{"id":1281,"date":"2018-02-28T17:28:36","date_gmt":"2018-02-28T09:28:36","guid":{"rendered":"https:\/\/gurumuda.net\/physics\/?p=1281"},"modified":"2018-02-28T17:28:36","modified_gmt":"2018-02-28T09:28:36","slug":"rotational-dynamics-problems-and-solutions","status":"publish","type":"post","link":"https:\/\/gurumuda.net\/physics\/rotational-dynamics-problems-and-solutions.htm","title":{"rendered":"Rotational dynamics \u2013 problems and solutions","gt_translate_keys":[{"key":"rendered","format":"text"}]},"content":{"rendered":"<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">1. A force F applied to a cord wrapped around a cylinder pulley. The <a href=\"https:\/\/gurumuda.net\/physics\/the-magnitude-of-net-torque-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">torque<\/a> is <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">N m and the <a href=\"https:\/\/gurumuda.net\/physics\/moment-of-inertia-particles-and-rigid-body-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">moment of inertia<\/a> is <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">1 kg <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">m<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">,<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"> what is the <a href=\"https:\/\/gurumuda.net\/physics\/angular-acceleration-and-linear-acceleration-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">angular acceleration<\/a> of the cylinder. <\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u><img loading=\"lazy\" decoding=\"async\" class=\"alignleft size-full wp-image-1282\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/02\/Rotational-dynamics-\u2013-problems-and-solutions-1.png\" alt=\"Rotational dynamics \u2013 problems and solutions 1\" width=\"157\" height=\"109\" \/>Known :<\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Torque (<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03c4<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">) = 2 N m<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">The moment of inertia (I) = <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">1 kg m<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u>Wanted:<\/u><\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"> The angular acceleration of the cylinder<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u>Solution :<\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03a3\u03c4<\/span><\/span> <span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= I <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03b1<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><i>\u03a3\u03c4 <\/i><\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><i>= net torque, I = moment of inertia, <\/i><\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><i>\u03b1 = angular acceleration<\/i><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Angular acceleration of cylinder :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03b1 = \u03a3\u03c4 \/ I = 2 \/ 1 = 2 rad\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p align=\"justify\"><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2. A force F applied to a cord wrapped around a cylinder pulley. The magnitude of the force is 10 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">N, the radius of the cylinder is 0.2 m and the moment of inertia is <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">1 kg <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">m<\/span><\/span>2,<span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"> W<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">hat is the angular acceleration of the cylinder?<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u><img loading=\"lazy\" decoding=\"async\" class=\"alignleft size-full wp-image-1283\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/02\/Rotational-dynamics-\u2013-problems-and-solutions-2.png\" alt=\"Rotational dynamics \u2013 problems and solutions 2\" width=\"154\" height=\"107\" \/>Known :<\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Force (F) = 10 N<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Radius of cylinder (R) = 0.2 m<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">The moment of inertia (I) = <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">1 kg m<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u>Wanted:<\/u><\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"> The angular acceleration of the cylinder.<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u>Solution :<\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03c4<\/span><\/span> <span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= F R <\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><i>\u03c4<\/i><\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><i> = torque, F = force, R = radius of cylinder<\/i><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Torque :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03c4 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= F R = (1<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">0 N)(0.2 m) = 2 N m<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03a3\u03c4<\/span><\/span> <span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= I <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03b1<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><i>\u03a3\u03c4 <\/i><\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><i>= net torque, I = moment of inertia, <\/i><\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><i>\u03b1 = angular acceleration<\/i><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Angular acceleration of cylinder :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03b1 = \u03a3\u03c4 \/ I = <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2 \/ 1 = 2 rad\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p align=\"justify\"><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">3. A force F applied to a cord wrapped around a cylinder pulley. The magnitude of force is 10 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">N, the radius of cylinder is 0.2 m and the mass of cylinder is 20 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">kg <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">m<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2,<\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">. W<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">hat is the angular acceleration of the cylinder.