Tusaale ahaan su'aalaha dabacsanaanta

21 Tusaalooyin Su'aalo ah oo ku saabsan Kala-baxa

Kordhinta Dhererka

1. Ul isku mid ah oo dhererkeedu yahay L, marka la jiido xoog F, dhererkeedu wuxuu ku kordhaa ∆L.

Si kororka dhererku u noqdo 4 ΔL, baaxadda xoogga jiidista ayaa ah...

A. 1/4 F

B. 1/2 F

C. 2 F

D. 4 F

E. 16 F

Dood

Waa la ogyahay in:

Xoogga jiidista 1 (F1 ₎ = F

Kordhinta dhererka 1 (∆L ₁ ) = ∆L

Kordhinta dhererka 2 (∆L ₂ ) = 4 ∆L

Su'aal: Xoogga jiidista 2 (F ₂ )

Jawaab:

Qaacidada sharciga Hooke:

k = F / ΔL

Sharaxaad: k = joogto ah oo laastikada ah, F = xoog jiidis ah, ΔL = kordhinta dhererka

Ulaha la isticmaalay waa isku mid si joogtada laastikada ah (k) ay isku mid u noqoto.

k ₁ = k ₂

F ₁ / ∆L ₁ = F ₂ / ∆L ₂

F / ΔL = F ₂ / 4ΔL

F / 1 = F ₂ / 4

F = F _2/4

F ₂ = 4F

Jawaabta saxda ah waa D.

2. Saddex ilo oo isku mid ah oo leh joogto gu' oo ah 200 N/m midkiiba ayaa loo habeeyey sida ku cad. Marka la siiyo culays dhan 100 garaam (dardargelinta cufisjiidadka g = 10 m/s), kordhinta dhererka isu-imaatinka gu'ga waa...

A. x = 0,50 cm

B. x = 0,75 cm

C. x = 0,85 cm

D. x = 1,00 cm

E. x = 1,50 cm

Dood

Waa la ogyahay in :

Cufka culayska (m) = 100 garaam = 0,1 kg

k ₁ = k ₂ = k ₃ = 200 N/m

w = mg = (0,1 kg)(10 m/s ² ) = 1 kg m/s ² = 1 Newton

La weydiiyay : Kordhinta dhererka guga guud ahaan ?

Jawaab :

Go'aaminta joogtada guga ee beddelka ah

Gu'ga 2 (k)₂) iyo guga 3 (k₃) oo loo habeeyey si is barbar socda. Joogtada guga ee u dhiganta waa:

k _p = k ₂ + k ₃ = 200 + 200 = 400 Nm ⁻¹

Gu'ga 1 (k ₁ ) iyo gu'ga beddelka is barbar socda (k _P ) waxaa loo diyaariyey si taxane ah. Joogtada gu'ga beddelka ah waa:

1/k _s = 1/k _p + 1/k ₁ = 1/400 + 1/200 = 1/400 + 2/400 = 3/400

ks ₌ 400/3 Nm ⁻¹

Joogtada guga ee u dhiganta ee isku-dhafka guga ee taxanaha ah waa 400/3 Nm ^-1

Go'aaminta kororka dhererka guga

Qaacidada sharciga Hooke:

= F / k = w / k

Kordhinta dhererka gu'ga waa:

= w / k

= 1: 400/3 = 1 x 3/400 = 3/400 = 0,0075 mitir = 0,75 cm

Jawaabta saxda ah waa B.

Joogtada Gu'ga

3. Tijaabo lagu sameeyay dabacsanaanta gu'ga, xog ayaa laga helay sida ku cad jadwalka hoose. Waxaa lagu soo gabagabeyn karaa in qiimaha joogtada gu'ga uu yahay….

A. 1.002 N/m

B. 1.201 N/m

C. 1.225 N/m

D. 1.245 N/m

E. 1.250 N/m

Dood

Qaacidada sharciga Hooke:

k = F / Δx

Joogtada guga:

k = 0,98/0,0008 = 1,96/0,0016 = 2,94/0,0024 = 3,92/0,0032 = 1.225 N/m

Jawaabta saxda ah waa C.

