1. A 0.2-kg ball, attached to the end of a horizontal cord, is revolved in a circle of radius 1 meter and ball’s maximum speed is 10 rpm. What is the magnitude of the aċċelerazzjoni ċentripeta and the magnitude of the tension force?
Magħruf:
Massa (m) = 0.2 kg
Radius (r) = 1 m
Veloċità angolari (ω) = 10 rev/min = 10 rev/60 s = 0.17 rev/s = (0.17)(6.28 rad)/s = 1 rad/s
Veloċità (v) = r ω = (1 m)(1 rad/s) = 1 m/s
Meħtieġ: as Share ΣF
Soluzzjoni:
(a) The magnitude of the centripetal acceleration
(b) The magnitude of the tension force
ΣF = ma
T = m as
T = (0.2 kg)(1 m/s2)
T = 0.2 kg m/s2
T = 0.2 N
2. A 1-kg ball at the end of a string is revolving uniformly in a horizontal circle of radius 1 m. The cord will break when the tension in it exceeds 100 N. What is the maximum speed the ball can have?
Magħruf:
Massa (m) = 1 kg
Radius (r) = 1 meter
Tension force (T) = forza ċentripetali (ΣF) = 100 N
Mfittxija: v maximum
Soluzzjoni:
[wpdm_package id='499′]
- Massa u piż
- Forza normali
- It-tieni liġi tal-moviment ta' Newton
- Forza ta 'frizzjoni
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- The motion of two bodies with the same acceleration on the rough horizontal surface with a friction force
- Motion on an inclined plane without friction force
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- Mozzjoni f'lift
- Il-moviment tal-ġisem huwa konness permezz ta' ħbula u taljoli
- Żewġ korpi bl-istess kobor ta' aċċelerazzjoni
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- Arrotondament ta' kurva inklinata – dinamika ta' moviment ċirkolari
- Moviment uniformi f'ċirku orizzontali
- Forza ċentripeta f'moviment ċirkolari uniformi
