Pakati pesimba rinokwevera zvinhu pasi

1. Tsanangudzo ye nzvimbo yegiravhiti

Muviri wakasimba unoumbwa nezvidimbu zvakawanda; saka, simba rekukwevera rinoshanda pane chimwe nechimwe chezvidimbu izvi. Nemamwe mashoko, chidimbu chimwe nechimwe chine huremu hwacho. Pakati pesimba rekukwevera chinhu ipo pachinhu apo huremu hwezvikamu zvese zvechinhu hunoonekwa sehwakaiswa pakati ipapo.

Nzvimbo yegiravhiti 1

Kana chinhu chakafanana (huwandu hwechikamu chimwe nechimwe chechinhu chakafanana kana chinhu chacho chakagadzirwa nezvinhu zvakafanana) uye chimiro chechinhu chacho chakaenzana (semuenzaniso sikweya, rectangular, denderedzwa)

ipapo huremu hwechinhu hunoenderana nepakati pehukuru hwechinhu, chiri pakati pechinhu. Kune matriangles, pakati pehukuru huri pa 1/3 awa (h = kureba kwetriangle).

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Nzvimbo yegiravhiti 2

2. Equation yepakati pegiravhiti

Kana chimiro chechinhu chakaenzana uye chinhu chacho chakafanana, ipapo pakati pesimba rinokwevera zvinhu pasi pechinhu chacho panoenderana nepakati pehukuru hwechinhu chacho,

uko pakati pesimba rinokwevera pasi nepakati pehukuru zviri pakati pechinhu. Kusiyana neizvi, kana chinhu chacho chakafanana asi chisina kuenzana, saka nzvimbo yehuremu hwechinhu inogona kuzivikanwa uchishandisa fomura inotevera.

Makorodheni ehuremu hwechinhu pa x-axis:

Nzvimbo yegiravhiti 3a

Makorodheni ehuremu hwechinhu pa y-axis:

Nzvimbo yegiravhiti 3b

x = pakati pechinhu chiri pa x-axis, y = pakati pechinhu chiri pa y-axis, A = nzvimbo. Kana chinhu chiri muzvikamu zvitatu, kunze kwekuona ma coordinates ehuremu hwechinhu pa x ne y axes, zvinoonawo ma coordinates ehuremu hwechinhu pa z-axis. Nzvimbo (A) inotsiviwa ne volume (V).

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Dambudziko remuenzaniso 1.

Sarudza makorokoto epakati pegiravhiti yechinhu chakafanana mumufananidzo uri padivi!

Solution:

Govanisa zvinhu kuita zvikamu zvitatu.

A 1 = (10-0)(10-0) = (10)(10) = 100

A2 = (20-10)(30-0) = (10)(30) = 300Nzvimbo yegiravhiti 4

A 3 = (30-20)(10-0) = (10)(10) = 100

x 1 = 1⁄2 (10-0) = 1⁄2 (10) = 5

x 2 = 1⁄2 (20-10) + 10 = 1⁄2 (10) + 10 = 5 + 10 = 15

x 3 = 1⁄2 (30-20) + 20 = 1⁄2 (10) + 20 = 5 + 20 = 25

y 1 = 1⁄2 (10-0) = 1⁄2 (10) = 5

y 2 = 1⁄2 (30-0) = 1⁄2 (30) = 15

y 3 = 1⁄2 (10-0) = 1⁄2 (10) = 5

Makorodheni ehuremu hwechinhu pa x-axis:

Nzvimbo yegiravhiti 5

Makorodheni ehuremu hwechinhu pa y-axis:

Nzvimbo yegiravhiti 6

Makoronesheni ehuremu hwechinhu ndeaya (15; 11)

Dambudziko remuenzaniso 2.

Sarudza makorokoto ehuremu hwechinhu chiri mumufananidzo!Nzvimbo yegiravhiti 7

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Solution:

Govanisa chinhu kuita zvikamu zviviri, nzvimbo 1 = sikweya, nzvimbo 2 = mativi matatu.

A 1 = (5-1)(3-0) = (4)(3) = 12

A 2 = 1⁄2 (6-0)(9-3) = 1⁄2 (6)(6) = (3)(6) = 18

x 1 = 1⁄2 (5-1) + 1 = 1⁄2 (4) + 1 = 2 + 1 = 3

x 2 = 1⁄2 (6-0) = 1⁄2 (6) = 3

y 1 = 1⁄2 (3-0) = 1⁄2 (3) = 1.5

y 2 = 1/3(9-3) + 3 = 1/3(6) + 3 = 2 + 3 = 5

Makorodheni ehuremu hwechinhu pa x-axis:

Nzvimbo yegiravhiti 8

Makorodheni ehuremu hwechinhu pa y-axis:

Nzvimbo yegiravhiti 9

Nhamba yehuremu hwechinhu ichi ndeye (3; 3.6)

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