1. Abbażi tal-figura t'hawn taħt, jekk ir-raġġ tal-kurvatura tal-wajer huwa 50 ċm, iddetermina l-kobor tal- kamp manjetiku fiċ-ċentru tal-kurvatura (fil-punt 0, ara l-figura hawn taħt). (µo = 4π.10-7 Wb.A-1 m-1)
Magħruf:
Raġġ (r) = 50 ċm = 0.5 m
Kurrent elettriku (I) = 1.5 Amperes
Il-permeabilità tal-vakwu (µo) = 4π.10-7 Wb.A-1 m-1
Mfittxija: Til-kobor tal-kamp manjetiku
Soluzzjoni:
360o = 1 ċirkonferenza ta' ċirku. 120o / 360o = 1/3 then 120o = 1/3 x ċirkonferenza of a circle.
The equation of the magnetic field at the center of the coil with several loops :
B = the magnitude of the magnetic field, N = number of loops, I = electric current, r = radius of curvature
In the above problem, there is only one loop so that N is eliminated from the equation. The wire coil on the above problem is not 1 circle but 1/3 circle :
The magnitude of the magnetic field at the center of curvature :
2. Based on the figure below, the electric current flows in the wire is 6-A and radius of curvature is R = 3π cm, to determine the magnitude of the magnetic field at point P.
Magħruf:
Radius of curvature (r) = 3π cm = (3π/100) m
= 3π/102 m = 3π.10-2 m
Kurrent elettriku (I) = 6 A
Il-permeabilità tal-vakwu (µo) = 4π.10-7 Wb.A-1 m-1
Meħtieġ: The magnitude of the magnetic field
Soluzzjoni:
360o = 1 ċirkonferenza of a circle. 45o / 360o = 1/8 then 45o = 1 / 8 x ċirkonferenza of a circle.
The magnitude of the magnetic field at the center of curvature :
3. Electric current flows in wire = 9-A, the radius of curvature (R) = 2π cm and µo = 4π.10-7 Wb.A-1.m-1, determine the magnitude of the magnetic field at point P.
Magħruf:
Radius of curvature (r) = 2π cm = (2π/100) m
= 2π/102 m = 2π.10-2 m
Kurrent elettriku (I) = 9 A
Il-permeabilità tal-vakwu (µo) = 4π.10-7 Wb.A-1 m-1
Meħtieġ: The magnitude of the magnetic field at point P
Soluzzjoni:
360o - 120o = 240o. 240o / 360o = 2/3 then 240o = 2/3 x ċirkonferenza of a circle.
The magnitude of the magnetic field at the center of curvature :
