{"id":1619,"date":"2018-03-23T17:37:11","date_gmt":"2018-03-23T09:37:11","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=1619"},"modified":"2023-08-10T00:50:02","modified_gmt":"2023-08-10T00:50:02","slug":"transverse-and-longitudinal-waves-problems-and-solutions","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/transverse-and-longitudinal-waves-problems-and-solutions.htm","title":{"rendered":"Transverse and longitudinal waves \u2013 problems and solutions","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"

Transverse and longitudinal waves \u2013 problems and solutions<\/span><\/p>\n

1. A wave<\/a> is traveling down a 3-m long wire for 0.3 seconds. What is the period of the wave? <\/span><\/p>\n

\"TransverseKnown :<\/u><\/span><\/p>\n

Time interval (t) = 0.3 seconds<\/span><\/p>\n

Wanted :<\/u> Period (T)<\/span><\/p>\n

Solution :<\/u><\/span><\/p>\n

1 wavelength<\/a> = 1 crests + 1 troughs<\/span><\/p>\n

Period = 2 x 0.1 second = 0.2 seconds<\/span><\/p>\n

2. The wave speed according to figure below is…<\/span><\/p>\n

\"Transverse<\/span><\/p>\n

Known :<\/u><\/span><\/p>\n

1 wavelength has 1 crests and 1 troughs. According to figure above, 1 wavelength = 2 meters x 4 = 8 meters.<\/span><\/span><\/p>\n

Periode of wave (T) = 0.5 x 4 = 2 seconds<\/span><\/p>\n

Wanted :<\/u> The wave speed (v)<\/span><\/p>\n

Solution :<\/u><\/span><\/p>\n

The wave speed :<\/span><\/p>\n

v = s \/ t = \u03bb \/ T = 8 meters \/ 2 seconds = 4 meters\/second<\/span><\/p>\n

3. The distance between point A and B is 30 cm. What is the wave speed according to figure below.<\/span><\/p>\n

Known :\"Transverse
\n<\/u><\/span><\/p>\n

From A to B, there is \u00be wavelength. If the distance between A and B is 30 cm, then the distance of \u00bc wavelength is 30 cm \/ 3 = 10 cm. Thus, 1 wavelength = 4 x 10 cm = 40 cm.<\/span><\/p>\n

According to the figure above, a period of the wave is 4 seconds.<\/span><\/p>\n

Wanted :<\/u> The wave speed<\/a> (v)<\/span><\/p>\n

Solution :<\/u><\/span><\/p>\n

v = d \/ t = \u03bb \/ t<\/span><\/p>\n

v = the wave speed, d = distance, \u03bb = wavelength, t = time interval<\/i><\/span><\/p>\n

The wave speed :<\/span><\/p>\n

v = \u03bb \/ t = 40 cm \/ 4 seconds = 10 cm \/ 1 second = 10 cm\/second<\/span><\/p>\n

4. If the distance of A and B = 250 cm, then the wave speed is…<\/span><\/p>\n

Known :\"Transverse<\/u><\/span><\/p>\n

Distance of A and B = 5\/4 wavelength = 250 cm. <\/span><\/p>\n

1\/4 wavelength = 250 cm \/ 5 = 50 cm<\/span><\/p>\n

1 wavelength = 4\/4 wavelength = 4 x 50 cm = 200 cm <\/span><\/p>\n

Period (T) = 2 seconds<\/span><\/p>\n

Wanted :<\/u> The wave speed <\/span><\/p>\n

Solution :<\/u><\/span><\/p>\n

Formula of the wave speed :<\/span><\/p>\n

v = d \/ t = \u03bb \/ t <\/span><\/p>\n

v = the wave speed, d = distance \u03bb = wavelength, t = time interval<\/i><\/span><\/p>\n

The wave speed :<\/span><\/p>\n

v = 200 cm \/ 2 seconds = 100 cm\/second<\/span><\/p>\n

5. Amplitude of wave are shown by….\"Transverse<\/span><\/p>\n

Solution :<\/span><\/p>\n

The amplitude of the wave is BB’ and DD”.<\/span><\/p>\n

    \n
  1. What distinguishes a transverse wave from a longitudinal wave in terms of particle motion?<\/strong><\/span>\n