4. Saddex ilo ayaa loo habeeyey sida ku cad sawirka soo socda. Haddii joogtada gu'ga k ₁ = k ₂ = 3 Nm ⁻¹ iyo k ³ = 6 Nm ⁻¹ , joogtada gu'ga waa…..

A. 1 Nm^-1

B. 3 Nm ⁻¹

C. 7,5 Nm ⁻¹

D. 12 Nm ⁻¹

E. 15 Nm ⁻¹

Dood

Waa la ogyahay in:

Joogtada guga 1 (k ₁ ) = Joogtada guga 2 (k ₂ ) = 3 Nm ⁻¹

Joogtada guga 3 (k3 ₎ = 6 Nm ⁻¹

La weydiiyay: joogto ah guga (k)

Jawaab:

Gu'ga 1 (k ₁ ) iyo gu'ga 2 (k ₂ ) ayaa si is barbar socda loo habeeyay. Joogtada guga ee u dhiganta waa:

k _p = k ₁ + k ₂ = 3 + 3 = 6 Nm ⁻¹

Guga beddelka is barbar socda (k _P ) iyo gu'ga 3 (k ₃ ) waxaa loo habeeyay si taxane ah. Joogtada gu'ga beddelka ah waa:

1/k _s = 1/k _p + 1/k ₃ = 1/6 + 1/3 = 1/6 + 2/6 = 3/6

k _s = 6/2 = 3 Nm ⁻¹

Joogtada guga ee u dhiganta ee isku-dhafka guga ee taxanaha-isbarbardhigga ah ee kor ku xusan waa 3 Nm ⁻¹

Jawaabta saxda ah waa B.

5. Gu' dhererkiisu yahay L waxaa si isdaba joog ah u jiida culays w xogta la helayna waa sida ku cad jadwalka soo socda. Iyada oo lagu salaynayo xogta jadwalka, waxaa lagu soo gabagabayn karaa in baaxadda joogtada gu'gu ay tahay….

A. 300 Nm^-1

B. 500 Nm ^-1

C. 600 Nm ^-1

D. 800 Nm ^-1

E. 1000 Nm ^-1

Dood

Qaacidada sharciga Hooke:

k = F /

Joogtada guga:

k = 10/0,02 = 20/0,04 = 30/0,06 = 40/0,08 = 500 Nm ^-1

Jawaabta saxda ah waa B.

6. Xogta ku jirta jadwalka tijaabada ee soo socota waa natiijooyinka tijaabo la xiriirta dabacsanaanta walxaha. Tijaabada, walaxda caagga ah ee la isticmaalay waxay ahayd tuubo gudaha mooto ah. (g = 10 m/s ² ). Iyada oo ku saleysan jadwalka kore, waxaa lagu soo gabagabeyn karaa in walaxda caagga ah ay leedahay joogto laastikada ah oo ah….

A. 122 N/m

B. 96 N/m

C. 69 N/m

D. 56 N/m

E. 40 N/m

Dood

Qaacidada sharciga Hooke :

k = F / = w / = mg /

Sharaxaad: k = dabacsanaan joogto ah, w = cufisjiidadka, m = cuf, g = dardargelinta cufisjiidadka awgeed, = kordhinta dhererka cinjirka

Joogtada guga:

k = 2/0,05 = 4/0,1 = 6/0,15 = 8/0,20 = 10/0,25 = 40 N/m

Jawaabta saxda ah waa E.

7. Saddex gu' ayaa loo habeeyey sida ku cad sawirka soo socda. Haddii joogtada gu'ga K1 ₌ 4K, markaa qiimaha joogtada ah ee habaynta gu'ga waa ....

A. 3/4K

B. 3K/4

C. 4K/3

D. 3K

E. 4K

Dood

Laba ilo oo is barbar socda. Joogtada guga ee u dhiganta labada ilo ee is barbar socda waa:

k _p = K + K = 2K

Laba gu' ayaa loo habeeyey si taxane ah. Joogtada guga ee u dhiganta labada gu' ee loo habeeyey si taxane ah waa:

1/k _s = 1/k _p + 1/K ₁ = 1/2K + 1/4K = 2/4K + 1/4K = 3/4K

k _s = 4K/3

Joogtada guga ee u dhiganta ee habaynta guga ee kor ku xusan waa 4K/3

Jawaabta saxda ah waa C.

