{"id":3003,"date":"2018-06-03T16:37:29","date_gmt":"2018-06-03T23:37:29","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=3003"},"modified":"2018-06-03T16:37:29","modified_gmt":"2018-06-03T23:37:29","slug":"two-parallel-conductors-carrying-currents-problems-and-solutions","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/two-parallel-conductors-carrying-currents-problems-and-solutions.htm","title":{"rendered":"Two parallel conductors carrying currents \u2013 problems and solutions","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">1. Wire P carrying current 6-A upward as shown in the figure below. If \u00b5<\/span><\/span><sub><span style=\"font-family: Times New Roman, serif\">o<\/span><\/sub><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> = 4\u03c0.10<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-7<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> wb A<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> m<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> and there is a repulsive force between wire P and Q 1.2.10<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-5<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> N.m<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">&#8211;<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">1. Determine the magnitude and direction of <a href=\"https:\/\/gurumuda.net\/physics\/electric-currents-electric-charges-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">electric current<\/a> on wire Q.<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><u>Known :<img loading=\"lazy\" decoding=\"async\" class=\"alignright size-full wp-image-3004\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/06\/Two-parallel-conductors-carrying-currents-\u2013-problems-and-solutions-1.png\" alt=\"Two parallel conductors carrying currents \u2013 problems and solutions 1\" width=\"103\" height=\"99\" \/><\/u><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">I<\/span><\/span><sub><span style=\"font-family: Times New Roman, serif\">P<\/span><\/sub><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> = 6 Ampere<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">\u00b5<\/span><\/span><sub><span style=\"font-family: Times New Roman, serif\">o<\/span><\/sub><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> = 4\u03c0 x 10<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-7<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> wb A<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1 <\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">m<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">F\/l = 1,2 x 10<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-5<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> N m<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">L = 1 meter<\/span><\/span><!--more--><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><u>Wanted:<\/u><\/span><\/span><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> Magnitude and direction of electric current on wire Q<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><u>Solution :<\/u><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><i>The direction of electric current on wire Q :<\/i><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">There is a repulsive force between wire P and Q so that the electric current on wire P has opposite direction with the electric current on wire Q. <\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">On wire P, electric current upward so that on wire Q electric current downward.<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><i>Electric current on wire Q :<\/i><\/span><\/span><\/p>\n<p align=\"justify\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-3005\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/06\/Two-parallel-conductors-carrying-currents-\u2013-problems-and-solutions-2.png\" alt=\"Two parallel conductors carrying currents \u2013 problems and solutions 2\" width=\"210\" height=\"261\" \/><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">2. Two wires parallel, L, and M are 2-cm apart (see figure). Wire M carries a current of 4-A. Both wires exert a repulsive force on each other 6 x 10<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-5<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> Nm<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">. Determine magnitude and direction of electric current on wire L. (\u00b5<\/span><\/span><sub><span style=\"font-family: Times New Roman, serif\">o<\/span><\/sub><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> = 4\u03c0.10<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-7<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> Wb.A<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">m<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">)<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><u>Known :<img loading=\"lazy\" decoding=\"async\" class=\"alignright size-full wp-image-3006\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/06\/Two-parallel-conductors-carrying-currents-\u2013-problems-and-solutions-3.png\" alt=\"Two parallel conductors carrying currents \u2013 problems and solutions 3\" width=\"141\" height=\"128\" \/><\/u><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">I<\/span><\/span><sub><span style=\"font-family: Times New Roman, serif\">M<\/span><\/sub><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> = 4 Ampere<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">\u00b5<\/span><\/span><sub><span style=\"font-family: Times New Roman, serif\">o<\/span><\/sub><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> = 4\u03c0 x 10<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-7<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> wb A<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1 <\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">m<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">F\/l = 6 x 10<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-5<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> N m<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">L = 2 cm = 0.02 m<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><u>Wanted:<\/u><\/span><\/span><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> Magnitude and direction of electric current on wire L<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><u>Solution :<\/u><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\"><i>The direction of the electric current on wire L :<\/i><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\">T<span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\"><span lang=\"en-US\">here is a repulsive force between the wire L and the wire M so that the electric current on the wire L is in opposite direction with the current on the wire M. <\/span><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\"><span lang=\"en-US\">On the wire M electric current is directed upwards so that on the wire L the electric current is downward.