{"id":1840,"date":"2018-04-14T15:33:44","date_gmt":"2018-04-14T07:33:44","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=1840"},"modified":"2023-08-09T08:25:59","modified_gmt":"2023-08-09T08:25:59","slug":"doppler-effect-problems-and-solutions","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/doppler-effect-problems-and-solutions.htm","title":{"rendered":"Doppler effect \u2013 problems and solutions","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">Doppler effect \u2013 problems and solutions<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">1.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">(1) an observer moving toward the stationery source<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">(2) source moving toward the stationary observer<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">(3) observer and source approach each other<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">(4) observer and source are moving at the same speed<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">If the pitch heard is higher than that of the emitted source frequency, then <span lang=\"en-US\">which statement <\/span><span lang=\"en-US\">above are <\/span><span lang=\"en-US\">correc<\/span><span lang=\"en-US\">t :<\/span><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">A. (1), (2) and (3)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">B. (1), (2), (3) and (4)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">C. (1) and (3)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">D. (1) and (4)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">E. (2) and (4)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Solution<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The equation of the <a href=\"https:\/\/gurumuda.net\/physics\/doppler-effect-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">Doppler effect<\/a> :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-1841\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-1.png\" alt=\"Doppler effect \u2013 problems and solutions 1\" width=\"142\" height=\"49\" \/><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">Sign rule :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The sound speed (v) always positive<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is positive if observer moving toward the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is negative if the observer moving away from the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) is positive if the source of the sound moving away from the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) is negative if the source of the sound moving toward the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) = 0 if an observer at rest<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) = 0 if source at rest<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">For example :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) = 60 m\/s, if observer at rest then v<sub>obs <\/sub>= 0<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) = 40 m\/s, if the source of the sound at rest then v<sub>source<\/sub> = 0<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The sound speed (v) = 340 m\/s <\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The frequency of sound (f) = 1000 Hertz<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>An observer moving toward the stationery source<\/u><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\"><i>The o<\/i><i>bserver <\/i><i>speed <\/i><i>(<\/i><i>v<\/i><sub><i>obs<\/i><\/sub><i>) is<\/i><i> positive if <\/i><i>observer moving toward <\/i><i>the source of the sound<\/i><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><i>The source of the sound at rest so <\/i><i>v<\/i><sub><i>source<\/i><i> <\/i><\/sub><i>= 0<\/i><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-1842\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-2-300x70.png\" alt=\"Doppler effect \u2013 problems and solutions 2\" width=\"300\" height=\"70\" srcset=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-2-300x70.png 300w, https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-2.png 395w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Source moving toward the stationary observer<\/u><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\"><i>The source speed (v<sub>source<\/sub>) is negative if the source of the sound moving toward an observer<\/i><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\"><i>Observer at rest so <\/i><i>(<\/i><i>v<\/i><sub><i>obs<\/i><\/sub><i>) <\/i><i>= 0<\/i><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-1852\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-3-1-300x70.png\" alt=\"Doppler effect \u2013 problems and solutions 3\" width=\"300\" height=\"70\" srcset=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-3-1-300x70.png 300w, https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-3-1.png 392w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Observer and source approach each other<\/u><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\"><i>The observer speed (v<sub>obs<\/sub>) is positive if observer moving toward the source of the sound<\/i><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\"><i>The source speed (v<\/i><sub><i>s<\/i><i>ource<\/i><\/sub><i>) is negative if the source of the sound moving toward the observer<\/i><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-1844\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-4-300x76.png\" alt=\"Doppler effect \u2013 problems and solutions 4\" width=\"300\" height=\"76\" srcset=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-4-300x76.png 300w, https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-4.png 381w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Observer and source are moving at the same speed<\/u><\/span><\/p>\n<p class=\"western\" lang=\"en-US\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">If the source of the sound and observer moves at the same speed then no Doppler effect occurs.