{"id":8150,"date":"2023-04-30T22:49:22","date_gmt":"2023-04-30T22:49:22","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=8150"},"modified":"2024-05-25T06:50:43","modified_gmt":"2024-05-25T06:50:43","slug":"the-resultant-force-equation","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/the-resultant-force-equation.htm","title":{"rendered":"The resultant force equation","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"

3 questions about The resultant force equation<\/span><\/p>\n

1. A car with a mass of 5 tonnes moves from rest in 50 seconds, reaching a speed of 72 km\/hour. The force on the car is\u2026<\/span><\/p>\n

Known:<\/u><\/span><\/p>\n

Mass (m) = 5 tons = 5000 kg<\/span><\/p>\n

Initial speed (vo) = 0<\/span><\/p>\n

Final speed (vt) = 72 km\/h = 20 m\/s<\/span><\/p>\n

Time interval (t) = 50 seconds<\/span><\/p>\n

Wanted:<\/u> Force (F)<\/span><\/p>\n

Solution:<\/u><\/span><\/p>\n

Calculate the acceleration using the Non Uniform Linear Motion formula:<\/span><\/p>\n

vt<\/sub> = vo<\/sub> + a t<\/span><\/p>\n

20 = 0 + a (50)<\/span><\/p>\n

20 = 50 a<\/span><\/p>\n

a = 20 \/ 50 = 0,4 m\/s2<\/sup><\/span><\/p>\n

Calculate the resultant force using Newton’s second law formula:<\/span><\/p>\n

\u03a3F = m a<\/span><\/p>\n

F = (5000)(0,4) = 2000 Newton<\/span><\/p>\n

2. A car has a mass of 1 ton, for 4 seconds its speed increases uniformly from 10 m\/s to 18 m\/s. Determine the magnitude of the force that accelerates the car.<\/span><\/p>\n

Known:<\/u><\/span><\/p>\n

The mass of the car (m) = 1 ton = 1000 kg<\/span><\/p>\n

Time interval (t) = 4 seconds<\/span><\/p>\n

Initial velocity (vo<\/sub>) = 10 m\/s<\/span><\/p>\n

Final velocity (vt<\/sub>) = 18 m\/s<\/span><\/p>\n

Wanted:<\/u> Force (F)<\/span><\/p>\n

Solution:<\/u><\/span><\/p>\n

Calculate the acceleration using the Non Uniform Linear Motion formula:<\/span><\/p>\n

vt<\/sub> = vo<\/sub> + a t<\/span><\/p>\n

18 = 10 + a (4)<\/span><\/p>\n

18 – 10 = a (4)<\/span><\/p>\n

8 = 4 a<\/span><\/p>\n

a = 8 \/ 4 = 2 m\/s2<\/sup><\/span><\/p>\n

Calculate the resultant force using Newton’s second law formula:<\/span><\/p>\n

\u03a3F = m a<\/span><\/p>\n

F = (1000)(2) = 2000 Newton<\/span><\/p>\n

3. The two force vectors are perpendicular to each other which results in a resultant of 10 N. If one of the force vectors is 6 N , determine the magnitude of the other force vector.<\/span><\/p>\n

Known:<\/u><\/span><\/p>\n

Resultant force (F) = 10 N<\/span><\/p>\n

Force 1 (F1<\/sub>) = 6 N<\/span><\/p>\n

Wanted:<\/u> Force 2 (F2<\/sub>)<\/span><\/p>\n

Solution:<\/u><\/span><\/p>\n

F2<\/sub> = 10 \u2013 6 = 4 Newton<\/span><\/p>\n

\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"

3 questions about The resultant force equation 1. A car with a mass of 5 tonnes moves from rest in 50 seconds, reaching a speed of 72 km\/hour. The force on the car is\u2026 Known: Mass (m) = 5 tons = 5000 kg Initial speed (vo) = 0 Final speed (vt) = 72 km\/h = … Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"3","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"The resultant force equation","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[3],"tags":[],"class_list":["post-8150","post","type-post","status-publish","format-standard","hentry","category-solved-problems-in-basic-physics"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/8150","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=8150"}],"version-history":[{"count":7,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/8150\/revisions"}],"predecessor-version":[{"id":9846,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/8150\/revisions\/9846"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=8150"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=8150"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=8150"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}