3 Tusaalooyin oo ka mid ah sharciga Gay-Lussac (mugga isochoric-joogto ah)
1. Tiro gaasas ah ayaa marka hore leh cadaadis P iyo heerkul T. Haddii gaasku maro hab isochoric ah si cadaadisku u noqdo 4 jeer cadaadiskii asalka ahaa, heerkulka gaasku wuxuu isu beddelaa...
Dood
Waa la garanayaa :
Cadaadiska bilowga ah (P)1) = P
Cadaadiska kama dambaysta ah (P)2) = 4P
Heerkulka bilowga ah (T)1) = T
La weydiiyay heerkulka ugu dambeeya (T)2)
Jawab :
Xukum Gay-Lussac (habka mugga isochoric ama joogtada ah) :
Heerkulka gaaska wuxuu isu beddelaa 4 jeer heerkulka bilowga ah.
2. Gaasku wuxuu ku jiraa weel xiran heerkulkii hore ee 27°C. Si loo labanlaabo cadaadiska, heerkulka qolka waa...
Dood
Waa la garanayaa :
Cadaadiska bilowga ah (P)1) = P
Cadaadiska kama dambaysta ah (P)2) = 2P
Heerkulka bilowga ah (T)1= 27oC + 273 = 300 K
La weydiiyay heerkulka ugu dambeeya (T)2)
Jawab :
Heerkulka qolka waa 327oC.
3. Taayirada mootooyinka waxay leeyihiin cadaadis cabbir ah oo ah 2 atm heerkul ah 27oC. Ka dib marka mootada la wado, heerkulka gudaha taayirka wuxuu isu beddelaa 47oC. Haddii ballaarinta la iska indho tiro markaas cadaadiska hawada ee taayirka ayaa isu beddelaya...
Dood
U beddel cadaadiska cabbirka cadaadis dhammaystiran. Cadaadis dhammaystiran = cadaadis cabbir + cadaadis jawi
Waa la garanayaa :
Cadaadiska hawada = 1 atm = 1 x 105 Pascal
Cadaadiska cabbirka bilowga ah = 2 atm = 2 x 105 Pascal
Cadaadiska ugu horreeya ee dhammaystiran (P)1) = 1 atm + 2 atm = 3 atm = 3 x 105 Pascal
Heerkulka bilowga ah (T)1= 27oC + 273 = 300 K
Heerkulka kama dambaysta ah (T)1= 47oC + 273 = 320 K
La weydiiyay Cadaadiska ugu dambeeya ee cabbirka
Jawab :
Cadaadiska cabbirka kama dambaysta ah = cadaadis dhammaystiran oo kama dambaysta ah - cadaadiska jawiga
Cadaadiska cabbirka kama dambaysta ah = 3,2 atm – 1 atm
Cadaadiska cabbirka kama dambaysta ah = 2,2 atm
