Tusaale Dhaqdhaqaaqa Wareega ah

11 Tusaalooyin Su'aalo ah oo ku saabsan Dhaqdhaqaaqa Wareega

1. Shay culeyskiisu yahay 10 kg waadhaqdhaqaaq wareeg ah oo siman xawaare dhan 4 ms^-1Haddii gacanka goobada uu yahay 0,5 mitir, markaas:
(1) Soo noqnoqoshada wareegga waa 4/π Hz
(2) Dardargelinta bartamaha32 ms waa^-2
(3) Xoogga dhexe waa 320 N
(4) Muddada waa 4π s.
Weedha saxda ah waa…
1. (1), (2), (3), iyo (4)
2. (1), (2), iyo (3)
3. (1), iyo (3) oo keliya
4. (2), iyo (4) oo keliya
5. (3), iyo (4) oo keliya
Dood
2. Shay wuxuu ku socdaa goobaabin leh gacan 6 mitir ah. Haddii shaygu uu wareego 16 jeer 2 daqiiqo gudahood, markaa xawaaraha toosan ee shaygu waa...
A. 0,8 p ms^-1
B. 1,0 p ms^-1
C. 1,2 p ms^-1
D. 1,4 p ms^-1
E. 1,6 p ms^-1
Dood
Waa la ogyahay in:
Gacanka (r) = 6 mitir
Xawaaraha xagasha (ω) = 16 wareeg / 2 daqiiqo = 8 wareeg / daqiiqo = 8 wareeg / 60 ilbiriqsi = 0,13 wareeg / ilbiriqsi.
Waxaa la weydiiyay: xawaaraha toosan (v)?
Jawaab:

Qaacidada xiriirka ka dhexeeya xawaaraha toosan (v) iyo xawaaraha xagasha (ω):

v = r ω = (6 mitir)(0,13 wareeg/ilbiriqsi) = 0,8 wareeg mitir/ilbiriqsi
Jawaabta saxda ah waa A.
Haddii lagu muujiyo raadiyaan:
1 kacaan = 2π radians = 2(3,14) = 6,28 radians
Xawaaraha xagasha = 8 (6,28) radians / 60 ilbiriqsi = 50,24 radians / 60 ilbiriqsi = 0,84 radians/ilbiriqsi
v = r ω = (6 mitir)(0,84 radiyaan/ilbiriqsi) = 5,04 radiyaan/ilbiriqsi

3. Barafeeye taageere oo leh gacan 20/π cm ah ayaa 4 jeer ku wareegi kara 1 ilbiriqsi gudahood. Xawaaraha toosan ee caaradda barafeeyuhu waa…
A. 3,2 ms^-1
B. 1,6 ms^-1
C. 1,3 ms^-1
D. 1,0 ms^-1
E. 0,8 ms^-1
Dood

4. Shay si siman ugu socda waddo wareegsan, xawaarihiisa toosan wuxuu ku xiran yahay...
A. cufnaanta iyo gacanka goobada
B. cufnaanta iyo muddada
C. cufnaanta iyo soo noqnoqoshada
D. muddada iyo gacanka waddada
E. xawaaraha xagasha iyo gacanka goobada
Dood

 

5. Shay wuxuu ku socdaa goobaabin leh gacan 50 cm ah. Haddii shaygu uu ku wareego 120 rpm, markaas waqtiga wareegga iyo xawaaraha shaygu waa siday u kala horreeyaan….
A. 0,5 s iyo 2π ms^-1
B. 0,5 s iyo 0,2π ms^-1
C. 0,5 s iyo π ms^-1
D. 2 s iyo 5π ms^-1
E. 2 s iyo 10π ms^-1
Dood
Waa la ogyahay in:
Gacanka (r) = 50 cm = 0,5 mitir
Xawaaraha xagasha (ω) = 120 rpm = 120 wareeg / 1 daqiiqo = 120 wareeg / 60 daqiiqo = 2 wareeg / 1 ilbiriqsi
1 kacaan = 2π radian
Xawaaraha xagasha (ω) = 2 (2π radians) / 1 ilbiriqsi = 4π radians/ilbiriqsi
Su'aal: Waqtiga wareegga (T) iyo xawaaraha toosan (v)
Jawaab:
Waqtiga ama muddada wareegga (T):
Xiliga waa waqtiga ay shay ku qaadato inuu dhammeeyo hal wareeg.
Shay wuxuu sameeyaa 2 wareeg 1 ilbiriqsikiiba = shay wuxuu sameeyaa 1 wareeg 0,5 ilbiriqsikiiba. Markaa waqtiga ama muddada wareegga waa 0,5 ilbiriqsi.
Xawaaraha walaxda (v):
v = r ω = (0,5 mitir)(4π radians/ilbiriqsi) = 2π mitir/ilbiriqsi
Jawaabta saxda ah waa A.

