{"id":2380,"date":"2018-05-04T03:17:12","date_gmt":"2018-05-03T19:17:12","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=2380"},"modified":"2023-08-06T15:39:11","modified_gmt":"2023-08-06T15:39:11","slug":"conservation-of-linear-momentum","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/conservation-of-linear-momentum.htm","title":{"rendered":"Conservation of linear momentum","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">Conservation of linear momentum<\/span><\/p>\n<p class=\"first-line-indent-western\" style=\"text-align: justify;\" align=\"justify\"><span lang=\"en-US\" style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">Law of conservation of linear momentum states that if there is no external force acting on two colliding objects, the momentum of the objects before the collision is equal to the momentum of the objects after the collision.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><span lang=\"en-US\">p<\/span><sub><span lang=\"en-US\">1<\/span><\/sub><span lang=\"en-US\"> + p<\/span><sub><span lang=\"en-US\">2 <\/span><\/sub><span lang=\"en-US\">= p<\/span><sub><span lang=\"en-US\">1<\/span><\/sub><span lang=\"en-US\"> \u2019 + p<\/span><sub><span lang=\"en-US\">2<\/span><\/sub><span lang=\"en-US\"> \u2019 \u2026&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.. Equation 1.4<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><span lang=\"en-US\">m<\/span><sub><span lang=\"en-US\">1 <\/span><\/sub><span lang=\"en-US\">v<\/span><sub><span lang=\"en-US\">1<\/span><\/sub><span lang=\"en-US\"> + m<\/span><sub><span lang=\"en-US\">2<\/span><\/sub><span lang=\"en-US\"> v<\/span><sub><span lang=\"en-US\">2<\/span><\/sub><span lang=\"en-US\"> = m<\/span><sub><span lang=\"en-US\">1<\/span><\/sub><span lang=\"en-US\"> v<\/span><sub><span lang=\"en-US\">1 <\/span><\/sub><span lang=\"en-US\">\u2019 + m<\/span><sub><span lang=\"en-US\">2<\/span><\/sub><span lang=\"en-US\"> v<\/span><sub><span lang=\"en-US\">2 <\/span><\/sub><span lang=\"en-US\">\u2019<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\"><span lang=\"en-US\" style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">If after collision both objects stick together,<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><span lang=\"en-US\">m<\/span><sub><span lang=\"en-US\">1 <\/span><\/sub><span lang=\"en-US\">v<\/span><sub><span lang=\"en-US\">1<\/span><\/sub><span lang=\"en-US\"> + m<\/span><sub><span lang=\"en-US\">2<\/span><\/sub><span lang=\"en-US\"> v<\/span><sub><span lang=\"en-US\">2<\/span><\/sub><span lang=\"en-US\"> = (m<\/span><sub><span lang=\"en-US\">1 <\/span><\/sub><span lang=\"en-US\">+ m<\/span><sub><span lang=\"en-US\">2<\/span><\/sub><span lang=\"en-US\"> ) v\u2019<\/span><!--more--><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><span lang=\"en-US\">where: m<\/span><sub><span lang=\"en-US\">1<\/span><\/sub><span lang=\"en-US\"> = mass of object 1, m<\/span><sub><span lang=\"en-US\">2 <\/span><\/sub><span lang=\"en-US\">= mass of object 2, v<\/span><sub><span lang=\"en-US\">1<\/span><\/sub><span lang=\"en-US\"> = speed of object 1 before collision, v<\/span><sub><span lang=\"en-US\">2<\/span><\/sub><span lang=\"en-US\"> = speed of object 2 before collision, v<\/span><sub><span lang=\"en-US\">1<\/span><\/sub><span lang=\"en-US\"> \u2019 = speed of object 1 after collision, v<\/span><sub><span lang=\"en-US\">2 <\/span><\/sub><span lang=\"en-US\">\u2019 = speed of object 2 after collision, v\u2019 = speed of both objects after collision <\/span><\/span><\/p>\n<p class=\"first-line-indent-western\" style=\"text-align: justify;\" align=\"justify\"><span lang=\"en-US\" style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"> v or v\u2019 has a positive sign if the object moves to the right and has a negative sign if the object moves to the left. If the objects\u2019 motion directions are unknown, but both objects move in opposite directions, either of v or v\u2019 has a positive sign while the other has a negative sign. If both objects move in the same direction, v or v\u2019 of both objects has the same direction. The positive or negative sign indicates the direction of the object\u2019s motion.<\/span><\/p>\n<div class=\"group w-full text-token-text-primary border-b border-black\/10 dark:border-gray-900\/50 bg-gray-50 dark:bg-[#444654]\">\n<div class=\"flex p-4 gap-4 text-base md:gap-6 md:max-w-2xl lg:max-w-[38rem] xl:max-w-3xl md:py-6 lg:px-0 m-auto\">\n<div class=\"relative flex w-[calc(100%-50px)] flex-col gap-1 md:gap-3 lg:w-[calc(100%-115px)]\">\n<div class=\"flex flex-grow flex-col gap-3\">\n<div class=\"min-h-[20px] flex flex-col items-start gap-3 overflow-x-auto whitespace-pre-wrap break-words\">\n<div class=\"markdown prose w-full break-words dark:prose-invert light\">\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">20 conceptual questions and answers about the conservation of linear momentum:<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>1. Question:<\/strong> What is linear momentum? <strong>Answer:<\/strong> Linear momentum, often just called momentum, is the product of an object&#8217;s mass and its velocity. It is a vector quantity and is represented by <span class=\"math math-inline\"><span class=\"katex\"><span class=\"katex-mathml\">\ufffd=\ufffd\ufffd\ufffd<\/span><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord mathnormal\">p<\/span><span class=\"mrel\">=<\/span><\/span><span class=\"base\"><span class=\"mord mathnormal\">m<\/span><span class=\"mord mathnormal\">xv<\/span><\/span><\/span><\/span><\/span>.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>2. Question:<\/strong> How does the conservation of linear momentum apply in collisions? <strong>Answer:<\/strong> The total momentum of a system before a collision is equal to the total momentum after the collision, provided no external forces act on the system.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>3. Question:<\/strong> In what scenarios is linear momentum conserved? <strong>Answer:<\/strong> Linear momentum is conserved in all scenarios where the net external force on the system is zero.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>4. Question:<\/strong> How does a rocket in space move forward given there&#8217;s no external force acting on it? <strong>Answer:<\/strong> A rocket in space expels gases backward, and due to the conservation of momentum, the rocket moves forward. The momentum of the expelled gases and the rocket remain equal and opposite, maintaining a net momentum of zero.