Muenzaniso weMienzaniso yeLinear Momentum

Mienzaniso 8 yeMibvunzo yeKumhanya Kwemutsara

1. Chinhu chine huremu hwe1 kg chinofamba nekumhanya kwe10 m/s. tichimhanya chinhu chacho…
Kukurukurirana
Zvinozivikanwa :
Huremu (m) = 1 kg
Kumhanya (v) = 10 m/s
Akabvunzwa : linear momentum (p)
Jawab :
Fomura yekukurumidza: p = mv
Tsananguro: p = simba, m = uremu, v = speed.
Simba rechinhu nderinotevera:
p = mv = (1)(10) = 10 kg m/s²

2. Zvinhu zviviri, chimwe nechimwe chine huremu hwe2 kg uye 4 kg, zviri kufamba nekumhanya kwe20 m/s. Kumhanya kwechinhu chimwe nechimwe kuri…
Kukurukurirana
Zvinozivikanwa :
Huremu hwechinhu A (m)_A) = 2 kg
Huremu hwechinhu B (m_B) = 4 kg
Kumhanya kwechinhu A (v)_A) = 20 m/s
Kumhanya kwechinhu B (v)_B) = 20 m/s
Akabvunzwa : simba rechinhu A (p)_A) uye simba rechinhu B (p_B)
Jawab :
Kumhanya kwechinhu A :
p_A = m_A v_A = (2)(20) = 40 kg m/s
Kumhanya kwechinhu B :
p_B = m_B v_B = (4)(20) = 80 kg m/s
Kana kumhanya kwezvinhu zvose kuri kwakafanana, chinhu chine huremu hukuru chinova nesimba guru.

3. Zvinhu A neB chimwe nechimwe chine huremu hwe2 kg. Chinhu A chinofamba nekumhanya kwe2 m/s uye chinhu B chinofamba nekumhanya kwe4 m/s. Kumhanya kwechinhu A nechinhu B ndiko…
Kukurukurirana
Zvinozivikanwa :
Huremu hwechinhu A (m)_A) = 2 kg
Huremu hwechinhu B (m_B) = 2 kg
Kumhanya kwechinhu A (v)_A) = 2 m/s
Kumhanya kwechinhu B (v)_B) = 4 m/s
Akabvunzwa : simba rechinhu A (p)_A) uye simba rechinhu B (p_B)
Jawab :
Kumhanya kwechinhu A :
p_A = m_A v_A = (2)(2) = 4 kg m/s
Kumhanya kwechinhu B :
p_B = m_B v_B = (2)(4) = 8 kg m/s
Kana huwandu hwezvinhu zvose zviri zviviri hwakafanana, chinhu chine kumhanya kukuru chine simba guru.

4. Chinhu chine huremu hwe5 kg chiri pachigaro. Simba rechinhu chacho…
Kukurukurirana
Zvinozivikanwa :
Huremu hwechinhu (m) = 5 kg
Kumhanya kwechinhu (v) = 0
Akabvunzwa : simba rechinhu (p)
Jawab :
p = mv = (5)(0) = 0
Kana chinhu chiri panzvimbo yakanyarara, zvisinei nekuti huremu hwechinhu chacho hwakakura sei, simba rechinhu chacho harisi zero.

5. Mumutambo webaseball, bhora rine huremu hwe 0,5 kg rinotanga kufamba nekumhanya kwe 2 m/s.^-1Bhora rinorohwa nesimba F rakapesana nekufamba kwebhora, saka kumhanya kwebhora kunoshanduka kuita 6 ms.^-1Kana bhora rikasangana nebat kwemasekondi 0,01, saka shanduko yekufamba kwebhora iri…

A. 8 kg ms^-1

B. 6 kg ms^-1

C. 5 kg ms^-1

D. 4 kg ms^-1

E. 2 kg ms^-1

Kukurukurirana

Zvinozivikanwa kuti:

Huremu hwebhora (m) = 0,5 kg

Kumhanya kwekutanga (v)_o) = 2 m/s

Kumhanya kwekupedzisira (v)_t) = -6 m/s

Nguva yepakati (t) = masekondi maviri

Akabvunzwa: Kuchinja kwesimba

Mhinduro:

Fomura yekuchinja kwekukurumidza:

∆p = mv_t - mv_o = m (v)_t - v_o)

∆p = (0,5 kg)(- 6 m/s – 2 m/s)

∆p = (0,5 kg)(-8)

∆p = 4 kg m/s

Mhinduro chaiyo ndiD.

6. Chinhu chine huremu hwemagiramu zana (100 grams) chinofamba nekumhanya kwe5 m/s^-1Kuti chinhu chisamhanye, simba rinodzivisa F rinoita 0,2 s. Hukuru hwesimba F ndi...

