Mutemo wegesi wakanaka - matambudziko nemhinduro

1. Ndinoshandisa magasi mumudziyo wakavharwa pakutanga ndiine vhoriyamu V uye tembiricha T. Tembiricha yekupedzisira i5/4T uye kumanikidzwa kwekupedzisira i2P. Vhoriyamu yekupedzisira yegasi chii?

Zvinozivikanwa:

Vhoriyamu yekutanga (V ₁ ) = V

Tembiricha yekutanga (T ₁ ) = T

Kupisa kwekupedzisira (T ₂ ) = 5/4 T

Kumanikidzwa kwekutanga (P ₁ ) = P

Kumanikidzwa kwekupedzisira (P ₂ ) = 2P

Kudiwa: Vhoriyamu Yokupedzisira (V ₂ )

Solution:

2. Tsvaga huwandu hwe2.00 mols yemagasi (gasi rakakodzera) paSTP. STP = Tembiricha Yakajairika uye Kumanikidzwa.

Zvinozivikanwa:

Mamoles egasi (n) = mamoles maviri echando

Tembiricha yakajairika (T) = 0 ^o C = 0 + 273 = 273 Kelvin

Kumanikidzwa kwakajairika (P) = 1 atm = 1.013 x 10 ⁵ Pa

Universal gas constant (R) = 8.315 Joule/mol e .Kelvin

Zvinodiwa : Huwandu hwemagasi (V)

Solution:

Equation yemutemo wegesi wakanaka (muhuwandu hwemamoles, n)

Huwandu hwemamoles maviri emagasi i44.8 litres.

Vhoriyamu ye1 mole yemagasi i45.4 litres / 2 = 22.4 litres.

Vhoriyamu ye1 mole yegesi chero ipi zvayo i22.4 litres.

3. 4 marita egasi reokisijeni ane tembiricha ye27°C uye kumanikidzwa kwe2 atm (1 atm = 10 ⁵ Pa) mumudziyo wakavharwa. Universal gas constant (R) = 8.314 J.mol e ⁻¹ .K ⁻¹ uye nhamba yaAvogadro ( N _​​A ) = 6.02 x 10 ²³ mamorekuru/mole e . Ndeapi mamorekuru emagasi eokisijeni ari mumudziyo?

Zvinozivikanwa:

Huwandu hwemagasi (V) = 4 marita = 4 dm ³ = 4 x 10 ^-3 m ³

Tembiricha yemagasi (T) = 27 ^o C = 27 + 273 = 300 Kelvin

Kumanikidzwa kwemagasi (P) = 2 atm = 2 x 10 ⁵ Pa

Gasi risingaperi repasi rose (R) = 8.314 J.mol e ⁻¹ .K ⁻¹

Nhamba yaAvogadro (N _A ) = 6.02 x 10 ²³

Zvinodiwa : Ndeapi mamorekuru emagasi eokisijeni ari mumudziyo (N)

Solution:

Mu mole imwe chete yemagasi eokisijeni, mune mamorekuru eokisijeni 1.93 x 10 ^{23 .}

4. Chirongo chine gasi reNeon (Ne, atomic mass = 20 u) patembiricha yakajairwa uye kumanikidzwa (STP ) chine vhoriyamu ye2 m3 ^. Tsvaga huremu hwegasi reNeon!

Zvinozivikanwa:

Kurema kweatomu ye neon = 20 gram/mol e = 0,02 kg/mol e

Tembiricha yakajairika (T) = 0 ^o C = 273 Kelvin

Kumanikidzwa kwakajairika (P) = 1 atm = 1.013 x 10 ⁵ Pascal

Vhoriyamu (V) = 2 m ³

Zvinodiwa : huremu (m) hwegasi re neon

Solution:

Pakupisa kwakajairika uye kumanikidzwa (STP), 1 mole chero magasi, sanganisira neon gasi, ine vhoriyamu 22.4 liters = 22.4 dm³ = 0.0448 XNUMX m³.

Muhuwandu hwe2 m3 ^, kune mamoles 44.6 egasi re neon.

Huremu hwemaatomu egasi reNeon hunosvika magiramu makumi maviri pamota.

Izvi zvinoreva kuti mu mole imwe chete mune magiramu makumi maviri kana 0.02 kg egasi re neon. Nekuti mu mole imwe chete mune 0.02 kg yegasi re neon saka mu 44.6 mole mune 44.6 moles x 0.02 kg/mole = 0.892 kg = 892 gramu dzegasi re neon.