{"id":1716,"date":"2018-04-04T13:00:48","date_gmt":"2018-04-04T05:00:48","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=1716"},"modified":"2023-08-10T00:11:20","modified_gmt":"2023-08-10T00:11:20","slug":"pressure-of-solids-problems-and-solutions","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/pressure-of-solids-problems-and-solutions.htm","title":{"rendered":"Pressure of solids \u2013 problems and solutions","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"

Pressure of solids \u2013 problems and solutions<\/span><\/p>\n

1. Mass<\/a> and volume of four blocks below are same. Which is the smaller pressure<\/a> exerted by block on the floor?<\/span><\/p>\n

\"PressureSolution<\/span><\/p>\n

P = F \/ A <\/span><\/p>\n

Based on this formula it is concluded that pressure (P) is directly proportional to force (F) and inversely proportional to surface area (A).<\/span><\/p>\n

The larger the force, the larger the pressure. The larger the surface area, the smaller the pressure.<\/span><\/p>\n

Based on the picture, the largest surface area in contact with the floor is object III, so the pressure of object III on the floor is the smallest <\/span><\/p>\n

2. If the mass of the four triangles below is the same, the greatest pressure on the floor is shown by the image …<\/span><\/span><\/p>\n

Solution\"Pressure<\/span><\/p>\n

P = F \/ A = w \/ A<\/span><\/p>\n

P = <\/i>pressure<\/i>, F = <\/i>force<\/i>, w = <\/i>weight<\/i><\/a>, A = <\/i>surface area<\/i><\/span><\/p>\n

Based on this formula it is concluded that pressure (P) is directly proportional to force (F) and inversely proportional to surface area (A).<\/span><\/p>\n

The larger the force, the <\/span>larger <\/span>the pressure. The larger the surface area, the smaller the pressure.<\/span><\/span><\/p>\n

The smallest surface area has the greatest pressure.<\/span><\/p>\n

3. The greatest pressure is shown by image …<\/span><\/span><\/p>\n

Solution\"Pressure<\/span><\/p>\n

P = F \/ A = w \/ A<\/span><\/p>\n

P = <\/i>pressure<\/i>, F = <\/i>force<\/i>, w = <\/i>weight<\/i>, A = <\/i>surface area<\/i><\/span><\/p>\n

Based on this formula it is concluded that pressure (P) is directly proportional to force (F) and inversely proportional to surface area (A).<\/span><\/p>\n

The larger the force, the <\/span>larger <\/span>the pressure. The larger the surface area, the smaller the pressure.<\/span><\/span><\/p>\n

The smallest surface area has the greatest pressure.<\/span><\/p>\n

4. The force of 500 Newton works on a surface of 2.5 m<\/span>2<\/span><\/sup>. <\/span>Determine <\/span>pressur<\/span>e.<\/span><\/span><\/p>\n

Known :<\/u><\/span><\/p>\n

Force (F) = 500 Newton<\/span><\/p>\n

Surface area (A) = 2.5 m2<\/sup><\/span><\/p>\n

Wanted :<\/u> Pressure (P)<\/span><\/p>\n

Solution :<\/u><\/span><\/p>\n

Pressure (P) :<\/span><\/p>\n

P = F \/ A <\/span><\/p>\n

P = 500 \/ 2.5 <\/span><\/p>\n

P = 200 N\/m2<\/sup><\/span><\/p>\n

P = 200 Pascal<\/span><\/p>\n

5. Mass of a box = 75 kg and acceleration due to gravity<\/a> (g) = 10 m\/s2<\/sup>. Determine the pressure on the floor.<\/span><\/p>\n

Known :\"Pressure<\/u><\/span><\/p>\n

Mass (m) = 75 kg<\/span><\/p>\n

Acceleration due to gravity (g) = 10 m\/s2<\/sup><\/span><\/p>\n

Weight (w) = m g = (75 kg)(10 m\/s2<\/sup>) = 750 kg m\/s2<\/sup> = 750 Newton <\/span><\/p>\n

Surface area (A) = 6 meters x 5 meters= 30 m2<\/sup><\/span><\/p>\n

Wanted :<\/u> Pressure on the floor<\/span><\/p>\n

Solution :<\/u><\/span><\/p>\n

P = F\/A = w\/A = 750\/30 = 25 N\/m2<\/sup><\/span><\/p>\n

6. Mass of a box is 24 kg. Acceleration due to gravity is 10 m\/s2<\/sup>. Determine the pressure on the floor.<\/span><\/p>\n

Known :\"Pressure<\/u><\/span><\/p>\n

Mass (m) = 24 kg<\/span><\/p>\n

Acceleration due to gravity (g) = 10 m\/s2<\/sup> <\/span><\/p>\n

Weight (w) = m g = (24 kg)(10 m\/s2<\/sup>) = 240 kg m\/s2 <\/sup>= 240 Newton<\/span><\/p>\n

Surface area (A) = 1 m x 0.4 m = 0.4 m2<\/sup><\/span><\/p>\n

Wanted :<\/u> The pressure on the floor<\/span><\/p>\n

Solution :<\/u><\/span><\/p>\n

P = F \/ A = w \/ A<\/span><\/p>\n

P = <\/i>pressure<\/i>, F = <\/i>force<\/i>, w = <\/i>weight<\/i>, A = <\/i>surface area<\/i><\/span><\/p>\n

Pressure on the floor :<\/span><\/p>\n

P = 240 N \/ 0.4 m2<\/sup> = 600 N\/m2<\/sup><\/span><\/p>\n

    \n
  1. What is pressure in the context of solids?<\/strong><\/span>\n