1. 1 kg yemvura pa 100oC yakasanganiswa ne 1 kg yemvura pa 10oC muhurongwa hwakasiyana. kupisa chaiko yemvura 4200 J/kg oC. Sarudza yekupedzisira tembiricha yemusanganiswa!
Zvinozivikanwa:
Misa yemvura inopisa (m1) = 1 kg
Kupisa kwemvura inopisa (T1= = 100oC
Mvura inotonhora yakawanda (m2) = 1 kg
Kupisa kwemvura inotonhora (T2= = 10oC
Zvaidiwa: Tembiricha yekupedzisira (T)
Solution:
Kurasikirwa nekupisa = Kupisa kwawanikwa (system yakaparadzaniswa)
m c ΔT = m c ΔT
m ΔT = m ΔT
m1 (T1 – T) = m2 (T - T2)
(1)(100 – T) = (1)(T – 10)
100 - T = T – 10
100 + 10 = T + T
110 = 2T
T = 110 / 2
T = 55
Tembiricha yekupedzisira ndeye 55oC.
2. Bhokisi remutobvu re3 kg pa80o yakaiswa mu10 kg yemvura. Kupisa kwemutobvu chaiwo i1400 J.kg-1C-1 uye kupisa kwemvura chaiyo i4200 J.kg-1C-1Tembiricha yekupedzisira mukuenzanisa kwekupisa ndeye 20oC. Sarudza tembiricha yekutanga yemvura!
Zvinozivikanwa:
Misa (m1) = 3 kg
Kupisa kwakananga kwemutobvu (c1) = 1400 J.kg-1C-1
Kupisa kwemutobvu (T1= = 80 oC
Mvura yakawanda (m2) = 10 kg
Kupisa kwemvura chaiyo (c2) = 4200 J.kg-1C-1
Kupisa kwekuenzana kwekupisa (T) = 20 oC
Zvaidiwa: Tembiricha yekutanga yemvura (T2)
Solution:
Kupisa kwakarasika = Kupisa kwawanikwa
Q tungamira =Q mvura
m1 c1 ΔT = m2 c2 ΔT
(3)(1400)(80-20) = (10)(4200)(20-T)
(4200)(60) = (42,000)(20-T)
252,000 = 840,000 – 42,000 T
42,000 T = 840,000 – 252,000
42,000 T = 588,000
T = 588,000 / 42,000
T = 14
Tembiricha yekutanga yemvura ndeye 14oC.
3. Bhokisi remhangura pa 100oC yakaiswa mu 128 gramu yemvura pa 30 oC. Kupisa kwemvura chaiyo ndiko 1 cal.g-1oC-1 uye kupisa kwemhangura chaiyo ndiko 0.1 cal.g-1oC-1. Kana tembiricha ye thermal equilibrium iri 36 oC, sarudza huremu hwemhangura!
Zvinozivikanwa:
Kupisa kwemhangura (T1= = 100 oC
Kupisa chaiko kwemhangura (c1= = 0.1 cal.g-1oC-1
Mvura yakawanda (m2) = magiramu 128
Tembiricha yemvura (T2= = 30 oC
Kupisa kwemvura chaiyo (c2= = 1 cal.g-1oC-1
Kupisa kwekuenzana kwekupisa (T) = 36 oC
Zvaidiwa: Huremu hwemhangura (m1)
Solution:
Kupisa kwakarasika = Kupisa kwawanikwa
Q Mhangura =Q mvura
m1 c1 ΔT = m2 c2 ΔT
(m1)(0.1)(100-36) = (128)(1)(36-30)
(m1)(0.1)(64) = (128)(1)(6)
(m1)(6.4) = 768
m1 = 768/6.4
m1 = 120
Huremu hwemhangura ndi 120 magiramu.
4. Chivharo chechando cheM-kg pa 0oC yakaiswa mu 340 gramu yemvura pa 20oC muhari. Kana kupisa kwekubatana yemvura = 80 cal g-1, kupisa kwemvura chaiyo ndiko 1 cal g-1 oC-1. Aizi yese inonyunguduka uye tembiricha ye kuenzana kwekupisa is 5oC, sarudza huwandu hwechando!
Zvinozivikanwa:
Mvura yakawanda (m) = magiramu 340
Kupisa kwechando (T ice= = 0oC
Kupisa kwemvura (T mvura= = 20oC
Kupisa kwekuenzana kwekupisa (T) = 5oC
Kupisa kwekubatana kwemvura (L= = 80 cal g-1
Kupisa kwemvura chaiyo (c mvura= = 1 cal g-1 oC-1
Zvaidiwa: Misa yechando (M)
Solution:
Kupisa kwakarasika = Kupisa kwawanikwa
Mvura yeQ = chando cheQ
m c (ΔT) = mes Les +m c (ΔT)
(340)(1)(20-5) = M (80) + M (1)(5-0)
(340)(15) = 80M + 5M
5100 = 85M
M = 5100/85
M = magiramu makumi matanhatu
[wpdm_package id='714′]
- Kuchinja zviyero zvekupisa
- Linear kuwedzera
- Kuwedzera kwenzvimbo
- Kuwedzera inzwi
- Heat
- Kuenzana kwekupisa kwemuchina
- Kupisa kwakananga uye kugona kupisa
- Kupisa kwakahwanda, kupisa kwekusanganiswa, kupisa kwekupfuta
- Kuchengetedza simba rekutamisa kupisa