8. Xarig caag ah oo dhererkiisu yahay L ayaa lagu dhejiyay culays si xogta la helay ay u noqoto sida ku cad jadwalka. Iyada oo lagu salaynayo jadwalka, waxaa lagu soo gabagabayn karaa in cabbirka joogtada guga uu yahay….

A. 250 Nm^-1

B. 360 Nm ^—1

C. 400 Nm ^—1

D. 450 Nm ^—1

E. 480 Nm ^—1

Dood

Qaacidada sharciga Hooke:

k = F /

Joogtada guga:

k = 2/0,0050 = 3/0,0075 = 4/0,01 = 400 Nm ^-1

Jawaabta saxda ah waa C.

9. Fiiri xogta tijaabada ah ee shan nooc oo taayirro caag ah A, B, C, D, iyo E ah oo lagu jiido xoog F si dhererkoodu u kordho. Taayirka caagga ah ee leh joogtada guga ugu yar waa…

Dood

Qaacidada sharciga Hooke:

k = F / Δx

Sharaxaad: k = joogto ah oo laastikada ah, F = xoog, Δx = kordhinta dhererka caagga

Joogtada dabacsanaanta ee caagga:

k _A = F / Δx = 1 / 0,05 = 20 N/m

k _B = F / Δx = 2 / 0,025 = 80 N/m

k _C = F / Δx = 1 / 0,025 = 40 N/m

k _D = F / Δx = 2 / 0,05 = 40 N/m

k _E = F / Δx = 2 / 0,25 = 8 N/m

Jawaabta saxda ah waa E.

10. Laga soo bilaabo tijaabada lagu go'aaminayo dabacsanaanta caagga iyadoo la isticmaalayo caagga taayirka, xogta la helay waxay u egtahay shaxda soo socota. Waxaa lagu soo gabagabeyn karaa in qiimaha ugu badan ee joogtada ah uu yahay tijaabada….

Dood

Qaacidada sharciga Hooke:

k = F / Δx

Joogtada guga:

k _A = 7/0,035 = 200 Nm ^-1

k _B = 8/0,025 = 320 Nm ^-1

k _C = 6/0,020 = 300 Nm ^-1

k _D = 9/0,045 = 200 Nm ^-1

k _E = 10/0,033 = 303 Nm ^-1

Joogtada ugu weyn ee laastikada waa 320 Nm ^-1.

Jawaabta saxda ah waa B.

11. Jaantuska hoose wuxuu muujinayaa xiriirka ka dhexeeya isbeddelka culayska (ΔF) iyo kororka dhererka (ΔX), jaantuska muujinaya qiimaha ugu yar ee joogtada laastikada ah...

Dood

Qaaciddada sharciga Hooke

k = F / Δx

Macluumaadka:

Δx = kordhinta dhererka, F = xoog, k = joogto ah oo laastikada ah

Joogtada ah ee dabacsanaanta

k _A = F / Δx = 1 / 8 = 0,125

k _B = F / Δx = 8 / 3 = 2,7

k _C = F / Δx = 6 / 6 = 1

k _D = F / Δx = 3 / 5 = 0,6

k _E = F / Δx = 2 / 4 = 0,5

Jawaabta saxda ah waa A.

12. Eeg garaafka xiriirka ka dhexeeya xoogga (F) iyo kororka dhererka (ΔX) ee hoose! Kee baa leh joogtada ugu weyn ee laastikada?

Dood

Joogtada ah ee dabacsanaanta

k _A = F / Δx = 50 / 10 = 5

k _B = F / Δx = 50 / 0,1 = 500

k _C = F / Δx = 5 / 0,1 = 50

k _D = F / Δx = 500 / 0,1 = 5000

k _E = F / Δx = 500 / 10 = 50

Jawaabta saxda ah waa D.

