Ngā ara iahiko hiko me ngā ātete i roto i te ātete whakarara me te ātete ā-roto – ngā raruraru me ngā otinga

Ngā ara iahiko hiko me ngā ātete i roto i te ātete whakarara me te ātete ā-roto – ngā raruraru me ngā otinga

1. I runga i te ahua i raro nei, mēnā ko te pūtake o te kaha hiko (emf) he 24 Volts, whakatauhia hiko hiko I.

Mōhiotia:

Pūtake o te emf = 24 Volt

Ātete ā-roto (r) = 2 Ōhms

Tuhinga 40 Ōhm, 20 Ōhm, me te 20 Ōhm.

Wanted: Electric current I

Rongoā:

Resistors connected in parallel, the equivalent resistor :

1/R = 1/40 + 1/20 + 1/20

1/R = 1/40 + 2/40 + 2/40

1/R = 5/40

R = 40/5

R = 8 Ōhm

Terminal voltage :

V = emf – I r

V = 24 – I 2

Electric current I :

V = IR

24 – I 2 = I 8

24 = I 8 + I 2

24 = I (10)

I = 24/10

I = 2.4 Āmpere

2. Based on figure below, if R₁ = 3 Ω, R₂ = 4 Ω, R₃ = 4 Ω and electric current is 0.5 A. Determine ngaohiko hiko.

Mōhiotia:

Electric current (I) = 0.5 Ampere

Ātete R₁ = 3 Ōhm

Ātete R₂ = 4 Ōhm

Ātete R₃ = 4 Ōhm

E hiahiatia ana: Electric voltage (V)

Rongoā:

Calculate the equivalent resistance :

R₂ me R₃ e honoa ana i te taha whakarara. Ko te ātete ōrite:

1/R₂₃ = 1/R₂ + 1/R₃ = 1/4 + 1/4 = 2/4

R₂₃ = 4/2 = 2 Ohm

R₁ me R₂₃ ka honoa raupapa. Ko te ātete ōrite:

R = R₁ + R₂₃ = 3 + 2 = 5 Ohm

Electric voltage :

V = IR = (0.5)(5) = 2.5 Ngāohiko