{"id":3283,"date":"2018-07-02T15:28:16","date_gmt":"2018-07-02T22:28:16","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=3283"},"modified":"2018-07-02T15:28:16","modified_gmt":"2018-07-02T22:28:16","slug":"pressure-of-fluids-problems-and-solutions","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/pressure-of-fluids-problems-and-solutions.htm","title":{"rendered":"Pressure of fluids \u2013 problems and solutions","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"

1. <\/span><\/span><\/p>\n

\"Pressure<\/p>\n

A<\/span><\/span>cceleration due to gravity is 10 N\/kg. The surface area of fish pressed by the water above it is 6 cm2<\/sup>. Determine the force of water above fish that acts on fish.<\/span><\/span><\/p>\n

Known :<\/u><\/span><\/span><\/p>\n

Acceleration due to gravity<\/a> (g) = 10 N\/kg<\/span><\/span><\/p>\n

Surface area of fish (A) = 6 cm2<\/sup> = 6 x 10-4 <\/sup>m2<\/sup><\/span><\/span><\/p>\n

Density<\/a> of water = 1 gram\/cm3 <\/sup>= 1 (10-3 <\/sup>kg) \/ 10-6<\/sup> m3<\/sup> = 103<\/sup> kg\/m3<\/sup> = 1000 kg\/m3<\/sup> <\/span><\/span><\/p>\n

Height of water = 100 cm \u2013 15 cm = 85 cm = 85 x 10-2<\/sup> meters<\/span><\/span><\/p>\n

Wanted :<\/u> Force of the water above fish that acts on fish<\/span><\/span><\/p>\n

Solution :<\/u><\/span><\/span><\/p>\n

Equation of pressure<\/a>:<\/span><\/span><\/p>\n

P = F \/ A<\/span><\/span><\/p>\n

F = P A<\/span><\/span><\/p>\n

F = \u03c1 g h A<\/span><\/span><\/p>\n

F = (1000)(10)(85 x 10-2<\/sup>)(6 x 10-4 <\/sup>m2<\/sup>)<\/span><\/span><\/p>\n

F = (104<\/sup>)(510 x 10-6<\/sup>)<\/span><\/span><\/p>\n

F = 510 x 10-2<\/sup><\/span><\/span><\/p>\n

F = 5.1 Newton<\/span><\/span><\/p>\n

2. The normal pressure of blood is 80 mm hg to 120 mm hg. This value is equal to\u2026<\/span><\/span><\/p>\n

A. 80 Pascal to 120 Pascal<\/span><\/span><\/p>\n

B. 800 Pascal to 1200 Pascal<\/span><\/span><\/p>\n

C. 10256 Pascal to 17589 Pascal<\/span><\/span><\/p>\n

D. 10526 Pascal to 15789 Pascal<\/span><\/span><\/p>\n

Known :<\/u><\/span><\/span><\/p>\n

The normal pressure of blood = 80 mm Hg \u2013 120 mm Hg<\/span><\/span><\/p>\n

Wanted:<\/u> This value is equal to\u2026 Pascal<\/span><\/span><\/p>\n

Solution :<\/u><\/span><\/span><\/p>\n

The height of mercury in a barometer (above the surface of the sea) = 760 mm Hg <\/span><\/span><\/p>\n

Pressure of air (above the surface of sea) = 1 atm = 1.0 x 105<\/sup> Pascal<\/span><\/span><\/p>\n

1 mm Hg = ……. Pascal?<\/span><\/span><\/p>\n

\"Pressure<\/p>\n

80 mm Hg = 80 x 131.58 Pascal = 10,526 Pascal <\/span><\/span><\/p>\n

120 mm Hg = 120 x 131.58 Pascal = 15,789 Pascal <\/span><\/span><\/p>\n

The correct answer is D.<\/span><\/span><\/p>\n

3. Above the surface of the sea, the height of mercury in a barometer is 760 mm. If at a place, the height of mercury in a barometer is 700 mm. Determine the pressure of air at that place.<\/span><\/span><\/p>\n

Known :<\/u><\/span><\/span><\/p>\n

The height of mercury in a barometer (above the surface of the sea) = 760 mm Hg <\/span><\/span><\/p>\n

Pressure of air (above the surface of sea) = 1 atm = 1,013 x 105<\/sup> Pascal<\/span><\/span><\/p>\n

Wanted:<\/u> Determine the pressure of air if the height of mercury is 700 mm <\/span><\/span><\/p>\n

Solution :<\/u><\/span><\/span><\/p>\n

760 mm Hg = 1.013 x 105<\/sup> Pascal <\/span><\/span><\/p>\n

700 mm Hg = ……… Pascal?<\/span><\/span><\/p>\n

\"Pressure<\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"

1. Acceleration due to gravity is 10 N\/kg. The surface area of fish pressed by the water above it is 6 cm2. Determine the force of water above fish that acts on fish. Known :<\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Pressure of fluids \u2013 problems and solutions","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[3],"tags":[],"class_list":["post-3283","post","type-post","status-publish","format-standard","hentry","category-solved-problems-in-basic-physics"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/3283","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=3283"}],"version-history":[{"count":0,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/3283\/revisions"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=3283"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=3283"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=3283"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}