Veloċità tal-mewġ trasversali – problemi u soluzzjonijiet
1.
Jekk l-intervall ta' ħin meħtieġ biex tivvjaġġa minn A sa B huwa ta' 2 sekondi, iddetermina l-veloċità tal- mewġa trasversali.
Magħruf:
Distanza AB = 6 metris
intervall ta 'ħin AB = 2 sekondi
Mfittxija: Veloċità tal-mewġa trasversali
Soluzzjoni:
1 wavelength has 1 crest and 1 trough. There is 4 wavelength between A and B. Distance between A and B is 6 meters so that 1 wavelength (λ) = Meter 6s / 4 = 1.5 meters.
It-time interval required to travel from A to B is 2 seconds so that the time interval required to travel 1 wavelength = period (T) = 2 seconds / 4 = 0.5 seconds.
The equation of the speed of wave :
v = λ f = λ / T
v = speed of wave, λ = wavelength, f = frekwenza, T = periodu
The speed of wave :
v = 1.5 meters / 0.5 sekunds
v = 3 meters/ sekond
2. If the time interval required to travel from A to B is 8 seconds, determine the speed of transverse wave.
Magħruf:
There are two wavelength.
1 wavelength (λ) = 2 x 4 meters = metru 8s
Period (T) = 8 sekunds / 2 tulijiet ta 'mewġ = 4 seconds / wavelength
Meħtieġ: Speed of wave (V)
Soluzzjoni:
The speed of wave calculated using the equation of the speed of wave :
v = f λ = λ/T
v = 8 meters / 4 sekunds
v = 2 meters/ sekond
