Zitsanzo za mafunso okambirana za Chain Rule mu Derivatives

Mafunso ndi Zitsanzo za Malamulo a Unyolo mu Zotumphukira

Lamulo la unyolo ndi limodzi mwa mfundo zofunika kwambiri mu differential calculus, lomwe limagwiritsidwa ntchito kuwerengera derivative ya ntchito yokhala ndi ntchito ziwiri kapena zingapo. M'nkhaniyi, tikambirana za lingaliro loyambira la lamulo la unyolo, momwe tingaligwiritsire ntchito, ndi zitsanzo za momwe limagwiritsidwira ntchito pamavuto obwera chifukwa cha unyolo omwe nthawi zambiri amabuka kusukulu yasekondale komanso ku koleji.

1. Chiyambi cha Lamulo la Unyolo

Tisanalowe mu chitsanzo cha vutoli, choyamba tiyeni timvetse tanthauzo la lamulo la unyolo. Lamulo la unyolo limati ngati tili ndi ntchito ziwiri zosiyana \( f \) ndi \( g \), ndipo tikufuna kupeza chochokera ku kapangidwe ka ntchito \( h = f(g(x)) \), ndiye kuti chochokera ku \( h \) ndi:

\[ h'(x) = f'(g(x)) \cdot g'(x) \]

Mwachidule, timawerengera derivative ya ntchito yakunja pa g(x), kenako timachulukitsa zotsatira zake ndi derivative ya ntchito yamkati \( g(x) \).

2. Kumvetsetsa Ntchito ya Kulemba

Tisanalowe mu zitsanzo za mavuto, ndikofunikira kumvetsetsa ntchito za kapangidwe kake. Ntchito ya kapangidwe kake ndi ntchito yomwe imapezeka poika ntchito imodzi mu ina. Mwachitsanzo, ngati tili ndi \( f(x) = \sin(x) \) ndi \( g(x) = x^2 \), ndiye kuti kapangidwe ka ntchito ziwirizi kadzakhala \( h(x) = f(g(x)) = \sin(x^2) \).

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Mu ntchito zopanga, nthawi zambiri timaganiza za \( g(x) \) ngati "ntchito yamkati" ndi \( f(x) \) ngati "ntchito yakunja". Mu chitsanzo ichi, ntchito yamkati ndi \( x^2 \) ndipo ntchito yakunja ndi sine.

3. Mafunso ndi Kukambirana Zitsanzo

Tiyeni tiwone zitsanzo za mavuto omwe amagwiritsa ntchito lamulo la unyolo kuti awathetse.

Chitsanzo 1:

Popeza ntchito \( y = \cos(3x^2) \), pezani chiyambi choyamba cha y poyerekeza ndi x.

Kukambirana:

Choyamba, timazindikira ntchito zamkati ndi zakunja. Apa, ntchito yamkati ndi \( g(x) = 3x^2 \) ndipo ntchito yakunja ndi \( f(g) = \cos(g) \).

Tikudziwa:

1. \( g'(x) = 6x \)
2. \( f'(g) = -\sin(g) \)

Malinga ndi lamulo la unyolo, timapeza:

\[ y' = f'(g(x)) \cdot g'(x) = -\sin(3x^2) \cdot 6x \]

Kotero, chochokera ku \( y = \cos(3x^2) \) ndi:

\[ y' = -6x \sin(3x^2) \]

Chitsanzo 2:

Pezani chiyambi cha \( h(x) = e^{5x^3 + 2x} \).

Kukambirana:

Apa ntchito yamkati ndi \( g(x) = 5x^3 + 2x \) ndipo ntchito yakunja ndi \( f(g) = e^g \).

Tikudziwa:

1. \( g'(x) = 15x^2 + 2 \)
2. \( f'(g) = e^g \)

Malinga ndi lamulo la unyolo, timapeza:

\[ h'(x) = f'(g(x)) \cdot g'(x) = e^{5x^3 + 2x} \cdot (15x^2 + 2) \]

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Kotero, chochokera pa \( h(x) = e^{5x^3 + 2x} \) ndi:

\[ h'(x) = (15x^2 + 2) e^{5x^3 + 2x} \]

Chitsanzo 3:

Pezani chiyambi cha \( y = \ln(4x^2 - 5) \).