Tamarta Suurtagalka ah ee Gu'ga

13. Garaafka (Fx) wuxuu muujinayaa xiriirka ka dhexeeya xoogga iyo kororka dhererka gu'ga. Cabbirka tamarta suurtagalka ah ee gu'ga iyadoo lagu saleynayo garaafka kore waa...

A. 20 joules

B. 16 joules

C. 3,2 joules

D. 1,6 joules

E. 1,2 joules

Dood

Waa la ogyahay in:

F = 40N

x = 0,08 mitir

Su'aal: Tamarta suurtagalka ah ee gu'ga

Jawaab:

Joogtada guga:

k = F / Δx = 40/0,08 = 500 N/m

Tamarta suurtagalka ah ee guga:

EP = 1/2 kx ² = 1/2 (500)(0,08) = (250)(0,08) = 20 Joules

Jawaabta saxda ah waa A.

14. Gu' waxaa la siiyaa culays dhan 2 kg sida ku cad sawirka soo socda. Haddii gu'gu uu la kulmo koror dhererkiisu yahay 5 cm oo dardar-gelintu ay sabab u tahay cufisjiidadka uu yahay 10 ms ^-2 , markaa tamarta laastikada ee gu'ga waa...

A. 4,0 J

B. 3,0 J

C. 2,5 J

D. 1,0 J

E. 0,5 J

Waa la ogyahay in :

Kordhinta dhererka (Δx) = 5 cm = 0,05 mitir

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s ²

Cufka culayska (m) = 2 kg

Miisaanka culayska (w) = mg = (2)(10) = 20 Newton

Su'aal : Tamarta suurtagalka ah ee caagga?

Waa la ogyahay in :

Kordhinta dhererka (Δx) = 5 cm = 0,05 mitir

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s ²

Cufka culayska (m) = 2 kg

Miisaanka culayska (w) = mg = (2)(10) = 20 Newton

Su'aal : Tamarta suurtagalka ah ee caagga?

15. Si loo fidiyo gu' 5 cm ah, waxaa loo baahan yahay xoog dhan 20 N. Tamarta suurtagalka ah ee gu'ga marka ay fidsan tahay 10 cm waa…

A. 2 Joule

B. 4 Joule

C. 20 Joule

D. 50 Joule

E. 100 Joule

Dood

Waa la ogyahay in :

Kordhinta dhererka (Δx) = 5 cm = 0,05 mitir

Xoogga (F) = 20 Newton

Su'aal : Waa maxay EP-ga gu'ga marka gu'gu uu gaaro 10 cm?

Jawaab :

Joogtada guga:

k = F / Δx = 20 / 0,05 = 400 N/m

Tamarta suurtagalka ah ee gu'ga marka Δx = 10 cm = 0,1 mitir:

EP = ½ k Δx ² = ½ (400)(0,1) ² = (200)(0,01)

EP = 2 Joule

Jawaabta saxda ah waa A.

Miisaanka Culayska

16. 

A. 6 N

B. 12 N

C. 30 N

D. 45 N

E. 60 N

Afar ilo oo isku mid ah, mid walbana leh joogto laastikada ah oo ah 800 Nm ⁻¹ , ayaa loo habeeyay taxane iyo is barbar socda (fiiri sawirka). Culayska laalaada w wuxuu sababaa in nidaamka gu'gu uu la kulmo koror guud oo dhererkiisu yahay 5 cm. Miisaanka culayska w waa…

Dood

Waa la ogyahay in :

k ₁ = k ₂ = k ₃ = k ₄ = 800 N m ⁻¹

= 5 cm = 0,05 m

Waxaa la weydiiyay : miisaanka culayska (w)?

