Mana - ngā raruraru me ngā otinga

Power is the rate at which work is done in a given period. Mathematically, power is the work/time ratio.

P = W/t

Description: P = power (Joule/second = Watt), W = work (Joule), t = time interval (second)

Based on this equation, it can be concluded that the greater the work rate, the greater the power. On the other hand, the smaller the work rate, the smaller the power. Work rate refers to the rate at which work is done.

A hi'o atoa  Te whakawhānui wera - ngā raruraru me ngā otinga

Power is a scalar. The SI unit of power is the Joule/second. The Joule/second = Watt (abbreviated as W), named so to pay homage to James Watt. The British imperial unit for power is foot-pound per second.

This unit is too small for practical purposes, so the greater unit horsepower (abbreviated as hp) is used. One horsepower = 550 foot-pound per second = 764 Watt = ¾ kilowatt.

The amount of work can also be expressed in power x time units, for instance, kilowatt-hour or kWh. One kWh refers to the work done at a constant rate of 1 kiloWatt for one hour.

1. He 50-kg person runs up the stairs 10 meters high in meneti 2. Acceleration Tuhinga o mua gravity (g) is 10 m/s2. Whakahuahia te mana.

Mōhiotia:

Mass (m) = 50 kg

teitei (h) = 10 metera

Whakaterenga na te kaha o te kaha (g) = 10 m/s2

wā wā (t) = 2 meneti = 2 (60) = 120 tuaruas

hiahia : Power (P)

Rongoā:

Formula of power :

P = W / t

P= mana, W = mahi, t =

Formula of Work :

W = F s = w h = m g h

W= mahi, F = kaha, w = taimaha, d = Tuhinga, h = teitei, m = mass, g = te whakaterenga nā te kaha ā-papa

W = m g h = (50)(10)(10) = 5000 Joule.

P = W / t = 5000 / 120 = 41.7 Joule/second.

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2. Calculate the power required of a 60-kg person who climbs a tree 5 meters high in 10 seconds. Acceleration due to gravity is 10 m/s2.

Mōhiotia:

Taumaha (m) = 60 kg

teitei (h) = 5 meters

Whakaterenga na te kaha o te kaha (g) = 10 m/s2

wā wā (t) = 10 hēkona

hiahia : Power

Rongoā:

Work :

W = m g h = (60)(10)(5) = 3000 Joule

Mana:

P = W / t = 3000 / 10 = 300 Joule/second.

3. A rotary comedy with a power of 300 watts and period of 5 minutes rotates 5 rounds. The energy it uses is ….

A. 15 kJ

B. 75 kJ

C. 90 kJ

D. 450 kJ

Mōhiotia:

Power (P) = 300 Watt = 300 Joule/second

Period (T) = 5 minutes = 5 (60 seconds) = 300 seconds

Number of rotation = 5

Hiahia: Energy used by the rotary comedy

Rongoā:

Mana - ngā raruraru me ngā otinga

Ko te whakautu tika ko D.

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  5. Te pūngao pūmanawa o ngā raruraru me ngā otinga o te puna rapa
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  10. Te whakamahinga o te tiakitanga o te pūngao miihini mō te nekehanga i runga i te paparangi piko
  11. Te whakamahinga o te tiaki i te pūngao miihini mō te nekehanga pere

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