Ngā Ture a Newton

E toru ngā ture nekehanga a Newton, arā, ko te ture tuatahi a Newton, ko te ture tuarua a Newton, me te ture tuatoru a Newton.

Te Ture Tuatahi a Newton

E ai ki te Ture Tuatahi a Newton, ko ia mea e okioki ana ka noho okioki tonu, ko ia mea rānei e neke ana i te rārangi tika i te tere pumau ka haere tonu i te neke i te rārangi tika i te tere pumau mena he kore te kaha katoa e pā ana ki te mea.

Whakaarohia tētahi mea e karapoti ana i a koe, hei tauira he tēpu, he toka rānei, he aha atu rānei. Ka noho tonu te tēpu e takoto ana ki te takoto mena kāore e nekehia, e kore rānei e tukuna he kaha o waho pēnei i te kaha pana, tō rānei. Waihoki, ko ētahi atu mea e takoto ana ki te takoto. Kāore he kaha e pā ana ki te tēpu, ki te toka rānei, ki tētahi atu mea rānei e takoto ana ki te takoto? He kaha e pā ana ki te mea, engari ko te tapeke o ngā kaha katoa e pā ana ki te mea, ki te kaha katoa rānei, he ōrite ki te kore. Ko ngā kaha e pā ana ki tētahi mea e takoto ana ki te takoto ki te mata o tētahi aorangi pēnei i a Papatūānuku ko te kaha ā-papa (w) me te kaha noa (N). Ko te ahunga o te kaha ā-papa he poutū ki waenganui o Papatūānuku, ko te ahunga o te kaha noa he poutū ki waenganui o Papatūānuku. He ōrite te rahi o ēnei kaha e rua engari he rerekē te ahunga, nō reira he ōrite te kaha katoa ki te kore.

Ā, me pēhea tētahi mea e neke ana i te rārangi tika me te tere pumau? Hei whakamārama i tēnei take, me kī ka panaia e koe tētahi mea, hei tauira, he wahi whakarewa, puta noa i te mata o te papa. Whai muri i te panaia, ka puhoi te nekehanga o te wahi whakarewa, kātahi ka mutu nā te kaha waku . Kia neke haere ai ngā wahi whakarewa, kia roa ake rānei, me whakangawari te mata o te papa me te mata o ngā wahi whakarewa. Ko te maeneene ake o te mata o te papa me te mata o ngā wahi whakarewa, ko te tawhiti ake o te nekehanga o ngā wahi whakarewa. Mena he tino maeneene te mata o te papa, ā, kāore he waku, ka haere tonu ngā wahi whakarewa ki te neke, ā, kāore e mutu. Kāore he kaha e pā ana ki tētahi wahi whakarewa e neke ana i runga i te mata papa tino maeneene? He kaha kei te mahi ki ngā wahi whakarewa, arā, ko te kaha ā-papa me ngā kaha noa. Ka mahi ēnei kaha e rua i te ahunga poutū, ā, kāore e pā ki te nekehanga o ngā wahi whakarewa i te ahunga whakapae mena he tino maeneene te papa.

Te Ture Tuarua a Newton

E ai ki te Ture Tuarua a Newton, ki te kore te kaha kupenga e pā ana ki tētahi mea i te kore, ka tere ake te mea. He rite te rahi o te whakaterenga ki te rahi o te kaha kupenga, ā, he rite whakamuri ki te papatipu o te mea. He rite te ahunga o te whakaterenga ki te ahunga o te kaha kupenga.

PĀNUITIA HOKI  Te ture tiaki i te pūngao miihini

ΣF = ma(1.2)

Whakaahuatanga: ΣF = te kaha katoa (kg m/s 2 ), m = te papatipu (kg), a = te whakaterenga (m/s 2 )

Ko te whārite 1.2 he tauākī pāngarau mō te ture tuarua a Newton.