A. 0,5 N

B. 1,0 N

C. 2,5 N

D. 10 N

E. 25 N

Kukurukurirana

Zvinozivikanwa kuti:

Huremu hwechinhu (m) = 100 magiramu = 100/1000 = 0,1 kg

Kumhanya kwekutanga kwechinhu (v)_o) = 5 m/s

Kumhanya kwekupedzisira kwechinhu (v)_t= = 0

Nguva yekurovera (Δt) = masekondi 0,2

Akabvunzwa: Hukuru hwesimba F

Mhinduro:

Dzidziso ye "impulse-momentum theorem" inotaura kuti "impulse" yakaenzana nekuchinja kwe "momentum".

Ini = ΔP

F (Δt) = m (v)_t - v_o)

F (0,2) = 0,1 (0 – 5)

F (0,2) = 0,1 (– 5)

F (0,2) = -0,5

F = -0,5 / 0,2

F = -2,5N

Hukuru hwesimba i2,5 Newtons. Chiratidzo chekuramba chinoratidza divi resimba. Chiratidzo chekuramba chinoratidza kuti simba racho rakanangana nekufamba kwechinhu.

Mhinduro chaiyo ndiC.

7.BBhora retenesi rine huremu hwemagiramu zana rinodonhedzwa pasi kubva pakukwirira kwe20 cm pasina kumhanya kwekutanga. Mushure mekurovera pasi, bhora rinosvetuka nekumhanya kwe1 m/s.^-1 uye (g = 10 ms^-2Kuchinja kwesimba rinoonekwa nebhora kuri…

A. 0,1 Ns

B. 0,3 Ns

C. 0,5 Ns

D. 0,8 Ns

E. 0,9 Ns

Kukurukurirana

Zvinozivikanwa :

Huremu hwebhora (m) = magiramu mashanu = 0,1 kg

Kureba (h) = 20 cm = 0,2 metres

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Kumhanya kwebhora mushure mekunge rarova pasi (v)_t) = 1 m/s

Akabvunzwa : kuchinja kwesimba rebhora

Jawab :

Kumhanya kwebhora risati rarova (v)_o)

Verenga kumhanya kwebhora usati warova uchishandisa fomura yekudonha kwemahara. Zvichienderana nekukwirira kwekudonha kwebhora kwemahara (h) = 0,2 metres, kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s² uye ndakabvunza kumhanya kwebhora kana rarova pasi, saka fomura yacho inoshandiswa v² = 2 gh

v² = 2 (10)(0,2) = 4

v = √4 = -2 m/s

Inopiwa chiratidzo chekusateerera nekuti bhora richifamba risati rasangana nepasi rinopesana nekwarakananga bhora richifamba mushure mekusangana nepasi.

Kuchinja kwesimba rebhora (Δp)

Δp = mv_t - mv_o = m (v)_t - v_o)

Δp = (0,1)(1 – (-2)) = (0,1)(1 + 2) = (0,1)(3) = 0,3 Newton Second

Mhinduro chaiyo ndeiyi B.

8. Chinhu chakatanga chichiputika chichiita zvikamu zviviri nechiyero che3:2. Chikamu chine huremu hwakakura chinokandwa nekumhanya kwe20 m/s.^-1 Saka kumhanya kunokandwa chikamu chidiki ndekwekuti…

A. 13,3 ms^-1

B. 20 ms^-1

C. 30 ms^-1

D. 40 ms^-1

E. 60 ms^-1

Kukurukurirana

Zvinozivikanwa kuti:

Huremu hwechinhu 1 usati wasangana = m

Kumhanya kwechinhu 1 chisati chasangana = 0 (chinhu chiri pazororo)

Huremu hwechikamu 1 mushure mekuroverana (m₁) = 3m

Huremu hwechikamu 2 mushure mekuroverana (m₂) = 2m

Kumhanya kwechikamu 1 mushure mekuroverana (v)₁') = 20 m/s

Akabvunzwa: Kumhanya kwechikamu 2 mushure mekuroverana (v)₂')

Mhinduro:

Fomura yemutemo wekuchengetedza simba:

m₁v₁ = m₁v₁' + m₂v₂'

(m)(0) = (3m)(20) + (2m) v₂'

0 = 60m + (2m) v₂'

60m = -2m v₂'

60 = -2 v₂'

v₂' = -60/2

v₂' = -30 m/s

Chiratidzo chekuramba chinoratidza kuti gwara rekufamba kwechikamu chechipiri rakapesana negwara rechikamu 1. Semuenzaniso, kana chikamu 1 chikandwa kumabvazuva, chikamu 2 chinokandwa kumadokero.

Mhinduro chaiyo ndiC.

Kwakabva mubvunzo:

Mibvunzo yeNational Examination Physics yeChikoro Chesekondari/Chikoro Chepamusoro Chebasa