Te tātai tauine pāmahana me te whakatikatika ine pāmahana

Ngā tauira pātai me ngā tātai mō ngā tauine pāmahana me te whakatikatika i ngā inemahana

Tauine pāmahana

1. Ko te pāmahana o te wai mahana e ai ki te tauine o te inemahana Celsius he 45. E ai ki te tauine Fahrenheit, ko tēnei pāmahana he….

A. 25
B. 57
C. 81
D. 113

Kōrero
E mōhiotia ana:
T_C = 45^oC
I pātaihia: T_F = ….. ^oF?
Whakautu:

Ko te whakautu tika ko D.

2. He inemahana rerekē e whakamahi ana i tētahi tauine ine me te ira tio o te wai he -15 ^o S me te ira koropupū o te wai he +60 ^o S. Mena he 10 o S te uara o te inemahana, ko te uara pāmahana i te tauine Fahrenheit ko….

A. 28^o
B. 35^o
C. 57^o
D. 92^o

Kōrero
E mōhiotia ana:
Te pūwāhi tio o te wai = -15^oS
Te pūwāhi koropupū o te wai = +60^oS
I pātaihia: 10^oS = …..^oF
Whakautu:
I te tauine Fahrenheit, ko te pūwāhi tio o te wai he 32^oF, ā, ko te pūwāhi koropupū o te wai he 212^oF. He rerekētanga 212 i waenganui i te pūwāhi tio me te pūwāhi koropupū o te wai^o - 32^o = 180^o.
I te tauine Celsius, ko te ira tio o te wai he 0^oC, ā, ko te pūwāhi koropupū o te wai he 100^oC. He rerekētanga 100°C i waenganui i te pūwāhi tio me te pūwāhi koropupū o te wai.^o - 0^o = 100^o.
I te tauine S, ko te pūwāhi tio o te wai he -15^oS, ā, ko te pūwāhi koropupū o te wai he 60^oS. He rerekētanga 60 i waenganui i te pūwāhi tio me te pūwāhi koropupū o te wai^o – (-15^o) = 60^o + 15^o = 75^o.

Tahurihia te tauine S ki te tauine Celsius:

Tahurihia te tauine Celsius ki te Fahrenheit:

Ko te whakautu tika ko D.

Te whakatikatika i te inemahana

3. Ka whakamahia he ngongo karāhe kī tonu i te waipiro hei inemahana. Ko te teitei o te pou waipiro ina pā te pito o te ngongo ki te hukapapa rewa me te wai kohua he 4 cm me te 28 cm, ia. Ko te pāmahana wai e 16 cm te teitei o te pou waipiro ko….. ^oC
A. 67,7
B. 50
C. 16
D. 12
Kōrero
E mōhiotia ana:
Ko te teitei o te pou waipiro ina pā te pito o te paipa ki te huka rewa = 4 cm
Ko te teitei o te pou waipiro ina pā te pito o te paipa ki te wai kohua = 28 cm
Pātai: Ko te pāmahana wai e 16 cm te teitei o te pou waipiro ko... ^oC
Whakautu:
Ko te pāmahana e rewa ai te huka (kei te rewa te huka) he 0^oC kia 4 cm te teitei o te pou waipiro, he ōrite ki te 4^oC. Ko te pāmahana o te wai kohua he 100^oC kia 28 cm te teitei o te pou waipiro, he ōrite ki te 100^oC.

Ko te rerekētanga o te teitei o te pou waipiro he 28 cm – 4 cm = 24 cm.
Ko te rerekētanga o te tauine pāmahana Celsius he 100^oC - 0^oC=100^oC.

100^oC / 24 henimita = 4,17 ^oC / henimita
Nō reira, he ōrite te pou waipiro 1 cm te teitei ki te 4,17 ^oC.

Ina 4 henemita te teitei o te pou waipiro, ko te pāmahana o te wai he 0.^oC. Mena he 16 henimita te teitei o te pou waipiro, he aha te pāmahana o te wai i roto i te Celsius? 16 henimita – 4 henimita = 12 henimita. Nō reira, 12 x 4,17 = 50,04 ^oC.
Ko te whakautu tika ko B.

4. Ko te mea kāore e hiahiatia ana hei whakatau i te tauine o te inemahana ko….
A. pūwāhi pumau o runga
B. te pūwāhi kohua
C. pūwāhi pumau o raro
Whānui tauine D.
Kōrero
Ko te pūwāhi pumau o runga (pūwāhi koropupū) me te pūwāhi pumau o raro (pūwāhi tio) te mea e hiahiatia ana hei whakatau i te tauine o te inemahana i runga i te pātai i runga ake nei ko te whānui o te tauine.
Ko te whakautu tika ko D.

5. Kei roto i te inemahana kore-whakarōpū te konutea. Ina whakanohoia ki roto i te hukapapa, e 5 cm te roa o te pou konutea, ā, ina whakanohoia ki roto i te wai kohua, e 30 cm te roa o te pou konutea. Ina whakaatuhia e te inemahana te 25^oKo te roa o te pou konukōrei ko….
A. 6,25 henemita
B. 10,25 henemita
C. 11,25 henimita
D. 22,50 henimita
Kōrero
E mōhiotia ana:
Ko te roa o te pou konukōre ina whakaurua ki roto i te huka rewa = 5 cm
Te roa o te pou konukōre ina whakanohoia ki te wai kohua = 30 cm
Pātai: Ko te roa o te pou mercury ina whakaatuhia e te inemahana te 25^oC
Whakautu:
Ko te pāmahana rewa o te hukapapa (kei te rewa te hukapapa) he 0^oC nō reira ko te roa o te pou mercury he 5 cm, he rite ki te 0^oC. Ko te pāmahana o te wai kohua he 100^oC nō reira ko te roa o te pou mercury he 30 cm, he rite ki te 100^oC.

Ko te rerekētanga o te roa o te pou konukōre he 30 cm – 5 cm = 25 cm.
Ko te rerekētanga o te tauine pāmahana Celsius he 100^oC - 0^oC=100^oC.

25 cm / 100^oC = 0,25 henimita / ^oC
Ki te piki ake te pou konukōre mā te 0,25 cm, he rite tonu ki te pikinga ake o te pāmahana wai mā te 1°C.

Ina 0 te pāmahana o te wai^oC, ko te roa o te pou mercury he 5 cm. Nō reira, ki te 25 te pāmahana o te wai^oC, ko te roa o te pou konukōre he 5 cm + (0,25 x 25) = 5 cm + 6,25 cm = 11,25 cm.
Ko te whakautu tika ko C.