6. Giraangiraha B iyo C waxaa lagu dhejiyay isla dhidibka giraangiraha A-na wuxuu la xiriiraa giraangiraha B sida ka muuqata sawirka dhinaca. Haddii giraangiraha giraangiraha A uu la mid yahay giraangiraha giraangiraha C = 30 cm, giraangiraha giraangiraha B = 60 cm, saamiga xawaaraha toosan ee u dhexeeya giraangiraha A, B, iyo C waa…

A. 1: 1: 1

B. 1: 2: 1

C. 1: 4: 1

D. 2: 2: 1

E. 4: 1: 2

Dood

Waa la ogyahay in :

Gacanka taayirada A (r _A ) = 30 cm = 0,3 mitir

Gacanka taayirada B (r _B ) = 60 cm = 0,6 mitir

Gacanka taayirada C (r _C ) = 30 cm = 0,3 mitir

La Doonayo : Isbarbardhigga xawaaraha toosan ee u dhexeeya taayirada A, B, iyo C

Jawaab :

Xawaaraha toosan ee giraangiraha A

Giraangiraha A iyo giraangiraha B way isku xiran yihiin sida sawirka kore ku xusan, sidaa darteed xawaaraha xagasha ee giraangiraha A lama mid aha xawaaraha xagasha ee giraangiraha B. Tani waa sababta oo ah wareegga giraangiraha B ayaa ka weyn kan giraangiraha A. Inta lagu jiro isla waqtigaas, marka giraangiraha A uu ku dhaqaaqo wareeg hal wareeg (360 ^o ), giraangiraha B ma gaarin hal wareeg (360 ^o ). Si kastaba ha ahaatee, inta lagu jiro isla waqtigaas, masaafada uu maro cidhifka giraangiraha A waxay la mid tahay masaafada uu maro cidhifka giraangiraha B. Markaa xawaaraha toosan ee cidhifka giraangiraha A (v _A ) wuxuu la mid yahay xawaaraha toosan ee cidhifka giraangiraha B (v _B ).

Xawaaraha toosan ee giraangiraha giraangiraha A:

v _A = r _A ω _A = 0,3 ω _A

Xawaaraha toosan ee giraangiraha B

Taayirada B iyo giraangiraha C way isku xiran yihiin, sidaa darteed giraangiraha B iyo giraangiraha C way isku wareegaan. Haddii giraangiraha B uu ku dhaqaaqo goobaabin hal wareeg (360)^o) ka dibna inta lagu jiro isla waqtiga kala-guurka giraangiraha C sidoo kale wuxuu ku dhaqaaqaa goobaabin hal wareeg (360^oMaadaama ay isku wareegaan, xawaaraha xagasha ee giraangiraha B (ω_B) waxay la mid tahay xawaaraha xagasha ee giraangiraha C (ω_C) = ω. Laakiin Xawaaraha toosan ee giraangiraha B (v)_B) ma aha mid la mid ah xawaaraha toosan ee giraangiraha C (v_C)

