Tusaale qulqulka korantada

4 Tusaalooyin oo ah Dhibaatooyinka Korontada

1. Goobta korontada oo ah 8000 N/C oo ku toosan dusha laba jibbaaran oo leh bedka dusha sare ee 10 m²Go'aanso qulqulka korantada taas oo dhex marta dusha laba jibbaaran!
Dood
Waa la ogyahay in:
Goobta korontada (E) = 8000 N/C
Bedka dusha sare (A) = 10 m²
θ = 0^o (xariiqyada goobta korontada waxay la jaanqaadaan xariiqyada caadiga ah)
La weydiiyay: Dareeraha korantada (Φ)
Jawaab:

Qaacidada qulqulka korantada:

Φ = EA cos θ
Sharaxaad: Φ = qulqulka korantada (Nm)²/C), E = garoon koronto (N/C), A = bedka dusha sare (m)²), θ = xagal u dhexeeya khadka korantada iyo xariiqda caadiga ah (xariiqda ku toosan dusha sare).

Baaxadda qulqulka korantada:

Φ = EA cos θ = (8000) (10) (cos 0) = (8000) (10) (1) = 80.000 = 8 x 10⁴ Nm²/C

2. Goob koronto oo 5000 N/C ah ayaa dhex marta dusha laba jibbaaran waxayna samaysaa xagal 60 ah.^o khadka caadiga ah. Bedka dusha sare ee labajibbaaran waa 2 m²Go'aami qulqulka korantada ee dusha sare ee laba jibbaaran!
Dood
Waa la ogyahay in:
Goobta korontada (E) = 5000 N/C
Bedka dusha sare (A) = 2 m²
θ = 60^o
La weydiiyay: Dareeraha korantada (Φ)
Jawaab:
Dareeraha korantada:
Φ = EA cos θ = (5000) (2) (cos 60) = (5000) (2) (0,5) = 5000 = 5 x 10³ Nm²/C

3. Goob koronto oo 4000 N/C ah ayaa dhex marta dusha sare ee baloog sida ku cad sawirka hoose. Balooggu waa 2 mitir dherer, 1 mitir ballac, iyo 1 mitir dherer. Go'aami qulqulka korantada ee dhex maraya baloogga!
Dood
Waa la ogyahay in:
Goobta korontada (E) = 5000 N/C
Bedka dusha sare (A) = 2 m²
La weydiiyay: Dareeraha korantada (Φ)
Jawaab:

Socodka korantada ee dhex mara baloogga

Iyada oo ku saleysan sawirka, khadadka garoonka korontada ee casaanka midabkiisu yahay ayaa si toosan ugu toosan dusha sare ee baloogga si ay ula jaanqaadaan xariiqda caadiga ah (samaynta xagal 0 ah).^o), halka khadadka kale ee goobta korontada ay barbar socdaan dusha sare si ay u siman yihiin xariiqda caadiga ah (samaynta xagal 90 ah^o).

Xariiqyada garoonka korontada ee cas ayaa gala baloogga laakiin dibadda ayay uga baxaan. Marka khadadka garoonka korontada ay u guuraan baloogga, waxay la mid tahay in dallac taban uu ku jiro baloogga gudahiisa, sidaas darteed qulqulka korontada waa taban. Taas beddelkeeda, marka khadadka garoonka korontada ay ka baxaan baloogga, waxay la mid tahay in dallac togan uu ku jiro baloogga gudahiisa, sidaas darteed qulqulka korontada waa togan. Xariiqyada garoonka korontada ee soo galaya baloogga waxay la mid yihiin khadadka garoonka korontada ee ka baxaya baloogga, sidaa darteed qulqulka korontada ee ka dhasha waa eber.

4. Goobo waxay leedahay gacan 0,5 mitir ah, bartamaha wareeggana waxaa ku yaal koronto koronto oo ah 10 μC. Go'aami qulqulka korantada ee dhex maraya wareegga!
Dood
Waa la ogyahay in:
Gacanka kubbadda (r) = 0,5 mitir
Dakhli koronto (Q) = 10 μC = 10 x 10^-6 C
La weydiiyay: Dareeraha korantada (Φ)
Jawaab:

Goobta korontada:

E = kq/r²
E = (9 x 10⁹ Nm²/C²)(10 x 10^-6 C) / 0,5²
E = (90 x 10³) / 0,25
E = 360 x 10³
E = 3,60 x 10⁵ N / C

Bedka dusha sare ee kubbadda:

A = 4 π r² = 4 (3,14)(0,5)² = (12,56)(0,25) = 3,14 m²

Dareeraha korantada:

Xariiqyada goobta korontada ku shaqeeya waxay ku toosan yihiin dusha sare waxayna la jaanqaadaan xariiqda caadiga ah si xagasha la sameeyay ay u noqoto 0.^o.
Φ = EA cos θ
Φ = (3,60 x 10)⁵)(3,14)(cos 0)
Φ = (11,304 x 10⁵) (1)
Φ = 11,304 x 10⁵
Φ = 1,13 x 10⁶ Nm²/C