Ngā pātai tauira vector

25 Ngā Tauira o ngā Raruraru Wetereo

1. E rua ngā kaha e tū poutū ana tetahi ki tetahi, ko te rahi o ia kaha he 3 N me te 4 N. Ko te rahi o te hua o ngā kaha e rua ko...
Kōrero
E mōhiotia ana:
F₁ = 3 N, F₂ = 4 N
Pātai: He aha te hua o ngā whārite e rua?
Whakautu:
E rua anake ngā whārite, ā, he poutū ngā whārite e rua tetahi ki tetahi, nō reira ka whakamahia te tātai Pythagoras hei whakaoti.
2. Mena ko te rahi o te whārite A = 4 waeine, ka hangaia he koki o te 30^o me te tuaka-x pai, ko te rahi o te ira i te tuaka-x me te tuaka-y ko...
Kōrero
E mōhiotia ana:
A = 4 ngā waeine, Koki = 30^o
I pātaihia: A_x me A_y ?
Whakautu:
3. E rua ngā whākapū kaha F₁ me F₂ he 5 N te rahi o ia whāriki, he 12 N hoki te rahi, he rite tonu te pūwāhi whakapā, ā, e tūtaki ana tetahi ki tetahi i te koki 60°, ko te uara hua o ngā whāriki e rua ko...
Kōrero
E mōhiotia ana:
F₁ = 5 N, F₂ = 12 N, koki = 60^o
Pātai: He aha te hua o ngā whārite e rua?
Whakautu:
E rua noa iho ngā whārite, ā, kāore ngā whārite e rua e poutū ana tetahi ki tetahi (kei te koki 60° tetahi ki tetahi).^o) nō reira, ko te otinga o te raruraru e whakamahi ana i te tātai kosinī.
4. i roto i₁ = 20 ngā waeine me te v₂ = 20 ngā waeine. E hia te rahi o te whārite hua?

Kōrero
Te tatau i te whārite wāhanga:
v_1x = v₁ whaimana 30^o = (20)(½√3) = -10√3
v_1y = v₁ hara 30^o = (20)(½) = 10
v_2x = v₂ whaimana 30^o = (20)(½√3) = 10√3
v_2y = v₂ hara 30^o = (20)(½) = 10

v_x = v₁x + v₂x = -10√3 + 10√3 = 0
v_y = v₁y + v₂y = 10 + 10 = 20

Whakaahuatanga: v_1x tohu kino nā te ahunga o v_1x ki te taha mauī, i te tuaka-x kino. v_2x he pai nā te mea kei te taha matau te ahunga, kei te taha rānei o te tuaka-x pai. v_1y me te v_2y he pai nā te mea kei te ahu whakarunga tōna ahunga i te ahunga o te tuaka-y pai. Hei kimi i te ahunga o ia whārite wāhanga, me te mea he pai, he kino rānei te whārite wāhanga, tuhia te whārite wāhanga ki te tuaka-x me te tuaka-y e ai ki te tauira pātai nama 2.

Te tatau i te hua o te whārite:
Ko te rahi o te whārite hua he 20 ngā waeine

5. E oma ana tētahi tamaiti i te tawhiti o te 80 m ki te raki, kātahi ka huri ki te rawhiti mō te 80 m, ā, ki te tonga mō te 20 mita. nekehanga ko tā te tamaiti i mahi ai…

A. 60 mita
B. 80 mita
C. 100 mita
D. 120 mita
E. 180 m

Kōrero

Te nekehanga o te veka

Whakamahia te tātai Pythagorean:
Te Tai Rāwhiti
Ko te whakautu tika ko C

6. E 6 mita te hikoi a Budi ki te rawhiti, kātahi ka 6 mita ki te tonga, me te 2 mita ki te rawhiti. Ko te nekehanga o Budi mai i tōna tūranga tīmatanga ko...

A. 20 mita
B. 14 mita
C. 12 mita
D. 10 mita
E. 8 m

Kōrero

Whakamahia te tātai Pythagorean:

Te ahunga ki te tonga-mā-rāwhiti
Ko te whakautu tika ko D.

7.

