Tusaale dhibaato awood koronto oo barbar socota oo ka jirta saxanka capacitor-ka

7 Tusaalooyin su'aalo ah oo ku saabsan awoodda capacitor-ka saxanka ee isbarbar socda

1. Kaaliyaha saxanka ee barbar socda oo leh awood C wuxuu leeyahay awood faaruq ah oo ε aho, aagga isgoyska A iyo masaafada u dhaxaysa taarikada d. Haddii aagga isgoyska ee kaanstarka la kordhiyo ilaa 4 jeer, masaafada u dhaxaysa taarikada waxay noqotaa 2d oo ogolaanshaha faakuumka wuxuu noqdaa 5εo, sidaas Awoodda capacitor-ka saxanka barbar socda waxay isu beddeshaa…
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Tusaale matoor kuleyl (isticmaalka sharciga labaad ee thermodynamics)

9 Tusaalooyin dhibaatooyinka matoorka kulaylka (isticmaalka sharciga labaad ee thermodynamics)

1. Hal wareeg, matoorku wuxuu nuugaa 3000 Joule oo kuleyl ah oo ka yimaada kayd heerkul sare leh wuxuuna diidaa 1000 Joule oo kuleyl ah oo ku rida kayd heerkul hooseeya. Go'aami waxtarka matoorka kulaylka!

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Mashiinka kulaylka Ereyga "carnot" ee ku jira su'aalaha boggan kuma eka matoorka Carnot. Matoorka Carnot waa matoor kuleyl ku habboon wuxuuna jiraa oo keliya aragti ahaan. Taas bedelkeeda, matoorka kulaylka ee lagu sheegay su'aashan waa matoor kuleyl dhab ah, ee maaha matoor kuleyl aragtiyeed (matoorka Carnot).

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Tusaalooyin su'aalo ah oo ku saabsan ku dhaqanka sharciga koowaad ee thermodynamics-ka hababka kala duwan ee thermodynamic-ka (isobaric, isothermal, isochoric)

11 Tusaalooyin su'aalo ah oo ku saabsan ku dhaqanka sharciga koowaad ee thermodynamics ee hababka kala duwan ee thermodynamic (isobaric, isothermal, isochoric)

1. Jaantuska hoose wuxuu muujinayaa wareegga thermodynamic-ka ee uu gaasku la kulmo. Shaqada uu gaaska ku sameeyo habka ABCD waa…

Su'aalo tusaale ah oo ku saabsan ku dhaqanka sharciga koowaad ee thermodynamics ee hababka kala duwan ee thermodynamic (isobaric, isothermal, isochoric) - 1Dood
Waa la garanayaa :
Cadaadiska 1 (P)1) = 2 x 105 Pa
Cadaadiska 2 (P)2) = 4 x 105 Pa
Mugga 1aad (V)1) = 1 m3
Mugga 2aad (V)2) = 3 m3
La weydiiyay Shaqada uu gaaska ku qabtay habka wareegga ABCD
Jawab :
Shaqada waxaa qabta gaas = bedka leydiga ABCD.
W = (P)2 - P1)(V2 - V1)
W = (4 x 105 - 2 x 105)(3 – 1)
W = (2 x 105) (2)
W = 4 x 105 Joule
Shaqada uu gaaska ku sameeyo habka wareegga ABCD waa 4 x 105 Joule.

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Tusaale ahaan ku dabaqidda sharciga koowaad ee thermodynamics habka isochoric (mugga joogtada ah)

3 Tusaalooyin su'aalo ah oo ku saabsan hirgelinta sharciga koowaad ee thermodynamics ee hababka isochoric (mugga joogtada ah)

1. Garaafka cadaadiska (P) ee ka dhanka ah mugga (V) ee gaaska maraya habka isochoric. Shaqada uu gaaska ku sameeyo habka AB waa…

Tusaale ahaan ku dabaqidda sharciga koowaad ee thermodynamics habka isochoric (mugga joogtada ah) - 1Dood
Geedi socodka AB = habka isochoric (mugga joogtada ah). Mugga isochoric, mugga gaaska (iyo mugga booska) isma beddelo sidaas darteed ma jiro shaqo uu gaasku qabto.

