{"id":2358,"date":"2018-05-01T13:13:25","date_gmt":"2018-05-01T05:13:25","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=2358"},"modified":"2023-08-08T12:16:18","modified_gmt":"2023-08-08T12:16:18","slug":"work-kinetic-energy-principle","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/work-kinetic-energy-principle.htm","title":{"rendered":"Work-Kinetic Energy principle","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">Work-Kinetic Energy principle<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">If net force works on an object, the object experiences acceleration (the object experiences displacement). When the object experiences acceleration, the speed of the object changes. In other words, the work done by the net force is related to the object\u2019s initial and final speed. <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The work done on an object by constant net force is:<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">W<sub>net<\/sub> = \u03a3F s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">Newton\u2019s second law states that if there is a net force working on an object, the object experiences acceleration.<!--more--><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">W<sub>net <\/sub>= (m a) s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">If the net force is constant, the acceleration experienced by the object is constant as well. Therefore, we can substitute a non-uniform linear motion equation for acceleration (a) and displacement (s).<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-2359\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/05\/Work-Kinetic-Energy-principle-1.png\" alt=\"Work-Kinetic Energy principle 1\" width=\"234\" height=\"109\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Incorporate the non-uniform linear motion equation into the work equation:<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-2360\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/05\/Work-Kinetic-Energy-principle-2-300x210.png\" alt=\"Work-Kinetic Energy principle 2\" width=\"300\" height=\"210\" srcset=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/05\/Work-Kinetic-Energy-principle-2-300x210.png 300w, https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/05\/Work-Kinetic-Energy-principle-2.png 336w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">Description: EK<sub>t <\/sub>= final kinetic energy, EK<sub>o<\/sub> = initial kinetic energy, m = mass, v<sub>t <\/sub>= final speed, v<sub>o<\/sub> = initial speed<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">This equation constitutes the work-kinetic energy theorem. The work-kinetic energy theorem informs us that net work or the work done by the net force on an object is equal to the change in the object\u2019s kinetic energy. It also informs us that an object\u2019s kinetic energy is equal to the net work required to accelerates the object from a stationary state to moving at a given speed, and vice versa.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Example question 5: Work-kinetic energy theorem<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">A car with a mass of 1000 kg moves from a stationary state. In an instant, the speed increases into 10 m\/s. How much is the net work done by the car\u2019s engines?<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Solution :<br \/>\n<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">Known: m = 1000 kg, v<sub>o<\/sub> = initial speed = 0 m\/s (at first, the car is at rest), v<sub>t<\/sub> = final speed = 10 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Wanted : The net work<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">W<sub>net<\/sub> = 1\u20442 m (v<sub>t<\/sub><sup>2<\/sup> \u2013 v<sub>o<\/sub><sup>2<\/sup>)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">W<sub>net <\/sub>= 1\u20442 (1000)(10<sup>2<\/sup> \u2013 0<sup>2<\/sup>) = (500)(100 \u2013 0) = (500)(100) = 50,000 Joule<\/span><\/p>\n<div class=\"flex-1 overflow-hidden\">\n<div class=\"react-scroll-to-bottom--css-pozvq-79elbk h-full dark:bg-gray-800\">\n<div class=\"react-scroll-to-bottom--css-pozvq-1n7m0yu\">\n<div class=\"flex flex-col text-sm dark:bg-gray-800\">\n<div class=\"group w-full text-token-text-primary border-b border-black\/10 dark:border-gray-900\/50 bg-gray-50 dark:bg-[#444654]\">\n<div class=\"flex p-4 gap-4 text-base md:gap-6 md:max-w-2xl lg:max-w-[38rem] xl:max-w-3xl md:py-6 lg:px-0 m-auto\">\n<div class=\"relative flex w-[calc(100%-50px)] flex-col gap-1 md:gap-3 lg:w-[calc(100%-115px)]\">\n<div class=\"flex flex-grow flex-col gap-3\">\n<div class=\"min-h-[20px] flex flex-col items-start gap-3 overflow-x-auto whitespace-pre-wrap break-words\">\n<div class=\"markdown prose w-full break-words dark:prose-invert light\">\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>1. What is the Work-Kinetic Energy principle?<\/strong> The Work-Kinetic Energy principle states that the net work done on an object is equal to the change in its kinetic energy. Mathematically, <span class=\"math math-inline\"><span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord\"><span class=\"mord mathnormal\">W<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\"><span class=\"mord mathnormal mtight\">n<\/span><span class=\"mord mathnormal mtight\">e<\/span><span class=\"mord mathnormal mtight\">t<\/span><\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mrel\">=<\/span><\/span><span class=\"base\"><span class=\"mord\">\u0394<\/span><span class=\"mord mathnormal\">K<\/span><span class=\"mord mathnormal\">E<\/span><\/span><\/span><\/span><\/span>, where <span class=\"math math-inline\"><span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord\">\u0394<\/span><span class=\"mord mathnormal\">K<\/span><span class=\"mord mathnormal\">E<\/span><\/span><\/span><\/span><\/span> is the final kinetic energy minus the initial kinetic energy.