<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">2. An observer at rest near the source of the sound of frequency 684 Hz. Another the source of the sound of 676 Hz moving toward the observer at 2 n\/s. If the speed of the sound waves in air is 340 m\/s, then what is the beat frequency heard by the observer.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The frequency of the source of the sound 1 (f<sub>1<\/sub>) = 684 Hz (rest)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The frequency of the source of the sound 2 (f<sub>2<\/sub>) = 676 Hz (move)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of the source of the sound 2 (v<sub>2<\/sub>) = 2 m\/s (moving toward the observer)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of the source of the sound waves in air (v) = 340 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted:<\/u> The beat frequency heard by the observer<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The equation of the Doppler effect :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-1845\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-5.png\" alt=\"Doppler effect \u2013 problems and solutions 4\" width=\"138\" height=\"50\" \/><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">Sign rule :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The sound speed (v) always positive<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is positive if observer moving toward the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is negative if observer moving away from the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) is positive if the source of the sound moving away from the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) is negative if the source of the sound moving toward the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) = 0 if an observer at rest<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) = 0 if source at rest<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-1846\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-6.png\" alt=\"Doppler effect \u2013 problems and solutions 6\" width=\"131\" height=\"177\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The beat frequency heard by the observer = 684 Hz \u2013 680 Hz = 4 Hz.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">3. A source of sound moving toward the stationary observer at 20 m\/s. The frequency of the source of the sound = 380 Hz. The speed of the sound <a href=\"https:\/\/gurumuda.net\/physics\/speed-of-the-mechanical-waves-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">waves<\/a> in air = 400 m s<sup>-1<\/sup>. What is the frequency of the sound waves heard by the observer?<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of the source of the sound (v<sub>source<\/sub>) = 20 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of observer (v<sub>p<\/sub>) = 0<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The frequency of the source of the sound (f) = 380 Hz<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of the source of the sound waves (v) = 400 m s<sup>-1<\/sup> <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted:<\/u> The frequency of the sound waves heard by the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-1847\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-7-300x43.png\" alt=\"Doppler effect \u2013 problems and solutions 7\" width=\"300\" height=\"43\" srcset=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-7-300x43.png 300w, https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-7.png 365w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">4. Car A moves at 72 km\/h and car B moves at 90 km\/h, approach each other. Car A honked with a frequency of 650 Hz. If the speed of the sound waves in air is 350 m\/s, then what is the frequency of sound heard by the driver of car B from car A.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of car A (v<sub>A<\/sub>) = 72 km\/h = 20 m\/s, approach car B<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of car B (v<sub>B<\/sub>) = 90 km\/h = 25 m\/s, approach car A<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The frequency of the sound of car A (f<sub>A<\/sub>) = 650 Hz <\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of the sound waves in air (v) = 350 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Wanted: Frequency of sound heard by the driver of the car B from car A<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The sound speed (v) always positive<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is positive if observer moving toward the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is negative if the observer moving away from the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) is positive if the source of the sound moving away from the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><span style=\"color: #000000;\">The source speed (v<sub>source<\/sub>) is negative if the source <\/span>of the sound moving toward the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) = 0 if an observer at rest<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) = 0 if source at rest<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-1848\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-8-300x90.png\" alt=\"Doppler effect \u2013 problems and solutions 8\" width=\"300\" height=\"90\" srcset=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-8-300x90.png 300w, https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-8.png 306w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">5. A source of sound moves at 10 m\/s approach a stationary observer. The frequency of the source of the sound is 380 Hz and the speed of the sound waves in air is 400 m\/s What is the frequency of the sound waves heard by the observer.