{"id":2077,"date":"2018-04-23T13:38:14","date_gmt":"2018-04-23T05:38:14","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=2077"},"modified":"2023-08-09T04:11:40","modified_gmt":"2023-08-09T04:11:40","slug":"collisions-problems-and-solutions","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/collisions-problems-and-solutions.htm","title":{"rendered":"Collisions \u2013 problems and solutions","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">Collisions \u2013 problems and solutions<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">1. Object A (3 kg) moves at a speed of 8 m\/s and object B (5 kg) moves at a speed of 4 m\/s. If the collision between the object A and B is perfectly elastic, what is the <a href=\"https:\/\/gurumuda.net\/physics\/average-velocity-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">velocity<\/a> of object A and B after the collision?<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><a href=\"https:\/\/gurumuda.net\/physics\/mass-and-weight-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">Mass<\/a> of object A (m<sub>1<\/sub>) = 3 kg<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Mass of object B (m<sub>2<\/sub>) = 5 kg<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The <a href=\"https:\/\/gurumuda.net\/physics\/average-speed-and-average-velocity-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">speed<\/a> of object A (v<sub>1<\/sub>) = 8 ms<sup>\u20131 <\/sup><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">The speed of object B (v<sub>2<\/sub>) = 4 ms<sup>\u20131<\/sup> <!--more--><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><a href=\"https:\/\/gurumuda.net\/physics\/perfectly-elastic-collisions-in-one-dimension-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">Perfectly elastic collision<\/a>.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted:<\/u> v<sub>1<\/sub>&#8216; and v<sub>2<\/sub>&#8216;<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">If both objects have the different mass and the velocity of both objects after the collision is not known yet, then the velocity after collision calculated using this equation :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-2078\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Collisions-\u2013-problems-and-solutions-1.png\" alt=\"Collisions \u2013 problems and solutions 1\" width=\"222\" height=\"95\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The direction of both objects is the same so that the velocity of both objects have the same sign. If both objects move in opposite direction then one velocity has plus sign and another velocity has minus sign.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The velocity of object A (v<sub>A<\/sub>) after the collision :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-2079\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Collisions-\u2013-problems-and-solutions-2-300x30.png\" alt=\"Collisions \u2013 problems and solutions 2\" width=\"300\" height=\"30\" srcset=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Collisions-\u2013-problems-and-solutions-2-300x30.png 300w, https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Collisions-\u2013-problems-and-solutions-2.png 448w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The velocity of object B (v<sub>B<\/sub>) after the collision :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-2080\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Collisions-\u2013-problems-and-solutions-3-300x35.png\" alt=\"Collisions \u2013 problems and solutions 3\" width=\"300\" height=\"35\" srcset=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Collisions-\u2013-problems-and-solutions-3-300x35.png 300w, https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Collisions-\u2013-problems-and-solutions-3.png 382w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Velocity of object A (v<sub>1<\/sub>&#8216;) after collision is 3 m\/s and velocity of object B (v<sub>2<\/sub>&#8216;) after collision is 7 m\/s.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">2. A ball has a momentum of P, collide a wall and reflected. The collision is perfectly elastic and its direction perpendicular to the wall. What is the change of the ball&#8217;s <a href=\"https:\/\/gurumuda.net\/physics\/linear-momentum-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">momentum<\/a>?<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Mass of ball = m<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The velocity of the ball before collision = v <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Velocity of ball after collision = -v (ball reflected leftward)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Ball&#8217;s momentum before collision (p<sub>o<\/sub>) = m v<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Ball&#8217;s momentum after collision (p<sub>t<\/sub>) = m (-v) = &#8211; m v<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted:<\/u> The change of the ball&#8217;s momentum<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The change of momentum :<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">\u0394p = p<sub>t<\/sub> \u2013 p<sub>o<\/sub> <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">\u0394p = &#8211; m v &#8211; m v<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">\u0394p = &#8211; 2 m v<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">\u0394p = -2p<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Minus sign indicates the direction of the ball. <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">3. Two objects, A and B, have the same mass move in an opposite direction and collide with each other. A moves east a speed of V and B move west at a speed of 2V. If the collision is perfectly elastic, then what is the velocity of both objects after the collision.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Both objects have the same mass. <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">A moves east at speed of V<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">B moves west at speed of 2V<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted:<\/u> The velocity of both objects after the collision<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">If both objects have the same mass and the collision is perfectly elastic, then after collision both objects change their velocity.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">After the collision, A moves west at 2V and B moves east at V.