Ko te hua o ngā kaha e toru i te ahua i te taha ko…

A. 24 N
B. 16 N
C. 12 N
D. 10 N
E. 4 N

Kōrero
E mōhiotia ana :
F₁ = 20 Newton, Koki i waenganui i te F₁ ā, ko te tuaka-x = 0
F₂ = 20 Newton, Koki i waenganui i te F₂ ā, ko te tuaka-x = 60
F₃ = 24 Newton, Koki i waenganui i te F₃ ā, ko te tuaka-x = 60
I pātaihia : Ko te hua o ngā kaha e toru (F₁, F₂ me F₃)
Whakautu :

Ngā wāhanga o te ira kaha i runga i ngā tuaka x me y
F_1x = (F₁)(cos 0) = (20)(1) = 20. He pai nā te mea kei te ahunga kotahi ki te tuaka x pai (ki te taha matau)
F_1y = (F₁)(hara 0) = (20)(0) = 0
F_2x = (F₂)(cos 60) = (20)(0,5) = -10. He kino nā te mea kei te ahunga kotahi ki te tuaka x tōraro (ki te taha mauī)
F_2y = (F₂)(sin 60) = (20)(0,5√3) = 10√3. He pai nā te mea kei te ahunga kotahi ki te tuaka y pai (ki runga)
F_3x = (F₃)(cos 60) = (24)(0,5) = -12. He kino nā te mea kei te ahunga kotahi ki te tuaka x tōraro (ki te taha mauī)
F_3y = (F₃)(sin 60) = (24)(0,5√3) = -12√3. He kino nā te mea kei te ahunga kotahi ki te tuaka y kino (ki raro)
Te hua o ngā wāhanga irahiko kaha i runga i ngā tuaka x me y
F_x =F_1x - F_2x - F_3x = 20 – 10 – 12 = -2
F_y =F_1y +F_2y - F_3y = 0 + 10√3 – 12√3 = -2√3
Te tuatoru o ngā hua rahinga wetere kāhua
Ko te whakautu tika ko E.

8.

Te whārite kaha F₁, F₂, me F₃ kei runga i te tūtohi Cartesian e whakaaturia ana i te pikitia:
Ko te hua o ngā whārite e toru ko…

A. √26 N
B. √76 N
C. √84 N
D. √168 N
E. √204 N

Kōrero
E mōhiotia ana :
F₁ = 12 Newton, Koki i waenganui i te F₁ ā, ko te tuaka-x = 30
F₂ = 10 Newton, Koki i waenganui i te F₂ ā, ko te tuaka-x = 90
F₃ = 8 Newton, Koki i waenganui i te F₃ ā, ko te tuaka-x = 30
I pātaihia : Ko te hua o ngā whārite kaha e toru (F₁, F₂ me F₃)
Whakautu :
Ngā wāhanga o te ira kaha i runga i ngā tuaka x me y
F_1x = (F₁)(cos 30) = (12)(0,5√3) = 6√3. He pai nā te mea kei te ahunga kotahi ki te tuaka x pai (ki te taha matau)
F_1y = (F₁)(hara 30) = (12)(0,5) = 6. Pai nā te mea kei te ahunga kotahi ki te tuaka y pai (ki runga)
F_2x = (F₂)(cos 90) = (10)(0) = 0.
F_2y = (F₂)(hara 90) = (10)(1) = -10. He kino nā te mea kei te ahunga kotahi ki te tuaka y kino (ki raro)
F_3x = (F₃)(cos 30) = (8)(0,5√3) = -4√3. He kino nā te mea kei te ahunga kotahi ki te tuaka x tōraro (ki te taha mauī)
F_3y = (F₃)(hara 30) = (8)(0,5) = -4. He kino nā te mea kei te ahunga kotahi ki te tuaka y kino (ki raro)
Te hua o ngā wāhanga irahiko kaha i runga i ngā tuaka x me y
F_x =F_1x +F_2x - F_3x = 6√3 + 0 – 4√3 = 2√3
F_y =F_1y - F_2y - F_3y = 6 – 10 – 4 = -8
Te hua o ngā whārite kaha e toru
Ko te whakautu tika ko B.

