{"id":4610,"date":"2021-06-27T16:52:30","date_gmt":"2021-06-27T23:52:30","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=4610"},"modified":"2023-08-01T11:48:34","modified_gmt":"2023-08-01T11:48:34","slug":"nonuniform-linear-motion","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/nonuniform-linear-motion.htm","title":{"rendered":"Nonuniform linear motion","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"<h3 class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">Definition of nonuniform linear motion<\/span><\/h3>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">Nonuniform linear motion is motion at constant acceleration. In other words, nonuniform linear motion = motion with the magnification of acceleration is constant and the direction of acceleration is constant. Direction of acceleration is constant = direction of velocity is constant = direction of <a href=\"https:\/\/gurumuda.net\/physics\/distance-and-displacement-problems-and-solutions.htm\">displacement<\/a> is constant = direction of motion is constant = the object moves in a straight line. The magnitude of <a href=\"https:\/\/gurumuda.net\/physics\/constant-acceleration-problems-and-solutions.htm\">constant acceleration<\/a> means that the magnitude of velocity or speed increases regularly.<!--more--><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">First example: <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">An object is initially at rest. One second later, the object moves at a speed of 2 m\/s. Two seconds later, the object moves at a speed of 4 m\/s. Three seconds later, the object moves at a speed of 6 m\/s. Four seconds later, the object moves at a speed of 8 m\/s. And so on\u2026<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">Every 1 second, the speed of the object increases by 2 m\/s. The object experience a constant acceleration of 2 m\/s per 1 second or 2 m\/s per second or 2 m\/s<sup>2<\/sup>.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">The second example: <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">An object initially moves at a speed of 10 m\/s. One second later.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">The speed is decreased to 9 m\/s. Two seconds later, the speed decreases to 8 m\/s. Three seconds later, the speed is decreased to 7 m\/s. Four seconds later, the speed is decreased to 6 m\/s. And so on \u2026 Every 1 second, the speed of the object decreases by 1 m\/s. The object has a constant deceleration of 1 m\/s per 1 second or 1 m\/s per second or 1 m\/s<sup>2<\/sup>.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\"><b>Equation of nonuniform linear motion<\/b><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">There are three equation formulas often used:<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">v<sub>t <\/sub>= v<sub>o<\/sub> + a t<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">d = v<sub>o<\/sub> t + 1\u20442 a t<sup>2<\/sup><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">v<sub>t<\/sub><sup>2 <\/sup>= v<sub>o<\/sub><sup>2 <\/sup>+ 2 a d<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">v<sub>o<\/sub> = initial speed (meter\/second), v<sub>t <\/sub>= final speed (meter\/second), a = acceleration (meter\/second square), t = time interval (second), d = distance (meter).<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">Sample problem 1:<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">A particle, initially at rest, then experiences a constant acceleration of 2 m\/s<sup>2<\/sup> for 10 seconds. Calculate the final velocity of the particle.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">Solution:<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\"><u>Without equation:<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">Acceleration (a) = 2 m\/s<sup>2<\/sup> means speed (v) increase by 2 m\/s each 1 second. After 2 second, v = 4 m\/s. After 10 seconds, v = 20 m\/s.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\"><u>Using equation:<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><u>Known:<\/u> v<sub>o<\/sub> = 0 m\/s (particle at rest), a = 2 m\/s<sup>2<\/sup>, t = 10 s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><u>Wanted:<\/u> v<sub>t<\/sub><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">v<sub>t <\/sub>= v<sub>o <\/sub>+ a t = 0 + (2)(10) = 20 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">Sample problem 2:<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">A car moves on a straight track at a speed of 60 km\/h. Because there is an obstacle, the driver brakes, so the car has a deceleration of 10 m\/s2. What distance does the car still travel until it stops after braking is done?<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\"><u>Known:<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">v<sub>o <\/sub>= 60 km\/jam = 60(1000 m)\/3600 s = 17 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">v<sub>t<\/sub> = 0 m\/s (car stop)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">2a = &#8211; 10 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><u>Wanted:<\/u> distance (d)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\"><u>Solution:<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">v<sub>t<\/sub><sup>2<\/sup> = v<sub>o<\/sub><sup>2 <\/sup>+ 2 a d<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">(0)<sup>2<\/sup> = (17)<sup>2 <\/sup>+ 2(-10) d<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">0 = 289 \u2013 20 d<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">289 = 20 d<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">d = 289 : 20 = 14.45 meters<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">Sample problem 3:<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">The graph below is a nonuniform linear motion graph, v represents speed, and t states time. The magnitude of the acceleration of objects based on the graph is \u2026<\/span><\/p>\n<p style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-4612\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/10\/Non-uniform-linear-motion-1.png\" alt=\"Non uniform linear motion 1\" width=\"127\" height=\"122\" \/><\/span><\/p>\n<p style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-4613\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/10\/Non-uniform-linear-motion-2.png\" alt=\"Non uniform linear motion 2\" width=\"199\" height=\"81\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">Sample problem 4:<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">The motion of a car produces a chart of speed (v) vs time (t) as shown in the figure on the side. If the area under the graph (shaded area) is 48 m, then the acceleration of the car is \u2026<\/span><\/p>\n<p style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-4614\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/10\/Non-uniform-linear-motion-3.png\" alt=\"Non uniform linear motion 3\" width=\"134\" height=\"106\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">Shaded area = total distance = 48 meters<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">v<sub>o<\/sub> = 8 m\/s, v<sub>t<\/sub> = 16 m\/s, t = 1 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">v<sub>t<\/sub> = v<sub>o<\/sub> + a t<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">16 = 8 + a (1)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">a = 16 \u2013 8<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">a = 8 m\/s<sup>2<\/sup><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif;font-size: 12pt\">or<\/span><\/p>\n<p style=\"text-align: justify\" align=\"justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-4615\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/10\/Non-uniform-linear-motion-4.png\" alt=\"Non uniform linear motion 4\" width=\"199\" height=\"42\" \/><\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><strong>Conceptual questions and answer about Nonuniform linear motion<\/strong><\/span><\/p>\n<ol style=\"text-align: justify\">\n<li><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><strong>What is nonuniform linear motion?<\/strong><\/span>\n<p><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">Nonuniform linear motion refers to the motion of an object along a straight line with a changing speed or velocity.<\/span><\/li>\n<li><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><strong>How is nonuniform linear motion represented on a distance-time graph?<\/strong><\/span>\n<p><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">Nonuniform linear motion is represented by a curved line on a distance-time graph.<\/span><\/li>\n<li><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><strong>What role does acceleration play in nonuniform linear motion?<\/strong><\/span>\n<p><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">Acceleration is a key factor in nonuniform linear motion. It is the rate at which velocity changes over time.<\/span><\/li>\n<li><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><strong>How can one identify nonuniform linear motion on a velocity-time graph?<\/strong><\/span>\n<p><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">Nonuniform linear motion is represented by a non-horizontal (increasing or decreasing) line on a velocity-time graph, indicating that velocity changes over time.<\/span><\/li>\n<li><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><strong>What is the unit of acceleration in the International System of Units (SI)?<\/strong><\/span>\n<p><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">The unit of acceleration in the SI system is meter per second squared (m\/s\u00b2).<\/span><\/li>\n<li><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><strong>What is the formula for displacement in nonuniform linear motion, given initial velocity, acceleration, and time?<\/strong><\/span>\n<p><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">The formula is s = ut + \u00bdat\u00b2, where s is displacement, u is initial velocity, a is acceleration, and t is time.<\/span><\/li>\n<li><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><strong>Can the displacement &#8216;s&#8217; be negative in nonuniform linear motion?<\/strong><\/span>\n<p><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">Yes, displacement &#8216;s&#8217; can be negative in nonuniform linear motion. This would indicate motion in the opposite direction to the chosen positive direction.<\/span><\/li>\n<li><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><strong>Is it possible for an object in nonuniform linear motion to come to a stop?<\/strong><\/span>\n<p><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">Yes, an object in nonuniform linear motion can come to a stop if its acceleration acts opposite to the direction of motion and sufficiently decreases the object&#8217;s velocity to zero.<\/span><\/li>\n<li><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><strong>What is the formula for final velocity in nonuniform linear motion, given initial velocity, acceleration, and time?<\/strong><\/span>\n<p><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">The formula is v = u + at, where v is final velocity, u is initial velocity, a is acceleration, and t is time.<\/span><\/li>\n<li><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\"><strong>How does the concept of jerk apply to nonuniform linear motion?<\/strong><\/span><\/li>\n<\/ol>\n<p style=\"text-align: justify\"><span style=\"font-size: 12pt;font-family: 'times new roman', times, serif\">Jerk is the rate of change of acceleration. In nonuniform linear motion, if acceleration is not constant and changes over time, then jerk is present.<\/span><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"<p>Definition of nonuniform linear motion Nonuniform linear motion is motion at constant acceleration. In other words, nonuniform linear motion = motion with the magnification of acceleration is constant and the direction of acceleration is constant. Direction of acceleration is constant = direction of velocity is constant = direction of displacement is constant = direction of &#8230; <a title=\"Nonuniform linear motion\" class=\"read-more\" href=\"https:\/\/gurumuda.net\/physics\/nonuniform-linear-motion.htm\" aria-label=\"Read more about Nonuniform linear motion\">Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Nonuniform linear motion","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[2],"tags":[],"class_list":["post-4610","post","type-post","status-publish","format-standard","hentry","category-basic-physics-tutorials"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/4610","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=4610"}],"version-history":[{"count":2,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/4610\/revisions"}],"predecessor-version":[{"id":8423,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/4610\/revisions\/8423"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=4610"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=4610"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=4610"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}