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>2. How is work related to a change in velocity of an object?<\/strong> Work done on an object can change its velocity. Specifically, the net work done on an object is equal to the change in its kinetic energy, and kinetic energy is related to the square of velocity. Thus, if positive net work is done on an object, its velocity (and therefore its kinetic energy) increases.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>3. What happens to the kinetic energy of an object when negative work is done on it?<\/strong> When negative work is done on an object, its kinetic energy decreases. This could result in the object slowing down.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>4. How does the Work-Kinetic Energy principle relate to Newton&#8217;s second law?<\/strong> Newton&#8217;s second law describes how a force affects an object&#8217;s motion, while the Work-Kinetic Energy principle relates the work done by that force to the change in kinetic energy. Both concepts are linked through the idea that forces can change an object&#8217;s state of motion and energy.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>5. Can the kinetic energy of an object be negative?<\/strong> No, kinetic energy is always non-negative. It is given by the formula <span class=\"math math-inline\"><span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord mathnormal\">K<\/span><span class=\"mord mathnormal\">E<\/span><span class=\"mrel\">= 1\/2 <\/span><\/span><span class=\"base\"><span class=\"mord\"><span class=\"mfrac\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mord mathnormal\">m <\/span><span class=\"mord\"><span class=\"mord mathnormal\">v<\/span><sup><span class=\"msupsub\"><span class=\"vlist-t\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2<\/span><\/span><\/span><\/span><\/span><\/span><\/sup><\/span><\/span><\/span><\/span><\/span>, where m is mass and v is velocity. Since both mass and the square of velocity are positive, kinetic energy is also positive or zero.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>6. How does the Work-Kinetic Energy principle apply to an object moving in a circular path?<\/strong> For an object moving in a circular path at constant speed, its kinetic energy remains constant since its speed is unchanged. However, the direction of its velocity changes continuously. If only centripetal forces (like tension or gravitational force) act on the object, the work done by these forces is zero as they act perpendicular to the direction of motion. Thus, no net work is done, and there&#8217;s no change in kinetic energy.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>7. In the absence of external forces, how does the kinetic energy of an object change?<\/strong> In the absence of external forces, no work is done on the object, which means its kinetic energy remains constant. This is a manifestation of the conservation of energy.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>8. What does it mean when the net work done on an object is zero?<\/strong> When the net work done on an object is zero, it means the object&#8217;s kinetic energy hasn&#8217;t changed. The object could still be moving, but its speed remains constant.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>9. Can an object have kinetic energy even if no work has been done on it?<\/strong> Yes, an object can have kinetic energy without any work being done on it in a given time frame. For instance, an object already in motion in outer space (far from gravitational bodies) will retain its kinetic energy and keep moving at a constant velocity, even if no external forces act on it.<\/span><\/p>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>10. How does the work done by nonconservative forces affect the kinetic energy of an object?<\/strong> The work done by nonconservative forces can increase or decrease the kinetic energy of an object, depending on the direction and magnitude of the force relative to the object&#8217;s motion. For instance, friction, a nonconservative force, usually does negative work, thereby decreasing an object&#8217;s kinetic energy.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"<p>Work-Kinetic Energy principle If net force works on an object, the object experiences acceleration (the object experiences displacement). When the object experiences acceleration, the speed of the object changes. In other words, the work done by the net force is related to the object\u2019s initial and final speed. The work done on an object by &#8230; <a title=\"Work-Kinetic Energy principle\" class=\"read-more\" href=\"https:\/\/gurumuda.net\/physics\/work-kinetic-energy-principle.htm\" aria-label=\"Read more about Work-Kinetic Energy principle\">Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Work-Kinetic Energy principle","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[2],"tags":[],"class_list":["post-2358","post","type-post","status-publish","format-standard","hentry","category-basic-physics-tutorials"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2358","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=2358"}],"version-history":[{"count":2,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2358\/revisions"}],"predecessor-version":[{"id":8588,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2358\/revisions\/8588"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=2358"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=2358"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=2358"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}