Equilibrium of the bodies on a inclined plane – application of the Newton’s first law problems and solutions

1. A 2-kg block lies on a rough inclined plane at an angle 37o to the horizontal. Determine the magnitude of the external force exerted on the block, so the block is not slides down the plane. (sin 37o = 0.6، کاز 37o = 0.8، g = 10 ms ثانیې-2، μk = 0.2)

Equilibrium of bodies on inclined plane – application of Newton's first law problems and solutions 1پیژندل شوی:

ډله (m) = 2 kg

سرعت د جاذبې له امله (g) = ۱۰ متره/ ثانیه2

Block’s د وزن (w) = m g = (2)(10) = 20 Newton

ګناه ۳۷o = 0.6

کاس 37o = 0.8

Coefficient of the حرکي رګونهk) = 0.2،XNUMX

The y-component of the weight (wy) = د کاس ایکس اینوم ایکسo = (۱۹.۶)(۰.۵) = ۹.۸ نیوټن

The x-component of the weight (wx) = w sin θ = (20)(sin 37) = (20)(0.6) = 12 Newton

the normal force (N) = wy = ۱۰ نیوټن

پراري : The external force (F)

د حل :

Equilibrium of bodies on inclined plane – application of Newton's first law problems and solutions 2wx = ۱۰ نیوټن

The force of the kinetic friction (fk) = μk N = (0.1)(16) = 1.6 Newton

The magnitude of the external force F exerted on the block :

ف + فk - wx = 0

ف = wx - fk

F = 12 – 1.6

F = 10.4 نیوټن

The external force F greater than 10.4 Newton.

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2. Mass of a block = 2 kg, coefficient of static friction µs = 0.4 and θ = 45o. Determine the magnitude of the force F so the block start to slides up.

Equilibrium of bodies on inclined plane – application of Newton's first law problems and solutions 3پیژندل شوی:

The coefficient of the static friction (µs) = 0.4،XNUMX

زاویه (θ) = 45o

د جاذبې قوې له امله سرعت (g) = 10 m/s2

Block’s mass (m) = 2 kilogram

Block’s weight (w) = m g = (2 kg)(10 m/s2) = ۱۰ کیلوګرامه متر مکعب/ثانیه2 = ۱۰ نیوټن

The x-component of the weight (wx) = w sin θ = (20)(sin 45) = (20)(0.5√2) = 10√2 Newton

The y-component of the weight (wy) = w cos θ = (20)(cos 45) = (20)(0.5√2) = 10√2 Newton

پراري : The magnitude of the force F

حل:

Equilibrium of bodies on inclined plane – application of Newton's first law problems and solutions 4Block starts to slide up, if Fwx + fs.

The x-component of the weight :

wx = ۹.۸√۳ نیوټن

the y-component of the weight :

wy = ۹.۸√۳ نیوټن

نورمال ځواک :

ن = wy = ۹.۸√۳ نیوټن

The force of the static friction :

fs = μs ن = (۰.۵)(۴۰√۲) = ۲۰√۲

The magnitude of the force F so that the block starts to slide up :

Fwx + fs

F ≥ ۴۰√۲ + 4√2

F ≥ 14√2 نیوټن

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  1. Particles in one-dimensional equilibrium
  2. Particles in two-dimensional equilibrium
  3. Equilibrium of bodies connected by cord and pulley
  4. Equilibrium of bodies on the inclined plane

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