Jawaab :

Go'aaminta joogtada guga ee beddelka ah

Gu'ga 1 (k)₁), guga 2 (k₂) iyo guga 3 (k₃) oo loo habeeyey si is barbar socda. Joogtada guga ee u dhiganta waa:

k _p = k ₁ + k ₂ + k ₃ = 800 + 800 + 800 = 2400 Nm ⁻¹

Guga beddelka is barbar socda (k _P ) iyo 4ta gu' ee (k ₄ ) waxaa loo habeeyay si taxane ah. Joogtada gu'ga beddelka ah waa:

1/k _s = 1/k _p + 1/k ₄ = 1/2400 + 1/800 = 1/2400 + 3/2400 = 4/2400

k _s = 2400/4 = 600 Nm ⁻¹

Joogtada guga ee u dhiganta ee isku-dhafka guga ee taxanaha-isbarbardhigga ah ee kor ku xusan waa 600 Nm ^-1

Go'aaminta miisaanka culayska

Qaacidada sharciga Hooke:

F=k ama w = k

Miisaanka culaysku waa:

w = (600 Nm ^-1 )(0,05 m) = 30 Newtons

Miisaanka culaysku waa 30 Newtons.

Jawaabta saxda ah waa C.

17. Afar ilo oo isku mid ah, mid walbana leh joogto laastikada ah oo ah 1600 N/m, ayaa loo habeeyay taxane iyo is barbar socda (fiiri sawirka). Culayska laalaada w wuxuu sababaa in nidaamka gu'gu uu la kulmo koror guud oo dhererkiisu yahay 5 cm. Miisaanka culayska w waa….

A. 60 N

B. 120 N

C. 300 N

D. 450 N

E. 600 N

Dood

Waa la ogyahay in :

k ₁ = k ₂ = k ₃ = k ₄ = 1600 N m ⁻¹

= 5 cm = 0,05 m

Waxaa la weydiiyay : miisaanka culayska (w)?

Jawaab :

Go'aaminta joogtada guga ee beddelka ah

Gu'ga 1 (k ₁ ), gu'ga 2 (k ₂ ) iyo gu'ga 3 (k ₃ ) ayaa si is barbar socda loo habeeyay. Joogtada guga ee u dhiganta waa:

k _P = k ₁ + k ₂ + k ₃ = 1600 + 1600 + 1600 = 4800 Nm ⁻¹

Guga beddelka is barbar socda (k _P ) iyo 4ta gu' ee (k ₄ ) waxaa loo habeeyay si taxane ah. Joogtada gu'ga beddelka ah waa:

1/k _s = 1/k _p + 1/k ₄ = 1/4800 + 1/1600 = 1/4800 + 3/4800 = 4/4800

k _s = 4800/4 = 1200 Nm ⁻¹

Joogtada guga ee u dhiganta ee isku-dhafka guga ee taxanaha ah waa 1200 Nm ^-1

Go'aaminta miisaanka culayska

Qaacidada sharciga Hooke:

F=k ama w = k

Miisaanka culaysku waa:

w = (1200 Nm ^-1 )(0,05 m) = 60 Newtons

Miisaanka culaysku waa 60 Newtons.

Jawaabta saxda ah waa A.

Laastikada iyo Balaastikada

18. Fiiri garaafka xiriirka ka dhexeeya xoogga ΔF iyo kororka dhererka Δx ee guga hoose!

Iyada oo ku saleysan garaafka, gu'gu wuxuu ahaan doonaa mid dabacsan marka uu laalaabanayo xoog...

A. 0 ilaa 4 N

B. 0 ilaa 8 N

C. 0 ilaa 12 N

D. 8 N ilaa 12 N

E. 8 N ilaa 16 N

Dood

Gu'gu wuu sii jiri doonaa haddii sharciga Hooke uu weli khuseeyo. Xisaab ahaan, sharciga Hooke waxaa lagu qeexay qaacidada:

k = ΔF / Δx

Sharaxaadda qaacidada:

k = joogto ah oo laastikada ah, ΔF = xoog, Δx = dhererka guga

Sharciga Hooke wuxuu dhigayaa in saamiga isbeddelka xoogga (ΔF) iyo isbeddelka dhererka (Δx) ee gu'gu uu had iyo jeer yahay mid joogto ah. Haddii qiimaha k isbeddelo, sharciga Hooke mar dambe ma khuseeyo gu'ga taasina waxay muujinaysaa in gu'gu uusan mar dambe dabacsanayn.