Mena he ōrite te rahi o te whakaterenga ki te kore (a = 0) ka huri te whārite 1.2 ki te whārite 1.1. Nō reira, ko te ture tuatahi a Newton he take motuhake o te ture tuarua a Newton.

I runga i te whārite 1.2, ka whakatauhia ko te nui ake o te kaha, ko te nui ake o te whakaterenga. I tetahi atu taha, ko te nui ake o te papatipu, ko te iti ake o te whakaterenga. Ka mārama ake te whanaungatanga i waenga i te kaha, te papatipu, me te whakaterenga i muri i te whakahaere i ngā whakamātautau e pā ana ki tēnei. Ko tētahi whakamātautau ka taea te whakahaere ko te whakamātautau hei whakatere i tētahi tereina hihiri i runga i ngā rēri mā te whakamahi i tētahi papatipu e hinga noa ana. Whakamahia he taima tohu hei whakatau i te whakaterenga o te tereina.

Te Ture Tuatoru a Newton

E ai ki te ture tuatoru a Newton, mēnā ka pā te kaha o te mea 1 ki te mea 2, ka pā te kaha o te mea 2 ki te mea 1 i taua wā anō. He rite tonu te rahi o ngā kaha e rua engari he rerekē te ahunga o ngā kaha e rua. Ka kiia tētahi kaha ko te mahi, ko tētahi atu kaha ko te tauhohenga (kaha mahi-tauhohenga).

Mahi F = – Tauhohenga F (1.3)

Ko te whārite 1.3 he tauākī pāngarau mō te ture tuatoru o Newton. Ko te tohu kino i te whārite 1.3 e tohu ana i te ahunga o te kaha.

Whakahaerehia he whakamātautau kia pai ake ai te mārama ki te ture tuatoru a Newton. Mena he papa reti tāu, pana ki te pakitara i a koe e tū ana i runga. Whai muri i te pana ki te pakitara, ka neke whakamuri te papa reti. Ka pana whakamua tō pana, ka neke whakamuri te papa reti. E whakaatu ana tēnei kei te pana anō hoki te pakitara ki a koe. Ina pana koe ki te pakitara, i taua wā anō, kei te pana anō hoki te pakitara ki a koe. Ka mahi tō kaha pana ki te pakitara, ka mahi te kaha pana o te pakitara ki a koe. He ōrite te rahi o ngā kaha e rua engari he rerekē te ahunga. Ka taea e koe te kī ko tētahi kaha he mahi, ko tētahi he tauhohenga.

Ko tētahi atu whakamātautau ka taea e koe ko te pupuhi i tētahi poihau rapa, kātahi ka tukuna i muri i te pupuhi me te whakakī i te hau. I muri i te tukunga, ka "rere" te poihau. Ko te ahunga o te nekehanga o te poihau he ritenga kē ki te ahunga e puta ana te hau mai i te poihau. Me pēhea te whakamārama i tēnei? Ina tukuna te waha o te poihau, ka panaia e te poihau te hau ki waho. I taua wā anō, ka panaia hoki te poihau e te hau. Mā te pana o te hau ka rere te poihau. Ka pā te pana o te poihau ki te hau, ā, ka pā te pana o te hau ki te poihau. He ōrite te kaha o ngā kaha e rua engari he ritenga kē te ahunga.

PĀNUITIA HOKI  Dielectric

Tauira raruraru

1. E whā ngā mea, panana = 4 kg, pukapuka = ​​0,8 kg, poitūkohu = 3,5 kg, māngo = 1,2 kg. Ka tōia te kete me te kaha o te 30 N i runga i te mata papatahi taratara ( μ = 0,4). Kia tika ai te neke o te kete (kāore e arohia te taumaha o te kete), ko ngā mea me whakauru ki roto i te kete ko...

