, F = ciidan, d = barakac

BSida ku cad qaacidada kor ku xusan, shaqada lagu sameeyay xoog iyo barokac ayaa jira.

Jawaabta saxda ah waa C.

13Andrew wuxuu riixayaa shay xoog leh oo ah 20 N si shaygu u dhaqaaqo dhaqdhaqaaq wareeg ah oo leh gacan 7 mitir ah. Go'aami shaqada uu Andrew qabtay laba jeer wareeg wareeg ah.

A. 0 Joule

B. 1400 Joule

C. 1540 Joule

D. 1760 Joule

Xalka:

Haddii qofku riixo kursiga curyaanka Laba jeer oo dhaqdhaqaaq wareeg ah kadib qofka iyo kursiga curyaamiinta ayaa ku soo laabanaya booskii asalka ahaa, sidaas darteed barokaca qofka waa eber.

Barakac = 0 markaa shaqada = 0.

Jawaabta saxda ah waa A.

14Qof ayaa shay dhulka ku riixaya isagoo wata xoog dhan 350 N. Dabaqa wuxuu sameeyaa xoog is jiidjiid ah oo dhan 70 N. Go'aami shaqada lagu sameeyay xoog si shayga loo dhaqaajiyo ilaa 6 mitir.

A. 45 J

B. 72 J

C. 1680 J

D. 2580 J

La yaqaan:

Xoogga riixitaanka (F) = 350 Newtons

Xoogga is-qabsiga (F)_lacag) = 70 Newton

Barkaca shayga (yada) = 6 mitir

SE buska: Shaqada (W)

Xalka:

Waxaa jira laba awoodood oo ku shaqeeya shayga, xoogga riixista (F) iyo xoogga is jiidista (F)_lacag) Xoogga riixitaanka wuxuu leeyahay jiho la mid ah kan dhaqaaqa shayga sababtoo ah xoogga riixitaanka wuxuu qabtaa shaqo togan. Dhinaca kale, xoogga isku dhaca wuxuu leeyahay jiho liddi ku ah oo leh dhaqaaqa shayga si xoogga isku dhaca uu u qabto shaqo taban.

Shaqada lagu sameeyo riix xoog:

W = F d = (350 Newton)(6 mitir) = 2100 Newton-mitir = 2100 Joules

Shaqada lagu sameeyo xoogga is jiidjiidka:

W = – (F)_lacag)(s) = – (70 Newton)(6 mitir) = – 420 Newton-mitir = – 420 Joules

Shabakadda:

W shabaq = 2100 Joules – 420 Joules

W net = 1680 Joule

Jawaabta saxda ah waa C.

15. Shay waxaa riixaya xoog jiif ah oo 14 Newton ah oo saaran dabaq qallafsan oo leh xoog isjiidjiid ah oo 10 Newton ah. Go'aami shaqada saafiga ah ee u dhaqaajinta shayga ilaa 8 mitir.

A. 0.5 Joule

B. 3 Joule

C. 32 Joule

D. 192 Joule

La yaqaan:

Xoogga riixista (F) = 14 Newton

Xoogga is-qabsiga (F)_lacag) = 10 Newton

Barkaca shayga (d) = 8 mitir

SE buska: Shaqada (W)

Xalka:

Waxaa jira laba awoodood oo ku shaqeeya shay, xoog riixid (F) iyo xoog is jiidid (F)_lacag).

Xoogga riixiddu wuxuu leeyahay jiho la mid ah kan dhaqaaqa shayga si xoogga riixiddu uu u qabto shaqo togan. Dhinaca kale, xoogga isku dhaca wuxuu leeyahay jiho liddi ku ah sida dhaqaaqa shayga si xoogga isku dhaca uu u qabto shaqo taban.

Shaqada lagu sameeyo riix xoog:

W = F s = (14 Newton)(8 mitir) = 112 mitir Newton = 112 Joules

Shaqada lagu sameeyo xoogga is jiidjiidka:

W = – (F)_lacag)(s) = – (10 Newton)(8 mitir) = – 80 mitir Newton = – 80 Joules

Shabakadda:

W shabaq = 112 Joules – 80 Joules

W net = 32 Joule

Jawaabta saxda ah waa C.

