Tusaale Su'aal Dood ah oo ku saabsan Stoichiometry Xal ah
Stoichiometry waa laan kiimiko ah oo barta xiriirka tirada ee u dhexeeya falgalayaasha iyo alaabada ku jira falgalka kiimikada. Stoichiometry-ga xalka waa mid gaar ah, maadaama uu diiradda saarayo falgallada kiimikada ee ka dhaca dareeraha, sida caadiga ah biyaha. Maqaalkan, waxaan ka hadli doonnaa tusaale ahaan dhibaatooyinka la xiriira stoichiometry-ga xalka si aan si fiican u fahanno fikraddan.
Fikradaha Aasaasiga ah ee Xalka Stoichiometry
Kahor inta aynaan guda gelin su'aalaha tusaalaha ah, waxaa jira fikrado aasaasi ah oo aan u baahanahay inaan fahanno:
1. Molarity (M): Xoogga xalka waxaa lagu muujiyaa molarity. Molarity waa tirada moles ee milanka halkii litir ee xalka (mol/L).
2. Mol: Halbeegga xaddiga walaxda ay ku jiraan walxaha tirada Avogadro (6.022 x 10²³).
3. Mugga Xalka: Badanaa lagu cabbiro litir (L).
Fahamkan aasaasiga ah awgeed, waxaan diyaar u nahay inaan u gudubno tusaale ahaan dhibaatooyinka iyo xalalka.
Su'aal Tusaale ah 1: Xisaabinta Miisaanka Xalka
Su'aal:
Maadaama 5 garaam oo NaCl ah (Sodium Chloride) lagu milmo 250 mL oo biyo ah, waa maxay molarity-ga xalka NaCl?
Xalka:
1. Xisaabi tirada burooyinka NaCl:
– Miisaanka molecular-ka (BM) ee NaCl: Na (23) + Cl (35.5) = 58.5 g/mol
– Tirada burooyinka = Cufnaanta / BM
““
Tirada burooyinka NaCl = 5 g / 58.5 g/mol ≈ 0.0855 mol
““
2. Mugga xalka u beddel mL una beddel L:
““
Mugga dareeraha = 250 mL = 0.250 L
““
3. Xisaabi molarity-ga (M):
““
Molarity (M) = Tirada moles / Mugga xalka
= 0.0855 mol / 0.250 L
≈ 0.342 M
““
Markaa, molarity-ga xalka NaCl waa 0.342 M.
Su'aal Tusaale ah 2: Falcelinta Dhexdhexaadnimada
Su'aal:
Waa maxay mugga 0.5 M HCl ee loo baahan yahay si loo dhexdhexaadiyo 50 mL oo ah 0.1 M NaOH?
Xalka:
Falcelinta dhacda:
““
HCl + NaOH → NaCl + H₂O
““
Falcelintani waxay ku dhacdaa saamiga 1:1.
1. Xisaabi tirada burooyinka NaOH:
““
Tirada burooyinka NaOH = Molarity x Mugga
= 0.1 M x 0.050 L
= 0.005 mol
““
2. Maadaama saamiga falcelintu yahay 1:1, tirada burooyinka HCl = tirada burooyinka NaOH = 0.005 mol.
3. Xisaabi mugga xalka HCl ee loo baahan yahay:
““
Mugga HCl = Tirada burooyinka / Molarity
= 0.005 mol / 0.5 M
= 0.01 L (ama 10 mL)
““
Markaa, mugga xalka HCl ee 0.5 M waa 10 mL.
Su'aal Tusaale ah 3: Titration-Asiidh-Saldhig
Su'aal:
Xal 25 mL ah oo CH₃COOH (acetic acid) ah ayaa lagu darayaa xal NaOH oo 0.1 M ah ilaa barta u dhiganta. 30 mL oo xal NaOH ah ayaa loo baahan yahay si loo gaaro barta u dhiganta. Xisaabi molarity-ga xalka CH₃COOH.
Xalka:
Falcelinta dhacda:
““
CH₃COOH + NaOH → CH₃COONa + H₂O
““
Falcelintani waxay sidoo kale ku dhacdaa saamiga 1: 1.
