{"id":934,"date":"2018-02-20T17:00:02","date_gmt":"2018-02-20T09:00:02","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=934"},"modified":"2018-02-20T17:00:02","modified_gmt":"2018-02-20T09:00:02","slug":"geosynchronous-satellite-problems-and-solutions","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/geosynchronous-satellite-problems-and-solutions.htm","title":{"rendered":"Geosynchronous satellite – problems and solutions","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"

1. What is the height of a geosynchronous satellite above Earth’s surface?<\/span><\/span><\/p>\n

G = universal constant = 6.67 x 10<\/span><\/span>-11<\/span><\/span><\/sup> N m<\/span><\/span>2<\/span><\/span><\/sup>\/kg<\/span><\/span>2<\/span><\/span><\/sup><\/p>\n

M = Earth’s mass<\/a> = 5.97 x 10<\/span><\/span>24<\/span><\/span><\/sup> kg <\/span><\/span><\/p>\n

T = 24 hours = 24 (3600 seconds) = 86,400 seconds = 8.64 x 10<\/span><\/span>4<\/span><\/span><\/sup> seconds<\/span><\/span><\/p>\n

Solution<\/span><\/span><\/p>\n

\"Geosynchronous<\/p>\n

Satellite’s height above Earth’s surface = 4.22 x 10<\/span><\/span>7<\/span><\/span><\/sup> m = 4.22 x 10<\/span><\/span>4 <\/span><\/span><\/sup>km = 42,200 km<\/span><\/span><\/p>\n

Satellite’s height above Earth’s surface = 6.38 x 10<\/span><\/span>6<\/span><\/span><\/sup> m = 6.38 x 10<\/span><\/span>3 <\/span><\/span><\/sup>km = 6380 km <\/span><\/span><\/p>\n

Satellite’s height above Earth’s surface <\/span><\/span>= satellite’s distance<\/a> from Earth’s center \u2013 Earth’s radius<\/span><\/span><\/p>\n

Satellite’s height above Earth’s surface <\/span><\/span>= 42,200 km \u2013 6380 km<\/span><\/span><\/p>\n

Satellite’s height above Earth’s surface <\/span><\/span>= 35,820 km<\/span><\/span><\/p>\n

<\/p>\n

2. What is the speed of a geosynchronous satellite ?<\/span><\/span><\/p>\n

Universal constant (G) = 6.67 x 10<\/span><\/span>-11<\/span><\/span><\/sup> N m<\/span><\/span>2<\/span><\/span><\/sup>\/kg<\/span><\/span>2<\/span><\/span><\/sup><\/p>\n

Earth’s mass (m<\/span><\/span>E<\/span><\/sub>) = 5.97 x 10<\/span><\/span>24 <\/span><\/span><\/sup>kg<\/span><\/span><\/p>\n

The distance between satellite and Earth’s center (r) = 4.22 x 10<\/span><\/span>7<\/span><\/span><\/sup> m<\/span><\/span><\/p>\n

Solution<\/span><\/span><\/p>\n

\"Geosynchronous<\/p>\n

or use this equation <\/span><\/span><\/p>\n

\"Geosynchronous<\/p>\n

[wpdm_package id=’949′]<\/p>\n

    \n
  1. Newton’s law of universal gravitation problems and solutions<\/a><\/li>\n
  2. Gravitational force, weight problems, and solutions<\/a><\/li>\n
  3. Acceleration due to gravity problems and solutions<\/a><\/li>\n
  4. Geosynchronous satellite problems and solutions<\/a><\/li>\n
  5. Kepler’s law problems and solutions problems and solutions<\/a><\/li>\n<\/ol>\n

    <\/p>\n

    \n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"

    1. What is the height of a geosynchronous satellite above Earth’s surface? G = universal constant = 6.67 x 10-11 N m2\/kg2 M = Earth’s mass = 5.97 x 1024 kg T = 24 hours = 24 (3600 seconds) = 86,400 seconds = 8.64 x 104 seconds Solution Satellite’s height above Earth’s surface = 4.22 … Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Geosynchronous satellite - problems and solutions","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[3],"tags":[],"class_list":["post-934","post","type-post","status-publish","format-standard","hentry","category-solved-problems-in-basic-physics"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/934","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=934"}],"version-history":[{"count":0,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/934\/revisions"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=934"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=934"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=934"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}