Te nekehanga rārangi – ngā raruraru me ngā otinga

1. Ka tere te haere o tētahi mea i te tere pumau 10 m/s. Tātaihia te te nekehanga raina o te mea.

Kua mohiotia :

Mass (m) = 1 kg

tere (v) = 10 m/s

E hiahiatia ana: te nekehanga rārangi (p)

Rongoā:

Te tātai o te nekehanga rārangi:

p = mv

p = te nekehanga rārangi, m = te papatipu, v = te tere

Te nekehanga raina:

p = mv = (1)(10) = 10 kg m/s²

2. E neke ana tētahi poraka 2-kg me tētahi poraka 4-kg i te tere pumau 20 m/s. He aha te nekehanga rārangi o ngā poraka?

Mōhiotia:

Mass o te poraka A (m_A) = 2 kirokaramu

Mass o te poraka B (m_B) = 4 kirokaramu

Te tere o te poraka A (v_A) = 20 m/s

Te tere o te poraka B (v_B) = 20 m/s

E hiahiatia ana: Te nekehanga rārangi o te poraka A (p_A) me te nekehanga raina o te poraka B (p_B)

Rongoā:

Te nekehanga rārangi o te poraka A :

p_A = m_A v_A = (2)(20) = 40 kg m/s

Te nekehanga rārangi o te poraka B :

p_B = m_B v_B = (4)(20) = 80 kg m/s

3. Ka neke tētahi poraka 2-kg i te tere pumau 2 m/s, ā, ka neke tētahi poraka 2-kg i te tere pumau 4 m/s. Tātaihia te nekehanga rārangi o ngā poraka.

Mōhiotia:

Mass o te poraka A (m_A) = 2 kirokaramu

Te taumaha o te poraka B (m_B) = 2 kirokaramu

Te tere o te poraka A (v_A) = 2 m/s

Te tere o te poraka B (v_B) = 4 m/s

E hiahiatia ana: te nekehanga rārangi o ngā poraka

Rongoā:

M rārangipūngao o te poraka A :

p_A = m_A v_A = (2)(2) = 4 kg m/s

Te nekehanga rārangi o te poraka B:

p_B = m_B v_B = (2)(4) = 8 kg m/s

4. He mea 5-kg te taumaha e okioki ana. He aha te nekehanga rārangi o te nekehanga?

Mōhiotia:

Taumaha (m) = 5 kg

Te tere o te mea (v) = 0

hiahia : te nekehanga raina (p)

Rongoā:

p = mv = (5)(0) = 0

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