एकसर आणि समांतर जोडणीतील स्प्रिंग्स

Article about the एकसर आणि समांतर जोडणीतील स्प्रिंग्स

1. Springs in series

If the spring is connected in series, as in the figure on the side, then:

1. The increase in the length of spring = the increase in length 1 + the increase in length 2

Δy = Δy₁ + Δy₁

2. The force experienced by equivalent spring = the force experienced by spring 1 = the force experienced by spring 2

F_s = एफ₁ = एफ₂

3. The equivalent spring’s constant (k_s)

१/के_s = 1/k₁ + १/के₂

नमुना समस्या १:

Two identical springs each have a constant of 100 N / m connected in series. If the spring’s arrangement is given a load so that it increases 4 cm in length, then the increase in the length of each spring is …

उपाय:

The total increase in the length of the two springs is 4 cm, therefore the increase in the length of each spring is 2 cm.

2. Springs in parallel

If the spring is connected in parallel, as in the figure on the side, then:

1. The increase in the length of the equivalent spring = the increase in the length of spring 1 = the increase in the length of spring 2

Δy = Δy₁ + Δy₁

2. The force experienced by the equivalent spring = the force that is experienced by spring 1 + the force experienced by spring 2

F_s = एफ₁ + एफ₂

3. The equivalent spring’s constant (k_p)

kp = k₁ +k₂

नमुना समस्या १:

Two springs each with constant c arranged in parallel. The स्प्रिंग स्थिरांक of this arrangement becomes …

उपाय:

The equivalent spring’s constant (k_p) = c + c = 2c