9. Tirohia te pikitia kei te taha. Ko te rahi o te hua o ngā kaha e toru ko…
A. 0
B. 2√3 N
C. 4√3 N
D. 8√3 N
E. 12√3 N
Kōrero
E mōhiotia ana :
F₁ = 4 Newton, Koki i waenganui i te F₁ ā, ko te tuaka-x = 30
F₂ = 6√3 Newton, Koki i waenganui i a F₂ ā, ko te tuaka-x = 0
F₃ = 2 Newton, Koki i waenganui i te F₃ ā, ko te tuaka-x = 90
I pātaihia : Te rahi o te hua o ngā kaha e toru (F₁, F₂ me F₃)
Whakautu :
Ngā wāhanga o te ira kaha i runga i ngā tuaka x me y
F_1x = (F₁)(cos 30) = (4)(0,5√3) = 2√3. He pai nā te mea kei te ahunga kotahi ki te tuaka x pai (ki te taha matau)
F_1y = (F₁)(hara 30) = (4)(0,5) = 2. Pai nā te mea kei te ahunga kotahi ki te tuaka y pai (ki runga)
F_2x = (F₂)(cos 0) = (6√3)(1) = -6√3. He kino nā te mea kei te ahunga kotahi ki te tuaka x tōraro (ki te taha mauī)
F_2y = (F₂)(hara 0) = (6√3)(0) = 0.
F_3x = (F₃)(cos 90) = (2)(0) = 0.
F_3y = (F₃)(hara 90) = (2)(1) = -2. He kino nā te mea kei te ahunga kotahi ki te tuaka y kino (ki raro)
Te hua o ngā wāhanga irahiko kaha i runga i ngā tuaka x me y
F_x =F_1x - F_2x +F_3x = 2√3 – 6√3 + 0 = -4√3
F_y =F_1y +F_2y - F_3y = 2 + 0 – 2 = 0
Te hua o ngā whārite kaha e toru
Ko te whakautu tika ko C.

10. Ka hikoi tika te tamaiti ki te hauauru mō te 10 mita, kātahi ka huri ki te tonga mō te 4 mita, ka huri anō ki te rawhiti mō te 13 mita. Ko te nekehanga o te tamaiti mai i te tūranga tīmatanga ko...
A. 4 mita ki te tonga mā uru
B. 5 mita ki te tonga
C. 5 mita ki te tonga-mā-rāwhiti
D. 10 mita ki te rawhiti
E. 10 mita ki te tonga-mā-rāwhiti

Kōrero

Ko te whakautu tika ko C.

11. Ko te hua o ngā kaha e toru i roto i te ahua i te taha ko…

A. 1,0 N
B. 1,5 N
C. 1,9 N
D. 2,0 N
E. 2,3 N
Kōrero
Tātaihia te rahi o ia waeine whārite:
F_1x = 10 N
F_1y = 0
F_2x = -10 cos 60 = – (10)(0,5) = – 5 N
F_2y = 10 hara 60 = (10)(0,87) = 8,7 N
F_3x = -12 cos 60 = – (12)(0,5) = – 6 N
F_3y = -12 hara 60 = – (12)(0,87) = – 10,4 N
Whakatauhia te hua o te whārite:

12. E toru ngā whākapū o tētahi pūwāhi arotahi e whakaaturia ana i te pikitia. Ko te rahi o ia whākapū ko:
|V₁ | = 30 ngā waeine
|V₂ | = 30 ngā waeine
|V₃ | = 40 ngā waeine
Ko te rahi o te hua o ngā whārite e toru ko...
A. 30 ngā waeine
B. 40 ngā waeine
C. 50 ngā waeine
D. 90 ngā waeine
E. 110 ngā waeine
Kōrero
E mōhiotia ana:
V₁ = 30, Koki i waenganui i te V₁ ā, ko te tuaka-x = 30^o
V₂ = 30, Koki i waenganui i te V₂ ā, ko te tuaka-x = 30^o
V₃ = 40, Koki i waenganui i te V₃ ā, ko te tuaka-x = 0^o
Pātai: Ko te hua o ngā whārite e toru (V₁V₂ me V₃)
Whakautu:
Ngā wāhanga o te ira kaha i runga i ngā tuaka x me y
V_1x = (V₁)(cos 30^o) = (30)(0,5√3) = 15√3. He pai nā te mea kei te ahunga kotahi ki te tuaka-x pai (ki te taha matau)
V_1y = (V₁)(hara 30^o) = (30)(0,5) = 15. Pai nā te mea kei te ahunga kotahi ki te tuaka-y pai (ki runga)
V_2x = (V₂)(cos 30^o) = (30)(0,5√3) = -15√3. He kino nā te mea kei te ahunga kotahi ki te tuaka-x kino (ki te taha mauī)
V_2y = (V₂)(hara 30^o) = (30)(0,5) = 15. Pai nā te mea kei te ahunga kotahi ki te tuaka-y pai (ki runga)
V_3x = (V₃)(cos 0^o) = (40)(1) = 40. Pai nā te mea kei te ahunga kotahi ki te tuaka-x pai (ki te taha matau)
V_3y = (V₃)(hara 0^o) = (40)(0) = 0