16. Go'aami shaqada shabakadda iyadoo lagu saleynayo sawirka hoose.

A. 360 Joule Work

B. 450 Joule

C. 600 Joule

D. 750 Joule

Xalka:

Shaqada = Xoog (F) x barokac (d)

Shaqada = Bedka saddexagalka 1 + bedka laydi + bedka saddexagalka 2

Work = 1/2(40-0)(3-0) + (40-0)(9-3) + 1/2(40-0)(12-9)

Shaqada = 1/2(40)(3) + (40)(6) + 1/2(40)(3)

Shaqada = (20)(3) + 240 + (20)(3)

Shaqada = 60 + 240 + 60

Shaqada = 360 Joule

Jawaabta saxda ah waa A.

17. Qori dhererkiisu yahay 60 cm ayaa si toosan loogu xiraa dhulka. Qorigu wuxuu ku dhufanayaa dubbe 10-kg ah oo laga soo qaaday dhererkiisu yahay 40 cm oo ka sarreeya dusha sare ee alwaaxda. Haddii celceliska awoodda iska caabbinta dhulku tahay 2 x 10³ N iyo dardargelinta cufisjiidadka awgeed waa 10 m/s², ka dibna qoryuhu si buuxda ayuu dhulka u geli doonaa ka dib…. garaacista.

A. 4

B. 16

C. 28

D. 30

La yaqaan:

Cufka dubbe (m) = 10 kg

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s²

Miisaanka dubbaha (w) = mg = (10)(10) = 100 kg m/s²

Barkaca dubbaha ka hor inta uusan qoriga ku dhicin (d) = 40 cm = 0.4 mitir

Iska caabbinta qoryaha (F) = 2 x 10³ N = 2000N

Dhererka alwaaxa = 60 cm = 0.6 mitir

La doonayo: TAlwaaxdu waxay gebi ahaanba dhulka geli doontaa ka dib marka…. ay ku dhufato.

Xalka:

Shaqada lagu sameeyo dubbaha marka dubbahu u dhaqaaqo ilaa 0.4 mitir waa:

W = F d = ws = (100 N)(0.4 m) = 40 Nm = 40 Joules

Shaqada ay qabato xoogga iska caabbinta dhulka:

W = F d = (2000 N)(0.6 m) = 1200 Nm = 1200 Joules

TAlwaaxdu waxay gebi ahaanba dhulka geli doontaa ka dib marka…. ay ku dhufato.

1200 Joules / 40 Joules = 30

Jawaabta saxda ah waa D.

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Akhri wax dheeraad ah

Sharciga Kepler - dhibaatooyinka iyo xalalka

1. Dhulka masaafada laga bilaabo Qorraxda waa 149.6 x 10⁶ km iyo muddada kacaanka dhulku waa 1 sano. Xisaabi T² /r³

La yaqaan:

T = 1 sano, r = 149.6 x 10⁶ km

rabay :T² /r³ = …?

Solution :

k = T² /r³= 1² / (149.6 x 10⁶)³ = 1 / (3348071.9 x 10¹⁸) = 2.98 x 10^-25sanadkii²/ km³

2. Joogtada guud (G) = 6.67 x 10^-11 Nm²/ kg²iyo Qorraxda 1.99 x 10³⁰ kg.

Sharciga Kepler - dhibaatooyinka iyo xalalka 2

3. Masaafada celceliska Dhulka u jirta Qorraxda waa 149.6 x 10⁶ km iyo celceliska masaafada Mercury u jirto Qorraxda waa 57.9 x 10⁶ km. Muddada kacaanka dhulku waa 1 sano, waa maxay muddada kacaanka meerkuriga?

La yaqaan:

r ee Dhulka = 149.6 x 10⁶ km

r ee meerkuriga = 57.9 x 10⁶ km

T ee Dhulka = 1 sano

SE buska: T ee meerkuriga?