2. Saddex mool oo gaas monatomic ah heerkul ah 47 o C iyo cadaadis ah 2 x 10 5 Pascal waxay maraan hab isochoric ah ilaa cadaadisku uu kordho 3 x 10 5 Pascal. Isbeddelka tamarta gudaha ee gaaska waa… Joogtada gaaska guud (R) = 8,315 J/mol.K

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Tusaale ahaan ku dabaqidda sharciga koowaad ee thermodynamics habka isothermal-ka (heerkulka joogtada ah)

5 tusaale oo ku saabsan ku dhaqanka sharciga koowaad ee thermodynamics hababka isothermal-ka (heerkulka joogtada ah)

1. Jaantuska hoose wuxuu muujinayaa gaas ku habboon oo la marinayo Habka isothermal-ka (habka). Shaqada uu gaaska ku qabto habka AB waa…
Tusaale ahaan ku dhaqanka sharciga koowaad ee thermodynamics habka isothermal-ka ee heerkulka joogtada ah 1Dood
Shaqada la qabtay = bedka ka hooseeya qalooca AB = bedka saddexagalka + bedka leydiga
W = [½ (8 x 105–4 x 105)(3-1)] + [4 x 105 (3-1)]
W = [½ (4 x 105)(2)] + [4 x 105 (2)
W = [4 x 105] + [8 x 105]
W = 12 x 105 Joule

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Tusaale ahaan ku dhaqanka sharciga koowaad ee thermodynamics habka isobaric (cadaadis joogto ah)

6 Tusaalooyin su'aalo ah oo ku saabsan ku dhaqanka sharciga koowaad ee thermodynamics ee hababka isobaric (cadaadis joogto ah)

1. Cadaadiska (P) - garaafka mugga (V) ee gaaska oo maraya habka isobaric. Shaqada uu gaaska ku sameeyo habka AB waa…

Tusaale ahaan ku dabaqidda sharciga koowaad ee thermodynamics habka isobaric ee cadaadiska joogtada ah 1Dood

Waa la garanayaa :
Cadaadiska (P) = 5 x 105 N / m2
Mugga bilowga ah (V)1) = 2 m3
Mugga kama dambaysta ah (V)2) = 6 m3
La weydiiyay : shaqada lagu qabtay habka AB

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Su'aalo tusaale ah oo ku saabsan sharciga koowaad ee thermodynamics

3 Tusaalooyin su'aalo ah oo ku saabsan sharciga koowaad ee thermodynamics

1. 3000 oo Joule oo kulayl ah ayaa lagu daraa nidaamka, nidaamkuna wuxuu sameeyaa 2500 Joule oo shaqo ah oo ku saabsan deegaanka. Isbeddelka tamarta gudaha ee nidaamka waa…

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Waa la garanayaa :
Kulayl (Q) = +3000 Joules
Shaqada (W) = +2500 Joules
La weydiiyay : isbeddellada tamarta gudaha
Jawab :

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Su'aalo tusaale ah oo ku saabsan aragtida kinetic ee gaasaska

19 Tusaalooyin oo ka mid ah Aragtida Kinetic ee Gaasaska

1. Gaaska ku habboon ee ku jira weel xiran wuxuu marka hore leeyahay cadaadis P iyo mugga V. Haddii cadaadiska gaaska la kordhiyo ilaa 4 jeer asalka ah oo mugga gaaska uu ahaado mid joogto ah, saamiga tamarta kicinta bilowga ah iyo tamarta kicinta ugu dambeysa ee gaaska waa...
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Waa la garanayaa :
Cadaadiska bilowga ah (P)1) = P
Cadaadiska kama dambaysta ah (P)2) = 4P
Mugga bilowga ah (V)1) = V
Mugga kama dambaysta ah (V)2) = V

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Su'aalo tusaale ah oo ku saabsan sharciga gaaska ee ku habboon

18 Tusaalooyin Su'aalo ku saabsan Sharciga Gaaska ee Ku Habboon

1. Gaaska ku habboon booska marka hore wuxuu leeyahay mugga V iyo heerkulka T. Haddii gaaska la kululeeyo si heerkulku u beddelo 5/4 T oo cadaadiskuna u beddelo 2P markaas mugga gaaska ayaa isu beddelaya...

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Waa la garanayaa :
Mugga bilowga ah (V)1) = V
Heerkulka bilowga ah (T)1) = T
Heerkulka kama dambaysta ah (T)2) = 5/4 T
Cadaadiska bilowga ah (P)1) = P
Cadaadiska kama dambaysta ah (P)2) = 2P
La weydiiyay Mugga kama dambaysta ah (V)2)

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Tusaalaha sharciga Gay-Lussac (mugga isochoric-joogto ah)

3 Tusaalooyin oo ka mid ah sharciga Gay-Lussac (mugga isochoric-joogto ah)

1. Tiro gaasas ah ayaa marka hore leh cadaadis P iyo heerkul T. Haddii gaasku maro hab isochoric ah si cadaadisku u noqdo 4 jeer cadaadiskii asalka ahaa, heerkulka gaasku wuxuu isu beddelaa...

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Waa la garanayaa :
Cadaadiska bilowga ah (P)1) = P
Cadaadiska kama dambaysta ah (P)2) = 4P
Heerkulka bilowga ah (T)1) = T
La weydiiyay heerkulka ugu dambeeya (T)2)

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