13. E rua ngā kaha (he pūwāhi whakapā) e tū poutū ana tetahi ki tetahi, ko ō rāua rahi he 12 N me te 5 N. Ko te rahi o te hua o ngā kaha e rua ko…
A. 17 N
B. 15 N
C. 13 N
D. 9 N
E. 7 N
Kōrero
E mōhiotia ana:
Kāhua 1 (F₁) = 12 Niutona
Kāhua 2 (F₂) = 5 Niutona
E hiahiatia ana: Te hua o ngā kaha e rua (ΣF)
Whakautu:
He poutū te hononga o ngā kaha e rua tetahi ki tetahi, nō reira ka tatauhia te kaha hua mā te whakamahi i te tātai Pythagoras.

14. E whakaaturia ana i te pikitia e whai ake nei ngā whārite e toru o tētahi pūwāhi arotahi. Ko te rahi o ia whārite ko:
|V₁| = 30 ngā waeine
|V₂| = 30 ngā waeine
|V₃| = 40 ngā waeine
Ko te rahi o te hua o ngā whārite e toru ko...
A. 30 ngā waeine
B. 40 ngā waeine
C. 50 ngā waeine
D. 90 ngā waeine
E. 110 ngā waeine
Kōrero
E mōhiotia ana:
v₁ = 30 ngā waeine, e hanga ana i te koki o te 30^o ki te tuaka-x tōraro.
v₂ = 30 ngā waeine, e hanga ana i te koki o te 30^o ki te tuaka-x pai.
v₃ = 40 ngā waeine, e hanga ana i te koki o te 0^o ki te tuaka-x pai.
I pātaihia: Te hua o te whārite
Whakautu:
Tātaihia ngā wāhanga whārite:
v_1x = v₁ whaimana 30^o = (30)(0,5√3) = -15√3 (tohu kino nā te mea kei te ahunga kotahi ki te tuaka-x kino)
v_1y = v₁ hara 30^o = (30)(0,5) = 15 (tohu pai nā te mea kei te ahunga kotahi ki te tuaka-y pai)
v_2x = v₂ whaimana 30^o = (30)(0,5√3) = 15√3 (tohu pai nā te mea kei te ahunga kotahi ki te tuaka-x pai)
v_2y = v₂ hara 30^o = (30)(0,5) = 15 (tohu pai nā te mea kei te ahunga kotahi ki te tuaka-y pai)
v_3x = v₃ whaimana 0^o = (40)(1) = 40 (tohu pai nā te mea kei te ahunga kotahi ki te tuaka-x pai)
v_3y = v₃ hara 0^o = (40)(0) = 0

15. Ko te hua o ngā kaha e toru i te pikitia i raro nei ko...
A. 0 N
B. 2 N
C. 2√3 N
D. 3 N
E. 3√3 N
Kōrero
E mōhiotia ana:
F₁ = 3 Ka hangaia e ngā Newton he koki o te 60^o ki te tuaka-x pai
F₂ = 3 Ka hangaia e ngā Newton he koki o te 0^o ki te tuaka-x kino
F₃ = 6 Ka hangaia e ngā Newton he koki o te 60^o ki te tuaka-y kino
I pātaihia: Te kaha hua
Whakautu:
Tātaihia te whārite wāhanga:
F_1x =F₁ whaimana 60^o = (3)(0,5) = 1,5 N (tohu pai nā te mea kei te ahunga o te tuaka-x pai)
F_1y =F₁ hara 60^o = (3)(0,5√3) = 1,5√3 N (he tohu pai nā te mea kei te ahunga o te tuaka-y pai)
F_2x =F₂ whaimana 0^o = (3)(1) = -3 N (tohu kino nā te mea kei te ahunga o te tuaka-x kino)
F_2y =F₂ hara 0^o = (3)(0) = 0
F_3x =F₃ whaimana 60^o = (6)(0,5) = 3 N (tohu pai nā te mea kei te ahunga o te tuaka-x pai)
F_3y =F₃ hara 60^o = (6)(0,5√3) = -3√3 N (tohu kino nā te mea kei te ahunga o te tuaka-y kino)

