5 Tusaalooyin Su'aalo Ku Saabsan Korontada
1. Nalalka TL waxaa lagu calaamadeeyay 10 W, 220 V. Taas macnaheedu waa nalalka waxay u baahan yihiin...
A. tamar 10 J/ilbiriqsi iyo hadda 0,045 A
B. tamar 10 J/ilbiriqsi iyo hadda 22 A
C. tamar 10 J/daqiiqo iyo hadda 0,045 A
D. tamar 10 J/daqiiqo iyo hadda 22 A
Dood
Waa la ogyahay in:
Awood (P) = 10 Watts
La weydiiyay: Laambaddu waxay u baahan tahay...
Jawaab:
Awoodda laambadda = 10 Watt = 10 Joules/ilbiriqsi.
Taas macnaheedu waa in laambaddani ay isticmaasho 10 Joules/ilbiriqsi tamar ah.
Qaacidada xiriirka ka dhexeeya korontada, danabka korontada iyo qulqulka korontada:
P = VI
Sharaxaad: P = awoodda korontada, V = danab koronto, I = koronto koronto
Markaa korontada waa:
I = P / V = 10 / 220 = 1/22 = 0,045 Amper
Jawaabta saxda ah waa A.
2. Bal eeg sawirka! Awoodda korantada ee wareeggan waa...
A. 2 watt
B. 24 watt
C. 48 watt
D. 72 watt
Dood
Waa la ogyahay in:
Iska caabbiye 1 (R 1 ) = 6 Ω
Iska caabbinta 2 (R 2 ) = 6 Ω
Danabka korontada (V) = 24 Volts
La weydiiyay: Awoodda korontada
Jawaab:
Iska-caabinta beddelka ah:
R1 iyo R2 Isku xiran taxane ahaan. Resistor-ka beddelka ah waa:
R = R1 + R2 = 6 Ω + 6 Ω = 12 Ω
Xoogga hadda korontada:
I = V/R = 24/12 = 2 Ampere
Awoodda korontada:
P = VI = (24)(2) = 48 Watts = 48 Joules/ilbiriqsi
3. 3 kiilowatt oo koronto ah ayaa lagu gudbiyaa 150 volts. Cabbirka qulqulka qulqulka waa...
A. 10 Amperes
B. 20 Ampere
C. 30 Ampere
D. 40 Ampere
Dood
Waa la ogyahay in:
Awoodda korontada (P) = 3 kiilo Watt = 3000 Watt
Danabka korontada (V) = 150 Volts
Su'aal: Xoogga hadda korontada (I)
Jawaab:
Qaacidada sheegaysa xiriirka ka dhexeeya korontada, danabka korontada iyo qulqulka korontada:
P = VI
Xisaabi qulqulka korantada adoo isticmaalaya qaacidada kore:
I = P/V
I = 3000 Watts / 150 Volts
I = 20 Amperes
Jawaabta saxda ah waa B.
4. Gurigu wuxuu isticmaalaa 4 laambadood oo 20-watt ah, 2 laambadood oo 60-watt ah, iyo TV 60-watt ah. Waxaa la shidaa celcelis ahaan 8 saacadood maalintii. Haddii korontadu ay ku kacayso Rp 111,30 kWhkiiba, immisa ayay ku kacaysaa 1 bil (30 maalmood)?
Dood
Waa la ogyahay in:
4 laambadood oo 20 Watt ah = 4 x 20 Watts = 80 Watts
2 laambadood oo 60 Watt ah = 2 x 60 Watts = 120 Watts
60 Watt TV = 60 Watts
Tirada korontada la isticmaalay:
80 Watts + 120 Watts + 60 Watts = 260 Watts
Muddada u dhaxaysa = 8 saacadood x 30 = 240 saacadood
La weydiiyay: Kharashka la bixin doono muddo 1 bil ah (30 maalmood)
Jawaab:
Tamarta = Awood x Waqti = 260 Watt x 240 saacadood = 62400 Watt saacadood = 62,4 kilo Watt saacadood = 62,4 kWh
Qiimaha = 62,4 kWh x Rp. 111,30 = Rp. 6945,12
5. Laba walxood oo kuleyliye koronto ku shaqeeya ayaa laga sameeyay laba fiilooyin oo isku mid ah oo dhexroorkoodu yahay 1 mm iyo 2 mm, mid walbana dhererkiisu yahay 2 m. Haddii labada fiilooyin ay ku xiran yihiin isha danab isku mid ah, markaa saamiga u dhexeeya wax soo saarka korontada ee fiilooyinka 1 mm iyo 2 mm waa…
A. 1: 1
B. 1: 2
C. 1: 4
D. 2: 1
E. 4: 1
Dood
Qaacidada iska caabbinta korantada iyo iska caabbinta gaarka ah:
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Sharaxaad: R = iska caabin, ρ = iska caabin gaar ah, l = dhererka gudbiyaha, A = bedka dusha sare ee gudbiyaha
Qaacidada sharciga Ohm:
V = IR
Sharaxaad: V = danab koronto, I = koronto koronto, R = iska caabin koronto
Qaacidada korontada:
P = VI
P = (IR) I
P = I 2 R

Iyada oo ku saleysan qaacidada kore, awoodda korontadu (P) waxay si liddi ah ugu dhigantaa dhexroorka siligga (d):

Saamiga u dhexeeya awoodda ay soo saarto silig dhexroorkiisu yahay 1 mm iyo 2 mm waa:
4: 1
Jawaabta saxda ah waa E.
Isha su'aasha:
Su'aalaha Imtixaanka Qaranka ee Sayniska ee Dugsiga Sare ee Hoose/Dugsiga Sare ee Islaamiga ah
Su'aalaha Fiisigiska ee SBMPTN