Xawaaraha toosan ee geeska giraangiraha B:

v _B = r _B ω _B = 0,6 ω _B = 0,6 ω

Xawaaraha toosan ee geeska giraangiraha C:

v _C = r _C ω _C = 0,3 ω _C = 0,3 ω

Xawaaraha toosan ee geeska giraangiraha A (v _A ) waa la mid yahay xawaaraha toosan ee geeska giraangiraha B (v _B )

v _A = v _B

0,3 ω _A = 0,6 ω

ω _A = 0,6 ω / 0,3

ω _A = 2 ω

Xawaaraha toosan ee giraangiraha A

v _A = 0,3 ω _A = 0,3 ( 2 ω) = 0,6 ω

Isbarbardhigga xawaaraha toosan ee u dhexeeya taayirada A, B, iyo C

v _A : v _B : v _C

0,6 ω : 0,6 ω : 0,3 ω

0,6: 0,6: 0,3

6: 6: 3

2: 2: 1

Jawaabta saxda ah waa D.

7. Saddex taayir ayaa isku xiran sida ka muuqata sawirka hoose.

Haddii R _A = 10 cm, R _B = 4 cm iyo R _C = 40 cm, markaa saamiga xawaaraha xagasha ee giraangiraha A iyo giraangiraha C waa…

A. 1: 1

B. 1: 2

C. 1: 4

D. 2: 1

E. 4: 1

Dood

Waa la ogyahay in :

Gacanka giraangiraha A (r _A ) = 10 cm

Gacanka taayirada B (r _B ) = 4 cm

Gacanka taayirada C (r _C ) = 40 cm

Su'aal : Saamiga xawaaraha xagal ee giraangiraha A iyo giraangiraha C

Jawaab :

Xawaaraha xagasha ee giraangiraha A iyo C

Wareegga giraangiraha A aad ayuu uga weyn yahay wareegga giraangiraha C. Marka giraangiraha C uu ku dhaqaaqo wareeg hal wareeg (360 ^o ), inta lagu jiro isla waqtiga kala-guurka giraangiraha A weli ma gaarin hal wareeg (360 ^o ). Sidaa darteed, xawaaraha xagasha giraangiraha A lama mid aha xawaaraha xagasha giraangiraha C.

Si kastaba ha ahaatee, giraangiraha A iyo C waxaa isku xira xarig ama silsilad. Maadaama ay isku xiran yihiin, inta lagu jiro isla waqtigaas, masaafada ay ku socoto geeska giraangiraha A waa la mid tahay masaafada ay ku socoto geeska giraangiraha C. Markaa xawaaraha toosan ee geeska giraangiraha C (v _C ) waa la mid yahay xawaaraha toosan ee geeska giraangiraha A (v _A ).

v _A = v _C

r _A ω _A = r _C ω _C

10 ω _A = 40 ω _C

ω _A / ω _C = 40 / 10

ω _A / ω _C = 4 / 1

Jawaabta saxda ah waa E.

8.

Saddex taayir A, B iyo C ayaa isku xiran sida ku cad sawirka. Haddii taayirada A, B iyo C ay yihiin 20 cm, 8 cm iyo 4 cm siday u kala horreeyaan, taayirada B-na ay ku wareegto xawaare xagal ah oo ah 10 rad.s.^-1, ka dibna giraangiraha C wuxuu ku wareegayaa xawaare xagal ah oo...

A. 80 rad.s^-1
B. 50 rad.s^-1
C. 40 rad.s^-1
D. 20 rad.s^-1
E. 10 rad.s^-1

Dood
Waa la garanayaa :
Gacanka giraangiraha A (r)_A) = 20 cm = 0,2 mitir
Gacanka taayirada B (r)_B) = 8 cm = 0,08 mitir
Gacanka taayirada C (r)_C) = 4 cm = 0,04 mitir
Xawaaraha xagasha ee giraangiraha B (ω)_B) = 10 rad/s
La weydiiyay Xawaaraha xagasha ee giraangiraha C (ω_C)
Jawab :