1. Xisaabi tirada burooyinka NaOH ee la isticmaalay:
““
Tirada burooyinka NaOH = Molarity x Mugga
= 0.1 M x 0.030 L
= 0.003 mol
““
2. Tirada burooyinka CH₃COOH waxay la mid tahay tirada burooyinka NaOH ee falceliyay (saamiga 1:1):
““
Tirada burooyinka CH₃COOH = 0.003 mol
““
3. Xisaabi molarity-ga CH₃COOH:
““
Molarity (M) = Tirada moles / Mugga
= 0.003 mol / 0.025 L
= 0.12 M
““
Markaa, molarity-ga xalka CH₃COOH waa 0.12 M.
Su'aal Tusaale ah 4: Kala-goynta Xalka
Su'aal:
Waa maxay mugga biyaha ee la rabo in lagu daro si loo qaso 100 mL oo ah xalka 1 M H₂SO₄ si xooggiisu u noqdo 0.25 M?
Xalka:
1. Isticmaal qaacidada kala-barxidda (M₁V₁ = M₂V₂):
– M₁ = 1 M
– V₁ = 100 mL
– M₂ = 0.25 M
2. Xisaabi V₂:
““
M₁V₁ = M₂V₂
1 M x 100 mL = 0.25 M x V₂
V₂ = (1 x 100) / 0.25
= 400 ml
““
3. Xisaabi mugga biyaha lagu darayo:
““
Mugga biyaha lagu daray = V₂ – V₁
= 400 mL – 100 mL
= 300 ml
““
Markaa, waxaa lagama maarmaan ah in lagu daro 300 mL oo biyo ah si loo milo xalka H₂SO₄ laga bilaabo 1 M ilaa 0.25 M.
Su'aal Tusaale ah 5: Falcelinta Roobabka
Su'aal:
Immisa garaam oo AgCl ah ayaa la sameeyaa marka 100 mL oo ah 0.1 M AgNO₃ xal lagu qaso 100 mL oo ah 0.1 M NaCl xal?
Xalka:
Falcelinta dhacda:
““
AgNO₃ + NaCl → AgCl (rooxitaan) + NaNO₃
““
Falcelintani waxay ku dhacdaa saamiga 1:1.
1. Xisaabi tirada burooyinka AgNO₃ iyo NaCl:
““
Tirada burooyinka AgNO₃ = Molarity x Mugga
= 0.1 M x 0.100 L
= 0.01 mol
Tirada burooyinka NaCl = Molarity x Mugga
= 0.1 M x 0.100 L
= 0.01 mol
““
2. Maadaama saamiga falgalku yahay 1:1, tirada burooyinka AgCl ee la sameeyay = Tirada burooyinka AgNO₃ ama NaCl:
““
Tirada burooyinka AgCl = 0.01 mol
““
3. Xisaabi cufka AgCl:
– Miisaanka molecular-ka ee AgCl = Ag (107.87) + Cl (35.45) = 143.32 g/mol
““
Cufka AgCl = Tirada burooyinka x BM
= 0.01 mol x 143.32 g/mol
= 1.4332g
““
Markaa, cufka AgCl ee la sameeyay waa 1.4332 garaam.
Gabagabo
Maqaalkani wuxuu ka hadlay dhowr tusaale oo dhibaatooyin iyo xalal ah oo ku saabsan stoichiometry xalka, oo ay ku jiraan xisaabinta molarity, falcelinta dhexdhexaadnimada, titrations-base-acid, milmida, iyo sameynta precipitate. Marka la fahmo tusaalooyinkan, waxaan si fiican u fahmi karnaa sida fikradda stoichiometry xalka loogu dabaqo xaaladaha dhabta ah ee adduunka. stoichiometry xalka ma aha oo kaliya muhiim u ah daraasadda kiimikada laakiin sidoo kale wuxuu leeyahay codsiyo ballaaran oo dhinacyo kala duwan ah sida farmashiyaha, bayoolajiga, iyo warshadaha kiimikada.