KōreroKōrero mō te Whakamātautau ā-Motu mō te Ahupūngao Kura Tuarua o te tau 2018 - 7

E mōhiotia ana:

Taumaha o te panana (m1 ) = 4 kg

Taumaha o te pukapuka (m² ) = 0,8 kg

Taumaha o te pōro (m3 ) = 3,5 kg

Taumaha o te māngo (m4 ) = 1,2 kg

Te kaha kume (F) = 30 N

Tauwehenga waku pumau ( μ s ) = 0,4

Te whakaterenga nā te kaha ā-papa (g) = 10 m/s 2

Kaua e aro ki te puranga kete

Ka mahi te kaha waku pumau (fs ) ina takoto kau ana te mea, ā, kua tata te neke, ko te kaha waku nekeneke ia ka mahi ina neke.

I pātaihia: Te taumaha o te mea

Whakautu:

Ka neke te kete ina rite te rahi o te kaha kukume (F) ki te rahi o te kaha waku pumau (fs ).

Tātaihia te rahi o te kaha waku pumau (f s ):

f s = μ s N = μ s w = μ s mg = (0,4)(m)(10)

fs = 4 m

Ka neke te kete tuturu:

F = fs

30 = 4 mita

m = 30/4

m = 7,5 kg

Taumaha o te panana 4 kg + taumaha o te pōro 3,5 kg = 7,5 kg

Ko ngā mea me whaowhina ki roto i te kete he panana me he pōro.

2. Pātai Whakamātautau ā-Motu SMA/MA 2014/2015 Nama 5

Kua honoa ngā mea A he 6 kg te taumaha me ngā mea B he 4 kg te taumaha mā te taura, ā, kua kumea mā te kaha F = 60 N e whakaatuhia ana i te pikitia e whai ake nei.

Mena kei te neke te pūnaha, ā, ko te tauwehenga o te waku nekeneke i waenga i te mata o te papa me ngā mea e rua he 0,5 (tg θ = 3/4), me te g = 10 ms -2 , ko te rahi o te kaha kume i roto i te taura T e hono ana i ngā mea e rua ko….

A. 28,8 NKōrero mō te Whakamātautau ā-Motu mō te Ahupūngao Kura Tuarua o te tau 2015 - 13

B. 30,0 N

C. 39,6 N

D. 48,0 N

E. 50,0 N

Kōrero

E mōhiotia ana:

Papatipu o te mea A (m A ) = 6 kg

Taumaha o te mea B (m B ) = 4 kg

Te kaha kume (F) = 60 Newton

Ko te tauwehenga o te waku nekeneke i waenga i te mea me te papa (μ k ) = 0,5

Te whakaterenga nā te kaha ā-papa (g) = 10 m/s 2

Pānga θ = 3/4

Pātai: E hia te rahi o te kume i roto i te taura T?

Whakautu:

Wāhanga whakapae o te kaha F:Kōrero mō te Whakamātautau ā-Motu mō te Ahupūngao Kura Tuarua o te tau 2015 - 14

F x = F cos θ

F x = (60)(4/5) = (4)(12) = 48 N

Wāhanga poutū o te kaha F:

F y = F sin θ

F y = (60)(3/5) = (3)(12) = 36 N

Te kaha noa o te mea A:

N A = w A = m A g = (6)(10) = 60 N

Te kaha noa o te mea B:

N B + F y – w B = 0

N B + F y = w B

N B = w B – F y = m B g – F y = (4)(10) – 36 = 40 – 36 = 4 N

Te kaha waku nekeneke i waenga i te mea A me te papa:

f kA = μ k N A = (0,5)(60) = 30 N

Te kaha waku nekeneke i waenga i te mea B me te papa:

PĀNUITIA HOKI  Ngā Tauira Pātai e Matapaki ana i te Nekehanga Ā-Whānui a Newton

f kB = μ k N B = (0,5)(4) = 2 N

Tātaihia te whakaterenga o ngā mea e rua:

ΣF = ma

F x – T + T – f kB – f kA = (m A + m B ) a

He rite tonu te kaha kume i roto i te aho T i te roanga o te aho, ā, he rerekē te ahunga, nō reira kua tangohia atu i te whārite.

