Zitsanzo 6 za mafunso okhudza kugwiritsa ntchito lamulo loyamba la thermodynamics pa njira za isobaric (kupanikizika kosalekeza)
1. Kupanikizika (P) - graph ya voliyumu (V) ya mpweya womwe ukudutsa mu njira ya isobaric. Ntchito yomwe mpweyawo ukugwira ntchito mu ndondomeko ya AB ndi…
Zokambirana
Ndizodziwika kuti :
Kupanikizika (P) = 5 x 105 N / m2
Voliyumu yoyamba (V)1) = 2 m3
Voliyumu yomaliza (V)2) = 6 m3
Anafunsa : ntchito yomwe yachitika mu ndondomeko AB
Yankhani :
W = P (V)2 - V1)
W = (5 x 105)(6 – 2) = (5 x 105(4)
W = 20 x 105 = 2x10 pa6 Joule
2. Kusiyana kwa ntchito yochitidwa ndi mpweya mu njira za AB ndi CD ndi…
Zokambirana
Ndizodziwika kuti :
Njira ya Isobaric AB :
Kupanikizika (P) = 6 atm = 6 x 105 N / m2
Voliyumu yoyamba (V)1) = malita 1 = 1 dm3 = 1x10 pa-3 m3
Voliyumu yomaliza (V)2) = malita 3 = 3 dm3 = 3x10 pa-3 m3
Njira ya isobaric ya CD :
Kupanikizika (P) = 4 atm = 4 x 105 N / m2
Voliyumu yoyamba (V)1) = malita 2 = 2 dm3 = 2x10 pa-3 m3
Voliyumu yomaliza (V)2) = malita 5 = 5 dm3 = 5x10 pa-3 m3
Anafunsa Kusiyana kwa ntchito yochitidwa ndi mpweya mu njira AB ndi CD
Yankhani :
Ntchito yochitidwa ndi gasi mu ndondomeko AB:
W = P (V)2 - V1)
W = (6 x 105)(3 x 10-3 - 1 x 10-3)
W = (6 x 105)(2 x 10-3)
W = 12 x 102 = 1200 Joule
Ntchito yomwe mpweya wachita mu ndondomeko ya CD:
W = P (V)2 - V1)
W = (4 x 105)(5 x 10-3 - 2 x 10-3)
W = (4 x 105)(3 x 10-3)
W = 12 x 102 = 1200 Joule
Kusiyana kwa ntchito yochitidwa ndi mpweya mu njira za AB ndi CD ndi 1200 - 1200 = 0.
3. Ntchito yomwe mpweya wachita mu ndondomeko ya ABC ndi…
Zokambirana
Ndizodziwika kuti :
Kupanikizika 1 (P)1) = 6 x 105 Pascal = 6 x 105 N / m2
Kupanikizika 2 (P)2) = 3 x 105 Pascal = 3 x 105 N / m2
Voliyumu 1 (V)1) = 2 cm3 = 2x10 pa-6 m3
Voliyumu 2 (V)2) = 6 cm3 = 6x10 pa-6 m3
Anafunsa : Kuyesetsa komwe kwachitika mu ndondomeko ya ABC.
Yankhani :
Mu ndondomeko ya AB, voliyumu imakhala yosasintha, kotero palibe ntchito yomwe imachitika ndi mpweya. Mpweya umagwira ntchito mu ndondomeko ya BC yokha. Choncho ntchito mu ndondomeko ya ABC = ntchito mu ndondomeko ya BC.
W = P2 (V2 - V1)
W = (3 x 105)(6 x 10-6 - 2 x 10-6)
W = (3 x 105)(4 x 10-6)
W = 12 x 10-1
W = 1,2 Joule
Ntchito yomwe yachitika mu ndondomeko ya ABC = 1,2 Joules.
4. Mawu olondola okhudza njira za thermodynamic ndi…
A. Isobaric ndi njira yosinthira mpweya pa mphamvu yosalekeza.
B. Isobaric ndi njira yosinthira mpweya pa kutentha kosasintha.
C. Isochoric ndi njira yosinthira mpweya pa mphamvu yosalekeza.
D. isotherm ndi njira yosinthira mpweya pa voliyumu yokhazikika.
E. Isochoric ndi njira yosinthira mpweya pa kutentha kosasintha.
Zokambirana
Isobaric = kupanikizika kosalekeza
Isochoric = voliyumu yosasinthasintha
Isothermic = kutentha kosalekeza
Yankho lolondola ndi A.
5. Kuyerekeza kwa khama mu njira I ndi II kutengera graph ili pansipa ndi...
A. 4: 3
B. 3: 4
C. 2: 3
D. 1: 2
E. 1: 3
Kukambirana:
Ndizodziwika kuti :
Njira Yoyamba: P = 15 N/m2, V1 = 15 m3, V2 = 35 m3
Njira Yachiwiri: P = 10 N/m2, V1 = 5 m3, V2 = 45 m3
Anafunsa :
Kuyerekeza khama (W) la ndondomeko I ndi ndondomeko II?
Yankhani :
Yankho lolondola ndi B.
6. Chithunzi cha PV cha mpweya wa helium womwe ukuchitika mu ndondomeko ya thermodynamic chawonetsedwa pachithunzi chili pansipa! Ntchito yomwe yachitika ndi mpweya wa helium mu ndondomeko ya ABC ndi…
A. 400 kJ
B. 500 kJ
C. 600 kJ
D. 800 kJ
E. 1000 kJ
Kukambirana:
Ndizodziwika kuti :
P1 = 2x10 pa5 N / m2
P2 = 1x10 pa5 N / m2
V1 = 5 m3
V2 = 15 m3
Anafunsa :
Kodi ntchito (W) mu ndondomeko ya ABC?
Yankhani :
Ntchito imachitika pokhapokha ngati mpweya wawonjezeka. Mu ndondomeko ya AB, mpweya wa mpweya umakhalabe wofanana, kotero palibe ntchito yomwe imachitika ndi mpweya wa helium. Mu ndondomeko ya BC, mpweya wa mpweya umawonjezeka, kotero ntchitoyo imachitika ndi mpweya wa helium.