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of the source of the sound (v<sub>s<\/sub>) = 20 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of observer (v<sub>p<\/sub>) = 0<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The frequency of the source of the sound (f) = 380 Hz<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of the sound waves in air (v) = 400 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted:<\/u> The frequency of the sound waves heard by the observer<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The sound speed (v) always positive<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is positive if observer moving toward the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is negative if the observer moving away from the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) is positive if the source of the sound moving away from observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) is negative if the source of the sound moving toward the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) = 0 if an observer at rest<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) = 0 if source at rest<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-1849\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-9.png\" alt=\"Doppler effect \u2013 problems and solutions 9\" width=\"215\" height=\"150\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">6. A car moving toward a stationary observer that emits 490 Hz sound wave. The beat frequency heard is 10 Hz. If the speed of the sound waves in air is 340 m\/s, what is the speed of the car?<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The frequency of sound (f) = 490 Hertz<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of the sound waves in air (v) = 340 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><span lang=\"en-US\">The <\/span><span lang=\"en-US\">observer <\/span><span lang=\"en-US\">approaches the sound source so that <\/span><span lang=\"en-US\">the frequency of sound heard is <\/span><span lang=\"en-US\">greater than the frequency of the sound source. The frequency of sound <\/span><span lang=\"en-US\">= <\/span>490 Hertz and the beat frequency = 10 Hertz so that the frequency of the sound heard by an observer (f&#8217;) = 500 Hertz.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Wanted:<\/u> the speed of the car<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The equation of the Doppler effect :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-1850\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-10.png\" alt=\"Doppler effect \u2013 problems and solutions 10\" width=\"138\" height=\"50\" \/><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">Sign rule :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The sound speed (v) always positive<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is positive if observer moving toward the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is negative if the observer moving away from the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) is positive if the source of the sound moving away from the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) is negative if the source of the sound moving toward the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) = 0 if an observer at rest<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) = 0 if source at rest<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-1851\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-11-274x300.png\" alt=\"Doppler effect \u2013 problems and solutions 11\" width=\"274\" height=\"300\" srcset=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-11-274x300.png 274w, https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/sites\/28\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-11.png 322w\" sizes=\"auto, (max-width: 274px) 100vw, 274px\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The speed of the car is 6.9 m\/s.<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">7. The police car that was ringing a 930 Hz siren chased after someone who ran away on a motorcycle with a speed of 72 km.jam<sup>-1<\/sup>. The speed of police cars reaches 108 km.hour<sup>-1<\/sup>. If the speed of sound in the air is 340 m.s-1, then the frequency of siren sounds heard by motorcyclists is &#8230;<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">Solution :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">Sign rule :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The sound speed (v) always positive<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is positive if observer moving toward the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) is negative if the observer moving away from the source of the sound<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) is positive if the source of the sound moving away from the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) is negative if the source of the sound moving toward the observer<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The observer speed (v<sub>obs<\/sub>) = 0 if an observer at rest<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The source speed (v<sub>source<\/sub>) = 0 if source at rest<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The frequency of the source of sound (f) = 930 Hz<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">The speed of observer (v<sub>p<\/sub>) = 72 km.hour<sup>-1<\/sup> = 72 (1000 meters) \/ 3600 (seconds) = 72,000\/3600 meters\/second = 20 m\/s = -20 m.s<sup>-1<\/sup><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">The speed of the source of sound (v<sub>source<\/sub>) = 108 km.hour<sup>-1 <\/sup>= 108 (1000 meters) \/ (3600 seconds) = 108,000 \/ 3600 meters\/second = 30 m\/s = -30 m.s<sup>-1<\/sup><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">The speed of the source of the sound waves (v) = 340 m.s<sup>-1<\/sup><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><u>Wanted :<\/u> The frequency of the sound waves heard by an observer (f\u2019)<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The equation of the Doppler effect :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-2744\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-1-1.png\" alt=\"Doppler effect \u2013 problems and solutions 1\" width=\"138\" height=\"236\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">8. An ambulance moves at 72 km.hour<sup>-1<\/sup> while sounding a siren with a frequency of 1500 Hz. Motorcyclists move at speeds of 20 m.s<sup>-1<\/sup> in opposite directions with ambulances. If the speed of sound in air is 340 m.s<sup>-1<\/sup>, then the ratio of frequencies heard by motorcyclists when approaching and away from the ambulance is &#8230;<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Known :<\/u><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\">The frequency of the source of sound (f) = 1500 Hz<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">The speed of observer (v<sub>p<\/sub>) = 20 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">The speed of the source of sound (v<sub>source<\/sub>) = 72 km\/hour = 72 (1000 meters) \/ 3600 seconds = 72,000\/3600 meters\/seconds = 20 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\">The speed of the source of the sound waves (v) = 340 m\/s<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><u>Wanted:<\/u> The ratio of frequencies heard by motorcyclists when approaching and away from the ambulance<\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><u>Solution :<\/u><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"color: #000000; font-size: 12pt; font-family: 'times new roman', times, serif;\">The equation of the Doppler effect :<\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-2745\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-2-1.png\" alt=\"Doppler effect \u2013 problems and solutions 2\" width=\"105\" height=\"48\" \/><\/span><\/p>\n<p class=\"western\" lang=\"en-US\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><b>Frequencies heard by motorcyclists approaching ambulances<\/b><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><span lang=\"en-US\"><i>Both are in opposite directions so that when the motorcycle approaches the ambulance car, the two approach each other. v<\/i><\/span><sub><span lang=\"en-US\"><i>p <\/i><\/span><\/sub><span lang=\"en-US\"><i>is positive if the listener approaches the sound source and v<\/i><\/span><sub><span lang=\"en-US\"><i>s <\/i><\/span><\/sub><span lang=\"en-US\"><i>is <\/i><\/span><span lang=\"en-US\"><i>negative if the sound source approaches the listener.<\/i><\/span><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-2746\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-3-2.png\" alt=\"Doppler effect \u2013 problems and solutions 3\" width=\"218\" height=\"90\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><b><span lang=\"en-US\">Frequencies are heard by motorcyclists as they move away from the ambulance<\/span><\/b><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-family: 'times new roman', times, serif; font-size: 12pt;\"><i><span lang=\"en-US\">Both are opposite direction so that when the motorcycle away from the ambulance, both of them away from each other. v<\/span><sub><span lang=\"en-US\">p <\/span><\/sub><span lang=\"en-US\">is negative if the listener is away from the sound source and v<\/span><sub><span lang=\"en-US\">s<\/span><\/sub> <span lang=\"en-US\">is <\/span><span lang=\"en-US\">positive if the sound source is away from the listener.<\/span><\/i><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-2747\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-4-1.png\" alt=\"Doppler effect \u2013 problems and solutions 4\" width=\"220\" height=\"90\" \/><\/span><\/p>\n<p class=\"western\" style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><b>T<\/b><b>he ratio of frequencies heard by motorcyclists when approaching and away from the ambulance<\/b><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-2748\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/04\/Doppler-effect-\u2013-problems-and-solutions-5-1.png\" alt=\"Doppler effect \u2013 problems and solutions 5\" width=\"179\" height=\"210\" \/><\/span><\/p>\n<p style=\"text-align: justify;\" align=\"justify\">\n<ol style=\"text-align: justify;\">\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>What is the Doppler effect?<\/strong><\/span>\n<ul>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Answer:<\/strong> The Doppler effect describes the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source.<\/span><\/li>\n<\/ul>\n<\/li>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>How does the Doppler effect manifest in sound waves?<\/strong><\/span>\n<ul>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Answer:<\/strong> When a sound source approaches an observer, the observer perceives a higher frequency (or pitch) than when the source is stationary. Conversely, as the sound source moves away from the observer, the perceived frequency is lower.