Fiiri garaafka kore oo faham xisaabinta soo socota.

k ₁ = ΔF / Δx = 4 / 2 = 2

k ₂ = ΔF / Δx = 8 / 4 = 2

k ₃ = ΔF / Δx = 12 / 7 = 1,7

Joogtada guga (k) waa joogto ilaa xoog jiidis ah oo ah 8 Newtons. Sidaa darteed, gu'gu wuxuu ahaan doonaa mid dabacsan marka la eego xoog jiidis ah oo ah 0 ilaa 8 Newtons.

Jawaabta saxda ah waa B.

19. Jaantuska soo socda wuxuu muujinayaa xiriirka ka dhexeeya kororka dhererka Δx iyo xoogga ΔF ee caagga lagu jiido xoog. Iyada oo ku saleysan garaafka, caaggu wuxuu beddeli doonaa sifooyinkiisa balaastikada ah marka xoog ku shaqeeyo caagga...

A. 0 ilaa 2 N

B. 0 ilaa 4 N

C. 2 N ilaa 6 N

D. 4 N ilaa 8 N

E. 6 N ilaa 8 N

Dood

Cinjirku wuu sii jiri doonaa dabacsanaan ilaa inta joogtada laastikada ay joogto tahay. Haddii joogtada laastikada ay bilaabato inay isbeddesho, cinjirku wuxuu bilaabaa inuu ka beddelo laastikada una beddelo balaastig. Laastikada macnaheedu waa ka dib marka xoogga la saaro, cinjirku wuxuu ku soo noqdaa qaabkiisii ​​​​asalka ahaa. Taas beddelkeeda, balaastiggu wuxuu la macno yahay in ka dib marka xoogga la saaro, cinjirku uusan ku soo noqon qaabkiisii ​​​​asalka ahaa.

U fiirso garaafka kore oo faham xisaabinta soo socota:

k ₁ = ΔF / Δx = 2 / 2 = 1

k ₂ = ΔF / Δx = 4 / 4 = 1

k ₃ = ΔF / Δx = 6 / 6 = 1

k ₄ = ΔF / Δx = 7 / 8 = 0,87

k ₄ = ΔF / Δx = 8 / 12 = 0,6

Cinjirku wuxuu beddeli doonaa dabacsanaantiisa marka xoog u dhexeeya 6 ilaa 8 Newtons lagu mariyo. Haddii xooggu ka weyn yahay 8 Newtons, cinjirku wuu jabayaa.

20. Fiiri garaafka xiriirka ka dhexeeya xoogga ΔF iyo kororka dhererka Δx ee guga hoose!
Iyada oo ku saleysan garaafka, gu'gu wuxuu ahaan doonaa mid dabacsan marka uu laalaabanayo xoog...

A. 0 ilaa 4 N
B. 0 ilaa 8 N
C. 0 ilaa 12 N
D. 8 N ilaa 12 N
E. 8 N ilaa 16 N

Dood
Gu'gu wuu sii jiri doonaa haddii sharciga Hooke uu weli khuseeyo. Xisaab ahaan, sharciga Hooke waxaa lagu qeexay qaacidada:
k = ΔF / Δx
Sharaxaadda qaacidada:
k = joogto ah oo laastikada ah, ΔF = xoog, Δx = dhererka guga

Sharciga Hooke wuxuu dhigayaa in saamiga isbeddelka xoogga (ΔF) iyo isbeddelka dhererka (Δx) ee gu'gu uu had iyo jeer yahay mid joogto ah. Haddii qiimaha k isbeddelo, sharciga Hooke mar dambe ma khuseeyo gu'ga taasina waxay muujinaysaa in gu'gu uusan mar dambe dabacsanayn.

Fiiri garaafka kore oo faham xisaabinta soo socota.
k₁ = ΔF / Δx = 4/2 = 2
k₂ = ΔF / Δx = 8/4 = 2
k₃ = ΔF / Δx = 12/7 = 1,7

Joogtada guga (k) waa joogto ilaa xoog jiidis ah oo ah 8 Newtons. Sidaa darteed, gu'gu wuxuu ahaan doonaa mid dabacsan marka la eego xoog jiidis ah oo ah 0 ilaa 8 Newtons.
Jawaabta saxda ah waa B.

