Muenzaniso wemubvunzo wekukurukurirana pamusoro pe acid-base titration

Muenzaniso weMibvunzo yeKukurukurirana kweAcid-Base Titration

Kuganhurirwa kweacid-base ndiyo imwe yenzira dzinonyanya kushandiswa mukuongorora huwandu hwezvinhu mumakemikari. Iyi nzira inosanganisira kuita pakati peacid nebase kuti tione huwandu hwemhinduro. Muchinyorwa chino, tichakurukura mienzaniso yakati wandei yematambudziko eacid-base titration nemhinduro dzawo, nechinangwa chekukubatsira kunzwisisa pfungwa huru uye maitiro ekuzviita.

Pfungwa Dzekutanga dzeAcid-Base Titration

Kuwanda kweacid-base kunosanganisira kuita kwe neutralization pakati pehydrogen ions (H⁺) kubva kuma acid ne hydroxide ions (OH⁻) kubva pa base kuti igadzire mvura (H₂O). Equivalence point ndiyo nzvimbo iyo nhamba yema moles e acid yakaenzana nenhamba yema moles e base yakawedzerwa. Panguva iyi, reaction pakati pe acid ne base yaitika zvachose.

Fomura Yakazara

Nzira huru inoshandiswa mu acid-base titration ndeiyi:

\[ n_{a} \cdot M_{a} \cdot V_{a} = n_{b} \cdot M_{b} \cdot V_{b} \]

di mana:
– \( n_{a} \) ndiyo valence yeasidhi,
– \( M_{a} \) ndiyo mwero weasidhi,
– \( V_{a} \) ihuwandu hweasidhi,
– \( n_{b} \) ndiyo valence yekutanga,
– \( M_{b} \) ndiyo mwero wehwaro,
– \( V_{b} \) ivhoriyamu yehwaro.

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Pepa reLitmus neZviratidzo

Mukuita kwetitration, zviratidzo zveacid-base zvakaita sephenolphthalein kana methyl orange zvinowanzo shandiswa kuona poindi yekuenzana. Zviratidzo izvi zvinoshandura ruvara pa pH chaiyo, zvichiratidza kuti poindi yekuenzana yasvika.

Mibvunzo yemuenzaniso nekukurukurirana

Muenzaniso Mubvunzo 1: Kuwanda kweAcid Yakasimba neBasi Rakasimba

Mubvunzo:
Zvinozivikanwa kuti 25 mL ye 0,1 M HCl solution inoiswa titration ne 0,1 M NaOH solution. Ndeupi huwandu hweNaOH hunodiwa kuti usvike pa equivalence point?

Kukurukurirana:
Mhinduro pakati peHCl neNaOH ndeiyi:
\[ HCl + NaOH \kurudyi NaCl + H_2O \]

Danho 1: Tsvaga mamoles eH⁺ kubva kuHCl
\[ n_{\text{HCl}} = M_{\text{HCl}} \times V_{\text{HCl}} \]
\[ n_{\text{HCl}} = 0,1 \times 0,025 = 0,0025 \text{mol} \]

Danho rechipiri: Sarudza huwandu hweNaOH hunodiwa
Nekuti HCl neNaOH zvine chiyero che1:1 mukuita (n = 1):
\[ n_{\text{HCl}} = n_{\text{NaOH}} \]
\[ M_{\text{NaOH}} \times V_{\text{NaOH}} = 0,0025 \text{mol} \]
\[ V_{\text{NaOH}} = \frac{0,0025 \text{ mol}}{0,1 \text{ M}} = 0,025 \text{ L} = 25 \text{ mL} \]

Saka, huwandu hweNaOH hunodiwa i25 mL.

Muenzaniso Mubvunzo 2: Kuwanda kweAcid Asidhi neBasi Rakasimba

Mubvunzo:
Huwandu hwe50 mL hwe 0,1 M acetic acid (CH₃COOH) solution hwakaiswa titration ne 0,1 M NaOH solution. Ndeupi huwandu hweNaOH hunodiwa kuti usvike pa equivalence point?

