Nkhani yokhudza Resistors mu mndandanda
Ngati zotsutsanazo zalumikizidwa monga momwe zasonyezedwera pachithunzichi, zotsutsanazo zimayikidwa motsatizana. Kukana kwa resistor kapena magetsi komwe kukubweraku kungakhale ngati zigawo za resistor, magetsi, kapena kukana kwina kwamagetsi.
Mphamvu yamagetsi imayenda kudzera mu kukana 1 (R)1) = ndi mtengo wamagetsi imayenda kudzera mu kukana 2 (R)2) = mphamvu yamagetsi imayenda kudzera mu kukana 3 (R)3). Zamagetsi zamagetsi (I) ndi mphamvu yamagetsi yomwe imayenda mkati mwa nthawi inayake (I = Q / t), motero mphamvu yamagetsi kudzera mu kukana 1 (I1) = mphamvu yamagetsi kudzera mu kukana 2 (I2) = mphamvu yamagetsi kudzera mu kukana 3 (I3Mwa masamu, mphamvu yonse yamagetsi (I) = I1 = Ine2 = Ine3.
Conversely, the electric voltage (V) decreases when the electric charge moves through each resistor. Electricity voltage also called an electric potential difference, is an electric potential energy per unit of electric charge. Electricity voltage is reduced because electricity is used in each electrical resistance. So, the total electrical voltage (V) is equal to the amount of electricity in each resistor. Mathematically, the total electric voltage (V) = V1 +V2 +V3. V = I R so the equation of the electric voltage is V = I R1 + IR2 + IR3. The electric current flowing on each resistor is equal so that this equation changes to V = I (R1 +R2 +R3).
Based on the above equation, it can be concluded that the total electrical resistance (R) or the equivalent resistance of the electrical resistance
which is connected in series is equal to the sum of each electrical resistance, mathematically R = R1 +R2 +R3. If there are only two resistors in series, the equivalent resistor (R) = R1 +R2. If there are four resistors in series, the equivalent resistor (R) = R1 +R2 +R3 +R4. Likewise, if there are five or more five resistors that are connected in series.
Sample problem 1:
If known, R1 = 2 Ω, R2 = 3 Ω ndi R3 = 4 Ω. All three resistors are connected in series. What is the value of the equivalent resistor? (Ω = Ahm).
yankho;
R = R1 +R2 +R3 = 2 + 3 + 4 = 9 Ω.
This result indicates that the equivalent resistance is greater than the value of the resistors connected in series.
Sample problem 2:
Two resistors R1 = 50 Ω and 50 Ω are connected in series and connected to a 12 Volt battery. Determine
(a) Kukana kofanana
(b) Mphamvu yamagetsi kudzera mu resistor iliyonse
yankho;
(a) R = R1 +R2 = 50 Ω + 50 Ω = 100 Ω.
(b) I = V / R = 12 Volt / 100 Ω = 0.12 A