<\/span><\/p>\n<p class=\"western\" lang=\"en-US\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><a href=\"https:\/\/gurumuda.net\/physics\/inelastic-collisions-in-one-dimension-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\"><b>Partially Elastic Collisions<\/b><\/a><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">4. Two objects with the same mass move along a straight line in opposite direction as shown in the figure below. If the velocity of object 2 after the collision (v<sub>2<\/sub>&#8216;) is 5 m\/s rightward, then what is the magnitude of the velocity of the object 1 after the collision.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Mass of each object = m<img loading=\"lazy\" decoding=\"async\" class=\"alignright size-medium wp-image-2081\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Collisions-\u2013-problems-and-solutions-4-300x73.png\" alt=\"Collisions \u2013 problems and solutions 4\" width=\"300\" height=\"73\" srcset=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Collisions-\u2013-problems-and-solutions-4-300x73.png 300w, https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Collisions-\u2013-problems-and-solutions-4.png 339w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Velocity of object 1 before collision (v<sub>1<\/sub>) = 8 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Velocity of object 2 after collision (v<sub>2<\/sub>) = 10 m\/s <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Velocity of object 2 after collision (v<sub>2<\/sub>&#8216;) = 5 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted :<\/u> Velocity of object 1 after collision (v<sub>1<\/sub>&#8216;) <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The collision is partially elastic.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">m<sub>1<\/sub> v<sub>1<\/sub>+ m<sub>2<\/sub> v<sub>2<\/sub> = m<sub>1<\/sub> v<sub>1<\/sub>\u2019 + m<sub>2<\/sub> v<sub>2<\/sub>\u2019<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">m (v<sub>1<\/sub> + v<sub>2<\/sub>) = m (v<sub>1<\/sub>\u2019 + v<sub>2<\/sub>\u2019)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">v<sub>1<\/sub> + v<sub>2<\/sub> = v<sub>1<\/sub>\u2019 + v<sub>2<\/sub>\u2019<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">8 + 10 = v<sub>1<\/sub>\u2019 + 5<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">18 = v<sub>1<\/sub>\u2019 + 5<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">v<sub>1<\/sub>\u2019 = 18-5<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">v<sub>1<\/sub>\u2019 = 13 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><b>Inelastic collision<\/b><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">5. A 10-gram bullet fired at 100 m s<sup>-1<\/sup> , collide a block of wood at rest. Mass of block is 490 gram. The collision is inelastic. What is the speed of the block and bullet after collision.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">mass of bullet (m<sub>1<\/sub>) = 10 gram <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Speed of bullet (v<sub>1<\/sub>) = 100 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Mass of block (m<sub>2<\/sub>) = 490 gram <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Speed of block (v<sub>2<\/sub>) = 0 m\/s (block at rest)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted :<\/u> The speed of the block and bullet after collision<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">m<sub>1 <\/sub>v<sub>1<\/sub> + m<sub>2<\/sub> v<sub>2<\/sub> = (m<sub>1<\/sub> + m<sub>2<\/sub>) v&#8217;<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">(10)(100) + (490)(0) = (10 + 490) v&#8217;<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">1000 + 0 = 500 v&#8217;<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">1000 =500 v&#8217;<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">v&#8217; = 1000 \/ 500<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">v&#8217; = 2 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">6. A truck moves at 10 m\/s collide a car moves at 20 m\/s. After collision, both truck and car move together at the same speed. Mass of truck is 1400 kg and mass of car is 600 kg. What is the velocity of both truck and car after collision.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">speed of truck (v<sub>1<\/sub>) = 10 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">speed of car (v<sub>2<\/sub>) = 20 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">mass of truck (m<sub>1<\/sub>) = 1400 kg<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">mass of car (m<sub>2<\/sub>) = 600 kg<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted :<\/u> The velocity of both truck and car after collision<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">m<sub>1<\/sub> v<sub>1<\/sub> + m<sub>2<\/sub> v<sub>2<\/sub> = (m<sub>1 <\/sub>+ m<sub>2<\/sub>) v<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">(1400)(10) + (600)(20) = (1400 + 600) v<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">14000 + 12000 = 2000 v<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">26000 = 2000 v<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">v = 13 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">7. A 20-gram bullet moves at 10 m\/s in a horizontal direction, collide a 60-gram block rest on a floor. After collision, bullet and block move together with the same speed and the same direction. What is the speed of both bullet and block.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Mass of bullet (m<sub>P<\/sub>) = 20 gram = 0.02 kg<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Mass of block (m<sub>B<\/sub>) = 60 gram = 0.06 kg<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The initial speed of bullet (v<sub>P<\/sub>) = 10 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The initial speed of block (v<sub>B<\/sub>) = 0<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted :<\/u> The speed of bullet and block after collision (v\u2019)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The collision is inelastic.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">m<sub>P<\/sub> v<sub>P <\/sub>+ m<sub>B <\/sub>v<sub>B<\/sub> = (m<sub>P<\/sub> + m<sub>B<\/sub>) v\u2019<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">(0.02)(10) + (0.06)(0) = (0.02 + 0.06) v\u2019<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">0.2 + 0 = 0.08 v\u2019<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">0.2 = 0.08 v\u2019<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">v\u2019 = 0.2 \/ 0.08<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">v\u2019 = 2.5 m\/s<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">8. Two objects, A and B, have the same mass = 1.5 kg approach each other and collide. Speed of object A (v<sub>A<\/sub>) = 4 m\/s and speed of object B (v<sub>B<\/sub>) = 5 m\/s. If the collision is inelastic, what is the speed of both objects after collision.