<\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u><img loading=\"lazy\" decoding=\"async\" class=\"alignleft size-full wp-image-1284\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/02\/Rotational-dynamics-\u2013-problems-and-solutions-3.png\" alt=\"Rotational dynamics \u2013 problems and solutions 3\" width=\"156\" height=\"107\" \/>Known :<\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Force (F) = 10 N<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Radius of cylinder (R) = 0.2 m<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Mass of cylinder (M) = 2<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">0 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">kg<\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u>Wanted :<\/u><\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"> Angular acceleration of cylinder<\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u>Solution :<\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03c4 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= F R = (1<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">0 N)(0.2 m) = 2 N m<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Moment of inertia :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">I = 1\u20442 M R<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2 <\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= 1\u20442 (20)(0.2)<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2 <\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= 1\u20442 (20)(0.04) = 0.4 kg m<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Angular acceleration of cylinder :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03b1 = \u03a3\u03c4 \/ I = <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2 \/ <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">0.4 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= 5 rad\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p align=\"justify\"><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">4. A 1-kg block hanging from a cord wrapped around a cylinder pulley. The moment of inertia of pulley is 1 kg <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">m<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"> and the radius of pulley is 0.2 m. What is the angular acceleration of the pulley. <a href=\"https:\/\/gurumuda.net\/physics\/acceleration-due-to-gravity-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">Acceleration due to gravity<\/a> is 10 m\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">. <\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u><img loading=\"lazy\" decoding=\"async\" class=\"alignleft size-full wp-image-1285\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/02\/Rotational-dynamics-\u2013-problems-and-solutions-4.png\" alt=\"Rotational dynamics \u2013 problems and solutions 4\" width=\"108\" height=\"175\" \/>Known :<\/u><\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Moment of inertia of pulley (I) = 1 kg m<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2 <\/span><\/span><\/sup><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><a href=\"https:\/\/gurumuda.net\/physics\/mass-and-weight-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">Mass<\/a> of block (m) = 1 kg<\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Acceleration due to gravity (g) = 10 m\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><a href=\"https:\/\/gurumuda.net\/physics\/gravitational-force-weight-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">Weight<\/a> (w) = m g = (1 kg)(10 m\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">) = 10 kg m\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"> = 10 N<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Radius of pulley (R) = 0.2 m<\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u>Wanted :<\/u><\/span><\/span> <span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Angular acceleration<\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u>Solution :<\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Torque :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03c4 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= F R = w R = (1<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">0 N)(0.2 m) = 2 N m<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Moment of inertia :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">I = 1 kg m<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Angular acceleration :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03b1 = \u03a3\u03c4 \/ I = <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2 \/ 1<\/span><\/span> <span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= 2 rad\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p align=\"justify\"><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">5. A 1-kg block hanging from a cord wrapped around a cylinder pulley. The mass of pulley is 20 kg <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">and the radius of pulley is 0,2 m. What is the angular acceleration of the pulley and the <a href=\"https:\/\/gurumuda.net\/physics\/free-fall-motion-problems-and-solutions.htm\" target=\"_blank\" rel=\"noopener\">free fall<\/a> acceleration of the block. Acceleration due to gravity is 10 m\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">.