{"id":1371,"date":"2018-03-05T10:49:09","date_gmt":"2018-03-05T02:49:09","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=1371"},"modified":"2018-03-05T10:49:09","modified_gmt":"2018-03-05T02:49:09","slug":"electric-potential-energy-problems-and-solutions","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/electric-potential-energy-problems-and-solutions.htm","title":{"rendered":"Electric potential energy \u2013 problems and solutions","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"

1. An electron is accelerated from rest through a potential difference 12 V. What is the change in electric potential energy<\/a> of the electron?<\/span><\/span><\/p>\n

\"ElectricKnown :<\/u><\/span><\/span><\/p>\n

The charge<\/a> on an electron (e) = -1.60 x 10-19<\/sup> Coulomb<\/span><\/span><\/p>\n

Electric potential<\/a> = voltage<\/a> (V) = 12 Volt <\/span><\/span><\/p>\n

Wanted:<\/u> The change in electric potential energy of the electron (\u0394PE)<\/span><\/span><\/p>\n

Solution :<\/u><\/span><\/span><\/p>\n

\u0394PE = q V = (-1.60 x 10-19<\/sup> C)(12 V) = -19.2 x 10-19<\/sup> Joule <\/span><\/span><\/p>\n

The minus sign indicates that the potential energy decreases. <\/span><\/span><\/p>\n

<\/p>\n

2. Two parallel plates are charged. The separation between the plates is 2 cm and the magnitude of the electric field<\/a> between the plates is 500 Volt\/meter. What is the change in potential energy of the proton when accelerated from the positively charged plate to the negatively charged plate. <\/span><\/span><\/p>\n

\"ElectricKnown :<\/u><\/span><\/span><\/p>\n

The magnitude of the electric field between the plates (E) = 500 Volt\/meter <\/span><\/span><\/p>\n

The distance<\/a> between the plates (s) = 2 cm = 0,02 m<\/span><\/span><\/p>\n

The charge on an proton = +1.60 x 10-19<\/sup> Coulomb<\/span><\/span><\/p>\n

Wanted :<\/u> The change in electric potential energy (\u0394PE) <\/span><\/span><\/p>\n

Solution :<\/u><\/span><\/span><\/p>\n

Electric potential :<\/span><\/span><\/p>\n

V = E s <\/span><\/span><\/p>\n

V = (500 Volt\/m)(0.02 m)<\/span><\/span><\/p>\n

V = 10 Volt<\/span><\/span><\/p>\n

The change in electric potential energy :<\/span><\/span><\/p>\n

\u0394PE = q V <\/span><\/span><\/p>\n

\u0394PE = (1,60 x 10-19<\/sup> C)(10 V)<\/span><\/span><\/p>\n

\u0394PE = 16 x 10-19 <\/sup>Joule<\/span><\/span><\/p>\n

\u0394PE = 1.6 x 10-1<\/sup>8<\/sup> Joule<\/span><\/span><\/p>\n

<\/p>\n

3. Two point charges are separated by a distance of 10 cm. Charge on point A =+9 \u03bcC <\/span>and charge on point B = <\/span>-4 \u03bcC. k = 9 x 10<\/span>9 <\/sup><\/span>Nm<\/span>2<\/sup><\/span>C<\/span>\u22122<\/sup><\/span>, 1 \u03bcC = 10<\/span>\u22126<\/sup><\/span> C. <\/span>What is the change in electric potential energy of charge on point B if accelerated to point A ? <\/span> <\/span><\/span><\/p>\n

\"Electric<\/p>\n

Known :<\/u><\/span><\/span><\/p>\n

Charge A (q1<\/sub>) = +9 \u03bcC = +9 <\/span>x <\/span>10<\/span>\u22126<\/sup><\/span> C<\/span> <\/span><\/span><\/p>\n

Charge <\/span>B<\/span> (q<\/span>1<\/sub><\/span>) = -4 \u03bcC = -4 <\/span>x <\/span>10<\/span>\u22126<\/sup><\/span> C<\/span> <\/span><\/span><\/p>\n

k = 9 x 10<\/span>9<\/sup><\/span> Nm<\/span>2<\/sup><\/span>C<\/span>\u22122<\/sup><\/span><\/span><\/span><\/p>\n

The distance between charge A and B (r) = 10 cm = 0.1 m = 10-1 <\/sup>m<\/span><\/span><\/p>\n

Wanted :<\/u> The change in electric potential energy (\u0394EP)<\/span><\/span><\/p>\n

Solution :<\/u><\/span><\/span><\/p>\n

\"Electric<\/p>\n

<\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"

1. An electron is accelerated from rest through a potential difference 12 V. What is the change in electric potential energy of the electron? Known : The charge on an electron (e) = -1.60 x 10-19 Coulomb Electric potential = voltage (V) = 12 Volt Wanted: The change in electric potential energy of the electron … Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Electric potential energy \u2013 problems and solutions","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[3],"tags":[],"class_list":["post-1371","post","type-post","status-publish","format-standard","hentry","category-solved-problems-in-basic-physics"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/1371","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=1371"}],"version-history":[{"count":0,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/1371\/revisions"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=1371"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=1371"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=1371"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}