<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Mass of object A (m<sub>A<\/sub>) = 1.5 kg<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Mass of object B (m<sub>B<\/sub>) = 1.5 kg<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Speed of object A before collision (v<sub>A<\/sub>) = 4 m\/s (positive rightward)<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Speed of object B before collision (v<sub>B<\/sub>) = -5 m\/s (negative leftward)<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted :<\/u> The speed of both objects after collision<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">m<sub>A<\/sub> v<sub>A<\/sub> + m<sub>B<\/sub> v<sub>B <\/sub>= (m<sub>A<\/sub> + m<sub>B<\/sub>) v&#8217;<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">(1.5)(4) + (1.5)(-5) = (1.5 + 1.5) v&#8217;<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">6 \u2013 7.5 = (3) v&#8217;<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">-1.5 = (3) v&#8217;<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">v&#8217; = -1.5 \/ 3<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">v&#8217; = -0.5 m\/s<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Minus sign indicates that after collision, both objects move leftward, same direction as object B.<\/span><\/p>\n<ol>\n<li style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>What is a collision in the context of physics?<\/strong> <em>Answer<\/em>: In physics, a collision refers to an event where two or more objects come in close contact with each other, typically exerting a force upon each other, resulting in an exchange of energy and momentum.<\/span><\/li>\n<li style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>How are elastic and inelastic collisions different?<\/strong> <em>Answer<\/em>: In an elastic collision, both momentum and kinetic energy are conserved. In an inelastic collision, momentum is conserved, but kinetic energy is not. Perfectly inelastic collisions are a subset where the colliding objects stick together after the collision.<\/span><\/li>\n<li style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Why is momentum always conserved in collisions?<\/strong> <em>Answer<\/em>: Momentum is conserved in collisions due to the conservation of momentum principle, which states that the total momentum of a closed system remains constant unless acted upon by external forces.<\/span><\/li>\n<li style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Is kinetic energy always conserved in collisions?<\/strong> <em>Answer<\/em>: No, kinetic energy is only conserved in elastic collisions. In inelastic collisions, some of the kinetic energy is transformed into other forms of energy, such as potential energy, sound, or heat.<\/span><\/li>\n<li style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Why might two cars stick together after a collision?<\/strong> <em>Answer<\/em>: If two cars stick together after a collision, it&#8217;s an example of a perfectly inelastic collision. The cars remain together due to mechanical interlocking, deformation, or other forces that overcome their ability to rebound from each other.<\/span><\/li>\n<li style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Can an object undergoing a collision experience a change in kinetic energy even if its speed remains unchanged?<\/strong> <em>Answer<\/em>: Yes, if an object changes its direction during a collision but not its speed, its velocity (a vector quantity) changes, but its speed (a scalar quantity) remains the same. Though the magnitude of its kinetic energy (dependent on speed) might not change, the object has undergone a change in energy distribution.<\/span><\/li>\n<li style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Why do billiard balls bounce off each other when they collide?<\/strong> <em>Answer<\/em>: Billiard balls undergo nearly elastic collisions. When one ball strikes another, the kinetic energy and momentum are transferred, causing the balls to bounce apart. The design and material of billiard balls make them efficient at conserving kinetic energy in these interactions.<\/span><\/li>\n<li style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>If two objects of different masses collide and stick together, will their combined velocity be the average of their initial velocities?<\/strong> <em>Answer<\/em>: Not necessarily. The combined velocity will depend on the law of conservation of momentum. If one object is much more massive than the other, the combined velocity will be closer to the initial velocity of the more massive object.<\/span><\/li>\n<li style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>In the real world, are there truly &#8220;elastic&#8221; collisions?<\/strong> <em>Answer<\/em>: In practice, no collision is perfectly elastic. While some collisions, like those between billiard balls, come close, there&#8217;s always some energy lost to other forms, such as sound or heat.<\/span><\/li>\n<li>\n<p style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>How does an airbag reduce the impact of a collision in a car accident?<\/strong> <em>Answer<\/em>: Airbags increase the time taken for a person&#8217;s momentum to change upon collision. By doing so, the force experienced by the person (which is inversely proportional to the time over which momentum changes) is reduced, minimizing potential injury.<\/span><\/p>\n<\/li>\n<\/ol>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"<p>Collisions \u2013 problems and solutions 1. Object A (3 kg) moves at a speed of 8 m\/s and object B (5 kg) moves at a speed of 4 m\/s. If the collision between the object A and B is perfectly elastic, what is the velocity of object A and B after the collision? Known : &#8230; <a title=\"Collisions \u2013 problems and solutions\" class=\"read-more\" href=\"https:\/\/gurumuda.net\/physics\/collisions-problems-and-solutions.htm\" aria-label=\"Read more about Collisions \u2013 problems and solutions\">Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Collisions \u2013 problems and solutions","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[3],"tags":[],"class_list":["post-2077","post","type-post","status-publish","format-standard","hentry","category-solved-problems-in-basic-physics"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2077","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=2077"}],"version-history":[{"count":2,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2077\/revisions"}],"predecessor-version":[{"id":8653,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/2077\/revisions\/8653"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=2077"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=2077"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=2077"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}