Kukambirana:

Ntchito yamkati ndi \( g(x) = 4x^2 – 5 \) ndipo ntchito yakunja ndi \( f(g) = \ln(g) \).

Tikudziwa:

1. \( g'(x) = 8x \)
2. \( f'(g) = \frac{1}{g} \)

Malinga ndi lamulo la unyolo, timapeza:

\[ y' = f'(g(x)) \cdot g'(x) = \frac{1}{4x^2 – 5} \cdot 8x \]

Kotero, chochokera ku \( y = \ln(4x^2 – 5) \) ndi:

\[ y' = \frac{8x}{4x^2 – 5} \]

Chitsanzo 4:

Popeza ntchito \( y = (3x^2 + 2x + 1)^4 \), pezani chochokera chake.

Kukambirana:

Ntchito yamkati ndi \( g(x) = 3x^2 + 2x + 1 \) ndipo ntchito yakunja ndi \( f(g) = g^4 \).

Tikudziwa:

1. \( g'(x) = 6x + 2 \)
2. \( f'(g) = 4g^3 \)

Malinga ndi lamulo la unyolo, timapeza:

\[ y' = f'(g(x)) \cdot g'(x) = 4(3x^2 + 2x + 1)^3 \cdot (6x + 2) \]

Kotero, chochokera ku \( y = (3x^2 + 2x + 1)^4 \) ndi:

\[ y' = 4(3x^2 + 2x + 1)^3 (6x + 2) \]

4. Milandu Yapadera ndi Kupanga Malamulo Okhudza Unyolo

Nthawi zina, lamulo la unyolo silimathera pa kapangidwe ka ntchito ziwiri zokha. Pali nthawi zina pamene ntchito imakhala ndi kapangidwe ka ntchito zoposa ziwiri, mwachitsanzo: \( h(x) = f(g(k(x))) \).

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Pa ntchito zitatu, lamulo la unyolo lingagwiritsidwe ntchito m'magawo:

\[ h'(x) = f'(g(k(x))) \cdot g'(k(x)) \cdot k'(x) \]

Titha kuona kuti mu gawo lililonse, timawerengera zotumphukira za zigawo zakunja tisanapite ku zotumphukira za zigawo zamkati.

Chitsanzo 5:

Popeza \( y = \sqrt{\ln(2x^2 + 1)} \), pezani chochokera chake.

Kukambirana:

Ntchito yamkati ndi \( k = 2x^2 + 1 \), pakati: \( g = \ln(k) \) ndi yakunja: \( f = \sqrt{g} \).

Tikudziwa:

1. \( k'(x) = 4x \)
2. \( g'(k) = \frac{1}{k} \)
3. \( f'(g) = \frac{1}{2\sqrt{g}} \)

Tiyeni tigwiritse ntchito lamulo la unyolo m'magawo:

\[ y' = f'(g(k(x))) \cdot g'(k(x)) \cdot k'(x) = \frac{1}{2\sqrt{\ln(2x^2 + 1)}} \cdot \frac{1}{2x^2 + 1} \cdot 4x \]

Kotero chochokera ku \( y = \sqrt{\ln(2x^2 + 1)} \) ndi:

\[ y' = \frac{4x}{2(2x^2 + 1)\sqrt{\ln(2x^2 + 1)}} \]

5. Kesimpulan

Lamulo la unyolo limagwira ntchito yofunika kwambiri pakuwerengera kosiyana, makamaka pokhudzana ndi kapangidwe ka ntchito. Kumvetsetsa ndikudziwa bwino lamulo la unyolo kumapereka maziko olimba othana ndi mavuto ovuta kwambiri pakuwerengera. Nkhaniyi yafotokoza zitsanzo zingapo zofunika kuti timvetsetse bwino momwe lamulo la unyolo limagwiritsidwira ntchito pazinthu zoyambira. Tikukhulupirira kuti kukambiranaku ndikothandiza kwa ophunzira ndipo kungagwiritsidwe ntchito pamavuto osiyanasiyana a masamu.

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