Xalka:

Sharciga Kepler - dhibaatooyinka iyo xalalka 3

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Akhri wax dheeraad ah

Dayax-gacmeedka Geosynchronous - dhibaatooyinka iyo xalalka

1. Waa maxay dhererka dayax-gacmeedka geosynchronous-ka ah ee ka sarreeya dusha sare ee Dhulka?

G = joogto caalami ah = 6.67 x 10^-11 N m²/ kg²

M = Dhulka mass = 5.97x10²⁴ kg

T = 24 saacadood = 24 (3600 ilbiriqsi) = 86,400 ilbiriqsi = 8.64 x 10⁴ seconds

Solution

Dayax-gacmeedka Geosynchronous - dhibaatooyinka iyo xalalka 1

Dhererka dayax-gacmeedka ee ka sarreeya dusha sare ee dhulka = 4.22 x 10⁷ m = 4.22 x 10⁴km = 42,200 km

Dhererka dayax-gacmeedka ee ka sarreeya dusha sare ee dhulka = 6.38 x 10⁶ m = 6.38 x 10³km = 6380 km

Dhererka dayax-gacmeedka ee ka sarreeya dusha sare ee dhulka = dayax-gacmeed masaafada laga bilaabo bartamaha Dhulka – gacanka Dhulka

Dhererka dayax-gacmeedka ee ka sarreeya dusha sare ee dhulka = 42,200 km – 6380 km

Dhererka dayax-gacmeedka ee ka sarreeya dusha sare ee dhulka = 35,820km

2. Waa maxay xawaaraha dayax-gacmeedka geosynchronous-ka ah?

Joogtada guud (G) = 6.67 x 10^-11 N m²/ kg²

Cufka dhulka (m_E) = 5.97 x 10²⁴kg

Masaafada u dhaxaysa dayax-gacmeedka iyo bartamaha Dhulka (r) = 4.22 x 10⁷ m

Solution

Dayax-gacmeedka Geosynchronous - dhibaatooyinka iyo xalalka 2

ama isticmaal isla'egtan

Dayax-gacmeedka Geosynchronous - dhibaatooyinka iyo xalalka 3

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Akhri wax dheeraad ah

Sharciga Cufisjiidadka Guud ee Newton - Dhibaatooyinka iyo Xalalka

1. The masaafada inta u dhaxaysa Qof 40-kg ah iyo qof 30-kg ah waa 2 m. Waa maxay baaxadda xoog gravitv mid walba wuxuu ku shaqeeyaa kan kale. Joogto caalami ah = 6.67 x 10^-11 N m² /kg²

La yaqaan:

m₁ = 40 kg, m₂ = 30 kg, r = 2 m, G = 6.67 x 10^-11 N m² /kg²

La doonayo: baaxadda xoogga cufisjiidadka (F)?

Xalka:

Sharciga cufisjiidadka guud ee Newton - dhibaatooyinka iyo xalalka 1

2. Masaafada u dhaxaysa Dhulka iyo Dayaxa (r) waa 3.84 x 10⁸ m. Waa maxay baaxadda xoogga cufisjiidadka ee midba midka kale ku hayo?

La yaqaan:

Dunida mass (m_E) = 5.97 x 10²⁴ kg

Cufka Dayaxa (m_M) = 7.35 x 10²² kg

Masaafada u dhaxaysa bartamaha Dhulka iyo bartamaha Dayaxa (r) = 3.84 x 10⁸ m

Joogto caalami ah (G) = 6.67 x 10^-11 N m² /kg²

SE buska: Baaxadda xoogga cufisjiidadka (F)

Xalka:

Sharciga cufisjiidadka guud ee Newton - dhibaatooyinka iyo xalalka 2

3. Waa maxay masaafada u dhaxaysa Dhulka, baaxadda cufisjiidadka dhulka iyo dayaxu ma eber baa?

La yaqaan:

Cufnaanta Dhulka = 5.97x10²⁴ kg

Cufka Dayaxa = 7.35x10²² kg

Masaafada u dhaxaysa bartamaha Dhulka iyo bartamaha Dayaxa (r) = 3.84 x 10⁸ m.

Joogtada guud (G) = 6.67 x 10^-11 N m² /kg²

SE buska: fogaanta Dhulka

Xalka:

Sharciga cufisjiidadka guud ee Newton - dhibaatooyinka iyo xalalka 3

Xoogga cufisjiidadka saafiga ah waa eber.

Sharciga cufisjiidadka guud ee Newton - dhibaatooyinka iyo xalalka 4

Isticmaal qaacidada labajibbaaran:

A = – 6.35

B = – 7.68 x 10⁸

C = 87.76 x 10^-14

Sharciga cufisjiidadka guud ee Newton - dhibaatooyinka iyo xalalka 5

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Akhri wax dheeraad ah