1. Хэрэв R1 = 2 Ом, R2 = 4 Ом, R3 = 6 Ω, тодорхойлно уу цахилгаан гүйдэл доорх хэлхээнд урсдаг.
Мэдэгдэж байгаа:
Эсэргүүцэл 1 (R)1) = 2 Ом 
Эсэргүүцэл 2 (R)2) = 4 Ом
Эсэргүүцэл 3 (R)3) = 6 Ом
EMF 1-ийн эх үүсвэр (E)1) = 9 V
EMF 2-ийн эх үүсвэр (E)2) = 3 V
Хүссэн: Цахилгаан гүйдэл (I)
Шийдэл:
This question relates to Кирхгофын хууль. How to solve this problem:
Эхлээд, choose the direction of the current. You can decide the opposite current or direction in the clockwise direction.
Хоёрдугаарт, when the current through the resistor (R) there is a potential decrease so that V = IR signed negative. Гурав дугаар, if the current moves from low to high voltage (- to +) then the source of emf (E) signed positive because of the charging of energy at the emf source. If the current moves from high to low voltage (+ to -) then the source of emf (E) signed negative because of the emptying of energy at the emf source.
In this solution, the direction of the current is the same as the direction of clockwise rotation.
– Хэт улаан туяа1 + Э1 – Хэт улаан туяа2 – Хэт улаан туяа3 - Е2 = 0
– 2 I + 9 – 4 I – 6 I – 3 = 0
– 12 I + 6 = 0
– 12 I = – 6
I = -6 / -12
Би = 0.5
The electric current flows in the circuit are 0.5 A. The electric current signed positive means that the direction of the electric current is the same as the direction of clockwise rotation. If the electric current is negative, then the electric current is opposite the clockwise direction.
2. Determine the electric current that flows in the circuit as shown in the figure below.
Шийдэл:
In this solution, the direction of the current is the same as the direction of clockwise rotation.
-20 – 5I -5I – 12 – 10I = 0
-32 – 20I = 0
-32 = 20I
I = -32 / 20
I = -1.6 A
Because the electric current is negative, the direction of the electric current is actually opposite to the clockwise direction. The direction of electric current is not the same as estimation.
3. Determine the electric current that flows in the circuit as shown in the figure below.
Шийдэл:
In this solution, the direction of current is the same as the direction of clockwise rotation.
– I – 6I + 12 – 2I + 12 = 0
-9I + 24 = 0
-9I = -24
I = 24 / 9
I = 8 / 3 A
4. An electric circuit consists of four resistors, R1 = 12 Ohm, R2 = 12 Ohm, R3 = 3 Ohm and R4 = 6 Ohm, are connected with source of emf E1 = 6 Volt, E2 = 12 Volt. Determine the electric current flows in the circuit as shown in figure below.
Мэдэгдэж байгаа:
Эсэргүүцэл 1 (R)1) = 12 Ом
Эсэргүүцэл 2 (R)2) = 12 Ом
Эсэргүүцэл 3 (R)3) = 3 Ом
Эсэргүүцэл 4 (R)4) = 6 Ом
EMF 1-ийн эх үүсвэр (E)1) = 6 вольт
EMF 2-ийн эх үүсвэр (E)2) = 12 вольт
Хүссэн: The electric current flows in the circuit (I)
Шийдэл:
Эсэргүүцэл 1 (R1) and resistor 2 (R2) are connected in parallel. The equivalent resistor :
1 / R12 = 1/R1 +1/R2 = 1/12 + 1/12 = 2/12
R12 = 12/2 = 6 Ω
In this solution, the direction of current is the same as the direction of clockwise rotation.
– Хэт улаан туяа12 - Е1 – Хэт улаан туяа3 - IR4 + Э2 = 0
– 6 I – 6 – 3I – 6I + 12 = 0
– 6I – 3I – 6I = 6 -12
– 15I = – 6
I = -6/-15
I = 2/5 A
5. Determine the electric current that flows in circuit as shown in figure below.
Мэдэгдэж байгаа:
Эсэргүүцэл 1 (R)1) = 10 Ом
Эсэргүүцэл 2 (R)2) = 6 Ом
Эсэргүүцэл 3 (R)3) = 5 Ом
Эсэргүүцэл 4 (R)4) = 20 Ом
EMF 1-ийн эх үүсвэр (E)1) = 8 вольт
EMF 2-ийн эх үүсвэр (E)2) = 12 вольт
Хүссэн: The electric current that flows in circuit
Шийдэл:
Эсэргүүцэл 3 (R3) and resistor 4 (R4) are connected in parallel. The equivalent resistor :
1 / R34 = 1/R3 +1/R4 = 1/5 + 1/20 = 4/20 + 1/20 = 5/20
R34 = 20/5 = 4 Ω
In this solution, the direction of current is the same as the direction of clockwise rotation.
– Хэт улаан туяа1 – Хэт улаан туяа2 - E1 – Хэт улаан туяа34 + Э2 = 0
– 10I – 6I - 8 - 4I + 12 = 0
– 10I – 6I - 4I = 8 - 12
- 20I = - 4
I = -4/-20
I = 1/5 A
I = 0.2 А
6. Determine the electric current that flows in circuit as shown in figure below.
Мэдэгдэж байгаа:
Эсэргүүцэл 1 (R)1) = 1 Ом
Эсэргүүцэл 2 (R)2) = 6 Ом
Эсэргүүцэл 3 (R)3) = 6 Ом
Эсэргүүцэл 4 (R)4) = 4 Ом
EMF 1-ийн эх үүсвэр (E)1) = 12 вольт
EMF 2-ийн эх үүсвэр (E)2) = 6 вольт
Хүссэн: The electric current that flows in circuit
Шийдэл:
Эсэргүүцэл 1 (R1) and resistor 2 (R2) are connected in parallel. The equivalent resistor :
1 / R12 = 1/R1 +1/R2 = 1/1 + 1/6 = 6/6 + 1/6 = 7/6
R12 = 6/7 Ω
The direction of current is the same as the direction of clockwise rotation.
E1 - Би R12 - Е2 - Би R4 – Хэт улаан туяа3 = 0
12 – (6/7)I – 6 – 4I – 6I = 0
12 – 6 – (6/7)I – 4I – 6I = 0
6 – (6/7)I – 10I = 0
6 = (6/7)I + 10I
6 = (6/7)I + (70/7)I
6 = (76/7)I
(6)(7) = 76I
42 = 76I
I = 42/76
I = 0.5 А