Xawaaraha xagal iyo xawaaraha toosan ee giraangiraha giraangiraha A
Giraangiraha A iyo giraangiraha B way isku xiran yihiin, sidaa darteed giraangiraha A iyo giraangiraha B way isku wareegaan. Haddii giraangiraha B uu ku dhaqaaqo goobaabin hal wareeg (360)^o) ka dibna inta lagu jiro isla waqtiga kala-guurka giraangiraha A sidoo kale wuxuu ku dhaqaaqaa wareeg hal wareeg ah (360^o) Sababtoo ah way isla wareegaan markaas xawaaraha xagal giraangir A (ω)_A) waxay la mid tahay xawaaraha xagasha ee giraangiraha B (ω_B).
Xawaaraha xagasha ee giraangiraha A :
ω_A = ω_B = 10 gacan/ilbiriqsi
Xawaaraha toosan ee giraangiraha A :
Cabbirka xawaaraha toosan ee geeska giraangiraha A waxaa lagu xisaabiyaa iyadoo la adeegsanayo qaacidada xiriirka ka dhexeeya xawaaraha toosan iyo xawaaraha xagasha, v = r ω.
v_A =r_A ω_A = (0,2 m)(10 rad/s) = 2 m/s

Xawaaraha xagal iyo xawaaraha toosan ee cidhifka giraangiraha C
Wareegga giraangiraha A aad ayuu uga weyn yahay wareegga giraangiraha C. Marka giraangiraha C uu ku dhaqaaqo goobaabin hal wareeg (360)^o), inta lagu jiro isla waqtiga kala-guurka giraangiraha A weli ma dhammaystirin hal wareeg (360^oSidaa darteed, xawaaraha xagasha ee giraangiraha A lama mid aha xawaaraha xagasha ee giraangiraha C.
Si kastaba ha ahaatee, giraangiraha A iyo C waxaa isku xira xarig ama silsilad. Maadaama ay isku xiran yihiin, isla waqtigaas, masaafada ay ku socoto geeska giraangiraha A waa la mid ah masaafada ay ku socoto geeska giraangiraha C. Markaa xawaaraha toosan ee geeska giraangiraha C (v)_C) waxay la mid tahay xawaaraha toosan ee geeska giraangiraha A (v_A).
Xawaaraha toosan ee giraangiraha C :
v_C =v_A = 2m/s
Xawaaraha xagasha ee giraangiraha C :
v_C =r_C ω_C
ω_C =v_C /r_C = 2 / 0,04 = 50 radyan/ilbiriqsi = 50 rad.s^-1.
Jawaabta saxda ah waa B.

9.

Nidaamka giraangiraha R-speck_A = 2 cm; R_B = 4 cm iyo R_C = 10 cm oo isku xiran sida sawirka ka muuqata. Taayirada B waxay ku wareegtaa 60 wareeg daqiiqaddii, sidaa darteed xawaaraha toosan ee taayirada C waa…

A. 8π cm.s^-1
B. 12 cm.s.^-1
C. 12π cm.s^-1
D. 24 cm.s.^-1
E. 24π cm.s^-1

Dood
Waa la garanayaa :
Gacanka giraangiraha A (r)_A) = 2cm
Gacanka taayirada B (r)_B) = 4cm
Gacanka taayirada C (r)_C) = 10cm
Xawaaraha xagasha ee giraangiraha B (ω)_B) = 60 kacaan/daqiiqo = 60 kacaan/60 ilbiriqsi = 1 kacaan/ilbiriqsi = 1(2π radian)/ilbiriqsi = 2π rad/s
La weydiiyay Xawaaraha toosan ee giraangiraha C (v)_C)
Jawab :
Xawaaraha toosan ee giraangiraha B
Xawaaraha toosan ee geeska giraangiraha B:
v_B =r_B ω_B = (4 cm)(2π rad/s) = 8π cm/s
Xawaaraha toosan ee giraangiraha A
Giraangiraha A iyo giraangiraha B waxaa ku xiran xarig sidaas darteed xawaaraha toosan ee geeska giraangiraha A (v)_A) waxay la mid tahay xawaaraha toosan ee geeska giraangiraha B (v_B).
v_A =v_B = 8π cm/s
Xawaaraha toosan ee giraangiraha C
Giraangiraha C iyo giraangiraha A waxaa ku xiran xarig sidaa darteed xawaaraha toosan ee geeska giraangiraha C waa (v)_C) waxay la mid tahay xawaaraha toosan ee geeska giraangiraha A (v_A).
v_C =v_A =v_B = 8π cm/s
Jawaabta saxda ah waa A.