<\/span><\/li>\n<\/ul>\n<\/li>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>What is the difference between redshift and blueshift in terms of the Doppler effect?<\/strong><\/span>\n<ul>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Answer:<\/strong> In terms of electromagnetic waves (like light), redshift refers to the shift of light towards longer wavelengths (or lower frequencies) when a source is moving away from an observer. Blueshift, on the other hand, refers to the shift of light towards shorter wavelengths (or higher frequencies) when the source is moving towards the observer.<\/span><\/li>\n<\/ul>\n<\/li>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>How does the Doppler effect apply to galaxies and their movement in the universe?<\/strong><\/span>\n<ul>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Answer:<\/strong> Many galaxies exhibit redshift, indicating they are moving away from us. This observation forms a key piece of evidence for the expansion of the universe.<\/span><\/li>\n<\/ul>\n<\/li>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>What role does the Doppler effect play in weather radar technology?<\/strong><\/span>\n<ul>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Answer:<\/strong> Doppler radar measures the change in frequency of the reflected radar signal caused by moving objects, like raindrops or hailstones. This allows meteorologists to detect the motion of precipitation and gauge wind speed and direction.<\/span><\/li>\n<\/ul>\n<\/li>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Is the Doppler effect observed only in sound and light waves?<\/strong><\/span>\n<ul>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Answer:<\/strong> No, the Doppler effect can be observed in any type of wave, be it sound, light, or other electromagnetic radiation. It simply requires relative motion between the source and the observer.<\/span><\/li>\n<\/ul>\n<\/li>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>How does the relative speed between the source and the observer affect the magnitude of the Doppler effect?<\/strong><\/span>\n<ul>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Answer:<\/strong> The greater the relative speed between the source and the observer, the more pronounced the Doppler shift. For instance, a fast-moving ambulance will produce a more noticeable change in pitch as it passes by compared to a slowly moving one.<\/span><\/li>\n<\/ul>\n<\/li>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Why do we not notice a Doppler shift in the light of a car&#8217;s headlights as it approaches us at night?<\/strong><\/span>\n<ul>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Answer:<\/strong> While the Doppler effect does occur for the car&#8217;s headlights, the speed of the car is much too small compared to the speed of light. Hence, the Doppler shift in frequency\/wavelength of the light is minuscule and not detectable by the human eye.<\/span><\/li>\n<\/ul>\n<\/li>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>How do animals like bats utilize the Doppler effect?<\/strong><\/span>\n<ul>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Answer:<\/strong> Bats use echolocation, emitting sound waves and listening to the echoes to locate and catch prey. The Doppler effect plays a role when the bat or its prey is moving, causing a shift in the frequency of the echoed sound waves, which the bat can detect and use to judge motion and distance.<\/span><\/li>\n<\/ul>\n<\/li>\n<li><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>How does the Doppler effect relate to the siren of an emergency vehicle?<\/strong><\/span><\/li>\n<\/ol>\n<ul>\n<li style=\"text-align: justify;\"><span style=\"font-size: 12pt; font-family: 'times new roman', times, serif;\"><strong>Answer:<\/strong> As an emergency vehicle with a siren approaches, the sound waves get compressed, leading to a higher frequency or pitch. As the vehicle passes and moves away, the sound waves get stretched, resulting in a lower frequency or pitch. This is the Doppler effect in action, and it&#8217;s why the siren sounds different as the vehicle approaches and then recedes.<\/span><\/li>\n<\/ul>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"<p>Doppler effect \u2013 problems and solutions 1. (1) an observer moving toward the stationery source (2) source moving toward the stationary observer (3) observer and source approach each other (4) observer and source are moving at the same speed If the pitch heard is higher than that of the emitted source frequency, then which statement &#8230; <a title=\"Doppler effect \u2013 problems and solutions\" class=\"read-more\" href=\"https:\/\/gurumuda.net\/physics\/doppler-effect-problems-and-solutions.htm\" aria-label=\"Read more about Doppler effect \u2013 problems and solutions\">Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Doppler effect \u2013 problems and solutions","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[3],"tags":[],"class_list":["post-1840","post","type-post","status-publish","format-standard","hentry","category-solved-problems-in-basic-physics"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/1840","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=1840"}],"version-history":[{"count":2,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/1840\/revisions"}],"predecessor-version":[{"id":8697,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/1840\/revisions\/8697"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=1840"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=1840"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=1840"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}