16. E rua ngā whākapū kaha F₁ me F₂ he 15 N te rahi o ia whāriki, he 9 N hoki te rahi, he rite tonu te pūwāhi whakapā, ā, e tūtaki ana tetahi ki tetahi i te koki 60°, ko te uara hua o ngā whāriki e rua ko...
A. 15 N
B. 20 N
C. 21 N
D. 24 N
E. 30 N
Kōrero
E mōhiotia ana:
Kāhua 1 (F₁) = 15 Niutona
Kāhua 2 (F₂) = 9 Niutona
Koki (θ) = 60^o
Pātai: Te hua o ngā whārite e rua
Whakautu:
E rua ngā whārite e hanga ana i tētahi koki o te 60^o kia tatauhia ai te hua o te wetere mā te whakamahi i te tātai cosine:

17. Ko te hua o ngā kaha e toru i roto i te ahua i te taha ko…
A. 24 N
B. 16 N
C. 12 N
D. 10 N
E. 4 N
Kōrero
E mōhiotia ana:
F₁ = 20 Newton, Koki i waenganui i te F₁ ā, ko te tuaka-x = 0
F₂ = 20 Newton, Koki i waenganui i te F₂ ā, ko te tuaka-x = 60
F₃ = 24 Newton, Koki i waenganui i te F₃ ā, ko te tuaka-x = 60
Pātai: Ko te hua o ngā kaha e toru (F₁, F₂ me F₃)
Whakautu:
Ngā wāhanga o te ira kaha i runga i ngā tuaka x me y
F_1x = (F₁)(cos 0) = (20)(1) = 20. He pai nā te mea kei te ahunga kotahi ki te tuaka-x pai (ki te taha matau)
F_1y = (F₁)(hara 0) = (20)(0) = 0
F_2x = (F₂)(cos 60) = (20)(0,5) = -10. He kino nā te mea kei te ahunga kotahi ki te tuaka-x kino (ki te taha mauī)
F_2y = (F₂)(sin 60) = (20)(0,5√3) = 10√3. He pai nā te mea kei te ahunga kotahi ki te tuaka-y pai (ki runga)
F_3x = (F₃)(cos 60) = (24)(0,5) = -12. He kino nā te mea kei te ahunga kotahi ki te tuaka-x kino (ki te taha mauī)
F_3y = (F₃)(sin 60) = (24)(0,5√3) = -12√3. He kino nā te mea kei te ahunga kotahi ki te tuaka-y kino (ki raro)

18. Ka neke tētahi mea mai i E ki F, ā, ka mutu ki G. Ko te ahua i raro nei, e whakaatu ana i te nekehanga o te 10 waeine, ko...

Kōrero

Ngā taunga pūwāhi E = x, y = 1, 1

Ngā taunga pūwāhi F = x, y = 9, 1

Ngā taunga pūwāhi G = x, y = 9, 7

Te roa o te EF = 9-1 = 8

Te roa o te FG = 7-1 = 6

Te roa o te EG =

Ko te whakautu tika ko A.

19. Ka haere tētahi tangata mā runga waka mai i A ki B, 30 km ki te raki, kātahi ka haere tonu ki C, 60 km ki te rawhiti, ā, ka tae ki te tāone D, 110 km ki te tonga. Ko te nekehanga o te waka mai i A ki D ko...

A. 200 kiromita

B. 140 kiromita

C. 120 kiromita

D. 100 kiromita

E. 80 kiromita

Kōrero

AA' = 60 kiromita

A'D = 110 km – 30 km = 80 km

Ko te whakautu tika ko D.

20. Ka haere a Andi mā runga motuka mai i te tāone A ki te raki ki te tāone B mō te 100 km, kātahi ka haere tonu ki te tāone C ki te rawhiti mō te 60 km, kātahi ka haere a Andi ki te tonga ki te tāone D mō te 20 km. Ko te nekehanga o te motuka ko…

A. 10 kiromita

B. 20 kiromita

C. 80 kiromita

D. 100 kiromita

E. 180 kiromita

Kōrero

D'D = 60 kiromita

AD' = 100 km – 20 km = 80 km

Ko te whakautu tika ko D.

