{"id":8135,"date":"2023-04-30T12:48:50","date_gmt":"2023-04-30T12:48:50","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=8135"},"modified":"2024-05-25T06:52:01","modified_gmt":"2024-05-25T06:52:01","slug":"normal-force-equation","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/normal-force-equation.htm","title":{"rendered":"Normal force equation","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"

3 questions about Normal force equation<\/span><\/p>\n

1. A block has a mass of 5 kg. If g = 10 m\/s2<\/sup>, determine:<\/span><\/p>\n

a) the weight of the block<\/span><\/p>\n

b) the normal force if the block is placed on a flat plane<\/span><\/p>\n

c) the normal force if the block rests on an inclined plane that forms an angle of 30o<\/sup> to the horizontal<\/span><\/p>\n

Known:<\/u><\/span><\/p>\n

The mass of the block (m) = 5 kg<\/span><\/p>\n

Acceleration due to gravity (g) = 10 m\/s2<\/sup><\/span><\/p>\n

Wanted:<\/u> w, N on the plane and N on the incline<\/span><\/p>\n

Solution:<\/u><\/span><\/span><\/p>\n

a) Beam weight<\/span><\/p>\n

w = m g = 5 (10) = 50 Newton<\/span><\/p>\n

b) The normal force if the block is in a flat plane<\/span><\/p>\n

N = w = 50 Newton<\/span><\/p>\n

c) The normal force if the block is on an inclined plane<\/span><\/p>\n

N = wy<\/sub> = w cos \u03b8 = 50 (cos 30) = 50 (\u00bd \u221a3) = 25\u221a3 Newton<\/span><\/p>\n

2. A 120 gram eraser is pressed perpendicularly to the board with a force of 15 N. What is the normal force acting on the eraser?<\/span><\/p>\n

Known<\/u>:\"Normal<\/u><\/span><\/p>\n

Mass (m) = 120 grams = 0.12 kg<\/span><\/p>\n

Force (F) = 15 Newton<\/span><\/p>\n

Wanted:<\/u> Normal force<\/span><\/p>\n

Solution:<\/u><\/span><\/p>\n

Normal force = thrust = 15 Newton<\/span><\/p>\n

3. Bottled drinking water that is still in the box is pulled with a force of F = 200 N which forms an angle of 37o<\/sup> with the horizontal. Sin 37o<\/sup> = 0.6. The mass of the cardboard and its contents is 20 kg. If the coefficient of static friction on the floor is 0.5 and the coefficient of kinetic friction on the floor is 0.2, determine the normal force acting on the cardboard.<\/span><\/p>\n

Known:\"Normal<\/u><\/span><\/p>\n

Pull force (F) = 200 N<\/span><\/p>\n

Sin 37 = 0,6<\/span><\/p>\n

Fy = F sin 37 = (200)(0,6) = 120 N<\/span><\/p>\n

Cardboard mass (m) = 20 kg<\/span><\/p>\n

The weight of the cardboard (w) = m g = (20)(10) = 200 N <\/span><\/p>\n

Wanted:<\/u> Normal force on cardboard (N)<\/span><\/p>\n

Solution:<\/u><\/span><\/p>\n

Calculate the normal force using the normal force formula:<\/span><\/p>\n

N = w \u2013 Fy <\/sub>= 200 \u2013 120 = 80 Newton <\/span><\/p>\n

\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"

3 questions about Normal force equation 1. A block has a mass of 5 kg. If g = 10 m\/s2, determine: a) the weight of the block b) the normal force if the block is placed on a flat plane c) the normal force if the block rests on an inclined plane that forms an … Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"3","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Normal force equation","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[3],"tags":[],"class_list":["post-8135","post","type-post","status-publish","format-standard","hentry","category-solved-problems-in-basic-physics"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/8135","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=8135"}],"version-history":[{"count":7,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/8135\/revisions"}],"predecessor-version":[{"id":9850,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/8135\/revisions\/9850"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=8135"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=8135"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=8135"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}