{"id":4832,"date":"2021-06-27T16:15:56","date_gmt":"2021-06-27T23:15:56","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=4832"},"modified":"2021-06-27T16:15:56","modified_gmt":"2021-06-27T23:15:56","slug":"springs-in-series-and-parallel","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/springs-in-series-and-parallel.htm","title":{"rendered":"Springs in series and parallel","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"

Article about the Springs in series and parallel<\/a><\/h3>\n

1. Springs in series<\/span><\/span><\/h3>\n

If the spring is connected in series, as in the figure on the side, then:<\/span><\/span><\/p>\n

1. The increase in the length of spring = the increase in length 1 + the increase in length 2<\/span><\/span><\/p>\n

\u0394<\/span><\/span>y = <\/span><\/span>\u0394<\/span><\/span>y<\/span><\/span>1 <\/span><\/span><\/sub>+ <\/span><\/span>\u0394<\/span><\/span>y<\/span><\/span>1 <\/span><\/span><\/sub><\/p>\n

2. The force experienced by equivalent spring = the force experienced by spring 1 = the force experienced by spring 2<\/span><\/span><\/p>\n

F<\/span><\/span>s <\/span><\/span><\/sub>= F<\/span><\/span>1<\/span><\/span><\/sub> = F<\/span><\/span>2<\/span><\/span><\/sub><\/p>\n

3. The equivalent spring’s constant (k<\/span><\/span>s<\/span><\/span><\/sub>)<\/span><\/span><\/p>\n

1\/k<\/span><\/span>s <\/span><\/span><\/sub>= 1\/k<\/span><\/span>1 <\/span><\/span><\/sub>+ 1\/k<\/span><\/span>2<\/span><\/span><\/sub><\/p>\n

Sample problem 1:<\/span><\/span><\/p>\n

Two identical springs each have a constant of 100 N \/ m connected in series. If the spring’s arrangement is given a load so that it increases 4 cm in length, then the increase in the length of each spring is …<\/span><\/span><\/p>\n

Solution:<\/span><\/span><\/p>\n

The total increase in the length of the two springs is 4 cm, therefore the increase in the length of each spring is 2 cm.<\/span><\/span><\/p>\n

2. Springs in parallel<\/span><\/span><\/h3>\n

\"SpringsIf the spring is connected in parallel, as in the figure on the side, then:<\/span><\/span><\/p>\n

1. The increase in the length of the equivalent spring = the increase in the length of spring 1 = the increase in the length of spring 2<\/span><\/span><\/p>\n

\u0394<\/span><\/span>y = <\/span><\/span>\u0394<\/span><\/span>y<\/span><\/span>1<\/span><\/span><\/sub> + <\/span><\/span>\u0394<\/span><\/span>y<\/span><\/span>1 <\/span><\/span><\/sub><\/p>\n

2. The force experienced by the equivalent spring = the force that is experienced by spring 1 + the force experienced by spring 2<\/span><\/span><\/p>\n

F<\/span><\/span>s<\/span><\/span><\/sub> = F<\/span><\/span>1 <\/span><\/span><\/sub>+ F<\/span><\/span>2<\/span><\/span><\/sub><\/p>\n

3. The equivalent spring’s constant (k<\/span><\/span>p<\/span><\/span><\/sub>)<\/span><\/span><\/p>\n

kp = k<\/span><\/span>1<\/span><\/span><\/sub> + k<\/span><\/span>2<\/span><\/span><\/sub><\/p>\n

Sample problem 2:<\/span><\/span><\/p>\n

Two springs each with constant c arranged in parallel. The spring constant<\/a> of this arrangement becomes …<\/span><\/span><\/p>\n

Solution:<\/span><\/span><\/p>\n

The equivalent spring’s constant (k<\/span><\/span>p<\/span><\/span><\/sub>) = c + c = 2c<\/span><\/span><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"

Article about the Springs in series and parallel 1. Springs in series If the spring is connected in series, as in the figure on the side, then: 1. The increase in the length of spring = the increase in length 1 + the increase in length 2 \u0394y = \u0394y1 + \u0394y1 2. The force … Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"Article about the Springs in series and parallel The equivalent spring's constant, The force experienced by the equivalent spring","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Springs in series and parallel","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[2],"tags":[],"class_list":["post-4832","post","type-post","status-publish","format-standard","hentry","category-basic-physics-tutorials"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/4832","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=4832"}],"version-history":[{"count":0,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/4832\/revisions"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=4832"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=4832"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=4832"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}