21. I te huihuinga "City Marathon Festival" i te Oketopa 2014 i Jakarta e whā ngā wāhanga oma, arā, ko te wāhanga marathon katoa (42 kiromita), kāwai hawhe marathon (21 kiromita), wāhanga 10 kiromita me te wāhanga 5 kiromita, kua whakatauhia te ara mō ia wāhanga. Ka tīmata tēnei reihi marathon mai i te Whare Hākinakina o Bung Karno ka mutu ki te Monument National (Monas). I whai wāhi tētahi o ngā kaiuru reihi, a Andri, ki te reihi. marathon katoa ā, ka taea anake e ia te haere i te ara mai i ngā pūwāhi A, B, me C pērā i whakaahua 2.

Mena he 1 km te roa o te pouaka kotahi, ko te nekehanga katoa i haerea e Andri ko…

A. 26 kiromita

B. 20 kiromita

C. 12 kiromita

D. 10 kiromita

E. 8 kiromita

Kōrero

Ko te roa o te taha o raro = 8 km, ko te roa o te taha o mua = 6 km.

Mā te whakamahi i te tātai Pythagorean, Te nekehanga = R = 10 km

Ko te whakautu tika ko D.

22. Ka haere tētahi tangata mā runga waka mai i A ki B, 30 km ki te raki, kātahi ka haere tonu ki C, 60 km ki te rawhiti, ā, ka tae ki te tāone D, 110 km ki te tonga. Ko te nekehanga o te waka mai i A ki D ko...

A. 200 kiromita

B. 140 kiromita

C. 120 kiromita

D. 100 kiromita

E. 80 kiromita

Kōrero

AA' = 60 kiromita

A'D = 110 km – 30 km = 80 km

Ko te whakautu tika ko D.

23. Ka haere a Andi mā runga motuka mai i te tāone A ki te raki ki te tāone B mō te 100 km, kātahi ka haere tonu ki te tāone C ki te rawhiti mō te 60 km, kātahi ka haere a Andi ki te tonga ki te tāone D mō te 20 km. Ko te nekehanga o te motuka ko…

A. 10 kiromita

B. 20 kiromita

C. 80 kiromita

D. 100 kiromita

E. 180 kiromita

Kōrero

D'D = 60 kiromita

AD' = 100 km – 20 km = 80 km

Ko te whakautu tika ko D.

Wāhanga Wāhanga

24. Ngā Pātai Whakamātautau ā-Motu 2000/2001
Ka neke te mea i te pūwāhi tohutoro i te tere v = (2i − 1,5h) ms^-1. I muri i te neke mō te 4 hēkona, kua neke te mea i te tawhiti o…
A. 2 mita
B. 10 mita
C. 12 mita
D. 14 mita
E. 25 m
Kōrero
E mōhiotia ana:
Tere i te ahunga whakapae (v_x) = 2 m/s
Te tere i te ahunga poutū (v_y) = 1,5 m/s
Wā wā (t) = 4 hēkona
I pātaihia: Te nekehanga o ngā mea
Whakautu:
Tātaihia te tere hua o te mea (v):

25. Ngā Pātai Whakamātautau ā-Motu 2007/2008 P4 Nama 3
Wēka F₁ = 14 N me F₂ = 10 Kua whakanohoia a N ki runga i tētahi hoahoa Cartesian e whakaaturia ana i te pikitia. Ko te hua o te wetetā mēnā ka whakaaturia ki ngā wetetā wae R = i + j ko….
A. 7i + 10√3 j
B. 7i + 10j
C. 3i + 7√3 j
D. 3i + 10j
E. 3i + 7j
Kōrero
Te tatau i te whārite wāhanga:
F_1x = (F₁)(cos 60^o) = (14)(0,5) = -7 N (tohu kino nā te mea kei te ahunga x kino)
F_1y = (F₁)(hara 60^o) = (14)(0,5√3) = 7√3 N (he tohu pai nā te mea kei te ahunga y pai)
F_2x = 10 N
F_2y = 0
Te tatau i te whārite wāhanga hua:
F_x =F_1x +F_2x +F_3x = -7 + 10 = 3 N
F_y =F_1y +F_2y +F_3y = 7√3 + 0 = 7√3 N
Ko te hua o te wekita mēnā ka whakaaturia i roto i ngā wekita kotahi:
R = 3 i + 7√3 j
Ko te whakautu tika ko C.

 

Pūtake pātai:

Ngā Pātai Ahupūngao Whakamātautau ā-Motu mō te Kura Tuarua/Kura Tuarua Mahi-ā-ringa

Ngā Pātai Wetereo
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