10.
Fiiro gaar ah u yeelo isku xirka giraangiraha soo socda! Gacanka giraangiraha waa R_A = 25 cm, R_B = 15 cm, R_C = 40 cm iyo giraangiraha C wuxuu ku wareegayaa xawaare wareeg ah oo ah 60 wareeg daqiiqaddii. Xawaaraha xagasha ee giraangiraha A waa…
A. 2,5π rad.s^-1
B. 3π rad.s^-1
C. 3,2π rad.s^-1
D. 3,5π rad.s^-1
E. 3,8π rad.s^-1
Dood
Waa la garanayaa :
Gacanka giraangiraha A (r)_A) = 25 cm = 0,25 mitir
Gacanka taayirada B (r)_B) = 15 cm = 0,15 mitir
Gacanka taayirada C (r)_C) = 40 cm = 0,4 mitir
Xawaaraha xagasha ee giraangiraha C (ω)_C) = 60 kacaan/daqiiqo = 60 kacaan/60 ilbiriqsi = 1 kacaan/ilbiriqsi = 1(2π radian)/ilbiriqsi = 2π rad/s
La weydiiyay Xawaaraha xagasha ee giraangiraha A (ω_A)
Jawab :
Xawaaraha toosan ee giraangiraha C
Xawaaraha toosan ee giraangiraha C:
v_C =r_C ω_C = (0,4 m)(2π rad/s) = 0,8π m/s
Xawaaraha toosan ee giraangiraha B
Giraangiraha C iyo giraangiraha B waxaa ku xiran xarig sidaa darteed xawaaraha toosan ee geeska giraangiraha C waa (v)_C) waxay la mid tahay xawaaraha toosan ee geeska giraangiraha B (v_B).
v_B =v_C = 0,8π m/s
Xawaaraha xagal iyo xawaaraha toosan ee giraangiraha giraangiraha A
Giraangiraha A iyo giraangiraha B way isku xiran yihiin sida ka muuqata sawirka kore, sidaa darteed xawaaraha xagasha ee giraangiraha A lama mid aha xawaaraha xagasha ee giraangiraha B. Tani waa sababta oo ah wareegga giraangiraha A ayaa ka weyn kan giraangiraha B. Inta lagu jiro isla waqtigaas, marka giraangiraha A uu ku dhaqaaqay goobaabin hal wareeg (360)^o), giraangiraha B weli ma gaarin hal wareeg (360^oSi kastaba ha ahaatee, inta lagu jiro isla waqtigaas, masaafada uu maro cidhifka giraangiraha A waa la mid ah masaafada uu maro cidhifka giraangiraha B. Markaa xawaaraha toosan ee cidhifka giraangiraha A (v_A) waxay la mid tahay xawaaraha toosan ee geeska giraangiraha B (v_B).
Xawaaraha toosan ee giraangiraha A
v_A =v_B =v_C = 0,8π m/s
Xawaaraha xagasha ee giraangiraha A
v_A =r_A ω_A
ω_A =v_A /r_A = 0,8π / 0,25 = 3,2π rad/s
Jawaabta saxda ah waa C.

11. Dhagax cufkiisu yahay m ayaa lagu xiraa dhammaadka xarig dhererkiisu yahay l ka dibna waxaa lagu wareejiyaa xawaare xagal ah ω ilaa wadada dhagaxu ay noqoto mid wareegsan oo ku taal diyaaradda toosan, xarigguna uu sameeyo xagal θ oo u jeeda dhinaca toosan (fiiri sawirka). Xawaaraha xagasha ee dhagaxa waa...

Dood

Jawaabta saxda ah waa C.