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>5. Question:<\/strong> Why does an ice skater spin faster when they pull their arms in? <strong>Answer:<\/strong> When the skater pulls their arms in, they reduce their moment of inertia. To conserve angular momentum, their rotational speed must increase.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>6. Question:<\/strong> Can momentum be conserved if there is an external force acting on a system? <strong>Answer:<\/strong> For the duration the external force acts, momentum won&#8217;t be conserved. However, over short time intervals, the change might be negligible and momentum approximately conserved.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>7. Question:<\/strong> What is an inelastic collision with respect to momentum? <strong>Answer:<\/strong> In an inelastic collision, momentum is conserved, but kinetic energy is not. Objects may stick together or deform during the collision.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>8. Question:<\/strong> How can a system gain momentum without an external force? <strong>Answer:<\/strong> A system can&#8217;t gain momentum without an external force. Newton&#8217;s third law ensures that actions within a system have equal and opposite reactions, so net momentum remains unchanged.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>9. Question:<\/strong> What is impulse and its relation to momentum? <strong>Answer:<\/strong> Impulse is the change in momentum of an object. It&#8217;s given by the product of the force acting on an object and the time duration over which it acts. Impulse is also a vector quantity.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>10. Question:<\/strong> How do airbags in cars use the concept of momentum? <strong>Answer:<\/strong> Airbags increase the time over which a collision occurs. This reduces the force experienced by occupants, changing the momentum more gradually and reducing injury.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>11. Question:<\/strong> How does bouncing differ from sticking in terms of momentum conservation in collisions? <strong>Answer:<\/strong> In both cases, momentum is conserved. However, when objects bounce, they may exchange more kinetic energy than when they stick together.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>12. Question:<\/strong> Can a single object have conserved momentum? <strong>Answer:<\/strong> An isolated object&#8217;s momentum is conserved unless acted upon by an external force.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>13. Question:<\/strong> How is momentum related to Newton&#8217;s third law? <strong>Answer:<\/strong> Newton&#8217;s third law states every action has an equal and opposite reaction. This ensures that momentum changes are balanced between interacting objects, leading to momentum conservation.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>14. Question:<\/strong> Why does a bullet fired from a gun make the gun recoil? <strong>Answer:<\/strong> As the bullet gains forward momentum, the gun gains an equal amount of backward momentum due to the conservation of momentum.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>15. Question:<\/strong> Can momentum be zero in a system with moving objects? <strong>Answer:<\/strong> Yes, if the vector sum of all individual momenta is zero. For instance, two objects of equal mass and speed moving in opposite directions have zero net momentum.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>16. Question:<\/strong> How does the center of mass motion relate to momentum conservation? <strong>Answer:<\/strong> The motion of a system&#8217;s center of mass is directly tied to the system&#8217;s total momentum. If no external forces act, the center of mass will move at a constant velocity.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>17. Question:<\/strong> Is momentum always conserved in explosions? <strong>Answer:<\/strong> Yes, the total momentum before an explosion (usually zero) is equal to the total momentum after, even though the pieces may be moving in different directions.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>18. Question:<\/strong> How do pool players use momentum conservation principles? <strong>Answer:<\/strong> When striking pool balls, players anticipate how balls will move post-collision based on momentum conservation, allowing them to predict shot outcomes.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>19. Question:<\/strong> Why doesn&#8217;t a car come to a stop immediately after turning off the engine? <strong>Answer:<\/strong> Due to its momentum. Unless acted upon by an external force (like friction), it will continue moving.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>20. Question:<\/strong> In a two-object system, if one object&#8217;s momentum increases, what happens to the other&#8217;s momentum? <strong>Answer:<\/strong> The other object&#8217;s momentum will decrease by an equal amount in the opposite direction, keeping the total momentum conserved.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">Understanding the conservation of linear momentum is foundational in physics and has applications ranging from basic mechanics to advanced fields of study.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"<p>Conservation of linear momentum Law of conservation of linear momentum states that if there is no external force acting on two colliding objects, the momentum of the objects before the collision is equal to the momentum of the objects after the collision. p1 + p2 = p1 \u2019 + p2 \u2019 \u2026&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.. Equation 1.4 m1 &#8230; <a title=\"Conservation of linear momentum\" class=\"read-more\" href=\"https:\/\/gurumuda.net\/physics\/conservation-of-linear-momentum.htm\" aria-label=\"Read more about Conservation of linear momentum\">Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Conservation of linear momentum","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[2],"tags":[],"class_list":["post-2380","post","type-post","status-publish","format-standard","hentry","category-basic-physics-tutorials"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2380","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=2380"}],"version-history":[{"count":2,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2380\/revisions"}],"predecessor-version":[{"id":8579,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2380\/revisions\/8579"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=2380"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=2380"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=2380"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}