{"id":2910,"date":"2018-05-31T08:22:23","date_gmt":"2018-05-31T00:22:23","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=2910"},"modified":"2023-08-06T14:26:21","modified_gmt":"2023-08-06T14:26:21","slug":"electric-circuits-with-resistors-in-parallel-and-internal-resistance-problems-and-solutions","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/electric-circuits-with-resistors-in-parallel-and-internal-resistance-problems-and-solutions.htm","title":{"rendered":"Electric circuits with resistors in parallel and internal resistance \u2013 problems and solutions","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"<p align=\"justify\">Electric circuits with resistors in parallel and internal resistance \u2013 problems and solutions<\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">1. Based on the figure below, if the source of electromotive force (emf) is 24 Volt, determine <a href=\"https:\/\/gurumuda.net\/physics\/electric-currents-electric-charges-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">electric current<\/a> I.<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"><u>Known :<img loading=\"lazy\" decoding=\"async\" class=\"alignright size-full wp-image-2911\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/05\/Electric-circuits-with-resistors-in-parallel-and-internal-resistance-\u2013-problems-and-solutions-1.png\" alt=\"Electric circuits with resistors in parallel and internal resistance \u2013 problems and solutions 1\" width=\"161\" height=\"164\" \/><\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">Source of emf = 24 Volt<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">Internal resistance (r) = 2 Ohm<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"><a href=\"https:\/\/gurumuda.net\/physics\/resistors-circuits-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">Resistor<\/a> 40 Ohm, 20 Ohm, and 20 Ohm.<\/span><\/span><!--more--><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"><u>Wante<\/u><span style=\"text-decoration: underline;\">d : <\/span><\/span><\/span><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">Electric current I<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"><u>Solution :<\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">Resistors connected in parallel, the equivalent resistor :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">1\/R = 1\/40 + 1\/20 + 1\/20<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">1\/R = 1\/40 + 2\/40 + 2\/40<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">1\/R = 5\/40<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">R = 40\/5<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">R = 8 Ohm<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">Terminal voltage :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">V = emf \u2013 I r<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">V = 24 \u2013 I 2<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">Electric current I :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">V = I R<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">24 \u2013 I 2 = I 8 <\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">24 = I 8 + I 2 <\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">24 = I (10)<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">I = 24\/10<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">I = 2.4 Ampere<\/span><\/span><\/p>\n<p align=\"justify\"><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">2. Based on figure below, if R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">1<\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> = 3 <\/span><\/span><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">\u03a9, R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">2<\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> = 4 \u03a9, R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">3<\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> = 4 \u03a9 and electric current is 0.5 A. Determine <a href=\"https:\/\/gurumuda.net\/physics\/electric-voltage-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">electric voltage<\/a>.<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"><u>Known :<img loading=\"lazy\" decoding=\"async\" class=\"alignright size-full wp-image-2912\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/05\/Electric-circuits-with-resistors-in-parallel-and-internal-resistance-\u2013-problems-and-solutions-2.png\" alt=\"Electric circuits with resistors in parallel and internal resistance \u2013 problems and solutions 2\" width=\"226\" height=\"143\" \/><\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">Electric current (I) = 0.5 Ampere<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">Resistor R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">1<\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> = 3 Ohm<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">Resistor R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">2 <\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">= 4 Ohm<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">Resistor R<\/span><\/span><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"><sub>3<\/sub> <\/span><\/span><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">= 4 Ohm<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"><u>Wanted :<\/u><\/span><\/span><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> Electric voltage (V)<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"><u>Solution :<\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">Calculate the equivalent resistance :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">2<\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> and R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">3<\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> are connected in parallel. The equivalent resistor :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\">1<span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">\/R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">23<\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> = 1\/R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">2<\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> + 1\/R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">3 <\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">= 1\/4 + 1\/4 = 2\/4<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">23 <\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">= 4\/2 = 2 Ohm<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">1<\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> and R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">23<\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> are connected in series. The equivalent resistor :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">R = R<\/span><\/span><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"><sub>1<\/sub> <\/span><\/span><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">+ R<\/span><\/span><sub><span style=\"font-family: Times new roman, serif;\">23<\/span><\/sub><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\"> = 3 + 2 = 5 Ohm<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">Electric voltage :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman, serif;\"><span style=\"font-size: medium;\">V = I R = (0.5)(5) = 2.5 Volt<\/span><\/span><\/p>\n<p align=\"justify\"><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"<p>Electric circuits with resistors in parallel and internal resistance \u2013 problems and solutions 1. Based on the figure below, if the source of electromotive force (emf) is 24 Volt, determine electric current I. Known : Source of emf = 24 Volt Internal resistance (r) = 2 Ohm Resistor 40 Ohm, 20 Ohm, and 20 Ohm.<\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Electric circuits with resistors in parallel and internal resistance \u2013 problems and solutions","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[3],"tags":[],"class_list":["post-2910","post","type-post","status-publish","format-standard","hentry","category-solved-problems-in-basic-physics"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2910","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=2910"}],"version-history":[{"count":1,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2910\/revisions"}],"predecessor-version":[{"id":8537,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2910\/revisions\/8537"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=2910"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=2910"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=2910"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}