Законы движения Ньютона – задачи и решения

Законы движения Ньютона – задачи и решения

Первый закон движения Ньютона

1. If no net force acts on an object, then :

(1) the object is not accelerated

(2) объект в состоянии покоя

(3) the change of velocity of an object = 0

(4) the object can not travels at a постоянная скорость

Which statement is correct.

Решение

The correct statement :

(1) The object is not accelerated

The net force causes acceleration of an object. So if no net force then objects is not accelerated.

(2) Object at rest

Newton’s first law of motion states that if no net force acts on an object then an object always at rest or the object is always traveling at a constant velocity.

(3) The change of velocity of an object = 0

Change of velocity = acceleration. No change of velocity means no acceleration. If no acceleration then no net force acts on an object.

The object in an elevator

2. The weight of a person in an elevator at rest = 500 N. Ускорение силы тяжести составляет 10 м/с2. When lift accelerated, the tension force is 750 N. What is the acceleration of lift.

Известно:

Человек вес (w) = 500 Newton = 500 kg m s-2 (lift at rest)

Acceleration of gravity (g) = 10 m s-2

Человек масса (m) = 500 / 10 = 50 kg

Tension force (T) = 750 N (lift accelerated)

Elevator’s mass ignored.

Разыскивается: Acceleration of elevator

решение:

Elevator at rest, no acceleration (a = 0). Force acts upward has plus sign and force acts downward has minus sign.

ΣF = ma

Т – w = 0

Т = w

T = 500 Ньютонов

If the elevator accelerated downward then the tension force smallest then 500 N. Otherwise, if the elevator accelerated upward then the tension force larger then 500 N.

The tension force = 750 N because the elevator accelerated upward. Force acts upward has plus sign and force acts downward has minus sign.

Т – в = ма

750 – 500 = 50 а

250 = 50 а

а = 250/50

a = 5.0 m s-2

3. An 60-kg person in an elevator accelerated downward at 3 m/s2. If acceleration due to gravity is 10 m/s2, what is the normal force exerted by elevator’s floor on person.

Известно:

Масса (м) = 60 кг

Acceleration of person and elevator (a) = 3 m/s2

Ускорение свободного падения (g) = 10 м/с²2

Вес (w) = мг = (60)(10) = 600 Ньютона

Разыскивается: Нормальная сила (N)

решение:

There are two forces acts on the person in the elevator, that is weight (w) of person and the normal force (N) exerted by the floor on the person. There are three vector quantities, that is weight (w), normal force (N) and acceleration of elevator, where weight acts downward, the normal force acts upward, acceleration of elevator is downward. Vector quantities that act downward have plus sign and vector количеств that act upward have minus sign.

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∑F = ma

w – N = (60)(3)

600 – N = 180

N = 600 – 180

Н = 420 Ньютонов

4. A 40-kg object in an elevator accelerated upward. If the elevator’s floor exerts 520 N on object and acceleration due to gravity is 10 m/s2. What is the acceleration of the elevator?

Известно:

Масса (м) = 40 кг

Normal force (N) = 520 N

Ускорение свободного падения (g) = 10 м/с²2

weight (w) = m g = (40)(10) = 400 N

В розыске: Acceleration of elevator

решение:

∑F = ma

400 – 520 = (40)(a)

-120 = (40)(a)

а = -120/40

а = -3 м/с2

Acceleration of elevator is 3 m/s2. Minus sign indicates that elevator travels upward.

5. An 60-kg object in an elevator accelerated downward at 3 m/s2. What is the force exerted by object on the elevator’s floor.

Известно:

Масса (м) = 60 кг

Вес (w) = мг = (60 кг)(10 м/с)2) = 600 кг м/с2 = 600 Ньютон

Acceleration of elevator (a) = 3 m/s2, downward

В розыске: Force exerted by object on the elevator’s floor.

решение:

Elevator accelerated downward at 3 m/s. Force acts downward has plus sign and force acts upward has minus sign.

w – N = ma

N = w – ma

N = 600 – (60)(3)

N = 600 – 180

Н = 420 Ньютонов

Force exerted by the object on the elevator’s floor = 420 N.

6. Two blocks are connected by a cord running over a pulley. Ignore the mass of the cord and pulley and any friction in the pulley. Mass of block A is 6 kg and mass of block B is 2 kg. Acceleration due to gravity is 10 m/s2. What is the tension force?

Известно:Newton's laws of motion – problems and solutions 1

mA = 6 кг, мB = 2 кг, g = 10 м/с²2

wA = мA g = (6 кг)(10 м/с2) = 60 кг м/с2

wB = мB g = (2 кг)(10 м/с2) = 20 кг м/с2

В розыске: tension force (T) ?

решение:

wA > жB так что mA движется вниз, MB движется вверх.

Второй закон Ньютона:

ΣF = ма

wA - вB = (мA + мB) в

60 – 20 = (6 + 2) а

40 = (8) а

а = 40 / 8 = 5 м/с2

Tension force :

mA движется вниз:

wA - ТA = мA a

60 - ТA = (6)(5)

60 - ТA = 30

TA = 60 - 30

T2 = 30 Ньютон

mB движется вверх:

TB - вB = мB a

TB – 20 = (2)(5)

TB - 20 = 10

TB = 10 + 20

T1 = 30 Ньютон

Tension force (T) = 30 Newton.

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7. Mass of object A = 5 kg, acceleration due to gravity (g) = 10 m s-2. Object A moves downward at 2.5 m.s-2. What is the mass of B ?

Известно:Newton's laws of motion – problems and solutions 2

Масса А (м)A) = 5 кг

Ускорение свободного падения (g) = 10 м/с²2

Acceleration of object A (a) = 2.5 m/s2

Weight A (wA) = (мA)(g) = (5)(10) = 50 Newton

В розыске: Масса объекта B (м)B)

решение:

Block A moves downward so weight of object A (wA) larger than weight of object B (wB).

Примените второй закон Ньютона:

ΣF = ма

wA - вB = (мA + мB) в

50 – (mB)(10) = (5 + mB) (2.5)

50 - 10 mB = 12.5 + 2.5 mB

50 – 12.5 = 2.5 мB + 10 мB

37.5 = 12.5 мB

mB = 3 кг

8. Acceleration due to gravity is 10 m/s2. What is the tension force.

Известно:

Масса объекта 1 (м)1) = 2 кгNewton's laws of motion – problems and solutions 3

Масса объекта 2 (м)2) = 3 кг

Ускорение свободного падения (g) = 10 м/с²2

Weight 1 (w1) = (м1)(g) = (2 kg)(10 m/s2) = 20 кг м/с2

Weight 2 (w2) = (м2)(g) = (3 kg)(10 m/s2) = 30 кг м/с2

В розыске: tension force (T)

решение:

w2 > ж1 так что m2 moves downward and m1 движется вверх.

Newton’s second law of motion :

ΣF = ма

w2 - в1 = (м1 + м2) в

30 – 20 = (2 + 3 ) а

10 = (5) а

а = 10 / 5 = 2 м/с2.

Tension force ?

m2 движется вниз

w2 - Т2 = м2 a

30 - Т2 = (3)(2)

30 - Т2 = 6

T2 = 30 - 6

T2 = 24 Ньютон

m1 движется вверх

T1 - в1 = м1 a

T1 – 20 = (2)(2)

T1 - 20 = 4

T1 = 20 + 4

T1 = 24 Ньютон

Tension force (T) = 24 Newton.

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