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Kukurukurirana:
Mhinduro pakati peacetic acid neNaOH ndeiyi:
\[ CH_3COOH + NaOH \museve wekurudyi CH_3COONA + H_2O \]

Danho 1: Sarudza mamota eH⁺ kubva kuCH₃COOH
\[ n_{\text{CH}_3\text{COOH}} = M_{\text{CH}_3\text{COOH}} \times V_{\text{CH}_3\text{COOH}} \]
\[ n_{\text{CH}_3\text{COOH}} = 0,1 \times 0,05 = 0,005 \text{mol} \]

Danho rechipiri: Sarudza huwandu hweNaOH hunodiwa
Nekuti chiyero chemole pakati peCH₃COOH neNaOH i1:1:
\[ n_{\text{CH}_3\text{COOH}} = n_{\text{NaOH}} \]
\[ M_{\text{NaOH}} \times V_{\text{NaOH}} = 0,005 \text{mol} \]
\[ V_{\text{NaOH}} = \frac{0,005 \text{ mol}}{0,1 \text{ M}} = 0,05 \text{ L} = 50 \text{ mL} \]

Saka, huwandu hweNaOH hunodiwa i50 mL.

Muenzaniso Mubvunzo 3: Polyprotic Titration yeStrong Acids neBases

Mubvunzo:
Zvinozivikanwa kuti 40 mL ye 0,05 M H₂SO₄ solution inoiswa titration ne 0,1 M KOH solution. Ndeupi huwandu hweKOH hunodiwa kuti usvike pa equivalence points yekutanga neyechipiri?

Kukurukurirana:
H₂SO₄ idiprotic acid inogona kuburitsa ma H⁺ ions maviri. Kuita kweKOH kune matanho maviri:
\[ H_2SO_4 + 2KOH \museve wekurudyi K_2SO_4 + 2H_2O \]

Danho 1: Sarudza mamota eH⁺ kubva kuH₂SO₄
\[ n_{\text{H}_2\text{SO}_4} = M_{\text{H}_2\text{SO}_4} \times V_{\text{H}_2\text{SO}_4} \]
\[ n_{\text{H}_2\text{SO}_4} = 0,05 \times 0,04 = 0,002 \text{mol} \]

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Danho rechipiri: Sarudza huwandu hweKOH hunodiwa padanho rega rega
Mukutanga kwetitration (kuburitsa H⁺ imwe):
\[ n_{\text{H}_2\text{SO}_4} = n_{\text{KOH}} \]
\[ M_{\text{KOH}} \times V_{\text{KOH}} = 0,002 \text{ mol} \]
\[ V_{\text{KOH}}_{\text{first}} = \frac{0,002 \text{ mol}}{0,1 \text{ M}} = 0,02 \text{ L} = 20 \text{ mL} \]

Muchikamu chechipiri (kubvisa H⁺ mbiri) kaviri mamota ekare anodiwa:
\[ n_{\text{KOH}}_{\text{second}} = 2 \times 0,002 \text{ mol} = 0.004 \text{ mol} \]
\[ V_{\text{KOH}}_{\text{second}} = \frac{0.004 \text{ mol}}{0,1 \text{ M}} = 0,04 \text{ L} = 40 \text{ mL} \]

Saka, huwandu hweKOH hunodiwa pachiyero chekutanga che equivalence i20 mL, uye pachiyero chechipiri che equivalence i40 mL.

Mhedziso

Kuburikidza nemienzaniso yakati wandei ye acid-base titration iri pamusoro apa, tadzidza mashandisiro ekuona huwandu hwemhinduro hunodiwa kuti tisvike pakaenzana mumhando dzakasiyana dze titrations. Zvakakosha kugara uchiteerera reaction stoichiometry uye kushandisa formula yekutanga ye titration nemazvo kuti uwane mhedzisiro chaiyo. Kuramba uchidzidzira nemarudzi akasiyana ematambudziko kuchabatsira kusimbisa kunzwisisa kwako kwe acid-base titrations mu analytical chemistry.

Siya mhinduro