F x – f kB – f kA = (m A + m B ) a

48 – 2 – 30 = (6 + 4) he

16 = 10

ā = 16/10

a = 1,6 m/s 2

Tātaihia te kaha kume o te taura T:

Whakaarohia te mea A. Ko ngā kaha e pā ana ki te mea A i te ahunga whakapae (whakapae) ko te kaha kume taura (T) e anga ana ki te taha matau me te kaha waku nekeneke (f kA ) e anga ana ki te taha maui.

ΣF = ma

T A – f kA = m A a

T A – 30 = (6)(1,6)

T A – 30 = 9,6

TA = 9,6 + 30 = 39,6 N

Whakaarohia te mea B. Ko ngā kaha e pā ana ki te mea B i te ahunga whakapae (whakapae) ko te kaha F x e anga ana ki te taha matau, te kaha waku nekeneke (f kB ) me te kaha kume taura (T) e anga ana ki te taha maui.

ΣF = ma

F x – f kB – T B = m B a

48 – 2 – T B = (4)(1,6)

46 – T B = 6,4

46 – 6,4 = T B

T B = 39,6 N

Nō reira, ko te kaha kume i roto i te taura e pā ana ki te mea A (T A ) = ko te kaha kume i roto i te taura e pā ana ki te mea B (T B ) = 39,6 N.

Ko te whakautu tika ko C.

3. Ngā Pātai Whakamātautau ā-Motu mō te Ahupūngao SMA/MA 2014/2015 Nama 5

Tirohia te pikitia e whai ake nei!

Nā te kaha F, ka neke te pūnaha o ngā mea. Mena he taratara te papa, ā, ko te tauwehenga o te waku nekeneke i waenga i ngā poraka e rua me te papa he 0,2, he aha te whakaterenga e pā ana ki ngā mea e rua? (cos 37 o = 0,8 , sin 37 o = 0,6)

A. 2,6 ms-2Kōrero mō te Whakamātautau ā-Motu mō te Ahupūngao Kura Tuarua o te tau 2015 - 15

B. 4,0 ms -2

C. 5,2 ms -2

D. 7,8 ms -2

E. 10,2 ms -2

Kōrero

E mōhiotia ana:

Papatipu o te mea A (m A ) = 4 kg

Taumaha o te mea B (m B ) = 2 kg

Te kaha kume (F) = 30 Newton

Ko te tauwehenga o te waku nekeneke i waenga i te mea me te papa (μ k ) = 0,2

Te whakaterenga nā te kaha ā-papa (g) = 10 m/s 2

cos 37 o = 0,8

hara 37 o = 0,6

Pātai: He aha te whakaterenga ka pā ki ngā mea e rua?

Whakautu:

Wāhanga whakapae o te kaha F:Kōrero mō te Whakamātautau ā-Motu mō te Ahupūngao Kura Tuarua o te tau 2015 - 16

F x = F cos θ

F x = (30)(0,8) = 24 N

Wāhanga poutū o te kaha F:

F y = F sin θ

F y = (30)(0,6) = 18 N

Te kaha noa o te mea A:

N A = w A = m A g = (4)(10) = 40 N

Te kaha noa o te mea B:

N B + F y – w B = 0

N B + F y = w B

N B = w B – F y = m B g – F y = (2)(10) – 18 = 20 – 18 = 2 N

Te kaha waku nekeneke i waenga i te mea A me te papa:

f kA = μ k N A = (0,2)(40) = 8 N

Te kaha waku nekeneke i waenga i te mea B me te papa:

f kB = μ k N B = (0,2)(2) = 0,4 N

Tātaihia te whakaterenga o ngā mea e rua:

ΣF = ma

F x – f kB – f kA = (m A + m B ) a

24 – 0,4 – 8 = (4 + 2) he

15,6 = 6

ā = 15,6/6

a = 2,6 m/s 2

Ko te whakautu tika ko A.