<\/span><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\"><i>Electric current on wire L:<\/i><\/span><\/span><\/p>\n<p align=\"justify\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-3007\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/06\/Two-parallel-conductors-carrying-currents-\u2013-problems-and-solutions-4-200x300.png\" alt=\"Two parallel conductors carrying currents \u2013 problems and solutions 4\" width=\"200\" height=\"300\" srcset=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/06\/Two-parallel-conductors-carrying-currents-\u2013-problems-and-solutions-4-200x300.png 200w, https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/06\/Two-parallel-conductors-carrying-currents-\u2013-problems-and-solutions-4.png 201w\" sizes=\"auto, (max-width: 200px) 100vw, 200px\" \/><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\">3. Wire P and Q are 1-m apart. Wire P carrying current 1-A. If \u00b5<\/span><\/span><sub><span style=\"font-family: Times new roman, serif\">o<\/span><\/sub><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\"> = 4<\/span><\/span><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\">\u03c0.10<\/span><\/span><sup><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\">-7<\/span><\/span><\/sup><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\"> Wb.A<\/span><\/span><sup><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\">.m<\/span><\/span><sup><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\">-1 <\/span><\/span><\/sup><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\">and there is an attractive force on each other 10<\/span><\/span><sup><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\">-7<\/span><\/span><\/sup><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\"> N.m<\/span><\/span><sup><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\">, determine magnitude and direction of electric current on wire Q.<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><u>Known :<\/u><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">I<\/span><\/span><sub><span style=\"font-family: Times New Roman, serif\">P<\/span><\/sub><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> = 1 Ampere<img loading=\"lazy\" decoding=\"async\" class=\"alignright size-full wp-image-3008\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/06\/Two-parallel-conductors-carrying-currents-\u2013-problems-and-solutions-5.png\" alt=\"Two parallel conductors carrying currents \u2013 problems and solutions 5\" width=\"108\" height=\"140\" \/><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">\u00b5<\/span><\/span><sub><span style=\"font-family: Times New Roman, serif\">o<\/span><\/sub><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> = 4\u03c0 x 10<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-7<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> wb A<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1 <\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">m<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">F\/l = 10<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-7<\/span><\/span><\/sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> N m<\/span><\/span><sup><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">-1<\/span><\/span><\/sup><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\">L = 1 meter<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><u>Wanted:<\/u><\/span><\/span><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"> Magnitude and direction of current on wire Q <\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\"><u>Solution :<\/u><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\"><i>The direction of electric current on wire Q : <\/i><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\">T<span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\"><span lang=\"en-US\">here is an attractive force between wire P and wire Q so that the direction of the electric current on the wire P is the same as the direction of current on wire Q. <\/span><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times new roman, serif\"><span style=\"font-size: medium\"><span lang=\"en-US\">On wire P the direction of electric current is downward so that on wire Q the direction of electric current is downward.<\/span><\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify\" align=\"justify\"><span style=\"font-family: Times New Roman, serif\"><span style=\"font-size: medium\"><i>Electric current on wire Q :<\/i><\/span><\/span><\/p>\n<p align=\"justify\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-3009 aligncenter\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/06\/Two-parallel-conductors-carrying-currents-\u2013-problems-and-solutions-6.png\" alt=\"Two parallel conductors carrying currents \u2013 problems and solutions 6\" width=\"192\" height=\"232\" \/><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"<p>1. Wire P carrying current 6-A upward as shown in the figure below. If \u00b5o = 4\u03c0.10-7 wb A-1 m-1 and there is a repulsive force between wire P and Q 1.2.10-5 N.m&#8211;1. Determine the magnitude and direction of electric current on wire Q. Known : IP = 6 Ampere \u00b5o = 4\u03c0 x 10-7 &#8230; <a title=\"Two parallel conductors carrying currents \u2013 problems and solutions\" class=\"read-more\" href=\"https:\/\/gurumuda.net\/physics\/two-parallel-conductors-carrying-currents-problems-and-solutions.htm\" aria-label=\"Read more about Two parallel conductors carrying currents \u2013 problems and solutions\">Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Two parallel conductors carrying currents \u2013 problems and solutions","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[3],"tags":[],"class_list":["post-3003","post","type-post","status-publish","format-standard","hentry","category-solved-problems-in-basic-physics"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/3003","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=3003"}],"version-history":[{"count":0,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/3003\/revisions"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=3003"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=3003"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=3003"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}