1. A 0.2-kg ball, attached to the end of a horizontal cord, is revolved in a circle of radius 1 meter and ball’s maximum speed is 10 rpm. What is the magnitude of the pecutan memusat and the magnitude of the tension force?
Diketahui:
Massa (m) = 0.2 kg
Radius (r) = 1 m
Halaju sudut (ω) = 10 rev/min = 10 rev/60 s = 0.17 rev/s = (0.17)(6.28 rad)/s = 1 rad/s
Halaju (v) = r ω = (1 m)(1 rad/s) = 1 m/s
Dikehendaki: as dan ΣF
Penyelesaian:
(a) The magnitude of the centripetal acceleration
(b) The magnitude of the tension force
ΣF = ma
T = m as
T = (0.2 kg)(1 m/s)2)
T = 0.2 kg m/s2
T = 0.2 N
2. A 1-kg ball at the end of a string is revolving uniformly in a horizontal circle of radius 1 m. The cord will break when the tension in it exceeds 100 N. What is the maximum speed the ball can have?
Diketahui:
Jisim (m) = 1 kg
Radius (r) = 1 meter
Tension force (T) = daya sentripetal (ΣF) = 100 N
Dikehendaki: v maximum
Penyelesaian:
[wpdm_package id='499']
- Jisim dan berat
- Daya biasa
- Hukum kedua Newton tentang gerakan
- Daya geseran
- Gerakan pada permukaan mendatar tanpa daya geseran
- The motion of two bodies with the same acceleration on the rough horizontal surface with a friction force
- Motion on an inclined plane without friction force
- Gerakan pada satah condong kasar dengan daya geseran
- Gerakan dalam lif
- Pergerakan jasad dihubungkan oleh tali dan takal
- Dua jasad dengan magnitud pecutan yang sama
- Membulatkan lengkungan rata – dinamik gerakan membulat
- Membulatkan lengkung miring – dinamik gerakan membulat
- Gerakan seragam dalam bulatan mendatar
- Daya memusat dalam gerakan membulat seragam
