3 mistoqsijiet dwar l-ekwazzjoni tal-forza riżultanti
1. Karozza b'massa ta' 5 tunnellati tiċċaqlaq minn pożizzjoni ta' wieqfa f'50 sekonda, u tilħaq veloċità ta' 72 km/siegħa. Il-forza fuq il-karozza hija…
Magħruf:
Massa (m) = 5 tunnellati = 5000 kg
Veloċità inizjali (vo) = 0
Veloċità finali (vt) = 72 km/h = 20 m/s
Intervall ta' ħin (t) = 50 sekondi
Mfittxija: Forza (F)
soluzzjoni:
Calculate the acceleration using the Non Uniform Linear Motion formula:
vt =vo + f'
20 = 0 + a (50)
20 = 50 a
a = 20 / 50 = 0,4 m/s2
Calculate the resultant force using Newton’s second law formula:
ΣF = ma
F = (5000)(0,4) = 2000 Newton
2. A car has a mass of 1 ton, for 4 seconds its speed increases uniformly from 10 m/s to 18 m/s. Determine the magnitude of the force that accelerates the car.
Magħruf:
The mass of the car (m) = 1 ton = 1000 kg
Intervall ta' ħin (t) = 4 sekondi
Veloċità inizjali (vo) = 10 m/s
Veloċità finali (vt) = 18 m/s
Mfittxija: Forza (F)
soluzzjoni:
Calculate the acceleration using the Non Uniform Linear Motion formula:
vt =vo + f'
18 = 10 + a (4)
18 – 10 = a (4)
8 = 4 a
a = 8 / 4 = 2 m/s2
Calculate the resultant force using Newton’s second law formula:
ΣF = ma
F = (1000)(2) = 2000 Newton
3. The two force vectors are perpendicular to each other which results in a resultant of 10 N. If one of the force vectors is 6 N , determine the magnitude of the other force vector.
Magħruf:
Resultant force (F) = 10 N
Forza 1 (F1) = 6 N
Mfittxija: Forza 2 (F2)
soluzzjoni:
F2 = 10 – 6 = 4 Newton
