Su'aalaha Tusaalaha ah ee Wareegga Korontada ee Hadda Beddelaya

6 Tusaalooyin ah Su'aalaha Wareegga Korontada ee Beddelka ah

1. Fiiri sawirka wareegga RLC ee soo socda! Haddii is-hortaagga wareegga uu yahay 250 Ω, markaa iska caabbinta iska caabbinta (R) waa…..

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 1A. 50 Ω

B. 200 Ω

C. 400 Ω

D. 600 Ω

E. 800 Ω

Dood

Waa la ogyahay in:

Z = 250 Ω

C = 8 m F = 8 x 10 -6 F

L = 0,8 H

V = 200 Volt

ω = 500 rad/s

Su'aal: Iska caabbinta iska caabbinta (R)

Jawaab:

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 2

Qaacidada guud ee is-hortaagga wareegga:

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 3

Jawaabta saxda ah waa B.

2. Fiiri wareegga RLC ee taxanaha soo socda! Farqiga suurtagalka ah ee ku wareegsan dhammaadka inductor-ka waa….

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 4A. 100 Volt

B. 200 Volt

C. 300 Volt

D. 350 Volt

E. 400 Volt

Dood

Waa la ogyahay in:

R = 40 W

X L = 150 W

X C = 120 W

V = 100 Volt

Su'aal: Farqiga suurtagalka ah ee ku yimaada dhammaadka inductor-ka

Jawaab:

Qaacidada guud ee is-hortaagga wareegga:

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 5

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 6

Jawaabta saxda ah waa C.

3. Eeg jaantuska wareegga RLC ee soo socda!
Tusaalaha Wareegga Korontada ee Hadda Beddelaya 7Xawaaraha ugu badan ee wareegga waa.. (1 µF = 10-6 F)

AKHRI SIDOO KALE  Tusaale dhibaato awood koronto oo barbar socota oo ka jirta saxanka capacitor-ka

A. 1,3 A
B. 1,5 A
C. 2,0 A
D. 2,4 A
E. 2√2 A

Dood

Waa la garanayaa :
Iska caabbiye (R) = 12 Ohm
Inductor (L) = 0,075 H
Kondensarka (C) = 500 µF = 500 x 10-6 F = 5 x 10-4 Farad
Danab (V) = Vo sin ωt = Vo sin 2πft = 26 sin 200t
La weydiiyay : Xawaaraha ugu badan ee wareegga
Jawab :

Falcelinta soo-gelinta (X)L) = ωL = (200)(0,075) = 15 Ohm
Falcelinta Awoodda (X)C= 1 / ωC = 1 / (200) (5 x 10-4) = 1 / (1000 x 10-4) = 1/10-1 = 101 = 10 Ohms   
Iska caabbiye (R) = 12 Ohm
Impedance (Z) :
Tusaalaha Wareegga Korontada ee Hadda Beddelaya 8Xoogga hadda jira (I) :
I = V / Z = 26 Volts / 13 Ohms
I = 2 Volts/Ohm
I = 2 Amperes
Jawaabta saxda ah waa C.

4. Wareegga RLC waxaa loo habeeyay sida ka muuqata sawirka hoose. Garaafka hirarka sine-ka ee ka dhashay haddiiL > XC waa…
Tusaalaha Wareegga Korontada ee Hadda Beddelaya 9Tusaalaha Wareegga Korontada ee Hadda Beddelaya 12Tusaalaha Wareegga Korontada ee Hadda Beddelaya 13Tusaalaha Wareegga Korontada ee Hadda Beddelaya 14
Dood

Macluumaadka:
XL = falcelinta inductive ama iska caabinta inductor
XC = falcelinta capacitive ama iska caabinta capacitor

Inductor-ka, danabka korontada (v) wuxuu ka horreeyaa qulqulka korontada (i) ¼ leexasho ama 90°.o.
Kaadhka korontada ku shaqeeya, korontada ku shaqeysa (i) waxay ka horreysaa danabka korontada ku shaqeeya (v) iyadoo la adeegsanayo ¼ wareeg ama 90°.o.

AKHRI SIDOO KALE  Tijaabada dardargelinta cuf-isjiidadka

Haddii X L > X C markaas wareeggu waa soo-jiidasho, sidaas darteed garaafka hirarka sine-ka ee ka dhashay wuxuu u eg yahay jawaabta C halkaas oo danabku (v) uu ku hoggaamiyo hadda (i) ¼ wareeg ama 90 o.

Jawaabta saxda ah waa C.

5. Fiiri sawirka soo socda!

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 15

Wareegga RLC waxaa loo habeeyay sida kor ku xusan. Garaafka hirarka sine-ka ee la soo saaray haddii X L > X C uu yahay...

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 16

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 16

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 17

Dood

Macluumaadka:

X L = falgalka soo-jiidashada ama iska-caabbinta soo-jiidashada ee inductor-ka, X C = falgalka soo-jiidashada ee capacitor-ka ama iska-caabbinta soo-jiidashada.

Inductor-ka, danabka korontada (V) wuxuu ka horreeyaa qulqulka korontada (I) ¼ wareeg ama 90 o.

Kaadhka korontada ku shaqeeya, korontada ku shaqeysa (I) waxay ka horreysaa danabka korontada ku shaqeeya (v) iyadoo la adeegsanayo ¼ wareeg ama 90 o.

Haddii X L > X C markaas wareeggu waa soo-jiidasho, sidaas darteed garaafka hirarka sine-ka ee ka dhashay wuxuu u eg yahay jawaabta C halkaas oo danabku (v) uu ku hoggaamiyo hadda (i) ¼ wareeg ama 90 o.

AKHRI SIDOO KALE  Tusaale ahaan ku dhaqanka sharciga koowaad ee thermodynamics habka isobaric (cadaadis joogto ah)

Jawaabta saxda ah waa C.

6. Wareegga RLC waxaa loo habeeyay sida ka muuqata sawirka hoose. Garaafka hirarka sine-ka ee la sameeyay haddii X L > X C uu yahay ...

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 18

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 19

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 20

Tusaalaha Wareegga Korontada ee Hadda Beddelaya 22

Dood

Macluumaadka:

X L = fal-celinta soo-jiidashada ama iska-caabbinta inductor-ka, X C = fal-celinta awoodda ama iska-caabbinta kaabsoolaha

Inductor-ka, danabka korontada (V) wuxuu ka horreeyaa qulqulka korontada (I) ¼ wareeg ama 90 o.

Kaadhka korontada ku shaqeeya, korontada ku shaqeysa (I) waxay ka horreysaa danabka korontada ku shaqeeya (v) iyadoo la adeegsanayo ¼ wareeg ama 90 o.

Haddii X L > X C markaas wareeggu waa soo-jiidasho, sidaas darteed garaafka hirarka sine-ka ee ka dhashay wuxuu u eg yahay jawaabta C halkaas oo danabku (v) uu ku hoggaamiyo hadda (i) ¼ wareeg ama 90 o.

Jawaabta saxda ah waa C.

Isha su'aasha:

Su'aalaha Imtixaanka Qaranka ee Fiisigiska ee SMA/MA U-ZC-2013/2014

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