21. Jaantuska soo socda wuxuu muujinayaa xiriirka ka dhexeeya kororka dhererka Δx iyo xoogga ΔF ee xarigga caagga ah ee lagu jiidayo xoog. Iyada oo ku saleysan garaafka, caaggu wuxuu beddeli doonaa sifooyinkiisa balaastikada ah marka xoog ku dhaqmo...

A. 0 ilaa 2 N
B. 0 ilaa 4 N
C. 2 N ilaa 6 N
D. 4 N ilaa 8 N
E. 6 N ilaa 8 N

Dood
Cinjirku wuu sii jiri doonaa dabacsanaan ilaa inta joogtada laastikada ay joogto tahay. Haddii joogtada laastikada ay bilaabato inay isbeddesho, cinjirku wuxuu bilaabaa inuu ka beddelo laastikada una beddelo balaastig. Laastikada macnaheedu waa ka dib marka xoogga la saaro, cinjirku wuxuu ku soo noqdaa qaabkiisii ​​​​asalka ahaa. Taas beddelkeeda, balaastiggu wuxuu la macno yahay in ka dib marka xoogga la saaro, cinjirku uusan ku soo noqon qaabkiisii ​​​​asalka ahaa.

U fiirso garaafka kore oo faham xisaabinta soo socota:
k₁ = ΔF / Δx = 2/2 = 1
k₂ = ΔF / Δx = 4/4 = 1
k₃ = ΔF / Δx = 6/6 = 1
k₄ = ΔF / Δx = 7/8 = 0,87
k₅ = ΔF / Δx = 8/12 = 0,6

Cinjirku wuxuu beddeli doonaa dabacsanaantiisa marka xoog u dhexeeya 6 ilaa 8 Newtons lagu mariyo. Haddii xooggu ka weyn yahay 8 Newtons, cinjirku wuu jabayaa.

Jawaabta saxda ah waa E.

Joogtada ah ee dabacsanaanta

22. Fiiri xogta tijaabada ah ee shan nooc oo taayirro caag ah A, B, C, D iyo E ah kuwaas oo lagu jiido xoog F si dhererkoodu u kordho. Taayirka caagga ah ee leh joogtada guga ugu yar waa…
Dood

Qaaciddada sharciga Hooke :
k = F / Δx
Sharaxaad: k = dabacsanaan joogto ah, F = gaya, Δx = kordhinta dhererka cinjirka
Joogtada dabacsanaanta ee caagga:
k_A = F / Δx = 1 / 0,05 = 20 N/m
k_B = F / Δx = 2 / 0,025 = 80 N/m
k_C = F / Δx = 1 / 0,025 = 40 N/m
k_D = F / Δx = 2 / 0,05 = 40 N/m
k_E = F / Δx = 2 / 0,25 = 8 N/m
Jawaabta saxda ah waa E.

23. Laga soo bilaabo tijaabada lagu go'aaminayo dabacsanaanta caagga iyadoo la isticmaalayo caagga taayirka, xogta la helay waxay u egtahay shaxda soo socota. Waxaa lagu soo gabagabeyn karaa in qiimaha ugu badan ee joogtada ah uu yahay tijaabada….
Dood
Qaacidada sharciga Hooke:
k = F / Δx
Joogtada guga:
k_A = 7/0,035 = 200 Nm^-1
k_B = 8/0,025 = 320 Nm^-1
k_C = 6/0,020 = 300 Nm^-1
k_D = 9/0,045 = 200 Nm^-1
k_E = 10/0,033 = 303 Nm^-1
Joogtada ugu weyn ee laastikada waa 320 Nm^-1.
Jawaabta saxda ah waa B.

Isha su'aasha:

Su'aalaha Imtixaanka Qaranka ee Fiisigiska ee Dugsiga Sare/Dugsiga Sare ee Xirfadda