<\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u><img loading=\"lazy\" decoding=\"async\" class=\"alignleft size-full wp-image-1286\" src=\"https:\/\/gurumuda.net\/physics\/wp-content\/uploads\/2018\/02\/Rotational-dynamics-\u2013-problems-and-solutions-5.png\" alt=\"Rotational dynamics \u2013 problems and solutions 5\" width=\"106\" height=\"178\" \/>Known :<\/u><\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Mass of pulley (M) = 2<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">0 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">kg<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Radius of pulley (R) = 0,2 m<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Mass of block (m) = 1 kg<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Acceleration due to gravity (g) = 10 m\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">Weight (w) = m g = (1 kg)(10 m\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">) = 10 kg m\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"> = 10 N<\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u>Wanted :<\/u><\/span><\/span> <span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"> the angular acceleration of the pulley and the free fall acceleration of the block.<\/span><\/span><\/p>\n<p class=\"western\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"><u>Solution :<\/u><\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">The torque :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03c4 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= F R = w R = (1<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">0 N)(0.2 m) = 2 N m<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">The moment of inertia of cylinder pulley :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">I = 1\u20442 M R<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2 <\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= 1\u20442 (20)(0.2)<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2 <\/span><\/span><\/sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= (10)(0.04) = 0.4 kg m<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">The angular acceleration of the pulley :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">\u03b1 = \u03a3\u03c4 \/ I = 2<\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\"> \/ <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">0.4 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">= 5 <\/span><\/span><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">rad\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">The free fall acceleration of the block :<\/span><\/span><\/p>\n<p class=\"western\" align=\"justify\"><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">a = R \u03b1 = (0.2)(5) = 1 m\/s<\/span><\/span><sup><span style=\"font-family: Times new roman,serif\"><span style=\"font-size: medium\">2<\/span><\/span><\/sup><!--more--><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"excerpt":{"rendered":"<p>1. A force F applied to a cord wrapped around a cylinder pulley. The torque is 2 N m and the moment of inertia is 1 kg m2, what is the angular acceleration of the cylinder. Known : Torque (\u03c4) = 2 N m The moment of inertia (I) = 1 kg m2 Wanted: The &#8230; <a title=\"Rotational dynamics \u2013 problems and solutions\" class=\"read-more\" href=\"https:\/\/gurumuda.net\/physics\/rotational-dynamics-problems-and-solutions.htm\" aria-label=\"Read more about Rotational dynamics \u2013 problems and solutions\">Read more<\/a><\/p>\n","protected":false,"gt_translate_keys":[{"key":"rendered","format":"html"}]},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","_seopress_robots_follow":"","_seopress_robots_imageindex":"","_seopress_robots_snippet":"","_seopress_robots_primary_cat":"","_seopress_robots_breadcrumbs":"","_seopress_robots_freeze_modified_date":"","_seopress_robots_custom_modified_date":"","_seopress_robots_canonical":"","_seopress_social_fb_title":"","_seopress_social_fb_desc":"","_seopress_social_fb_img":"","_seopress_social_fb_img_attachment_id":0,"_seopress_social_fb_img_width":0,"_seopress_social_fb_img_height":0,"_seopress_social_twitter_title":"","_seopress_social_twitter_desc":"","_seopress_social_twitter_img":"","_seopress_social_twitter_img_attachment_id":0,"_seopress_social_twitter_img_width":0,"_seopress_social_twitter_img_height":0,"_seopress_redirections_value":"","_seopress_redirections_enabled":"","_seopress_redirections_enabled_regex":"","_seopress_redirections_logged_status":"","_seopress_redirections_param":"","_seopress_redirections_type":0,"_seopress_analysis_target_kw":"Rotational dynamics \u2013 problems and solutions","_seopress_news_disabled":"","_seopress_video_disabled":"","_seopress_video":[],"_seopress_pro_schemas_manual":[],"_seopress_pro_rich_snippets_disable_all":"","_seopress_pro_rich_snippets_disable":[],"_seopress_pro_schemas":[],"footnotes":""},"categories":[3],"tags":[],"class_list":["post-1281","post","type-post","status-publish","format-standard","hentry","category-solved-problems-in-basic-physics"],"gt_translate_keys":[{"key":"link","format":"url"}],"_links":{"self":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/1281","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/comments?post=1281"}],"version-history":[{"count":0,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/posts\/1281\/revisions"}],"wp:attachment":[{"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/media?parent=1281"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/categories?post=1281"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gurumuda.net\/physics\/wp-json\/wp\/v2\/tags?post=1281"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}